I'm trying to get percentage of missed calls for each user, so I used the following sql query:
select distinct a__contact
, count (case when a__type = 'missed'
then 1 else 0 end) / count(*) * 100
as "percentage of missed calls"
from table
group by 1
However, for each user I got 100 which do not seem to be correct output at all. Could someone help me to identify the error in my query? thank you so much!
Here is a simpler way to express the logic you want:
select a__contact,
avg(case when a__type = 'missed' then 100.0 else 0 end) as percentage_missed_calls
from table
group by 1;
Your version is failing because you are using count() in the numerator. You really intend sum(). count() counts the number of non-NULL values and both "1" and "0" are non-NULL.
Related
There is a table of accidents and output the share of accidents number 2 to all accidents I wrote this code, but I can not make it work:
select ((select count("ID") from "DTP" where "REASON"=2)/count("REASON"))
from "DTP"
group by "ID"
Something like this (not tested):
select id, count(case reason when 2 then 1 end)/count(*) as proportion
from your_table
-- where ... (if you need to filter, for example by date)
group by id
;
count(*) counts all the rows in a group (that is, all the rows for each separate id). The case expression returns 1 when the reason is 2 and it returns null otherwise; count counts only non-null values, so it will count the rows where the reason is 2.
You can use avg():
select id,
avg(case when reason = 2 then 1.0 else 0 end)
from "DTP"
group by "ID"
This produces the ratio for each id -- based on your sample query. If you only want one row for all the data, then:
select avg(case when reason = 2 then 1.0 else 0 end)
from "DTP";
i have looked for a simple example to sum two queries together and get a final output as a single value. I have set up a simple query below to use as an example.
SELECT Count (banana)
FROM FRUIT_BASKET
WHERE CONDITION = 'ROTTEN'
/ -- THEN DIVIDE THIS NUMBER BY
SELECT Count (banana)
FROM FRUIT_BASKET
* 100 -- TO GET A PERCENTAGE
Any help will be great thankyou all
This should do it:
SELECT COUNT(CASE WHEN CONDITION = 'ROTTEN' THEN banana END) * 100 / COUNT(banana)
FROM FRUIT_BASKET
You can do conditional aggregation:
select
count(case when condition = 'ROTTEN' then banana end)
/ count(banana) * 100
from fruit_basket
I like using AVG() for this:
SELECT AVG(CASE WHEN Condition = 'Rotten' THEN 100.0 ELSE 0 END)
FROM FRUIT_BASKET
WHERE banana IS NOT NULL;
I would definitely consider the divide by zero scenario in such case.
So better to use avg aggregate function as suggested by gordon or handle divide by zero scenario by yourself as following:
select
count(case when condition = 'ROTTEN' then banana end)
/ decode(count(banana),0,1) * 100
from fruit_basket
Cheers!!
I have a query like:
select nvl(nvl(sum(a.quantity),0)-nvl(cc.quantityCor,0),0)
from RCV_TRANSACTIONS a
LEFT JOIN (select c.shipment_line_id,c.oe_order_line_id,nvl(sum(c.quantity),0) quantityCor
from RCV_TRANSACTIONS c
where c.TRANSACTION_TYPE='CORRECT'
group by c.shipment_line_id,c.oe_order_line_id) cc on (a.shipment_line_id=cc.shipment_line_id and a.shipment_line_id=7085740)
where a.transaction_type='DELIVER'
and a.shipment_line_id=7085740
group by nvl(cc.quantityCor,0);
The query runs OK, but returns no value. I want it to return 0 if there is no quantity found. Where have I gone wrong?
An aggregation query with a GROUP BY returns no rows if all rows are filtered out.
An aggregation query with no GROUP BY always returns one row, even if all rows are filtered out.
So, just remove the GROUP BY. And change the SELECT to:
select coalesce(sum(a.quantity), 0) - coalesce(max(cc.quantityCor), 0)
I may be wrong, but it seems you merely want to subtract CORRECT quantity from DELIVER quantity for shipment 7085740. You don't need a complicated query for that. Especially your GROUP BY clauses make no sense if that is what you are after.
One way to write this query would be:
select
sum(case when transaction_type = 'DELIVER' then quantity else 0 end) -
sum(case when transaction_type = 'CORRECT' then quantity else 0 end) as diff
from rcv_transactions
where shipment_line_id = 7085740;
I had a query like this and was trying to return 'X' when the item is not valid.
SELECT case when segment1 is not null then segment1 else 'X' end
--INTO v_orgValidItem
FROM mtl_system_items_b
WHERE segment1='1676001000'--'Jul-00'--l_item
and organization_id=168;
..but it was returning NULL.
Changed to use aggregation with no group by and now it returns 'X' when the item is not valid.
SELECT case when max(segment1) is not null then max(segment1) else 'X' end valid
--INTO v_orgValidItem
FROM mtl_system_items_b
WHERE segment1='1676001000'--'Jul-00'--l_item
and organization_id=168;--l_ship_to_organization_id_pb;
Here is another example, proving the order of operations really matters.
When there is no match for this quote number, this query returns NULL:
SELECT MAX(NVL(QUOTE_VENDOR_QUOTE_NUMBER,0))
FROM PO_HEADERS_ALL
WHERE QUOTE_VENDOR_QUOTE_NUMBER='foo.bar';
..reversing the order of MAX and NVL makes all the difference. This query returns the NULL value condition:
SELECT NVL(MAX(QUOTE_VENDOR_QUOTE_NUMBER),0)
FROM PO_HEADERS_ALL
WHERE QUOTE_VENDOR_QUOTE_NUMBER='foo.bar';
I have a result set such as:
Code No
1 *
1 -
1 4
1
1
Now i basically want a query that has 2 columns, a count for the total amount and a count for those that dont have numbers.
Code No_Number Total
1 4 5
Im assuming this needs a group by and a count but how can i do the 2 different counts in a query like this?
This is what i had so far, but i am a bit stuck with the rest of it
SELECT CODE,NO
Sum(Case when No IN ('*', '-', '') then 1 else 0 end) as Count
I think you basically just need GROUP BY:
SELECT CODE,
SUM(Case when No IN ('*', '-', '') then 1 else 0 end) as Count,
COUNT(*) as total
FROM t
GROUP BY CODE;
Well, this took a moment :-), however here it is...I have used a CASE statement to create and populate the No_Number column; the database gives the row in the original table a value of 1 if the original table value is a number or gives it a NULL and discards it from the COUNT if not. Then when it makes the count it is only recognising values which were originally numbers and ignoring everything else..
If the result set is in a table or temp table:
SELECT Code,
COUNT(CASE WHEN [No] NOT LIKE '[0-9]' THEN 1 ELSE NULL END) AS No_Number,
COUNT(Code) AS Total
FROM <tablename>
GROUP BY Code
If the result set is the product of a previous query you can use a CTE (Common Table Expression) to arrive at the required result or you could include parts of this code in the earlier query.
I need help with a query. Consider the following table:
I need to select first the sum of each Code from table. I am doing it with simple sum and group by statement. Then I have to subtract the results from each code sum where type='r'
1) Say for first part of query, we will get 2 rows from SUM (one with total USD and one with total YEN)
2) Now I need to subtract from these results the corresponding USD, YEN value which has Type='r'
I have to do it inside SQL and not a stored procedure.
Why not use a WHERE statement to say WHERE Type != 'r' so that those values never even get added to sum in the first place...
SELECT `Code`, SUM(`Amount`) AS `Total`
FROM `Table`
WHERE `Type` != 'r'
GROUP
BY `Code`;
Something like that.
select code, l.amount - r.amount
from
(select code, sum(amount) as amount from my_table group by code) l
left join (select code, sum(amount) as amount from my_table where type = 'r' group by code) r
on l.code = r.code
You can do this in a single, simple query:
select
code,
sum(case when type = 'r' then (-1 * amount) else amount end) as sum
from
yourtable
group by
code
Basically, you're changing the sign of the rows that have type = 'r', so when you sum all rows for a particular code you'll get the correct answer.
Does it have to be a single query?
I'd say SUM the total, then SUM the subcategory where Type='r', then subtract one from the other.
You could do this in one line of SQL, but I'm pretty sure it would be either joining the table with itself or using a subquery. Either way, it's doing the same amount of work as the above.
Try:
select code,
sum(amount) gross_total,
sum(case when type = 'r' then amount else 0 end) type_r_total,
sum(case when type != 'r' then amount else 0 end) net_total
from yourtable
group by code;
to see the overall totals, type R only totals and non-type R totals for each currency on one row per currency, in a single pass.