I am sure this is easy to accomplish but after spending the whole day trying I had to give up and ask for your help.
I have a table that looks like this
| PatientID | VisitId | DateOfVisit | FollowUp(Y/N) | FollowUpWks |
----------------------------------------------------------------------
| 123456789 | 2222222 | 20180802 | Y | 2 |
| 123456789 | 3333333 | 20180902 | Y | 4 |
| 234453656 | 4443232 | 20180506 | N | NULL |
| 455344243 | 2446364 | 20180618 | Y | 12 |
----------------------------------------------------------------------
Basically I have a list of PatientIDs, each patient can have multiple visits (VisitID and DateOfVisit). FollowUp(Y/N) specifies whether the patients has to be seen again and in how many weeks (FollowUpWks).
Now, what I need is a query that extracts PatientsID, DateOfVisit (the most recent one and only if FollowUp is YES) and the FollowUpWks field.
Final result should look like this
| PatientID | VisitId | DateOfVisit | FollowUp(Y/N) | FollowUpWks |
----------------------------------------------------------------------
| 123456789 | 3333333 | 20180902 | Y | 4 |
| 455344243 | 2446364 | 20180618 | Y | 12 |
----------------------------------------------------------------------
The closest I could get was with this code
SELECT PatientID,
Max(DateOfVisit) AS LastVisit
FROM mytable
WHERE FollowUp = True
GROUP BY PatientID;
The problem is that when I try adding the FollowUpWks field to the SELECT I get the following error: "The query does not include the specified expression as part of an aggregate function." However, if I add FollowUpWks to the GROUP BY statement than I get all visits, not just the most recent ones.
You need to match back to the most recent visit. One method uses a correlated subquery:
SELECT t.*
FROM mytable as t
WHERE t.FollowUp = True AND
t.DateOfVisit = (SELECT MAX(t2.DateOfVisit)
FROM mytable as t2
WHERE t2.PatientID = t.PatientID
);
Related
I need help getting the User which has an 'IN' and 'Out' in Column isIN. If the user has an IN and OUT do not select them in the list. I need to select the user who has only had an IN. Please I need help. Thanks in advance.
This is the table:
| Users | IsIN |
|:------------------:|:-----:|
| MHYHDC61TMJ907867 | IN |
| MHYHDC61TMJ907867 | OUT |
| MHYHDC61TMJ907922 | IN |
| MHYHDC61TMJ907922 | OUT |
| MHYHDC61TMJ907923 | IN |
| MHYHDC61TMJ907923 | OUT |
| MHYHDC61TMJ907924 | IN | - I need to get only this row
| MHYHDC61TMJ907925 | IN |
| MHYHDC61TMJ907925 | OUT |
| MHYHDC61TMJ908054 | IN | - I need to get only this row
| MHYHDC61TMJ908096 | IN | - I need to get only this row
| MHYHDC61TMJ908109 | IN | - I need to get only this row
Need to get the result like
| Users | IsIN |
|:------------------:|:-----:|
| MHYHDC61TMJ907924 | IN |
| MHYHDC61TMJ908054 | IN |
| MHYHDC61TMJ908096 | IN |
| MHYHDC61TMJ908109 | IN |
I tried using this query and sample query below but it doesn't work.
select s.[Users], s.[isIn] [dbo].[tblIO] s
where not exists (
select 1
from [dbWBS].[dbo].[tblIO] s2
where s2.[Users] = s.[Users] and s2.isIn = 'IN'
);
You can use not exists:
select s.*
from sample s
where not exists (select 1
from sample s2
where s2.user = s.user and s2.inout = 'OUT'
);
If you want only users that meet the condition (and not the full rows):
select user
from sample s
group by user
having min(inout) = max(inout) and min(inout) = 'IN';
Bearing in mind that an 'OUT' IsIn must be always preceded by an 'IN' record, you could use a query like this:
select s.Users, 'IN' as IsIn
from sample s
group by s.Users
having count(distinct s.IsIn) = 1
I have a one tables in Postgresql and cannot find how to build a query.
The table contains columns nr_serii and deleteing_time. I trying to count nr_serii and substract from this positions with deleting_time.
My query:
select nr_serii , count(nr_serii ) as ilosc,count(deleting_time) as ilosc_delete
from MyTable
group by nr_serii, deleting_time
output is:
+--------------------+
| "666666";1;1 |
| "456456";1;0 |
| "333333";3;0 |
| "333333";1;1 |
| "111111";1;1 |
| "111111";3;0 |
+--------------------+
The part of table with raw data:
+--------------------------------+
| "666666";"2020-11-20 14:08:13" |
| "456456";"" |
| "333333";"" |
| "333333";"" |
| "333333";"" |
| "333333";"2020-11-20 14:02:23" |
| "111111";"" |
| "111111";"" |
| "111111";"2020-11-20 14:08:04" |
| "111111";"" |
+--------------------------------+
And i need substract column ilosc and column ilosc_delete
example:
nr_serii:333333 ilosc:3-1=2
Expected output:
+-------------+
| "666666";-1 |
| "456456";1 |
| "333333";2 |
| "111111";2 |
| ... |
+-------------+
I think this is very simple solution for this but i have empty in my head.
I see what you want now. You want to subtract the number where deleting_time is not null from the ones where it is null:
select nr_serii,
count(*) filter (where deleting_time is null) - count(deleting_time) as ilosc_delete
from MyTable
group by nr_serii;
Here is a db<>fiddle.
I have the following table running on Postgres SQL 9.5:
+---+------------+-------------+
|ID | trans_id | message |
+---+------------+-------------+
| 1 | 1234567 | abc123-ef |
| 2 | 1234567 | def234-gh |
| 3 | 1234567 | ghi567-ij |
| 4 | 8902345 | ced123-ef |
| 5 | 8902345 | def234-bz |
| 6 | 8902345 | ghi567-ij |
| 7 | 6789012 | abc123-ab |
| 8 | 6789012 | def234-cd |
| 9 | 6789012 | ghi567-ef |
|10 | 4567890 | abc123-ab |
|11 | 4567890 | gex890-aj |
|12 | 4567890 | ghi567-ef |
+---+------------+-------------+
I am looking for the rows for each trans_id based on a LIKE query, like this:
SELECT * FROM table
WHERE message LIKE '%def-234%'
This, of course, returns just three rows, the three that match my pattern in the message column. What I am looking for, instead, is all the rows matching that trans_id in groups of messages that match. That is, if a single row matches the pattern, get all the rows with the trans_id of that matching row.
That is, the results would be:
+---+------------+-------------+
|ID | trans_id | message |
+---+------------+-------------+
| 1 | 1234567 | abc123-ef |
| 2 | 1234567 | def234-gh |
| 3 | 1234567 | ghi567-ij |
| 4 | 8902345 | ced123-ef |
| 5 | 8902345 | def234-bz |
| 6 | 8902345 | ghi567-ij |
| 7 | 6789012 | abc123-ab |
| 8 | 6789012 | def234-cd |
| 9 | 6789012 | ghi567-ef |
+---+------------+-------------+
Notice rows 10, 11, and 12 were not SELECTed because there was not one of them that matched the %def-234% pattern.
I have tried (and failed) to write a sub-query to get the all the related rows when a single message matches a pattern:
SELECT sub.*
FROM (
SELECT DISTINCT trans_id FROM table WHERE message LIKE '%def-234%'
) sub
WHERE table.trans_id = sub.trans_id
I could easily do this with two queries, but the first query to get a list of matching trans_ids to include in a WHERE trans_id IN (<huge list of trans_ids>) clause would be very large, and would not be a very inefficient way of doing this, and I believe there exists a way to do it with a single query.
Thank you!
This will do the job I think :
WITH sub AS (
SELECT trans_id
FROM table
WHERE message LIKE '%def-234%'
)
SELECT *
FROM table JOIN sub USING (trans_id);
Hope this help.
Try this:
SELECT ID, trans_id, message
FROM (
SELECT ID, trans_id, message,
COUNT(*) FILTER (WHERE message LIKE '%def234%')
OVER (PARTITION BY trans_id) AS pattern_cnt
FROM mytable) AS t
WHERE pattern_cnt >= 1
Using a FILTER clause in the windowed version of COUNT function we can get the number of records matching the predefined pattern within each trans_id slice. The outer query uses this count to filter out irrelevant slices.
Demo here
You can do this.
WITH trans
AS
(SELECT DISTINCT trans_id
FROM t1
WHERE message LIKE '%def234%')
SELECT t1.*
FROM t1,
trans
WHERE t1.trans_id = trans.trans_id;
I think this will perform better. If you have enough data, you can do an explain on both Sub query and CTE and compare the output.
I have a table with following stock data where we have couple of columns like date, ticker, open and close(stock prices).
To query this data, I want to know which stock has given the highest margin on particular date. So if I have 516 different stocks, my query should return 516 rows of ticker, date, open, close and a new column Margin(which will be max(close-open)).
| deep_stocks.date_ | deep_stocks.ticker | deep_stocks.open | deep_stocks.close |
+--------------------+---------------------+-------------------+--------------------+--+
| 20100721 | A | 27.68 | 27.58 |
| 20100722 | A | 27.95 | 28.72 |
| 20100723 | A | 28.56 | 29.3 |
| 20100726 | A | 29.22 | 29.64 |
| 20100727 | A | 29.73 | 28.87 |
| 20100728 | A | 28.79 | 28.78 |
| 20100729 | A | 28.97 | 28.15 |
| 20100730 | A | 27.78 | 27.93 |
| 20100802 | A | 28.35 | 28.82 |
| 20100803 | A | 28.7 | 27.84 |
I have written a query where my approach was:
Step 1 - Get the difference between Close and Open prices (Inner/Sub query)
Step 2 - Get the maximum of margin for every stock (used group by with max function)
Step 3 - Join the results with Main Table and get the data.
I'll put my query in solution or comments can someone please correct it as it is taking more time. Also I would like to know can we have any other alternative approach.
As already told about my approach please find below query:
SELECT ds.ticker, ds.date_, ds.close, ds.open, ds.Margin FROM
(SELECT ticker, date_, close, open, case(close-open)>0 when true then round(close-open,2) else 0 end as Margin FROM DataStocks) ds
JOIN
(SELECT dsIn.ticker, max(dsIn.Margin) mxMargin FROM
(select ticker, case(close-open)>0 when true then round(close-open,2) else 0 end as Margin FROM DataStocks ) dsIn group by dsIn.ticker) dsEx
ON ds.ticker=dsEx.ticker AND ds.Margin=dsEx.mxMargin ORDER BY ds.Margin;
Do we have any other alternatives for this query or can it be possible to optimize it.
my table name is tbl1. The fileds are id,name,txdate.
| ID | NAME | TXDATE |
| 1 | RAJ | 1-1-2013 |
| 2 | RAVI | |
| 3 | PRABHU | 25-3-2013 |
| 4 | SAT | |
Now i want to use select query for check txdate < 2-2-2013 in which rows have txdate not empty and the select also retrun which rows have txdate empty.
The Result is like this
| ID | NAME | TXDATE |
| 1 | RAJ | 1-1-2013 |
| 2 | RAVI | |
| 4 | SAT | |
Any feasible solution is there?.
With out using union it is possible?.
Assuming that the TXDATE is of data type DATE then you can use WHERE "TXDATE" < '2013-2-2' OR "TXDATE" IS NULL. Something like:
SELECT *
FROM table1
WHERE "TXDATE" < '2013-2-2'
OR "TXDATE" IS NULL;
See it in action:
SQL Fiddle Demo
I don't now what database your are using and what data type the TXDATE is.
I just tried on my postgreSQL 9.2, with a field "timestamp without time zone".
I have three rows in the table , like:
ac_device_name | ac_last_heartbeat_time
----------------+-------------------------
Nest-Test1 |
Nest-Test3 |
Nest-Test2 | 2013-04-10 15:06:18.287
Then use below statement
select ac_device_name,ac_last_heartbeat_time
from at_device
where ac_last_heartbeat_time<'2013-04-11';
It is ok to return only one record:
ac_device_name | ac_last_heartbeat_time
----------------+-------------------------
Nest-Test2 | 2013-04-10 15:06:18.287
I think you can try statement like:
select * from tbl1 where TXDATE<'2-2-2013' and TXDATE is not NULL
this statement also works in my environment.