Laravel/SQL: return rows where column Equals NOT 'something" and NULL - sql

Question

LARAVEL 5.4 (but probably it's a more general SQL question)
Hello! I have a table with a structure:
Suppose it's my model 'Table'.
I want a query which:
uses (receives) variables :
$id of array ['id', 'string', integer]
where string is '<' or '>'
$status_not_bad = bool;
(if true - include all rows where 'status' !== 'bad' AND 'status' IS NULL);
for example, we are given:
$id = ['id', '>', 0];
$status_not_bad = true;
Table::thisquery() ... ->get();
"get rows where status is not bad and id > 0" returns rows 1 and 3.
but if we given:
$id = ['id', '<', 3];
$status_not_bad = true;
Table::thisquery() ... ->get();
"get rows where status is not bad and id < 3" returns row 1
(it should be same query which return those results using those variables).

Answer 1

I've never used laravel before so my syntax could be off, but I know you want to use MySQL's ifNull function for this:
Table::where([['id', '>', 0], ['number', '>', 2])->whereRaw("IfNull(status, 'blah') <> 'bad'")->get();

Answer 2

Just chain your ->where() clauses. Maybe also consider wrapping them to prevent conflicting with any additional:
$results = Table::where("id", ">" 0)
->orWhere("number", ">", 2)
->orWhereNull("status")
->get();
Or, wrapped:
$results = Table::where(function($query){
$query->where("id", ">" 0)
->orWhere("number", ">", 2)
->orWhereNull("status");
})->get();
If you want to see what the actual query you're executing is, replace ->get() with ->toSql(), and use dd($result);:
$results = Table::where(...)->toSql();
dd($results);
Edit: Sounds like we need multiple wrapping queries, due to multiple conditions:
$results = Table::where(function($query){
$query->where("status", "!=", "bad")
->where("id", "<", 3); -- "status is not bad and id < 3"
})->orWhere(function($query){
$query->where("status", "!=", "bad")
->where("id", ">", 0); -- "status is not bad and id > 0"
})->get();
That should handle paired conditions as noted in your comment.