Impala Version: 5.12.2
I need to match string which contains \%， for example, a\%b. In impala shell，I use the following sql for test:
select 'a\\%b' like 'a\\\%b';
The result is right:
sql result
select '\\%' like '\\\%'；
I expected the result to be true, but actually I got false:
sql result
I think both \ and % should be escaped in like, so I use '\\\%'. I don't known why the second sql doesn't work, could anyone explain it?
By the way, if I need to match string which contains two slash， for example a\b\c， I tried the flowing sql:
select 'a\\b\\c' like '%\\%\\%';
but the result is false:
sql result
Here，the % is used as wildcard, so I don't escape it. could anyone give a right sql?
Thanks for any advice.
The first result that you are listing does not match with your query, it should be True. Your second query is wrong, you need to escape the backlash as this \\\\
This query should do the job
select 'a\\b\\c' like '%\\\\%\\\\%';
Anyway I would recommend use regex
select regexp_like('a\\b\\c','(.*?)\\\\{1}(.*?)\\\\{1}(.*?)'); -- true
select regexp_like('a\\bc','(.*?)\\\\{1}(.*?)\\\\{1}(.*?)'); -- false
select regexp_like('a\\\\','(.*?)\\\\{1}(.*?)\\\\{1}(.*?)'); -- true
select regexp_like('\\\\','(.*?)\\\\{1}(.*?)\\\\{1}(.*?)'); -- true
select regexp_like('\\b\\c','(.*?)\\\\{1}(.*?)\\\\{1}(.*?)'); -- true
select regexp_like('ab\\','(.*?)\\\\{1}(.*?)\\\\{1}(.*?)'); -- false
Related
when i execute the following select statement i am getting the below error.
I am trying to execute the below statement in Oracle server 9.1.
I believe due to this i am getting this error.
I know we can excute the query for single quotes by '%Blondeau D''Uva%'. But i am looking for query which will pass the special character value as parameter.
Kindluy let me know how to escape single quotes in old oracle server
ERROR :
ORA-00933: SQL Command not properly ended
Error at line : 1 Column : 50
Query:
Select * FROM TABLEA where UI_FNAME like q'[%Michael%]' and UI_LNAME like q'[ %Blondeau D'Uva%]';
On oracle the following should work
Select *
FROM TABLEA
where UI_FNAME like '[%Michael%]'
and UI_LNAME like '[ %Blondeau D''Uva%]';
So no duplicate where
And you have to quote the ' between D und Uva
And probably the q before the ' is wrong ... so I have removed it as well.
Ok tried it out with the q operator:
Select *
FROM employees
where first_name like q'[%Michael%]'
and last_name like q'[ %Blondeau D'Uva%]';
No errors no row ...
Two things about your query:
Two times usage of where where there should be just one.
About the second condition. You have used q'[ %Blondeau D'Uva%]' in like clause. I think that won't give you the result you might be looking for. This has nothing to do with your error, but still, it would not hurt to re-check the query.
Try this, this shouldn't run you into any error :
Select * FROM TABLEA
where UI_FNAME like q'[%Michael%]'
and UI_LNAME like q'[%Blondeau D'Uva%]';
Cheers!
As others have tried to give you an answer, but I think you probably need to keep % outside brackets -
Select *
FROM TABLEA
where UI_FNAME like '%[Michael]%'
and UI_LNAME like '%[ Blondeau D''Uva]%';
I have a table with about 200 million records. One of the columns is defined as varchar(100) and it's included in a full text index. Most of the values are numeric. Only few are not numeric.
The problem is that it's not working well. For example if a row contains the value '123456789' and i look for '567', it's not returning this row. It will only return rows where the value is exactly '567'.
What am I doing wrong?
sql server 2012.
Thanks.
Full text search doesn't support leading wildcards
In my setup, these return the same
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'28400')
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"2840*"')
This gives zero rows
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"*840*"')
You'll have to use LIKE or some fancy trigram approach
The problem is probably that you are using a wrong tool since Full-text queries perform linguistic searches and it seems like you want to use simple "like" condition.
If you want to get a solution to your needs then you can post DDL+DML+'desired result'
You can do this:
....your_query.... LIKE '567%' ;
This will return all the rows that have a number 567 in the beginning, end or in between somewhere.
99% You're missing % after and before the string you search in the LIKE clause.
es:
SELECT * FROM t WHERE att LIKE '66'
is the same as as using WHERE att = '66'
if you write:
SELECT * FROM t WHERE att LIKE '%66%'
will return you all the lines containing 2 'sixes' one after other
I have some records in a column that contain IDs and some of these records contain multiple IDs separated by commas. Additionally there are some records where I have ",3" and ",2" when they should simply be "3" and "2". I do not have write privileges in this DB so updating those records is not an option.
I am trying to write a query that returns records that have a comma where the value to the left of any comma in the record is greater than 0 e.g. "2,3", "2,3,12" etc but NOT ",3" or ",2".
What would this expression look like in MS Access?
Thanks in advance.
If you want to remove the starting comma from the records when you return them, you can do so using a simple query:
SELECT IIF(MyField LIKE ",*", Right(MyField, Len(MyField)-1), MyField)
FROM MyTable
To answer your original question, you could simply use Val:
SELECT * FROM YourTable WHERE Val([YourField]) > 0
I would simply use:
select t.*
from t
where val not like ",*";
This doesn't handle the 0 part, but you don't give any examples in your answer. Perhaps this answers that part:
select t.*
from t
where val not like ",*" and val not like "*0,*";
I have a data source like following
If I ran the following sql query it removes all the records with "Seg Type" MOD and ignores the Fnn range given.
select * from NpsoQueue
where SegmentType not in ('MOD')
and Fnn not between 0888452158 and 0888452158
I want the query to consider both conditions. So, if I ran the query it should remove only the first record
The logic in your where clause is incorrect
Use
select * from NpsoQueue
where NOT (
SegmentType = 'MOD'
and Fnn between '0888452158' and '0888452158'
)
Also, a number with a leading zero is a string literal so you need to put single quotes around it to preserve the leading zero and stop implicit casts happening
As mentioned by #TriV you could also use OR. These are fundamental boolean logic concepts, i.e. not related to SQL Server or databases
I'm having some trouble understanding WHY a select statement isn't working in a query I'm making.
I've got the SELECT and FROM lines functioning. With just those, ALL results from my selected table are displayed - 517 or so
What I want to do is display results based on a pattern using LIKE - What I have so far
SELECT *
FROM Tbl_ServiceRequestMatrix
WHERE Tbl_ServiceRequestMatrix.[Application/Form] LIKE 'P%';
This returns 0 results - despite the fact that the column selected DOES have entries that start with 'P'
I also tried utilising brackets, see if that was the issue - still displays 0 results:
SELECT *
FROM Tbl_ServiceRequestMatrix
WHERE ((Tbl_ServiceRequestMatrix.[Application/Form])='p%');
Can any one help me understand why my WHERE ** LIKE statement is causing 0 results to be displayed?
The wildcard character in MS Access is (by default) * instead of %:
WHERE Tbl_ServiceRequestMatrix.[Application/Form] LIKE "P*"
LIKE Statement has different parameters in different sql languages.
In MS Access you need * Instead of % in LIKE Statement.