I am trying to use LEFT JOIN, NOT EXISTS and NOT IN, where I want records from pursuit table, expect matching records from condition table using foreign key instance = id. When I execute the query, it shows empty (no records).
LEFT JOIN
SELECT p.id, p.dept
FROM
pursuit p LEFT JOIN condition c USING (dept)
WHERE
p.id = c.instance
NOT EXISTS
SELECT p.id, p.dept
FROM
pursuit p
WHERE
p.id NOT EXISTS IN (SELECT c.instance FROM condiiton c)
NOT IN
SELECT p.id, p.dept
FROM
pursuit p
WHERE
p.id NOT IN (SELECT c.instance FROM condiiton c)
TABLES
condition
id instance dept
1 3 5
5 2 5
2 7 5
3 4 5
4 10 5
5 2 3
6 15 6
pursuit
id name dept
3 C1 5
2 C9 5
7 C77 5
4 C9 5
10 C6 5
19 C23 5
17 C45 5
15 C12 5
23 C33 5
3,2,7,4 = matching records of dept 5
19,17,15,23 = not matching records of dept 5
Output
id name dept
19 C23 5
17 C45 5
15 C12 5
23 C33 5
Edit2:
SELECT p.id, p.dept
FROM pursuit p LEFT JOIN condition c
on (p.id = c.instance and p.dep=c.dep)
WHERE c.instance IS NULL
this returns rows of pursuit not present in condition table
I would use NOT EXISTS instead :
SELECT P.*
FROM pursuit p
WHERE NOT EXISTS (SELECT 1
FROM condition c
WHERE p.id = c.instance
);
The only problem were with NOT EXISTS you haven't established any relation between them.
Related
I have three tables :
field:
f_id
f_start
f_end
1
10
20
2
15
25
3
5
10
person :
p_id
p_name
1
Roger
2
John
3
Alicia
affect :
id
fk_field
fk_person
1
2
1
2
1
2
3
3
3
And I would like to select the dates and the names associated to. Like this
p_name
f_start
f_end
Roger
15
25
John
10
20
Alicia
5
10
I'm new to SQL and I don't know if i have to use JOIN or not... Thanks
You must join all 3 tables on their related columns:
SELECT p.p_name, f.f_start, f.f_end
FROM person p
INNER JOIN affect a ON a.fk_person = p.p_id
INNER JOIN field f ON f.f_id = a.fk_field;
Depending on your requirement you may need LEFT instead of INNER joins, but for this sample data the INNER joins will do.
I have two tables total_sales_store :
store. total_sales
23 198750953.849999
29 77141561.3099999
9 77789512.9899997
15 89133935.9200002
3 57586980.0699998
32 166819624.16
26 143416610.79
12 144287538.149999
35 131520910.08
6 223756634.64
43 90565869.4100002
21 108118179.92
27 253856294.88
38 55159990.42
7 81598450.1399996
and storesdata:
store. type
1 A
2 A
3 B
4 A
5 B
6 A
7 B
8 A
9 B
10 B
11 A
I want to full join the two table so that I have this desired table:
store. Type. totalsales
1 A 123124
2 B 141221
3 C 134141
4 A. 234234
5 B 2323
6 C 123214
...
So I used the following query:
SELECT A.Store,a.total_sales
FROM totalsales_store A
FULL JOIN
(
SELECT [Type], Store
FROM storesdata
) B
ON A.Store = B.Store
ORDER BY total_sales DESC
But what I got is this:
[enter image description here][3]
which neglects the Type column. What can I do to make this work? Thank you!
With a FULL JOIN you will get all results from both tables, even when they don't match each other, so you should account for the NULL store values across tables. Otherwise simply include the Type column in the select.
I didn't see a need for a sub-query.
SELECT
ISNULL(A.Store, B.Store) Store,
B.Type,
a.total_sales
FROM
totalsales_store A
FULL JOIN storesdata B ON
A.Store = B.Store
ORDER BY
a.total_sales DESC
I suspect you can get away with
SELECT
A.Store,
B.Type,
a.total_sales
FROM
totalsales_store A
JOIN storesdata B ON
A.Store = B.Store
ORDER BY
a.total_sales DESC
Table: ProductionOrder
Id Ordernumber Lotsize
1 Order1 50
2 Order 2 75
3 WO-order1 1
4 WO-order2 1
Table: history
Id ProductionOrderID Completed
1 3 1
2 3 1
3 4 1
4 4 1
Table: ProductionOrderDetail
ID ProductionOrderID ProductionOrderDetailDefID Content
1 1 16 50
2 1 17 7-1-2018
3 2 16 75
4 2 17 7-6-2018
Start of my code:
Select p.ID, p.OrderNumber,
Case productionOrderDetailDefID
Where(Select pd1.productionOrderDetailDefID where ProductionOrderDetialDefID = 16) then min(pd1.content)
from ProductionOrder p
Left join History h1 on p.id = h1.productionOrderID
Left Join ProductionOrderDetail pd1 on p.ID = ProductionOrderID
The result in trying to get is
Id Ordernumber Lotsize Productionorder Completed
1 Order1 50 WO-order1 2
2 Order 2 75 WO-order2 2
Any help would be appreciated.
Try this
SELECT ordernumber,lotsize,Ordernumber,count(Ordernumberid)
FROM productionorder inner join history on productionorder.id = history.Ordernumberid
GROUP BY Ordernumber;
A bit of weird joins going on here. You should add this to a SQL fiddle so that we can see our work easier.
A link to SQL fiddle: http://sqlfiddle.com/
Here is my first attempt
SELECT
po.id
, po.ordernumber
, po.lotsize
, po2.productionorder
, SUM(h.completed)
FROM productionorder as po
INNER JOIN history as h
ON h.id = po.id
INNER JOIN prodcuctionorder as po2
ON po2.ordernumberid = h.ordernumberid
WHERE po.id NOT EXISTS IN ( SELECT ordernumberid FROM history )
GROUP BY
po.id
, po.ordernumber
, po.lotzise
, po2.productionorder
How far does that get you?
id address retailer
1 A 11
2 A 11
3 A 11
4 A 12
5 A 13
6 B 12
7 B 12
8 B 13
My output should be
id address retailer
1 A 11
4 A 12
5 A 13
6 B 12
8 B 13
i.e my query should return id's which have same address but not same retailer.
How toget this?
Try to use group by clause as below:
select min(id), address, retailer
from tab
group by address, retailer
Assuming you're joining on columns with no duplicates, which is by far the most common case:
An inner join of A and B gives the result of A intersect B, i.e. the inner part of a venn diagram intersection.
An outer join of A and B gives the results of A union B, i.e. the outer parts of a venn diagram union.
Examples:
Suppose you have two Tables, with a single column each, and data as follows:
A B
- -
1 3
2 4
3 5
4 6
Note that (1,2) are unique to A, (3,4) are common, and (5,6) are unique to B.
Inner join:
An inner join using either of the equivalent queries gives the intersection of the two tables, i.e. the two rows they have in common.
select *
from a
INNER JOIN b on a.a = b.b;
select a.*,b.*
from a,b
where a.a = b.b;
a | b
--+--
3 | 3
4 | 4
Left outer join:
A left outer join will give all rows in A, plus any common rows in B.
select *
from a
LEFT OUTER JOIN b on a.a = b.b;
select a.*,b.*
from a,b
where a.a = b.b(+);
a | b
--+-----
1 | null
2 | null
3 | 3
4 | 4
Full outer join:
A full outer join will give you the union of A and B, i.e. All the rows in A and all the rows in B. If something in A doesn't have a corresponding datum in B, then the B portion is null, and vice versa.
select *
from a
FULL OUTER JOIN b on a.a = b.b;
a | b
-----+-----
1 | null
2 | null
3 | 3
4 | 4
null | 6
null | 5
select min(id) as id,address, retailer
from table1
group by address, retailer
order by id
The query you need is:
SELECT min(id), address, retailer
FROM table1 AS t1
group by address, retailer
order by address
Here's the source
Use This: It's working:
SELECT * FROM `sampletable` GROUP BY address, retailer
I have three tables tblClients, tblClientsActivities and tblActivities
tblClients and tblClientsActivities are joined together to produce Table A below
SELECT * from tblClientsActivities
left join tblclients on tblClientsActivities.fk_cid=tblclients.pk_cid
PK_AID FK_CID FK_AID
1 4 1
2 4 2
3 4 4
4 5 1
5 5 3
6 5 5
7 6 1
8 6 2
9 7 6
10 8 3
The problem is how do i remove all clients where FK_AID <> 1
Description
Simple use a WHERE clause.
Sample
SELECT * FROM tblClientsActivities
LEFT JOIN tblclients on tblClientsActivities.fk_cid=tblclients.pk_cid
WHERE FK_AID <> 1
With a restriction used in a WHERE clause:
SELECT * from tblClientsActivities
left join tblclients on tblClientsActivities.fk_cid=tblclients.pk_cid
where FK_AID != 1