consider we have a table with this columns
Id
fk_newsId
fk_NewsGroupId
fk_NewsZoneId
I need to select all records with same fk_NewsGroup and fk_NewsZone
something like this
+----+-----------+--------------+-------------+
| Id | fk_NewsId | fk_NewsGroup | fk_NewsZone |
+----+-----------+--------------+-------------+
| 1 | 60 | 5 | 8 |
| 2 | 30 | 5 | 8 |
| 3 | 31 | 9 | 20 |
| 4 | 5 | 9 | 20 |
| 5 | 12 | 9 | 20 |
| 6 | 1000 | 20 | 11 |
| 7 | 21 | 20 | 11 |
| 8 | 6 | 20 | 11 |
+----+-----------+--------------+-------------+
how can do that?
I tride group by like this
but it dosnt give desired output
select fk_NewsId, fk_NewsGroup,fk_NewsZone from tbl_test
group by fk_NewsGroup,fk_NewsZone,fk_NewsId
You can try to use COUNT with window function, to get the count by fk_NewsGroup and fk_NewsZone columns.
then get count greater than one.
SELECT *
FROM (
SELECT *,COUNT(*) OVER(PARTITION BY fk_NewsGroup,fk_NewsZone ORDER BY fk_NewsZone) cnt
FROM tbl_test
)t1
where t1.cnt > 1
dbfiddle
Not absolutely clear as to what you mean, but something like so:
SELECT t.Id, t.fk_NewsId, t.fk_NewsGroup, t.fk_NewsZone FROM tbl_test t
INNER JOIN (
SELECT fk_NewsGroup,fk_NewsZone, COUNT(*) AS Counted FROM tbl_test
GROUP BY fk_NewsGroup,fk_NewsZone
HAVING COUNT(*) > 1) g
ON t.fk_NewsGroup = g.fk_NewsGroup
AND t.fk_NewsZone = g.fk_NewsZone
DBFiddle example
I would use Group by and do it like:
select max(id) as Id, Max(fk_NewsId) as fk_NewsId, fk_NewsGroup,fk_NewsZone from #temp
group by fk_NewsGroup,fk_NewsZone
I'm looking to group counts into categories of (0+, 5+, 10+, 15+, etc.)
So an agent with 7 leads should be counted in the 0+, 5+ groups, but not 10+, 15+.
Postgres Query:
WITH agent_stats AS (
SELECT agent_id, FLOOR(COUNT(*)/5) AS count_category
FROM leads
GROUP BY 1
)
SELECT count_category, COUNT(*)
FROM agent_stats
GROUP BY 1
ORDER BY 1
Result:
| count_category | count |
| 0 | 12 |
| 5 | 18 |
| 15 | 9 |
| 20 | 4 |
Desired:
| count_category | count |
| 0 | 43 |
| 5 | 31 |
| 15 | 13 |
| 20 | 4 |
The simplest way is probably a cumulative sum:
WITH agent_stats AS (
SELECT agent_id, FLOOR(COUNT(*)/5) AS count_category
FROM leads
GROUP BY 1
)
SELECT count_category, COUNT(*),
SUM(COUNT(*)) OVER (ORDER BY count_category DESC)
FROM agent_stats
GROUP BY 1
ORDER BY 1;
I have a table
Id | Aisle | OddEven | Bay | Size | Y-Axis
3 | A1 | Even | 14 | 10 | 100
1 | A1 | Even | 16 | 10 |
6 | A1 | Even | 20 | 10 |
12 | A1 | Even | 26 | 5 | 150
10 | A1 | Even | 28 | 5 |
11 | A1 | Even | 32 | 5 |
2 | A1 | Odd | 13 | 10 | 100
5 | A1 | Odd | 17 | 10 |
4 | A1 | Odd | 19 | 10 |
9 | A1 | Odd | 23 | 5 | 150
7 | A1 | Odd | 25 | 5 |
8 | A1 | Odd | 29 | 5 |
want to look like this
Id | Aisle | OddEven | Bay | Size | Y-Axis
1 | A1 | Even | 14 | 10 | 100
2 | A1 | Even | 16 | 10 | 110
3 | A1 | Even | 20 | 10 | 120
4 | A1 | Even | 26 | 5 | 150
5 | A1 | Even | 28 | 5 | 155
6 | A1 | Even | 32 | 5 | 160
7 | A1 | Odd | 13 | 10 | 100
8 | A1 | Odd | 17 | 10 | 110
9 | A1 | Odd | 19 | 10 | 120
10 | A1 | Odd | 23 | 5 | 150
11 | A1 | Odd | 25 | 5 | 155
12 | A1 | Odd | 29 | 5 | 160
I need a select query and update query. What its doing is there are already some Y-Axis Number been filled (at the start of the Odd/Even) then I need to take the previous row's Y-Axis column's value and adds to the current rows's size which = to current Y-Axis. Needs to keep doing it until it finds another Y-Axis has the value it skips the calculation and next row is using that number.
My thinking process is this:
Id will definitely be used, however, the Id is not sequence as shown my example
so I need to have
ROW_Number OVER (PARTITION BY Aisle,OddEven,Bay Order BY Aisle,OddEven,Bay)
Then some kind of JOIN the same table but the ON is T1.RN = T2.RN - 1
Where I am stuck is but the first row has not previous value it will try to update that value.
Anyone have an idea for SQL Query 2008 for Select and Update will be greatly appreciated! Thanks.
You seem to want a cumulative sum. This would be easier in SQL Server 2012+. You can do this in SQL Server 2008 using outer apply:
select t.*, cume_value
from t outer apply
(select sum(size) + sum(yaxis) as cume_value
from t t2
where t2.aisle = t.aisle and t2.oddeven = t.oddeven and
t2.bay < t.bay
) t2;
A little more difficult on 2008, but I think this is what you are looking for
Declare #Table table (Id int,Aisle varchar(25),OddEven varchar(25),Bay int,Size int,[Y-Axis] int)
Insert Into #Table values
(3,'A1','Even',14,10 ,100),
(1,'A1','Even',16,10 ,0),
(6,'A1','Even',20,10 ,0),
(12,'A1','Even',26,5,150),
(10,'A1','Even',28,5,0),
(11,'A1','Even',32,5,0),
(2,'A1','Odd',13,10 ,100),
(5,'A1','Odd',17,10 ,0),
(4,'A1','Odd',19,10 ,0),
(9,'A1','Odd',23,5,150),
(7,'A1','Odd',25,5,0),
(8,'A1','Odd',29,5,0)
;with cteBase as (
Select *
,IDNew=Row_Number() over (Order By Aisle,Bay)
,RowNr=Row_Number() over (Order By Aisle,OddEven,Bay)
From #Table
)
, cteGroup as (Select TmpRowNr=RowNr,GrpNr=Row_Number() over (Order By RowNr) from cteBase where [Y-Axis]>0)
, cteFinal as (
Select A.*
,GrpNr = (Select max(GrpNr) from cteGroup Where TmpRowNr<=RowNr)
From cteBase A
)
Select ID=Row_Number() over (Order By A.OddEven,A.Bay)
,A.Aisle
,A.OddEven
,A.Bay
,A.Size
,[Y-Axis] = Sum(case when B.[Y-Axis]>0 then B.[Y-Axis] else B.Size end)
From cteFinal A
Join cteFinal B on (B.RowNr<=A.RowNr and A.GrpNr=B.GrpNr)
Group By
A.IDNew
,A.Aisle
,A.OddEven
,A.Bay
,A.Size
Order By A.OddEven,A.Bay
Returns
ID Aisle OddEven Bay Size Y-Axis
1 A1 Even 14 10 100
2 A1 Even 16 10 110
3 A1 Even 20 10 120
4 A1 Even 26 5 150
5 A1 Even 28 5 155
6 A1 Even 32 5 160
7 A1 Odd 13 10 100
8 A1 Odd 17 10 110
9 A1 Odd 19 10 120
10 A1 Odd 23 5 150
11 A1 Odd 25 5 155
12 A1 Odd 29 5 160
I gotta leave my computer so update query should be easy to move on from here.
Below is the select query;
select row_number() over (order by oddeven,bay) id,
Aisle,
OddEven,
Bay,
Size,
max(ISNULL([Y-Axis],0)) over (partition by Aisle, OddEven,Size order by bay)
+ sum(CASE WHEN [Y-Axis] is null THEN Size ELSE 0 END) over (partition by Aisle,OddEven,size order by Bay) as [Y-Axis]
from oddseven
order by id
I have two tables and I want to combine their data.
The first table
+------------+-----+------+-------+
| BusinessID | Lat | Long | Stars |
+------------+-----+------+-------+
| abc123 | 32 | 74 | 4.5 |
| abd123 | 32 | 75 | 4 |
| abe123 | 33 | 76 | 3 |
+------------+-----+------+-------+
The second table is:
+------------+-----+------+-------+
| BusinessID | day | time | count |
+------------+-----+------+-------+
| abc123 | 1 | 14 | 5 |
| abc123 | 1 | 15 | 6 |
| abc123 | 2 | 13 | 1 |
| abd123 | 4 | 12 | 4 |
| abd123 | 4 | 13 | 8 |
| abd123 | 5 | 11 | 2 |
+------------+-----+------+-------+
So what I want to do is find all the Businesses that are in a specific radius and have more check ins in the next hour than the current.
So the results are
+------------+
| BusinessID |
+------------+
| abd123 |
| abc123 |
+------------+
Because they have more check-ins in the next hour than the previous (6 > 5, 8 > 4)
What is more it would be helpful if the results where ordered by their difference in check-ins number. Ex. ( 8 - 4 > 6 - 5 )
SELECT *
FROM table2 t2
WHERE t2.BusinessID IN (
SELECT t1.BusinessID
FROM table1 t1
WHERE earth_box(ll_to_earth(32, 74), 4000/1.609) #> ll_to_earth(Lat, Long)
ORDER by earth_distance(ll_to_earth(32, 74), ll_to_earth(Lat, Long)), stars DESC
) AND checkin_day = 1 AND checkin_time = 14;
From the above query I can find the businesses in a radius and then find their check-ins in the specified time. Ex. 14. What I need to do now is to find the number of check-ins in the 15 hour (of the same businesses) and find if the number of the check-ins is greater than it was in the previous time.
I think you want something like this:
SELECT
t1.BusinessID
FROM
table1 t1
JOIN
(SELECT
*,
"count" - LAG("count") OVER (PARTITION BY BusinessID, "day" ORDER BY "time") "grow"
FROM
table2
WHERE
/* Some condition on table2 */) t2
ON t1.BusinessID = t2.BusinessID AND t2.grow > 0
WHERE
/* Some condition on table1 */
ORDER BY
t2.grow DESC;
I have a table as follow:
id |minutes |sumOfMinutes|Date
_______________________________________
1 | 5 | | 20141106
1 | 7 | | 20141106
2 | 1 | | 20141106
2 | 9 | | 20141106
3 | 8 | | 20141106
How can I store sum of minutes in the third column for rows under the same month, so that i have:
id |minutes |sumOfMinutes| Date
_____________________________________
1 | 5 | 12 | 20141106
1 | 7 | 12 | 20141112
2 | 1 | 18 | 20141006
2 | 9 | 18 | 20141007
3 | 8 | 18 | 20141009
Use SUM() and Group by
SELECT table1.id, table1.minutes, SUM(monthTot.minutes), table1.Date
FROM table 1
JOIN table1 AS monthTot ON
MONTH(monthTot.date) = MONTH(table1.date)
GROUP BY table1.id, table1.minutes, table1.Date
sum with partition by option can be used to achieve this.
select id, [minutes],
sum([minutes]) over ( partition by month([date]) ) as sumOfMinutes,
[Date]
from Table1