Convert datetime to UTC beginning of the day - Oracle db - sql

For example:
I've got datetime in Oracle database like: 18/08/21 13:51:23,420460500 (y/m/d) and I want convert to type: 18/08/20 22:00:00,000000000.
Could you please let me know how can I do this?
I've tried SYS_EXTRACT_UTC("MyDate") but it does not work in that case.

From the format of your question, I'm assuming you have a TIMESTAMP value, since Oracle doesn't have a "datetime" data type. You can truncate the time component to midnight (the beginning of the day) with the TRUNC function, though it returns a DATE data type. I'm not sure where the 22:00 in your question is coming from.

Related

How to convert Local_Timestamp into UTC Timestamp?

The Timestamp is the localtime of the DB2 Server.
The date was stored in the time zone Europe / Berlin.
I would like to convert the then stored date to UTC. Is there a way to calculate this in DB2 Dialect?
Check out the TO_UTC_TIMESTAMP scalar function
values TO_UTC_TIMESTAMP(TIMESTAMP'2019-10-01 00:00:00', 'Europe/Berlin')
Please note the second parameter is case sensitive.
There is also a FROM_UTC_TIMESTAMP if needed.
Your best bet is to use the TIMEZONE function and to use CURRENT TIMEZONE as help for the input.
The function converts date and time from one to another timezone. The register CURRENT TIMEZONE gives you the difference between server timezone and UTC.
As #data_henrik pointed out, CURRENT TIMEZONE is the special register to use, it can be simply subtracted from CURRENT TIMESTAMP e.g.:
db2 "values CURRENT TIMESTAMP - CURRENT TIMEZONE"
1
--------------------------
2019-10-16-11.36.24.025651
1 record(s) selected.

Oracle Date Conversion from a sybase table

I am trying to use Oracle SQL Developer to import a CSV file to a table. One of the fields is in day/time format. An example of such a date is '9/15/1993 12:00:00.000 AM'. IN SQL Developer when it asks me what date format to use I enter MM/DD/YYYY HH:MI:SS AM but this creates a ORA-01855 error complaining about AM so I imagine something is wrong. Any ideas?
It's probably more likely to be the milliseconds rather than the AM/PM indicator. Convert to a timestamp first then cast to date: String to date in Oracle with milliseconds

Conversion date in the format timestamp

I have a date as a timestamp . I have to replace it every day on the date of beginning of 7:00:00 hours a day from the date of timestamp for example . 11-07-2016 7:00:00
For example, I have a date after changing 837072216 837241200 it will need a scalar function .
Your question is very unclear. In fact, there is no actual question...
Never-the-less, you appear to be asking about a conversion from timestamp to a date or time. This is not possible; despite its name, timestamp does not represent a date(time). It is used for versioning of rows, and it's deprecated and replaced by rowversion. Source.

EXTRACT the date and time - (Teradata)

I am trying to extract the date and time from a field in Teradata.
The field in question is:
VwNIMEventFct.EVENT_GMT_TIMESTAMP
Here is what the data look like:
01/02/2012 12:18:59.306000
I'd like the date and time only.
I have tried using EXTRACT(Date, EXTRACT(DAY_HOUR and a few others with no success.
DATE_FORMAT() does not appear to work since I'm on Teradata.
How would I select the date and time from VwNIMEventFct.EVENT_GMT_TIMESTAMP?
If the datatype of EVENT_GMT_TIMESTAMP is a TIMESTAMP, it's simple Standard SQL:
CAST(EVENT_GMT_TIMESTAMP AS DATE)
CAST(EVENT_GMT_TIMESTAMP AS TIME)
If it's a CHAR you need to apply a FORMAT, too:
CAST(CAST(EVENT_GMT_TIMESTAMP AS TIMESTAMP FORMAT 'dd/mm/yyyyBhh:mi:SS.s(6)') AS DATE)
CAST(CAST(EVENT_GMT_TIMESTAMP AS TIMESTAMP FORMAT 'dd/mm/yyyyBhh:mi:SS.s(6)') AS TIME)
Edit:
For simply changing the display format you need to add a FORMAT and a CAST to a string:
CAST(CAST(EVENT_GMT_TIMESTAMP AS FORMAT 'YYYYMMDDHHMI') AS CHAR(12))
or
CAST(CAST(EVENT_GMT_TIMESTAMP AS FORMAT 'YYYYMMDDHHMISS') AS CHAR(14))
If you don't care about display, just want to truncate the seconds:
EVENT_GMT_TIMESTAMP - (EXTRACT(SECOND FROM EVENT_GMT_TIMESTAMP) * INTERVAL '1.000000' SECOND)
Working with timestamps is a bit tricky :-)
I know this is an old topic, but I've struggled with this too. Try:
CAST(EVENT_GMT_TIMESTAMP AS TIMESTAMP(0))
The result will be
01/02/2012 12:18:59
The datatype will still be timestamp, but it will just be the date and time with no microseconds (looks just like a datetime object in Microsoft SQL).

Convert date value to PST for comparison:Oracle

I have 2 questions:
I want to compare a field whose data type is "Date" against a given date. The DB is oracle and being a mysql guy I'm finding it difficult to come up with simple queries.
The field("date_closed") stores date in UTC format (24-Aug-2011 18:55:11 for example) and I want to convert it to PST for comparison.
I tried this query but it returns some extra rows in the data set(obviously):
select * from table1 where trunc(date_closed)=to_date('2011-08-24','yyyy-mm-dd')
How do I covert to PST format before comparison?
In the same query how do I compare "date_closed" against the current date?
You need the NEW_TIME function
Dates don't include timezone in Oracle, and are assumed to be in the database timezone (which may by UTC but probably isn't). You should look at the TIMESTAMP WITH TIMEZONE data types.
Also, bear in mind that if you are comparing to the current date - I assume that you want to strip off the timestamp and compare only the day.
So, if new_time(date_closed,'GMT','PST') translates the date , your where clause will be comparing something like
trunc(new_Time(date_closed,'GMT','PST')) = trunc(sysdate)
to get all records with date_closed on the current day in PST.