I have a date as a timestamp . I have to replace it every day on the date of beginning of 7:00:00 hours a day from the date of timestamp for example . 11-07-2016 7:00:00
For example, I have a date after changing 837072216 837241200 it will need a scalar function .
Your question is very unclear. In fact, there is no actual question...
Never-the-less, you appear to be asking about a conversion from timestamp to a date or time. This is not possible; despite its name, timestamp does not represent a date(time). It is used for versioning of rows, and it's deprecated and replaced by rowversion. Source.
Related
I need to convert 2021-10-03 15:10:00.0 as 2021-10-03T15:10:00-04:00
I tried with.
from_utc_timestamp(from_unixtime(unix_timestamp('2021-10-03 15:10:00.0', "yyyy-MM-dd HH:mm:ss.S"),"yyyy-MM-dd'T'HH:mm:ssXXX"),"America/New_York")
I got Null value
Any suggestions please
from_utc_timestamp can accept timestamp or compatible string (yyyy-MM-dd HH:mm:ss.S), or bigint, not this: "yyyy-MM-dd'T'HH:mm:ssXXX"
Hive timestamps are timezoneless. Once you converted from UTC to America/NY, the timezone information is lost, only you know in which timezone it is, having timestamp converted it is already impossible to derive the timezone from it.
You can concatenate with timezone, conversion like this returns what you need but it works for particular date only. In December -05:00 timezone should be usedm not +04:00:
date_format(from_utc_timestamp('2021-10-03 15:10:00.0',"America/New_York"),"yyyy-MM-dd'T'HH:mm:ss+04:00") --This is wrong!!!
From_utc_timestamp is Daylight saving aware. It can be -05:00 or -04:00 depending on the date.
Consider this example, first returns 5, second returns 4:
select (unix_timestamp("2020-01-01 12:00:00.0")-unix_timestamp(from_utc_timestamp("2020-01-01 12:00:00.0","America/New_York")))/60/60
select (unix_timestamp("2020-10-19 12:00:00.0")-unix_timestamp(from_utc_timestamp("2020-10-19 12:00:00.0","America/New_York")))/60/60
So, you can get current time zone corresponding to America/New_York for the same timestamp and concatenate it with converted timestamp:
select concat(date_format(from_utc_timestamp('2021-10-03 15:10:00.0',"America/New_York"),"yyyy-MM-dd'T'HH:mm:ss"),'+0',
--get hrs shift
(unix_timestamp("2021-10-03 15:10:00.0")-unix_timestamp(from_utc_timestamp("2021-10-03 15:10:00.0","America/New_York"))) div 3600,':00')
Result:
2021-10-03T11:10:00+04:00
It should work correctly with different timestamps taking into account daylight saving time for America/New_York.
I have a Oracle SQL statement where I have to get the current timestamp as one of the columns. But I dont require the Timezone which CURRENT_TIMESTAMP gives or the AM/PM given by LOCALTIMESTAMP.
I require the current timestamp in 24hr format without the timezone.
Is it possible to get that in Oracle SQL?
It seems you're mixing 2 concepts here: "datatype" and "date format mask".
data type: LOCALTIMESTAMP returns datatype TIMESTAMP and CURRENT_TIMESTAMP returns datatype TIMESTAMP WITH TIME ZONE. TIMESTAMP is similar to DATE but has a higher precision. As usual... checking the docs is worth it.
date format mask: determines how you display the date information. Americans can't read 24 hour format, the rest of the world is confused by AM/PM. Fortunately, you can decide how you want to display the date as explained in the oracle docs.
If you just want to return the current date in 24 hour format you could do something like:
SELECT
TO_CHAR(SYSDATE,'DD-MON-YYYY HH24:MI:SS') as mydate,
<other columns>
FROM
<table_name>
If you need the date to be more precise and you require fractional seconds then you can use SYSTIMESTAMP instead of DATE with a format mask 'DD-MON-YYYY HH24:MI:SS.FF9'
For example:
I've got datetime in Oracle database like: 18/08/21 13:51:23,420460500 (y/m/d) and I want convert to type: 18/08/20 22:00:00,000000000.
Could you please let me know how can I do this?
I've tried SYS_EXTRACT_UTC("MyDate") but it does not work in that case.
From the format of your question, I'm assuming you have a TIMESTAMP value, since Oracle doesn't have a "datetime" data type. You can truncate the time component to midnight (the beginning of the day) with the TRUNC function, though it returns a DATE data type. I'm not sure where the 22:00 in your question is coming from.
I found below code in my existing project.
select * from mytable where SomeColumn_date >= trunc(sysdate)-.25/24;
Sample value for SomeColumn_date is 22-JUN-17 05:46:55
How does SomeColumn_date >= trunc(sysdate)-.25/24 work on Date data type?
Different database engines allow different operations to be applied to date data types. For the most part, an operation of <Date Value> +/- 1 will add or subtract one day to that date value. This is syntactically equivalent to the dateadd function when using days.
In your example here, the -.25/24 resolves to the number equivalent of -15 minutes, which is then subtracted from your date value.
It is essentially a much less readable version of datedd(min,-15,<Date Value>).
From the documentation of TRUNC (I'm guessing you are using Oracle):
The TRUNC (date) function returns date with the time portion of the day truncated to the unit specified by the format model fmt. [...] If you omit fmt, then date is truncated to the nearest day.
The result of trunc(sysdate) would be the present date without the time component. Now .25/24 (actually meaning 0.25/24) is substracted from that. If you substract a date using - the operand is always in days. 0.25/24 would be a form to express a quarter of an hour.
So trunc(sysdate)-.25/24 would result in yesterday 23:45.
Ok so 2 things are happening here:
trunk(date,fmt)
The TRUNC (date) function returns date with the time portion of the day truncated to the unit specified by the format model fmt. If you omit fmt, then date is truncated to the nearest day.
So if you have suppose 22-JUN-17 05:46:55 you get 22-JUN-17. Since you don't have the fmt
DATETIME - .25/24 implies .25 hours before your current Date time.
But since you have only DATE all it does is .25 hours before todays 12:00 AM i.e yesterdays 11:45PM
SomeColumn_date >= trunc(sysdate)-.25/24
So suppose if its 22-JUN-2017 right now the date is compared to 21-JUN-2017 11:45 PM
NOTE: - is for before current time, + is for after the current time
I have 2 questions:
I want to compare a field whose data type is "Date" against a given date. The DB is oracle and being a mysql guy I'm finding it difficult to come up with simple queries.
The field("date_closed") stores date in UTC format (24-Aug-2011 18:55:11 for example) and I want to convert it to PST for comparison.
I tried this query but it returns some extra rows in the data set(obviously):
select * from table1 where trunc(date_closed)=to_date('2011-08-24','yyyy-mm-dd')
How do I covert to PST format before comparison?
In the same query how do I compare "date_closed" against the current date?
You need the NEW_TIME function
Dates don't include timezone in Oracle, and are assumed to be in the database timezone (which may by UTC but probably isn't). You should look at the TIMESTAMP WITH TIMEZONE data types.
Also, bear in mind that if you are comparing to the current date - I assume that you want to strip off the timestamp and compare only the day.
So, if new_time(date_closed,'GMT','PST') translates the date , your where clause will be comparing something like
trunc(new_Time(date_closed,'GMT','PST')) = trunc(sysdate)
to get all records with date_closed on the current day in PST.