I have some records in a column that contain IDs and some of these records contain multiple IDs separated by commas. Additionally there are some records where I have ",3" and ",2" when they should simply be "3" and "2". I do not have write privileges in this DB so updating those records is not an option.
I am trying to write a query that returns records that have a comma where the value to the left of any comma in the record is greater than 0 e.g. "2,3", "2,3,12" etc but NOT ",3" or ",2".
What would this expression look like in MS Access?
Thanks in advance.
If you want to remove the starting comma from the records when you return them, you can do so using a simple query:
SELECT IIF(MyField LIKE ",*", Right(MyField, Len(MyField)-1), MyField)
FROM MyTable
To answer your original question, you could simply use Val:
SELECT * FROM YourTable WHERE Val([YourField]) > 0
I would simply use:
select t.*
from t
where val not like ",*";
This doesn't handle the 0 part, but you don't give any examples in your answer. Perhaps this answers that part:
select t.*
from t
where val not like ",*" and val not like "*0,*";
Related
I have string column that looks usually approximately like this:
https://mapy.cz/zakladni?x=16.3360208&y=49.6718038&z=8&source=firm&id=13123554
https://mapy.cz/turisticka?x=15.9380354&y=50.1990211&z=11&source=base&id=2197
https://mapy.cz/turisticka?x=12.8611357&y=49.8051338&z=16&source=base&id=1703157
I would like to group data by source which is part of the string - four letters behind "source=" (in the case above: firm) and then simply count them. Is there a way to achieve this directly in SQL code? I am using hadoop.
Data is a set of strings that look like above. My expected result is summary table with two columns: 1) Each type of the source (there is about 20 possible and their length is different so I cannot use sipmle substring). Ideally I am looking for solution that says: For the grouping use four letters that come after "source=" 2) Count of their occurences in all the strings.
There is just one source type in each string.
You can use regexp_extract():
select substr(regexp_extract(url, 'source[^&]+'), 8)
You can use charindex in MSSQL to get position of string and extract record
;with cte as (
SELECT SUBSTRING('https://mapy.cz/zakladni?x=16.3360208&y=49.6718038&z=8&source=firm&id=13123554',
charindex('&source=','https://mapy.cz/zakladni?x=16.3360208&y=49.6718038&z=8&source=firm&id=13123554')
+8,4) AS ExtractString )
select ExtractString,count(ExtractString) as count from cte group by ExtractString;
There is equivalent function LOCATE in hiveql for charindex.
I have a table with about 200 million records. One of the columns is defined as varchar(100) and it's included in a full text index. Most of the values are numeric. Only few are not numeric.
The problem is that it's not working well. For example if a row contains the value '123456789' and i look for '567', it's not returning this row. It will only return rows where the value is exactly '567'.
What am I doing wrong?
sql server 2012.
Thanks.
Full text search doesn't support leading wildcards
In my setup, these return the same
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'28400')
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"2840*"')
This gives zero rows
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"*840*"')
You'll have to use LIKE or some fancy trigram approach
The problem is probably that you are using a wrong tool since Full-text queries perform linguistic searches and it seems like you want to use simple "like" condition.
If you want to get a solution to your needs then you can post DDL+DML+'desired result'
You can do this:
....your_query.... LIKE '567%' ;
This will return all the rows that have a number 567 in the beginning, end or in between somewhere.
99% You're missing % after and before the string you search in the LIKE clause.
es:
SELECT * FROM t WHERE att LIKE '66'
is the same as as using WHERE att = '66'
if you write:
SELECT * FROM t WHERE att LIKE '%66%'
will return you all the lines containing 2 'sixes' one after other
Please help me because I have been unable to get this right.
What is the access SQL to select this column(columnA) so that it returns a resultset with distinct values sorted first according to numbers and then to letters.
Here is the columns values: {10A,9C,12D,11G,9B,10C,9R,8T}
I have tried 'Select distinct ColumnA from tblClass order by 1'
but it returns {10A,10C,11G,12D,8T,9B,9C,9R} which is not what I want.
Thank you in advance.
You can use the Val() function for this. From the help topic: "The Val function stops reading the string at the first character it can't recognize as part of a number"
Val(10A) will give you 10, Val(9C) will give you 9, and so on. So in your query, order by Val(ColumnA) first, then ColumnA.
SELECT DISTINCT Val([ColumnA]) AS number_part, ColumnA
FROM tblClass
ORDER BY Val([ColumnA]), ColumnA;
SELECT DISTINCT ColumnA
FROM tblClass
ORDER BY CInt(LEFT(ColumnA,len(ColumnA)-1)), RIGHT(ColumnA,1);
If there last character is a letter and the others are a number.
Your data type is a string so it's sorting correctly, to get the result you want you're going to have to split your values into numeric and alphabetic parts and then sort first on the numeric then the alphabetic. Not being an Access programmer I can't help you with exactly how you're going to do that.
order by 1?
Don't you mean order by ColumnA?
SELECT DISTINCT ColumnA
FROM tblClass
ORDER BY ColumnA
I had a similar problem and used a dummie workaround:
changing a list of {10A,10C,11G,12D,8T,9B,9C,9R}
into {10A,10C,11G,12D,08T,09B,09C,09R} by adding the 0 before each <10 number.
now all items are the same length and access will sort correctly into {08T, 09B, 09C, 09R, 10A, 10C, 11G, 12D}
.
To achieve this, I copied this column into excel column A and used IF(LEN(A2)<3, concatenate("0", A2))
I found a weird problem with MySQL select statement having "IN" in where clause:
I am trying this query:
SELECT ads.*
FROM advertisement_urls ads
WHERE ad_pool_id = 5
AND status = 1
AND ads.id = 23
AND 3 NOT IN (hide_from_publishers)
ORDER BY rank desc
In above SQL hide_from_publishers is a column of advertisement_urls table, with values as comma separated integers, e.g. 4,2 or 2,7,3 etc.
As a result, if hide_from_publishers contains same above two values, it should return only record for "4,2" but it returns both records
Now, if I change the value of hide_for_columns for second set to 3,2,7 and run the query again, it will return single record which is correct output.
Instead of hide_from_publishers if I use direct values there, i.e. (2,7,3) it does recognize and returns single record.
Any thoughts about this strange problem or am I doing something wrong?
There is a difference between the tuple (1, 2, 3) and the string "1, 2, 3". The former is three values, the latter is a single string value that just happens to look like three values to human eyes. As far as the DBMS is concerned, it's still a single value.
If you want more than one value associated with a record, you shouldn't be storing it as a comma-separated value within a single field, you should store it in another table and join it. That way the data remains structured and you can use it as part of a query.
You need to treat the comma-delimited hide_from_publishers column as a string. You can use the LOCATE function to determine if your value exists in the string.
Note that I've added leading and trailing commas to both strings so that a search for "3" doesn't accidentally match "13".
select ads.*
from advertisement_urls ads
where ad_pool_id = 5
and status = 1
and ads.id = 23
and locate(',3,', ','+hide_from_publishers+',') = 0
order by rank desc
You need to split the string of values into separate values. See this SO question...
Can Mysql Split a column?
As well as the supplied example...
http://blog.fedecarg.com/2009/02/22/mysql-split-string-function/
Here is another SO question:
MySQL query finding values in a comma separated string
And the suggested solution:
http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_find-in-set
I have a table say, ITEM, in MySQL that stores data as follows:
ID FEATURES
--------------------
1 AB,CD,EF,XY
2 PQ,AC,A3,B3
3 AB,CDE
4 AB1,BC3
--------------------
As an input, I will get a CSV string, something like "AB,PQ". I want to get the records that contain AB or PQ. I realized that we've to write a MySQL function to achieve this. So, if we have this magical function MATCH_ANY defined in MySQL that does this, I would then simply execute an SQL as follows:
select * from ITEM where MATCH_ANY(FEAURES, "AB,PQ") = 0
The above query would return the records 1, 2 and 3.
But I'm running into all sorts of problems while implementing this function as I realized that MySQL doesn't support arrays and there's no simple way to split strings based on a delimiter.
Remodeling the table is the last option for me as it involves lot of issues.
I might also want to execute queries containing multiple MATCH_ANY functions such as:
select * from ITEM where MATCH_ANY(FEATURES, "AB,PQ") = 0 and MATCH_ANY(FEATURES, "CDE")
In the above case, we would get an intersection of records (1, 2, 3) and (3) which would be just 3.
Any help is deeply appreciated.
Thanks
First of all, the database should of course not contain comma separated values, but you are hopefully aware of this already. If the table was normalised, you could easily get the items using a query like:
select distinct i.Itemid
from Item i
inner join ItemFeature f on f.ItemId = i.ItemId
where f.Feature in ('AB', 'PQ')
You can match the strings in the comma separated values, but it's not very efficient:
select Id
from Item
where
instr(concat(',', Features, ','), ',AB,') <> 0 or
instr(concat(',', Features, ','), ',PQ,') <> 0
For all you REGEXP lovers out there, I thought I would add this as a solution:
SELECT * FROM ITEM WHERE FEATURES REGEXP '[[:<:]]AB|PQ[[:>:]]';
and for case sensitivity:
SELECT * FROM ITEM WHERE FEATURES REGEXP BINARY '[[:<:]]AB|PQ[[:>:]]';
For the second query:
SELECT * FROM ITEM WHERE FEATURES REGEXP '[[:<:]]AB|PQ[[:>:]]' AND FEATURES REGEXP '[[:<:]]CDE[[:>:]];
Cheers!
select *
from ITEM where
where CONCAT(',',FEAURES,',') LIKE '%,AB,%'
or CONCAT(',',FEAURES,',') LIKE '%,PQ,%'
or create a custom function to do your MATCH_ANY
Alternatively, consider using RLIKE()
select *
from ITEM
where ','+FEATURES+',' RLIKE ',AB,|,PQ,';
Just a thought:
Does it have to be done in SQL? This is the kind of thing you might normally expect to write in PHP or Python or whatever language you're using to interface with the database.
This approach means you can build your query string using whatever complex logic you need and then just submit a vanilla SQL query, rather than trying to build a procedure in SQL.
Ben