For example, if the below is the table
SupId ItemId Status
1 1 Available
1 2 OOS
2 3 Available
3 4 OOS
3 5 OOS
4 6 OOS
5 7 NULL
I am looking to fetch distinct suppliers whose all items are OOS or NULL.
One solution is to get all the suppliers who has atleast one active item (active suppliers) and then add a clause NOT IN active suppliers to pick non active supplier.
Is there any better way to achieve the same?
One option, using aggregation:
SELECT SupId
FROM yourTable
GROUP BY SupId
HAVING
SUM(CASE WHEN Status = 'OOS' OR Status IS NULL THEN 1 ELSE 0 END) = COUNT(*) AND
(MAX(Status) = 'OOS' OR COUNT(Status) = 0);
This assumes you want suppliers who have only all NULL or all OOS status. If you just want to limit to both these two status values, then use this:
SELECT SupId
FROM yourTable
GROUP BY SupId
HAVING SUM(CASE WHEN Status <> 'OOS' AND Status IS NOT NULL THEN 1 ELSE 0 END) = 0;
Try:
SELECT DISTINCT SupId FROM my_table t
WHERE NOT EXISTS(SELECT 1 FROM my_table
WHERE SupId = t.SupId
AND [Status] IS NOT NULL
AND [Status] <> 'OOS')
SELECT DISTINCT SupId
FROM Table
WHERE SupId <> (
SELECT DISTINCT SupId
FROM Table
WHERE Status NOT IN ('OOS',NULL)
)
I would use NOT EXISTS :
SELECT t.*
FROM table t
WHERE NOT EXISTS (SELECT 1 FROM table t1 WHERE t1.supid = t.supid and t1.status <> 'OOS');
I would use group by and having:
select suppid
from t
group by suppid
having (min(Status) = 'OOS' and max(Status) = 'OOS') or
min(Status) is null;
Related
I have a problem figuring out how to count duplicates in a table like below:
Campaign
Approved
Disqualified
campaign-1
1
null
campaign-1
null
2
campaign-2
5
null
campaign-2
null
3
My query:
select
"Campaign"
,case when "Status" = 'Approved' then count("Id") end as "Approved"
,case when "Status" = 'Disqualified' then count("Id") end as "Disqualified"
from "table"
group by "Campaign","Status"
having count(*) > 1
order by "Campaign"
I would like to have a table as result below?
result:
Campaign
Approved
Disqualified
campaign-1
1
2
campaign-2
5
3
...
You must group by Campaign only.
Also, it is easier to use SUM() instead of COUNT(), because SQLite evaluates boolean expressions like Status = 'Approved' as 1 or 0:
SELECT Campaign,
SUM(Status = 'Approved') AS Approved,
SUM(Status = 'Disqualified') AS Disqualified
FROM "table"
GROUP BY Campaign
HAVING COUNT(*) > 1
get_info = """
WITH query1 AS
(
SELECT Campaign,
SUM(Approved) AS sum_a,
SUM(Disqualified) AS sum_d
FROM Campaign
GROUP BY Campaign
)
SELECT Campaign, sum_a, sum_d FROM query1
GROUP BY Campaign
"""
I have these columns
Id Status
----------
1 pass
1 fail
2 pass
3 pass
How do I select all that only have a status of pass but if the Id has at least one fail it will not be selected as well.
If same id can have multiple passes
SELECT id
from table
WHERE status = 'pass'
and id NOT IN (SELECT id FROM table WHERE status = 'fail')
You need to use GROUP BY & HAVING clause
SELECT Id
FROM yourtable
GROUP BY Id
HAVING Sum(case when status ='pass' then 1 else 0 end) = count(status)
HAVING clause can be changed to
HAVING Count(case when status ='pass' then 1 end) = count(status)
I just hate chatty case statement, so
SELECT Id
FROM table1
GROUP BY Id
HAVING COUNT(DISTINCT [Status]) = 1 AND MIN([Status]) = 'pass'
or
SELECT Id
FROM table1
GROUP BY Id
HAVING COUNT(NULLIF([Status], 'fail')) = 1 AND COUNT(NULLIF([Status], 'pass')) = 0
The second query only works when status has two values 'pass' and 'fail'.
I have table which list a number of cases and assigned primary and secondary technicians. What I am trying to accomplish is to aggregate the number of cases a technician has worked as a primary and secondary tech. Should look something like this...
Technician Primary Secondary
John 4 3
Stacy 3 1
Michael 5 3
The table that I am pulling that data from looks like this:
CaseID, PrimaryTech, SecondaryTech, DOS
In the past I have used something like this, but now my superiors are asking for the number of secondary cases as well...
SELECT PrimaryTech, COUNT(CaseID) as Total
GROUP BY PrimaryTech
I've done a bit of searching, but cant seem to find the answer to my problem.
Select Tech,
sum(case when IsPrimary = 1 then 1 else 0 end) as PrimaryCount,
sum(case when IsPrimary = 0 then 1 else 0 end) as SecondaryCount
from
(
SELECT SecondaryTech as Tech, 0 as IsPrimary
FROM your_table
union all
SELECT PrimaryTech as Tech, 1 as IsPrimary
FROM your_table
) x
GROUP BY Tech
You can group two subqueries together with a FULL JOIN as demonstrated in this SQLFiddle.
SELECT Technician = COALESCE(pri.Technician, sec.Technician)
, PrimaryTech
, SecondaryTech
FROM
(SELECT Technician = PrimaryTech
, PrimaryTech = COUNT(*)
FROM Cases
WHERE PrimaryTech IS NOT NULL
GROUP BY PrimaryTech) pri
FULL JOIN
(SELECT Technician = SecondaryTech
, SecondaryTech = COUNT(*)
FROM Cases
WHERE SecondaryTech IS NOT NULL
GROUP BY SecondaryTech) sec
ON pri.Technician = sec.Technician
ORDER By Technician;
SELECT COALESCE(A.NAME, B.NAME) AS NAME, CASE WHEN A.CASES IS NOT NULL THEN A.CASES ELSE 0 END AS PRIMARY_CASES,
CASE WHEN B.CASES IS NOT NULL THEN B.CASES ELSE 0 END AS SECONDARY_CASES
FROM
(
SELECT COUNT(*) AS CASES, PRIMARYTECH AS NAME FROM YOUR_TABLE
GROUP BY PRIMARYTECH
) AS A
FULL OUTER JOIN
(
SELECT COUNT(*) AS CASES, SECONDARYTECH AS NAME FROM YOUR_TABLE
GROUP BY SECONDARYTECH
) AS B
ON A.NAME = B.NAME
SQL query question
I have a query like
select proposal_id, service_id,account_type
from table1
The result is like this:
proposal_id service_id account_type
1 1001 INTERVAL
1 1002 INTERVAL
2 1003 NON INTERVAL
2 1004 NON INTERVAL
3 1005 NON INTERVAL
3 1006 INTERVAL
I want to write a query: for each proposal_id, if all the service have INTERVAL then get 'INTERVAL', if all NON-INTERVAL get 'NON-INTERVAL', if both, get 'Both'
For the example above, it should return
proposal_id account_type
1 INTERVAL
2 NON-INTERVAL
3 BOTH
Data:
declare #table table (id int, sid int, acc nvarchar(20))
insert #table VALUES (1,1001,'INTERVAL'),(1,1002,'INTERVAL'),(2,1003,'NON INTERVAL'),(2,1004,'NON INTERVAL'),
(3,1005,'NON INTERVAL'),(3,1006,'INTERVAL')
Query:
select x.Id
, CASE counter
WHEN 1 THEN x.Account_Type
ELSE 'BOTH'
END AS Account_Type
from (
select Id, Count(DISTINCT(acc)) AS counter, MAX(acc) As Account_Type
from #table
GROUP BY Id
) x
Results
Id Account_Type
----------- --------------------
1 INTERVAL
2 NON INTERVAL
3 BOTH
SELECT
b.proposal_id
,CASE
WHEN s1.proposal_id IS NOT NULL AND s2.proposal_id IS NOT NULL THEN 'BOTH'
WHEN s1.proposal_id IS NOT NULL THEN 'INTERVAL'
WHEN s2.proposal_id IS NOT NULL THEN 'NON-INTERVAL'
ELSE 'UNKNOWN'
END [account_type]
FROM table1 b
LEFT JOIN(
SELECT proposal_id,account_type FROM table1 WHERE account_type = 'INTERVAL'
) s1
ON b.proposal_id = s1.proposal_id
LEFT JOIN (
SELECT proposal_id,account_type FROM table1 WHERE account_type = 'NON-INTERVAL'
)s2
ON b.proposal_id = s2.proposal_id
You could use count distinct to determinate if it is both then use CASE to determinate what to display
SELECT DISTINCT proposal.proposal_id,
CASE cou
WHEN 1 THEN type ELSE 'Both' END as TYPE
FROM proposal
INNER JOIN (SELECT proposal_id, count(distinct type) cou
FROM proposal GROUP BY proposal_id) inn
ON proposal.id = inn.id
select proposal_id,
case when count(distinct account_type) > 1 then 'BOTH'
else max(account_type)
end
from table1
group by proposal_id
You have the fiddler here.
If I have a table with a schema like this
table(Category, SubCategory1, SubCategory2, Status)
I would like to group by Category, SubCategory1 and aggregate the Status such that
if not all Status values over the group have a certain value Status will be 0 otherwise 1.
So my result set will look like
(Category, SubCategory1, Status)
I don't want to write a function. I would like to do it inside the query.
Assuming that status is a numeric data type, use:
SELECT t.category,
t.subcategory1,
CASE WHEN MIN(t.status) = MAX(t.status) THEN 1 ELSE 0 END AS status
FROM dbo.TABLE_1 t
GROUP BY t.category, t.subcategory1
You can test that both the minimum and maximum status for each group are equal to your desired value:
SELECT
category,
subcategory1,
CASE WHEN MIN(status) = 42 AND MAX(status) = 42 THEN 1 ELSE 0 END AS Status
FROM table1
GROUP BY category, subcategory1
Let's say you want to find groups that have all status values under 100
SELECT category, subcategory1,
CASE WHEN MAX(status) < 100 THEN 0 ELSE 1 END AS Status
FROM table1
GROUP BY category, subcategory1
All groups with status under 100 will have Status set to 0, and all groups with at least one status >= 100 will be set to 1.
I think that's what you're asking for, but if not let me know.
I would like to group by Category,
SubCategory1 and aggregate the Status
such that if not all Status values
over the group have a certain value
Status will be 0 otherwise 1.
I'm interpreting this as "If there exists a Status value in a given group not equal to a given parameter, the returned Status will be 0 otherwise 1".
Select T.Category, T.SubCategory1
, Case
When Exists(
Select 1
From Table As T2
Where T2.Category = T.Category
And T2.SubCategory1 = T.SubCategory1
And T2.Status <> #Param
) Then 0
Else 1
End As Status
From Table As T
Group By t.Category, T.SubCategory1
Something like that :
select
Category,
SubCategory1,
(
case
when good_record_count = all_record_count then 1
else 0
end
) as all_records_good
from (
select
t.Category,
t.SubCategory1,
sum( cast(coalesce(t.Status, 'GOOD', '1', '0') as int) ) good_record_count,
count(1) all_record_count
from
table_name t
group by
t.Category, t.SubCategory1
)