How do I use sql to get the whole month name in sql server?
I did't find a way using DATEPART(mm, mydate) or CONVERT(VARCHAR(12), CreatedFor, 107).
Basically I need in the format: April 1 2009.
SELECT DATENAME(MONTH, GETDATE())
+ RIGHT(CONVERT(VARCHAR(12), GETDATE(), 107), 9) AS [Month DD, YYYY]
OR Date without Comma Between date and year, you can use the following
SELECT DATENAME(MONTH, GETDATE()) + ' ' + CAST(DAY(GETDATE()) AS VARCHAR(2))
+ ' ' + CAST(YEAR(GETDATE()) AS VARCHAR(4)) AS [Month DD YYYY]
If you are using SQL Server 2012 or later, you can use:
SELECT FORMAT(MyDate, 'MMMM dd yyyy')
You can view the documentation for more information on the format.
Most answers are a bit more complicated than necessary, or don't provide the exact format requested.
select Format(getdate(), 'MMMM dd yyyy') --returns 'October 01 2020', note the leading zero
select Format(getdate(), 'MMMM d yyyy') --returns the desired format with out the leading zero: 'October 1 2020'
If you want a comma, as you normally would, use:
select Format(getdate(), 'MMMM d, yyyy') --returns 'October 1, 2020'
Note: even though there is only one 'd' for the day, it will become a 2 digit day when needed.
109 - mon dd yyyy (In SQL conversion)
The required format is April 1 2009
so
SELECT DATENAME(MONTH, GETDATE()) + RIGHT(CONVERT(VARCHAR(12), GETDATE(), 109), 9)
Result is:
select datename(DAY,GETDATE()) +'-'+ datename(MONTH,GETDATE()) +'- '+
datename(YEAR,GETDATE()) as 'yourcolumnname'
Related
How to get the system date in SQL Server with the format of MM dd, yyyy?
I tried everything but I couldn't get the correct format MM dd, yyyy
Use this query,
SELECT FORMAT(Getdate(), 'MM dd, yyyy')
SELECT CONVERT(VARCHAR(12), GETDATE(), 107)
try this query this will help you.
Here's one way:
DECLARE #mydate date = getdate()
SELECT CAST(DATEPART(MONTH, #mydate) as varchar)
+ ' '
+ CAST(DATEPART(DAY, #mydate) as varchar)
+ ', '
+ CAST(DATEPART(YEAR, #mydate) as varchar)
How can I get the string from GETDATE() in D-MMM-YYYY format, e.g 3 May 2016
If I use CONVERT(VARCHAR, GETDATE(), 106), I would get a leading zero on day which is not what I want.
If you are on SQL Server 2012 or later, use FORMAT:
SELECT FORMAT(GETDATE(), 'd MMM yyyy')
Edit: some of the answers below are just flat-out wrong so I'm adding a solution for older versions of SQL Server. 2005 is the earliest that I can get my hands on:
SELECT CASE
WHEN CONVERT(varchar(20), GETDATE(), 106) LIKE '0%'
THEN SUBSTRING(CONVERT(varchar(20), GETDATE(), 106), 2, 20)
ELSE CONVERT(varchar(20), GETDATE(), 106)
END
SELECT case when left(convert(varchar(20),[DateColumn],106),1) ='0'
then right(convert(varchar(20),[DateColumn],106),len(convert(varchar(20),[DateColumn],106))-1)
else convert(varchar(20),[DateColumn],106)
end
FROM [DB].[dbo].[Table]
Some sample output :
29 Apr 2016
2 Apr 2016
If you cannot use FORMAT (Below SQL Server 2012)
DECLARE #date DATE = '20160503'
SELECT REPLACE(DATEPART(DAY, #date),' 0','') + ' ' +
CONVERT(CHAR(3), #date, 0) + ' ' +
CAST(DATEPART(YEAR, #date) AS CHAR(4))
I have searched and i cannot seem to find the answer. I have tried using different styles, but none of them give me exactly what i want.
I am trying to convert a datetime, that I have calculated. However I need it to display the full month.
SELECT CONVERT(VARCHAR(25),DATEADD(dd, #codelife, getdate()),107)
the above line works fine, EXCEPT it displays the date like
Feb 27, 2014
I need it to display date like
February 27, 2014 etc.....
any suggestions?
Nathan's answer seems solid, however if you're using SQL Server 2012 you can make use of the FORMAT() function:
SELECT FORMAT(GETDATE(),'MMMM dd, yyyy')
Or in your case:
SELECT FORMAT(DATEADD(dd, #codelife, getdate()),'MMMM dd, yyyy')
I always use http://www.sql-server-helper.com/tips/date-formats.aspx as my reference
SELECT DATENAME(MM, GETDATE()) + RIGHT(CONVERT(VARCHAR(12), GETDATE(), 107), 9) AS [Month DD, YYYY]
I would declare your date as a variable and do something like:
DECLARE #myDate DATETIME
SET #myDate = DateAdd(dd, #codelife, getdate());
SELECT DATENAME(MM, #myDate) + RIGHT(CONVERT(VARCHAR(12), #myDate, 107), 9) AS [Month DD, YYYY]
You may have to do it in 2 steps.
DECLARE #codelife INT = 120
DECLARE #codedate DATETIME = (SELECT (DATEADD(D, #codelife, GETDATE())))
SELECT DATENAME(MM, #codedate) + SUBSTRING(CONVERT(VARCHAR(25), #codedate, 107), 4, 25)
SELECT DATENAME(MONTH, GETDATE())
+ RIGHT(CONVERT(VARCHAR(12), GETDATE(), 107), 9) AS [Month DD, YYYY]
OR Date without Comma Between date and year, you can use the following
SELECT DATENAME(MONTH, GETDATE()) + ' ' + CAST(DAY(GETDATE()) AS VARCHAR(2))
+ ' ' + CAST(YEAR(GETDATE()) AS VARCHAR(4)) AS [Month DD YYYY]
I answered the same question a couple of days ago have a look here sql server Get the FULL month name from a date
How can I display a DATETIME value (2010-12-02 15:20:17.000) as 02/12-2010 15:20?
For SQL Server:
select stuff(convert(varchar, getdate(), 105), 3, 1, '/') + ' ' + left(convert(varchar, getdate(), 8), 5)
DateTime is a DateTime is a DateTime - it just holds a date and time and doesn't have any string representation, really.
See the CAST and CONVERT topic in the SQL Server Books Online for details - it shows all supported date formats that SQL Server supports.
For your source format (2010-12-02 15:20:17.000) you could probably use style no. 121
DECLARE #source VARCHAR(50)
SET #source = '2010-12-02 15:20:17.000'
DECLARE #Date DATETIME
SELECT #Date = CONVERT(DATETIME, #source, 121)
SELECT #Date
but your target format is a bit odd..... I don't see any "out of the box" style that would match your needs. You'll need to use some string manipulation code to get that exact format.
Use MSSQL's build-in function to convert datetime to string with format,
SELECT CONVERT(VARCHAR(8), GETDATE(), 1) AS [MM/DD/YY] --2/5/12
SELECT CONVERT(VARCHAR(10), GETDATE(), 103) AS [DD/MM/YYYY] --5/2/2012
You need to create custom function to get various format to use like this;
SELECT dbo.ufn_FormatDateTime(GETDATE(),'YYYY-MM-DD HH:mm:SS tt')
--Output : 2012-02-05 01:58:38 AM
SELECT dbo.ufn_FormatDateTime(GETDATE(),'(dddd) mmmm dd, yyyy hh:mm:ss.fff tt')
--Output : (Sunday) February 05, 2012 01:58:38.723 AM
SELECT dbo.ufn_FormatDateTime(GETDATE(),'dd/MM/yyyy')
--Output : 05/02/2012
SELECT dbo.ufn_FormatDateTime(GETDATE(),'yyyy MMM, dd (ddd) hh:mm:ss tt')
-- Output : 2012 Feb, 05 (Sun) 01:58:38 AM
Get the code snippet from this link.
http://www.tainyan.com/codesnippets/entry-62/sql-server-date-time-format-function.html
http://msdn.microsoft.com/en-us/library/ms189491.aspx
Is this what you're looking for?
Assuming Oracle:
select TO_CHAR(SYSDATE, "dd/mm-yyyy HH24:mi")
from DUAL;
Assuming SQL Server:
select STR(DATEPART(DAY, GETDATE()), 2)
+ '/'
+ STR(DATEPART(MONTH, GETDATE()), 2)
+ '-'
+ STR(DATEPART(YEAR, GETDATE()), 4)
+ ' '
+ STR(DATEPART(HOUR, GETDATE()), 2)
+ ':'
+ STR(DATEPART(MINUTE, GETDATE()), 2);
Little example I use for Germany and Switzerland: dd.mm.yyyy hh:mm
SELECT CONVERT(varchar, GETDATE(), 104) + ' ' + LEFT(CONVERT(varchar, GETDATE(), 108), 5)
How do I in SQL Server 2005 use the DateAdd function to add a day to a date
Use the following function:
DATEADD(type, value, date)
date is the date you want to manipulate
value is the integere value you want to add (or subtract if you provide a negative number)
type is one of:
yy, yyyy: year
qq, q: quarter
mm, m: month
dy, y: day of year
dd, d: day
wk, ww: week
dw, w: weekday
hh: hour
mi, n: minute
ss or s: second
ms: millisecond
mcs: microsecond
ns: nanosecond
SELECT DATEADD(dd, 1, GETDATE()) -- will return a current date + 1 day
http://msdn.microsoft.com/en-us/library/ms186819.aspx
DECLARE #MyDate datetime
-- ... set your datetime's initial value ...'
DATEADD(d, 1, #MyDate)
Try following code will Add one day to current date
select DateAdd(day, 1, GetDate())
And in the same way can use Year, Month, Hour, Second etc. instead of day in the same function
The following query I have used in SQL Server 2008, it may be help you.
For add day
DATEADD(DAY,20,GETDATE())
*20 is the day quantity
DECLARE #date DateTime
SET #date = GetDate()
SET #date = DateAdd(day, 1, #date)
SELECT #date
Select getdate() -- 2010-02-05 10:03:44.527
-- To get all date format
select CONVERT(VARCHAR(12),getdate(),100) +' '+ 'Date -100- MMM DD YYYY' -- Feb 5 2010
union
select CONVERT(VARCHAR(10),getdate(),101) +' '+ 'Date -101- MM/DDYYYY'
Union
select CONVERT(VARCHAR(10),getdate(),102) +' '+ 'Date -102- YYYY.MM.DD'
Union
select CONVERT(VARCHAR(10),getdate(),103) +' '+ 'Date -103- DD/MM/YYYY'
Union
select CONVERT(VARCHAR(10),getdate(),104) +' '+ 'Date -104- DD.MM.YYYY'
Union
select CONVERT(VARCHAR(10),getdate(),105) +' '+ 'Date -105- DD-MM-YYYY'
Union
select CONVERT(VARCHAR(11),getdate(),106) +' '+ 'Date -106- DD MMM YYYY' --ex: 03 Jan 2007
Union
select CONVERT(VARCHAR(12),getdate(),107) +' '+ 'Date -107- MMM DD,YYYY' --ex: Jan 03, 2007
union
select CONVERT(VARCHAR(12),getdate(),109) +' '+ 'Date -108- MMM DD YYYY' -- Feb 5 2010
union
select CONVERT(VARCHAR(12),getdate(),110) +' '+ 'Date -110- MM-DD-YYYY' --02-05-2010
union
select CONVERT(VARCHAR(10),getdate(),111) +' '+ 'Date -111- YYYY/MM/DD'
union
select CONVERT(VARCHAR(12),getdate(),112) +' '+ 'Date -112- YYYYMMDD' -- 20100205
union
select CONVERT(VARCHAR(12),getdate(),113) +' '+ 'Date -113- DD MMM YYYY' -- 05 Feb 2010
SELECT convert(varchar, getdate(), 20) -- 2010-02-05 10:25:14
SELECT convert(varchar, getdate(), 23) -- 2010-02-05
SELECT convert(varchar, getdate(), 24) -- 10:24:20
SELECT convert(varchar, getdate(), 25) -- 2010-02-05 10:24:34.913
SELECT convert(varchar, getdate(), 21) -- 2010-02-05 10:25:02.990
---==================================
-- To get the time
select CONVERT(VARCHAR(12),getdate(),108) +' '+ 'Date -108- HH:MM:SS' -- 10:05:53
select CONVERT(VARCHAR(12),getdate(),114) +' '+ 'Date -114- HH:MM:SS:MS' -- 10:09:46:223
SELECT convert(varchar, getdate(), 22) -- 02/05/10 10:23:11 AM
----=============================================
SELECT getdate()+1
SELECT month(getdate())+1
SELECT year(getdate())+1