I'm using this query:
select convert(nvarchar(MAX), getdate(), 100);
It's returning
Aug 16 2018 3:45PM
I'm trying to get this date format instead:
16 AUG 15:45
Please help me achieve it. Thanks
Try this: with format function
SELECT upper(FORMAT( getdate(), 'dd MMM HH:mm', 'en-US'))
This gets you what you want, and without using the awfully slow FORMAT function:
SELECT D, CONVERT(varchar(6),DATEADD(HOUR, -1, D),13) + ' ' + CONVERT(varchar(5),CONVERT(time(0),DATEADD(HOUR, -1, D)),14)
FROM (VALUES(CONVERT(datetime2(0),'2018-08-16T15:45:00'))) V(d);
Edit: Seems the OP moved the goals posts again (initially they wanted the time changed from 01:38 AM to 13:38, and then 03:45 PM to 14:45), and as a result DATEADD isn't required. I haven't bothered removing this though, as it was correct at the time; and I don't trust the goal posts won't move again.
Try this
upper case 'Aug' to 'AUG'
SELECT UPPER( FORMAT( GETUTCDATE(), 'dd MMM HH:mm', 'en-US' ) )
use upper and 'dd MMM HH:mm', 'en-US' format
SELECT Upper( FORMAT( getdate(), 'dd MMM HH:mm', 'en-US' ))
it reutrns 16 AUG 11:03
Try this
Query:
select UPPER(FOrmat(GETDATE(),'dd MMM HH:mm'))
Result:
16 AUG 17:04
Related
I'm converting from SQL Oracle to Microsoft SQL Server
>= trunc(current_date, 'DD') converting to >= CONVERT(DATE, GETDATE())
But it's not giving me the same result.
My question is what does trunc(current_date, 'DD') look like (What format?)? I'm not able to test it as the old database has been deleted.
Should the conversion be convert(varchar, getdate(), 105) instead?
if you are going to store this as string type in mssql, this is the nearest datetime format that I can think of.
SELECT CONVERT(VARCHAR(50),DATEADD(day, DATEDIFF(day, '19000101', GETDATE()), '19000101'), 126) + 'Z'
Trunc in oracle will always return date as an output.
Trunc by DD will truncate time portion and give the floor date, not the nearest date.
So consider that your_date is 24-sep-2019 05:30:00 PM.
Select trunc(your_date, 'DD') from dual
Will give following result
24-sep-2019
-- see time portion is truncated
-- and return type is also date
Now, you can convert this query accordingly in mssql.
Cheers!!
In Sql Server for following query you get the out put as '25 Sep 2019'
select convert(varchar, getdate(), 106)
In Oracle to get the same date output as '25 Sep 2019' you can use the below query.
SELECT
TO_CHAR(
TRUNC(TO_DATE( '25 Sep 2019 15:35:32', 'DD Mon yyyy HH24:MI:SS' )),'DD Mon yyyy')
FROM
dual;
My date field has value format to be : Feb 15 2019. Is there a way to convert this to MMDDYYYY format?
Desired output: 02152019
Query I tried: SELECT convert(varchar, getdate(), 112) - this query is showing YYYYMMDD format :(
Any help?
select format( convert(date, 'Feb 15 2019'), 'MMddyyyy')
-- results to: 02152019
-- But again, your application is to take care about format!!!
Try this query,
select replace(convert(varchar, getdate(),101),'/','')
You can try this
Select convert(varchar(12), convert(date, 'Feb 15 2019'), 112)
or
SELECT REPLACE(CONVERT(VARCHAR(10), GETDATE(), 101), '/', '') AS [MMDDYYYY]
This will give output - 20190215.
You can pass different value like 101. For different output see Here.
I tried below query to get date format as 25 Sep 2018 but it is not converting the date type and actual date format is in dd/mm/yyyy format.
Please help.
select convert(varchar, FOUNDEDYEAR, 108)FROM EDELGIVE_KYC_DETAILSS
try like below
SELECT (convert(NVARCHAR, getdate(), 106))
25 Sep 2018
select (convert(NVARCHAR, FOUNDEDYEAR, 106))FROM EDELGIVE_KYC_DETAILSS
SELECT (convert(NVARCHAR, convert(datetime, '25/09/2018', 103), 106))
output
25 Sep 2018
I am working on a query in SQL server 2012 where I need to get datetime format as 01/03/2017 16:06:21 AM.
How do I do that?
If you really do want 24 hour format with AM/PM and you want to do this only using Convert, try:
for mm/dd/yyyy HH:mm:ss AM
select convert(varchar(10),getdate(),101) + ' '
+ convert(varchar(8),getdate(),114) + ' '
+ RIGHT( convert(varchar,getdate(),9),2)
for dd/mm/yyyy HH:mm:ss AM
select convert(varchar(10),getdate(),103) + ' '
+ convert(varchar(8),getdate(),114) + ' '
+ RIGHT( convert(varchar,getdate(),9),2)
In sql server 2012+ you can use format()
for dd/MM:
select format(getdate(), 'dd/MM/yyyy hh:mm:ss tt')
for MM/dd:
select format(getdate(), 'MM/dd/yyyy hh:mm:ss tt')
For 24 hour format, switch to HH instead of hh, but then why would you need AM/PM?
for dd/MM:
select format(getdate(), 'dd/MM/yyyy HH:mm:ss tt')
for MM/dd:
select format(getdate(), 'MM/dd/yyyy HH:mm:ss tt')
Try this code and change the numbers to Format
Select CONVERT(VARCHAR,GETDATE(),21)
//OutPut---------------
21=2017-03-14 19:17:28
//-----------------------------
0=Mar 14 2017 7:17PM
1=03/14/17
2=17.03.14
3=14/03/17
4=14.03.17
5=14-03-17
6=14 Mar 17
7=Mar 14, 17
8=19:17:28
9=Mar 14 2017 7:17:28:467PM
10=03-14-17
11=17/03/14
12=170314
13=14 Mar 2017 19:17:28:470
14=19:17:28:473
20=2017-03-14 19:17:28
21=2017-03-14 19:17:28.477
22=03/14/17 7:17:28 PM
23=2017-03-14
24=19:17:28
25=2017-03-14 19:17:28.480
100=Mar 14 2017 7:17PM
101=03/14/2017
102=2017.03.14
103=14/03/2017
104=14.03.2017
105=14-03-2017
106=14 Mar 2017
107=Mar 14, 2017
108=19:17:28
109=Mar 14 2017 7:17:28:497PM
110=03-14-2017
111=2017/03/14
112=20170314
113=14 Mar 2017 19:17:28:503
114=19:17:28:503
How do I use sql to get the whole month name in sql server?
I did't find a way using DATEPART(mm, mydate) or CONVERT(VARCHAR(12), CreatedFor, 107).
Basically I need in the format: April 1 2009.
SELECT DATENAME(MONTH, GETDATE())
+ RIGHT(CONVERT(VARCHAR(12), GETDATE(), 107), 9) AS [Month DD, YYYY]
OR Date without Comma Between date and year, you can use the following
SELECT DATENAME(MONTH, GETDATE()) + ' ' + CAST(DAY(GETDATE()) AS VARCHAR(2))
+ ' ' + CAST(YEAR(GETDATE()) AS VARCHAR(4)) AS [Month DD YYYY]
If you are using SQL Server 2012 or later, you can use:
SELECT FORMAT(MyDate, 'MMMM dd yyyy')
You can view the documentation for more information on the format.
Most answers are a bit more complicated than necessary, or don't provide the exact format requested.
select Format(getdate(), 'MMMM dd yyyy') --returns 'October 01 2020', note the leading zero
select Format(getdate(), 'MMMM d yyyy') --returns the desired format with out the leading zero: 'October 1 2020'
If you want a comma, as you normally would, use:
select Format(getdate(), 'MMMM d, yyyy') --returns 'October 1, 2020'
Note: even though there is only one 'd' for the day, it will become a 2 digit day when needed.
109 - mon dd yyyy (In SQL conversion)
The required format is April 1 2009
so
SELECT DATENAME(MONTH, GETDATE()) + RIGHT(CONVERT(VARCHAR(12), GETDATE(), 109), 9)
Result is:
select datename(DAY,GETDATE()) +'-'+ datename(MONTH,GETDATE()) +'- '+
datename(YEAR,GETDATE()) as 'yourcolumnname'