Get the sum of a count column in SQL - sql

I have the following query
SELECT
dtc.coupon_type_company_name,
COUNT(*) * dtc.coupon_type_company_coupon_amount AS 'Total_Coupon_To_Be_Used',
dtc.coupon_type_company_coupon_months_combinable
FROM
[dbo].[coupon_type_Company_User] dtcu
JOIN
coupon_type_Company dtc ON dtcu.coupon_type_Company_ID = dtc.id
JOIN
person p ON dtcu.userID = p.userID
WHERE
coupon_type_company_coupon_is_combinable = 1
OR coupon_type_company_has_coupon = 1
AND dtc.companyID = 1081
AND p.is_active = 1
GROUP BY
dtc.coupon_type_company_name,dtc.coupon_type_company_coupon_amount,
dtc.coupon_type_company_coupon_months_combinable
This returns the following:
What I want to have however is just one column and one row that should take the SUM of my middle column (count(*)*dtc.coupon_type_company_coupon_amount).
How could I achieve this and prevent doing this in my code backend (C#)

You can wrap your query like this:
SELECT SUM(Total_Coupon_To_Be_Used) AS the_sum
FROM (
your query
) s

Use a "Table Expression", as in:
select sum(Total_Coupon_To_Be_Used) from (
SELECT dtc.coupon_type_company_name,
count(*) * dtc.coupon_type_company_coupon_amount as 'Total_Coupon_To_Be_Used',
dtc.coupon_type_company_coupon_months_combinable
FROM [dbo].[coupon_type_Company_User] dtcu
JOIN coupon_type_Company dtc ON dtcu.coupon_type_Company_ID = dtc.id
JOIN person p ON dtcu.userID = p.userID
WHERE coupon_type_company_coupon_is_combinable = 1
or coupon_type_company_has_coupon = 1
and dtc.companyID = 1081
AND p.is_active = 1
GROUP BY
dtc.coupon_type_company_name,dtc.coupon_type_company_coupon_amount,
dtc.coupon_type_company_coupon_months_combinable
) x

Related

Rails - how to convert output of find_by_sql (array) to an ActiveRecord relation?

I am in a need of running a complex SQL query and because I didn't know how to construct the query using ActiveRecod, I had to use a raw SQL query by using find_by_sql:
scope :get_cars, -> do
find_by_sql('select * from
(SELECT cars.*,
manufacturer.company_name AS manufacturer_company_name,
services.a_num AS service_a_num,
(SELECT car_documents.file_url FROM car_documents
WHERE car_documents.car_id = cars.id AND car_documents.doc_type = 1 LIMIT 1) AS doc1_file_url,
(SELECT car_documents.file_s3_url FROM car_documents
WHERE car_documents.cart_id = cars.id AND car_documents.doc_type = 3 LIMIT 1) AS file_inv,
(SELECT car_data.demand_lvl FROM car_data
WHERE car_data.car_id = cars.id) AS demand_lvl,
(SELECT car_logs.invoice FROM car_logs
WHERE car_logs.car_id = cars.id AND car_logs.invoice = 1 LIMIT 1) AS invoice_sent
FROM "cars"
INNER JOIN "services" ON "services"."id" = "cars"."service_id"
LEFT JOIN manufacturers ON manufacturers.id = cars.manufacturer_id
WHERE (cars.status_id != 6
AND cars.delivery_date < NOW() - INTERVAL \'15 days\'
) ORDER BY cars.pickup_date ASC) t
Where doc1_file_url IS NULL OR file_inv IS NULL OR invoice_sent IS NULL')
end
The output is an array. How do I convert this array into an ActiveRecord object? Or possibly, is there any workaround?
I think, You can use the from() method from the Active Record interface. You can use a subquery as a table for a SQL select statement with help of from() method. check the below example. In this way, you will get the active record object.
subquery = Setting.limit(10)
Setting.from("(#{subquery.to_sql}) settings")
In your case,
subquery = "(SELECT cars.*,
manufacturer.company_name AS manufacturer_company_name,
services.a_num AS service_a_num,
(SELECT car_documents.file_url FROM car_documents
WHERE car_documents.car_id = cars.id AND car_documents.doc_type = 1 LIMIT 1) AS doc1_file_url,
(SELECT car_documents.file_s3_url FROM car_documents
WHERE car_documents.cart_id = cars.id AND car_documents.doc_type = 3 LIMIT 1) AS file_inv,
(SELECT car_data.demand_lvl FROM car_data
WHERE car_data.car_id = cars.id) AS demand_lvl,
(SELECT car_logs.invoice FROM car_logs
WHERE car_logs.car_id = cars.id AND car_logs.invoice = 1 LIMIT 1) AS invoice_sent
FROM "cars"
INNER JOIN "services" ON "services"."id" = "cars"."service_id"
LEFT JOIN manufacturers ON manufacturers.id = cars.manufacturer_id
WHERE (cars.status_id != 6
AND cars.delivery_date < NOW() - INTERVAL \'15 days\'
) ORDER BY cars.pickup_date ASC)"

How to get fields from multiple tables

I want to get fields from 2 different tables . The last field candidate_score_id has a many to one relationship. So how should I join the below 2 queries
1) To get candidate_score_id from the candidate_score table.
select candidate_score_id from candidate_score a where
a.assessment_id = NEW.assessment_id and
a.candidate_id = NEW.candidate_id and
a.attempt_Count = NEW.attempt_count;
2) To insert different fields in to the candidate_score_details table. The field in this table should be obtained by query above.
insert into candidate_score_details(candidate_score_details_id, candidate_id, assessment_id, attempt_count, score_type, score_tag,correct, candidate_score_id)
select uuid();
select a.candidate_id, a.assessment_id,a.attempt_count,"BY-COMPLEXITY",
case c.complexity
when 1 then "HIGH"
when 2 then "MEDIUM"
when 3 then "LOW"
end, count(*) from candidate_answer a, answer_key b, question_meta_data c where a.candidate_id = NEW.candidate_id and
a.assessment_id = NEW.assessment_id and
a.attempt_count = NEW.attempt_count and
a.assessment_id = b.assessment_id and
a.question_id = b.question_number and
a.response = b.answer and
a.question_id = c.question_number
group by a.candidate_id, a.assessment_id, a.attempt_count, c.complexity;
Just looking at the SQL joining aspect of your question, you'll need to specify the table I THINK you're aliasing a 2nd table with the "NEW" reference. If that's the case, then the query would be (replacing "OTHER_TABLE_NAME" with the name of the 2nd table:
select a.candidate_score_id
from candidate_score a
left join OTHER_TABLE_NAME new on
and a.assessment_id = NEW.assessment_id
and a.candidate_id = NEW.candidate_id
and a.attempt_Count = NEW.attempt_count
Seems that Query 1 has the same 3 criteria on the "candidate_score" table as for the "candidate_answer" table in Query 2.
So how about adding a LEFT JOIN of "candidate_score" to "candidate_answer" on those 3 fields?
For example:
INSERT INTO candidate_score_details
(
candidate_score_details_id,
candidate_id,
assessment_id,
attempt_count,
score_type,
score_tag,
correct,
candidate_score_id
)
SELECT
uuid(),
answer.candidate_id,
answer.assessment_id,
answer.attempt_count,
'BY-COMPLEXITY' AS score_type,
(CASE meta.complexity
WHEN 1 THEN 'HIGH'
WHEN 2 THEN 'MEDIUM'
WHEN 3 THEN 'LOW'
END) AS score_tag,
COUNT(*) AS correct,
MAX(score.candidate_score_id) AS max_candidate_score_id
FROM candidate_answer AS answer
JOIN answer_key AS akey
ON (akey.assessment_id = answer.assessment_id AND akey.question_number = answer.question_id AND akey.answer = answer.response)
LEFT JOIN candidate_score AS score
ON (score.candidate_id = answer.candidate_id AND score.assessment_id = answer.assessment_id AND score.attempt_count = answer.attempt_count)
LEFT JOIN question_meta_data AS meta
ON meta.question_number = answer.question_id
WHERE answer.candidate_id = NEW.candidate_id
AND answer.assessment_id = NEW.assessment_id
AND answer.attempt_count = NEW.attempt_count
GROUP BY answer.candidate_id, answer.assessment_id, answer.attempt_count, meta.complexity;

How to use alias of a subquery to get the running total?

I have a UNION of 3 tables for calculating some balance and I need to get the running SUM of that balance but I can't use PARTITION OVER, because I must do it with a sql query that can work in Access.
My problem is that I cannot use JOIN on an alias subquery, it won't work.
How can I use alias in a JOIN to get the running total?
Or any other way to get the SUM that is not with PARTITION OVER, because it does not exist in Access.
This is my code so far:
SELECT korisnik_id, imePrezime, datum, Dug, Pot, (Dug - Pot) AS Balance
FROM (
SELECT korisnik_id, k.imePrezime, r.datum, SUM(IIF(u.jedinstven = 1, r.cena, k.kvadratura * r.cena)) AS Dug, '0' AS Pot
FROM Racun r
INNER JOIN Usluge u ON r.usluga_id = u.ID
INNER JOIN Korisnik k ON r.korisnik_id = k.ID
WHERE korisnik_id = 1
AND r.zgrada_id = 1
AND r.mesec = 1
AND r.godina = 2017
GROUP BY korisnik_id, k.imePrezime, r.datum
UNION ALL
SELECT korisnik_id, k.imePrezime, rp.datum, SUM(IIF(u.jedinstven = 1, rp.cena, k.kvadratura * rp.cena)) AS Dug, '0' AS Pot
FROM RacunP rp
INNER JOIN Usluge u ON rp.usluga_id = u.ID
INNER JOIN Korisnik k ON rp.korisnik_id = k.ID
WHERE korisnik_id = 1
AND rp.zgrada_id = 1
AND rp.mesec = 1
AND rp.godina = 2017
GROUP BY korisnik_id, k.imePrezime, rp.datum
UNION ALL
SELECT uu.korisnik_id, k.imePrezime, uu.datum, '0' AS Dug, SUM(uu.iznos) AS Pot
FROM UnosUplata uu
INNER JOIN Korisnik k ON uu.korisnik_id = k.ID
WHERE korisnik_id = 1
GROUP BY uu.korisnik_id, k.imePrezime, uu.datum
) AS a
ORDER BY korisnik_id
You can save a query (let's name it Query1) for the UNION of the 3 tables and then create another query that returns each row in the first query and calculates the sum of the rows that are before it (optionally checking that they are in the same group).
It should be something like this:
SELECT *, (
SELECT SUM(Value) FROM Query1 AS b
WHERE b.GroupNumber=a.GroupNumber
AND b.Position<=a.Position
) AS RunningSum
FROM Query1 AS a
However, it's more efficient to do that in the report.

Return a Count of 0 When No Rows

OK, I've looked this up and tried a number of solutions, but can't get it to work. I'm a bit of a novice. Here's my original query - how can I get it to return 0 for an account when there are no results in the student table?
SELECT a.NAME
,count(s.student_sid)
FROM account a
JOIN inst i ON a.inst_sid = i.root_inst_sid
JOIN inst_year iy ON i.inst_sid = iy.inst_sid
JOIN student s ON iy.inst_year_sid = s.inst_year_sid
WHERE s.demo = 0
AND s.STATE = 1
AND i.STATE = 1
AND iy.year_sid = 16
AND a.account_sid IN (
20187987
,20188576
,20188755
,52317128
,20189249
)
GROUP BY a.NAME;
Use an outer join, moving the condition on that table into the join:
select a.name, count(s.student_sid)
from account a
join inst i on a.inst_sid = i.root_inst_sid
join inst_year iy on i.inst_sid = iy.inst_sid
left join student s on iy.inst_year_sid = s.inst_year_sid
and s.demo = 0
and s.state = 1
where i.state = 1
and iy.year_sid = 16
and a.account_sid in (20187987, 20188576, 20188755, 52317128, 20189249)
group by a.name;
count() does not count null values, which s.student_sid will be if no rows join from student.
You need to LEFT JOIN and then SUM() over the group where s.student_sid is not null:
select
a.name,
sum(case when s.student_sid is null then 0 else 1 end) as student_count
from account a
join inst i on a.inst_sid = i.root_inst_sid
join inst_year iy on i.inst_sid = iy.inst_sid
left join student s
on iy.inst_year_sid = s.inst_year_sid
and s.demo = 0
and s.state = 1
where i.state = 1
and iy.year_sid = 16
and a.account_sid in (20187987, 20188576, 20188755, 52317128, 20189249)
group by a.name;
This is assuming that all of the fields in the student table that you are filtering on are optional. If you don't want to enforce removal of records where, say, s.state does not equal 1, then you need to move the s.state=1 predicate into the WHERE clauses.
If, for some reason, you are getting duplicate student IDs and students are being counted twice, then you can change the aggregate function to this:
count(distinct s.student_id) as student_count
...which is safe to do as count(distinct ...) ignores null values.

Get count from table given input from another

I have 3 tables: filer_info, filer_persent and persent_email, connected via:
filer_info.filer_info_id = filer_persent.filer_info_id
filer_persent.persent_info_id = persent_email.persent_info_id
I want to find all rows where I have multiple type PRIMARY in the persent_email table (ie count > 1). And the only thing I want to return in the query is filer_info.filer_ident and the count.
This gives me every row, but I only want the data where filer_ident > 1 in the returned rows.
select * from filer_info f
inner join filer_persent fp on f.filer_info_id=fp.filer_info_id
inner join persent_email p on fp.persent_info_id=p.persent_info_id
where fp.filer_persent_kind_cd = 'FILER' and p.persent_email_kind_cd='PRIMARY'
order by f.filer_ident
SELECT filer_ident, cnt
FROM (
SELECT filer_info_id, COUNT(*) cnt
FROM filer_persent fp
JOIN persent_email p
USING (persent_info_id)
WHERE (fp.filer_persent_kind_cd, p.persent_email_kind_cd) = ('FILER', 'PRIMARY')
HAVING COUNT(*) > 1
) с
JOIN filer_info f
USING (filer_info_id)
WHERE filer_ident > 1
ORDER BY
f.filer_ident