I have SQL Query:
SELECT Date, Hours, Counts FROM TRANSACTION_DATE
Example Output:
Date | Hours | Counts
----------------------------------
01-Feb-2018 | 20 | 5
03-Feb-2018 | 25 | 3
04-Feb-2018 | 22 | 3
05-Feb-2018 | 21 | 2
07-Feb-2018 | 28 | 1
10-Feb-2018 | 23 | 1
If you can see, there are days that missing because no data/empty, but I want the missing days to be shown and have a value of zero:
Date | Hours | Counts
----------------------------------
01-Feb-2018 | 20 | 5
02-Feb-2018 | 0 | 0
03-Feb-2018 | 25 | 3
04-Feb-2018 | 22 | 3
05-Feb-2018 | 21 | 2
06-Feb-2018 | 0 | 0
07-Feb-2018 | 28 | 1
08-Feb-2018 | 0 | 0
09-Feb-2018 | 0 | 0
10-Feb-2018 | 23 | 1
Thank you in advanced.
You need to generate a sequence of dates. If there are not too many, a recursive CTE is an easy method:
with dates as (
select min(date) as dte, max(date) as last_date
from transaction_date td
union all
select dateadd(day, 1, dte), last_date
from dates
where dte < last_date
)
select d.date, coalesce(td.hours, 0) as hours, coalesce(td.count, 0) as count
from dates d left join
transaction_date td
on d.dte = td.date;
Related
I have a sql table that stores data every 15 minutes, but I want to fetch the maximum value every 4 hour.
This is my Actual table:
+----+----+----+-------------------------+
| Id | F1 | F2 | timestamp |
+----+----+----+-------------------------+
| 1 | 24 | 30 | 2019-03-25 12:15:00.000 |
| 2 | 22 | 3 | 2019-03-25 12:30:00.000 |
| 3 | 2 | 4 | 2019-03-25 12:45:00.000 |
| 4 | 5 | 35 | 2019-03-25 13:00:00.000 |
| 5 | 18 | 23 | 2019-03-25 13:15:00.000 |
| ' | ' | ' | ' |
| 16 | 21 | 34 | 2019-03-25 16:00:00.000 |
+----+----+----+-------------------------+
The Output I am looking for is:
+----+----+----+
| Id | F1 | F2 |
+----+----+----+
| 1 | 24 | 35 |1st 4 Hours
+----+----+----+
| 2 | 35 | 25 |Next 4 Hours
+----+----+----+
I did use the query
select max(F1) as F1,
max(F2) as F2
from table
where timestamp>='2019/3/26 12:00:01'
and timestamp<='2019/3/26 16:00:01'
and it returns the first 4 hours value but when I Increase the timestamp from 4 hrs to 8 hrs it will still give me 1 max value rather than 2 per 4 hours.
I did try with the group by clause but wasn't able to get the expected result.
This should work
SELECT Max(f1),
Max(f2), datepart(hh,timestamp), convert(date,timestamp)
FROM TABLE
WHERE datepart(hh,timestamp)%4 = 0
AND timestamp>='2019/3/26 12:00:01'
AND timestamp<='2019/3/26 16:00:01'
GROUP BY datepart(hh,timestamp), convert(date,timestamp)
ORDER BY convert(date,timestamp) asc
Here is a relatively simple method:
select convert(date, timestamp) as dte,
(datepart(hour, timestamp) / 4) * 4 as hour,
max(F1) as F1,
max(F2) as F2
from table
group by convert(date, timestamp), (datepart(hour, timestamp) / 4) * 4;
This puts the date and hour into separate columns; you can use dateadd() to put them in one column.
Try this query:
declare #startingDatetime datetime = '2017-10-04 12:00:00';
select grp, max(F1) F1, max(F2) F2
from (
select datediff(hour, #startingDatetime, [timestamp]) / 4 grp, *
from MyTable
where [timestamp] > #startingDatetime
) a group by grp
My table structure is as follows:
group_id | cust_id | ticket_num
------------------------------
60 | 12 | 1
60 | 12 | 2
60 | 12 | 3
60 | 12 | 4
60 | 30 | 5
60 | 30 | 6
60 | 31 | 7
60 | 31 | 8
65 | 02 | 1
I want to fetch all the data for group_id=60 and find the count of ticket_num for each customer in that group. My output should be like this:
cust_id | ticket_count | ticket_num
------------------------------
12 | 4 | 1
12 | | 2
12 | | 3
12 | | 4
30 | 2 | 5
30 | | 6
31 | 2 | 7
31 | | 8
I tried this query:
SELECT gd.cust_id, Count(gd.cust_id),gd.ticket_num
FROM Group_details gd
WHERE gd.group_id = 65
GROUP BY gd.cust_id;
But this query is not working.
You appear to want the ANSI/ISO standard row_number() functions and count() as a window function:
select gd.cust_id, count(*) over (partition by gd.cust_id) as num_tickets,
row_number() over (order by gd.cust_id) as ticket_seqnum
from group_details gd
where gd.group_id = 60;
use aggregate and subquery
select t2.*,t1.ticket_num from Group_details t1
inner join
(
SELECT gd.cust_id, Count(gd.ticket_num) as ticket_count
FROM Group_details gd where gd.group_id = 60
GROUP BY gd.cust_id
) t2 on t1.cust_id=t2.cust_id
http://sqlfiddle.com/#!9/dd718b/1
The user will input a date range, and I want to output in SQL every date between and including that range in the number of concurrent uses of said equipment.
In this example, the user date range is 03/08/2016 to 03/09/2016, so you can see below I include anything on or between those dates (grouped by category, but I've simplified here by only using 'powerchair')
The table schema is as follows;
trans_date | trans_end_date | eq_category
17/03/2016 | 16/10/2016 | POWERCHAIR
08/08/2016 | 08/08/2016 | POWERCHAIR
12/08/2016 | 12/08/2016 | POWERCHAIR
17/08/2016 | 18/08/2016 | POWERCHAIR
22/08/2016 | 22/08/2016 | POWERCHAIR
26/08/2016 | 26/08/2016 | POWERCHAIR
02/09/2016 | 02/09/2016 | POWERCHAIR
And I would like to output;
date | concurrent_use
03-08-2016 | 1
04-08-2016 | 1
05-08-2016 | 1
06-08-2016 | 1
07-08-2016 | 1
08-08-2016 | 2
09-08-2016 | 1
10-08-2016 | 1
11-08-2016 | 1
12-08-2016 | 2
13-08-2016 | 1
14-08-2016 | 1
15-08-2016 | 1
16-08-2016 | 1
17-08-2016 | 2
18-08-2016 | 2
19-08-2016 | 1
20-08-2016 | 1
21-08-2016 | 1
22-08-2016 | 2
23-08-2016 | 1
24-08-2016 | 1
25-08-2016 | 1
26-08-2016 | 2
27-08-2016 | 1
28-08-2016 | 1
29-08-2016 | 1
30-08-2016 | 1
31-08-2016 | 1
01-09-2016 | 1
02-09-2016 | 2
03-09-2016 | 1
Anything 1 or 0, I can then filter out as there mustn't have been any equipment out concurrently that day.
I don't think this is a gaps/islands problem, but I'm drawing a blank trying to get this in an SQL statement.
Try like below. You need to generate dates using recursive cte. Then we need to count the no of occurrences of each date falling in range.
;WITH CTE
AS (SELECT CONVERT(DATE, '2016-08-03', 103) DATE1
UNION ALL
SELECT Dateadd(DAY, 1, DATE1) AS DATE1
FROM CTE
WHERE Dateadd(DD, 1, DATE1) <= '2016-09-03')
SELECT C.DATE1,
Count(1) OCCURENCES
FROM CTE C
JOIN #TABLE1 T
ON C.DATE1 BETWEEN [TRANS_DATE] AN [TRANS_END_DATE]
GROUP BY C.DATE1
You need a set of numbers or dates. So, if you want everything in that range:
with d as (
select cast('2016-08-03' as date) as d
union all
select dateadd(day, 1, d.d)
from d
where d < '2016-09-03'
)
select d.d, count(s.trans_date)
from d left join
schema s
on d.d between s.trans_date and s.trans_date_end
group by d.d;
I'm not sure if both the start and end dates are included in the range.
My Sales data for first two weeks of june, Monday Date i.e 1st Jun , 8th Jun are below
date | count
2015-06-01 03:25:53 | 1
2015-06-01 03:28:51 | 1
2015-06-01 03:49:16 | 1
2015-06-01 04:54:14 | 1
2015-06-01 08:46:15 | 1
2015-06-01 13:14:09 | 1
2015-06-01 16:20:13 | 5
2015-06-01 16:22:13 | 1
2015-06-01 16:27:07 | 1
2015-06-01 16:29:57 | 1
2015-06-01 19:16:45 | 1
2015-06-08 10:54:46 | 1
2015-06-08 15:12:10 | 1
2015-06-08 20:35:40 | 1
I need a find weekly avg of sales happened in a given range .
Complex Query:
(some_manipulation_part), ifact as
( select date, sales_count from final_result_set
) select date_part('h',date )) as h ,
date_part('dow',date )) as day_of_week ,
count(sales_count)
from final_result_set
group by h, dow.
Output :
h | day_of_week | count
3 | 1 | 3
4 | 1 | 1
8 | 1 | 1
10 | 1 | 1
13 | 1 | 1
15 | 1 | 1
16 | 1 | 8
19 | 1 | 1
20 | 1 | 1
If I try to apply avg on the above final result, It is not actually fetching correct answer!
(some_manipulation_part), ifact as
( select date, sales_count from final_result_set
) select date_part('h',date )) as h ,
date_part('dow',date )) as day_of_week ,
avg(sales_count)
from final_result_set
group by h, dow.
h | day_of_week | count
3 | 1 | 1
4 | 1 | 1
8 | 1 | 1
10 | 1 | 1
13 | 1 | 1
15 | 1 | 1
16 | 1 | 1
19 | 1 | 1
20 | 1 | 1
So I 've two mondays in the given range, it is not actually dividing by it. I am not even sure what is happening inside redshift.
To get "weekly averages" use date_trunc():
SELECT date_trunc('week', my_date_column) as week
, avg(sales_count) AS avg_sales
FROM final_result_set
GROUP BY 1;
I hope you are not actually using date as name for your date column. It's a reserved word in SQL and a basic type name, don't use it as identifier.
If you group by the day of week (DOW) you get averages per weekday. and sunday is 0. (Use ISODOW to get 7 for Sunday.)
I have a pretty strange business requirement that I need to fulfill with the following two tables:
STOCK_TB (As of 20150319)
PRODUCT_ID STOCK_QTY
A 20
B 15
STOCK_MODIFIED_TB
PRODUCT_ID MODIFIED_QTY MODIFIED_DATE_FROM MODIFIED_DATE_TO
A 10 20150315 20150318
B -5 20150314 20150316
A -2 20150314 20150316
STOCK_TB represents the current stock of inventory, while STOCK_MODIFIED_TB represents the quantity of stocks modified in a date range. I need to select results of stocks for previous dates. Suppose the result was retrieved on 20150319 for dates 20150314-20150319. This is what the result should look like:
DATE PRODUCT_ID STOCK_QTY
20150314 A 18
20150314 B 10
20150315 A 28
20150315 B 10
20150316 A 28
20150316 B 10
20150317 A 30
20150317 B 15
20150318 A 30
20150318 B 15
20150319 A 20
20150319 B 15
In other words, the stocks for previous dates would be added/subtracted based on the date range given in STOCK_MODIFIED_TB
Is selecting data like this possible without cursors?
I'll try with this answer, of course my subquery in select looking not so well with performance I guess... :
SQLFIddleExample
SELECT cast(a.Date as date) Date,
st.PRODUCT_ID,
st.STOCK_QTY + isnull((SELECT SUM(MODIFIED_QTY)
FROM STOCK_MODIFIED_TB
WHERE MODIFIED_DATE_FROM <= CONVERT(VARCHAR(10), a.Date, 112)
AND MODIFIED_DATE_TO >= CONVERT(VARCHAR(10), a.Date, 112)
AND PRODUCT_ID = st.PRODUCT_ID ),0) STOCK_QTY
FROM STOCK_TB st,
(select DATEADD(day, number, '2015-01-01') Date
from master..spt_values
where type = 'p' ) a
WHERE a.Date between '2015-03-14' and '2015-03-19'
ORDER BY a.Date, st.PRODUCT_ID
Result:
| Date | PRODUCT_ID | STOCK_QTY |
|------------|------------|-----------|
| 2015-03-14 | A | 18 |
| 2015-03-14 | B | 10 |
| 2015-03-15 | A | 28 |
| 2015-03-15 | B | 10 |
| 2015-03-16 | A | 28 |
| 2015-03-16 | B | 10 |
| 2015-03-17 | A | 30 |
| 2015-03-17 | B | 15 |
| 2015-03-18 | A | 30 |
| 2015-03-18 | B | 15 |
| 2015-03-19 | A | 20 |
| 2015-03-19 | B | 15 |