I have a SQL Server 2008 table and a specific column Title which contains a mixture of strings that all start with 'WM' and end in a store number, for example WM24 or WM1234.
What I'd like to do is normalize all the rows to a standard format of WMXXXX' (where XXXX is a 4-digit store number). So WM26 would become WM0026 and WM123 would become WM0123, but WM1234 is unaffected.
Is this doable?
You can use SUBSTRING(Title, 3, LEN(Title) - 2) or RIGHT(Title, Len(Title)-2)) or Replace(Title, 'WM', '') to pull off the numbers from the WM. Then pad it out with zeros.
Here it is with the Substring():
SELECT 'WM' + Right('0000' + Substring(Title, 3, LEN(Title) - 2), 4) as title
FROM yourtable;
Or Right():
SELECT 'WM' + Right('0000' + RIGHT(Title, Len(Title)-2)), 4) as title
FROM yourtable;
Or Replace():
SELECT 'WM' + Right('0000' + Replace(Title, 'WM', '')), 4) as title
FROM yourtable;
Sure this is pretty simple. But I have to ask, if every single row starts with "WM" why bother? That is incredibly redundant. Start by removing that prefix then make a 4 character string of what is left.
select 'WM' + right('0000' + substring(YourColumn, 3, len(YourColumn)), 4)
from YourTable
Related
I have to extract the next number out of given numbers. My table contains numbers like below. The main product is always with .1 at the end and could or not contains his subproducts e.g:
07.0001.1 (main product)
07.0001.2 (his sub)
07.0001.3 (his sub)
etc..
01.1453.1
01.1453.2
03.3456.1
03.3456.2
03.3456.3
03.5436.1
03.5436.2
03.5436.3
03.5436.4
12.7839.1
12.7839.2
12.3232.1
12.4444.1
12.4444.2
13.7676.1
i want to pass first to digits of a number to the query and based on that get all which starts with that and then get the highest number out of next four and return this number + 1.
So if we would take above example inputs if i say 12 then it should find this product: 12.7839.x and return 12.7839 + 1 so 12.7840
Another example if i say 03 then should find 03.5436 so 03.5436 + 1 so should return 03.5437
Hope you know what i mean.
I am not so familiar with SQL but this is how far i am:
select * from tbArtikel where Nummer LIKE '12.%'
This is another alternate for achieving the desired results. Providing the option to pass number to be queried. Consider following SQL statements
CREATE TABLE tblDummyExample
(
Number VARCHAR(64)
)
INSERT INTO tblDummyExample
VALUES ('07.0001.1')
, ('07.0001.2')
, ('07.0001.3')
, ('01.1453.1')
, ('01.1453.2')
, ('03.3456.1')
, ('03.3456.2')
, ('03.3456.3')
, ('03.5436.1')
, ('03.5436.2')
, ('03.5436.3')
, ('03.5436.4')
, ('12.7839.1')
, ('12.7839.2')
, ('12.3232.1')
, ('12.4444.1')
, ('12.4444.2')
, ('13.7676.1')
DECLARE #startWith VARCHAR(2) = '12' -- provide any number as input
SELECT #startWith + '.'+ CAST((MAX(CAST(SUBSTRING(ex.Number, (CHARINDEX('.', ex.Number, 1) + 1), (CHARINDEX('.', ex.Number, (CHARINDEX('.', ex.Number, 1) + 1)) - (CHARINDEX('.', ex.Number, 1) + 1))) AS INT)) + 1) AS VARCHAR(16))
FROM tblDummyExample ex
WHERE ex.Number LIKE #startWith+'%'
I'm sure, this solution is not restricted to any specific SQL Server version.
Try this, extract the first two parts, convert the 2nd to a numeric value, add one and convert back to a string again:
select
parsename(max(nummer), 3) + '.' -- 03
+ ltrim(max(cast(parsename(nummer, 2) as int) +1)) -- 5436 -> 5437
+ '.1'
from tbArtikel
where Nummer LIKE '03.%'
Try like this,
DECLARE #table TABLE (col VARCHAR(10))
INSERT INTO #table
VALUES ('01.1453.1')
,('01.1453.2')
,('03.3456.1')
,('03.3456.2')
,('03.3456.3')
,('03.5436.1')
,('03.5436.2')
,('03.5436.3')
,('03.5436.4')
,('12.7839.1')
,('12.7839.2')
,('12.3232.1')
,('12.4444.1')
,('12.4444.2')
,('13.7676.1')
SELECT TOP 1 left(col, charindex('.', col, 1) - 1) + '.' + convert(VARCHAR(10), convert(INT, substring(col, charindex('.', col, 1) + 1, charindex('.', col, charindex('.', col, 1) + 1) - (charindex('.', col, 1) + 1))) + 1)
FROM #table
WHERE col LIKE '03.%'
ORDER BY 1 DESC
I want to convert numbers to 3 decimal places for each number between the character ".". For example:
1.1.5.2 -> 001.001.005.002
1.2 -> 001.002
4.0 -> 004.000
4.3 ->004.003
4.10 -> 004.010
This is my query:
SELECT ItemNo
FROM EstAsmTemp
This is fairly easy once you understand all the steps:
Split the string into the individual data points.
Convert the parsed values into the format you want.
Shove the new values back into a delimited list.
Ideally you shouldn't store data with multiple datapoints in a single intersection like this but sometimes you just have no choice.
I am using the string splitter from Jeff Moden and the community at Sql Server Central which can be found here. http://www.sqlservercentral.com/articles/Tally+Table/72993/. There are plenty of other decent string splitters out there. Here are some excellent examples of other options. http://sqlperformance.com/2012/07/t-sql-queries/split-strings.
Make sure you understand this code before you use it in your production system because it will be you that gets the phone call at 3am asking for it to be fixed.
with something(SomeValue) as
(
select '1.1.5.2' union all
select '1.2' union all
select '4.0' union all
select '4.3' union all
select '4.10'
)
, parsedValues as
(
select SomeValue
, right('000' + CAST(x.Item as varchar(3)), 3) as NewValue
, x.ItemNumber as SortOrder
from something s
cross apply dbo.DelimitedSplit8K(SomeValue, '.') x
)
select SomeValue
, STUFF((Select '.' + NewValue
from parsedValues pv2
where pv2.SomeValue = pv.SomeValue
order by pv2.SortOrder
FOR XML PATH('')), 1, 1, '') as Details
from parsedValues pv
group by pv.SomeValue
I decided to change it in the presentation layer, per Zohar Peled's comment.
You did not mention the number of '.' separator a column can have. I assume, the max is 4 and the solution is below.
SELECT STUFF(ISNULL('.' + RIGHT('000' + PARSENAME(STRVALUE,4),4),'') + ISNULL('.' + RIGHT('000' + PARSENAME(STRVALUE,3),4) ,'') + ISNULL('.' + RIGHT('000' + PARSENAME(STRVALUE,2),4) ,'') + ISNULL('.' + RIGHT('000' + PARSENAME(STRVALUE,1),4),''),1,1,'')
FROM (VALUES('1.1.5.2'), ('1.2'), ('4.0'),('4.3'), ('4.10')) A (STRVALUE)
I have a numeric column formatted that contains data like:
8547.22
-1254.22
For reasons beyond my control I need to present the results of a select in this format (this is one field of a much larger select statement) I can't add any new functions either.
-$8,547.22
$1,254.22
So to be clear I need to add money formatting ('$' and ',') and also reverse positive numbers to negative and vice versa.
I've tried the following which obviously doesn't work:
case
when a.principal_outstanding like '-%'
then '$' + (SELECT RIGHT(REPLACE(CONVERT(varchar(20), (CAST(SUM(a.principal_outstanding) AS money)), 1), '.00', ''), LEN((REPLACE(CONVERT(varchar(20), (CAST(SUM(a.principal_outstanding) AS money)), 1), '.00', '')))) - 1)
when a.principal_outstanding not like '-%'
then '-' + '$' + (REPLACE(CONVERT(varchar(20), (CAST(SUM(a.principal_outstanding) AS money)), 1), '.00', ''))
else 'ERROR2'
end as '<currentBalance>'
Any suggestions?
If you must do this in your SQL query (and not the client):
SELECT '$' + CONVERT(VARCHAR, CAST(TheValue * -1 AS MONEY), 1)
FROM TheTable
Edit: Since you're using negative numbers, it gets even more ugly, but does the job.
SELECT CASE WHEN TheValue <= 0
THEN '$' + CONVERT(VARCHAR, CAST(TheValue * -1 AS MONEY), 1)
ELSE '-$' + CONVERT(VARCHAR, CAST(TheValue AS MONEY), 1)
END
FROM TheTable
The DBMS in this case is SQL Server 2012.
I need a SQL query that will grab just the numbers from a device name. I've got devices that follow a naming scheme that SHOULD look like this:
XXXnnnnn
or
XXXnnnnn-XX
Where X is a letter and n is a number which should be left padded with 0's where appropriate. However, not all of the names are properly padded in this way.
So, imagine you have a column that looks something like this:
Name
----
XXX01234
XXX222
XXX0390-A2
XXX00965-A1
I need an SQL query that will return results from this example column as follows.
Number
------
01234
00222
00390
00965
Anyone have any thoughts? I've tried things like casting the name first as a float and then as an int, but to be honest, I'm just not skilled enough with SQL yet to find the solution.
Any help is greatly appreciated!
SQL Server does not have great string parsing functions. For your particular example, I think a case statement might be the simplest approach:
select (case when number like '___[0-9][0-9][0-9][0-9][0-9]%'
then substring(number, 4, 5)
when number like '___[0-9][0-9][0-9][0-9]%'
then '0' + substring(number, 4, 4)
when number like '___[0-9][0-9][0-9]%'
then '00' + substring(number, 4)
when number like '___[0-9][0-9]%'
then '000' + substring(number, 4, 2)
when number like '___[0-9][0-9]%'
then '0000' + substring(number, 4, 1)
else '00000'
end) as EmbeddedNumber
This might work :
SELECT RIGHT('00000'
+ SUBSTRING(Col, 1, ISNULL(NULLIF((PATINDEX('%-%', Col)), 0) - 1, LEN(Col))), 5)
FROM (SELECT REPLACE(YourColumn, 'XXX', '') Col
FROM YourTable)t
SQLFIDDLE
This will work even when XXX can be of different len:
DECLARE #t TABLE ( n NVARCHAR(50) )
INSERT INTO #t
VALUES ( 'XXXXXXX01234' ),
( 'XX222' ),
( 'X0390-A2' ),
( 'XXXXXXX00965-A1' )
SELECT REPLICATE('0', 5 - LEN(n)) + n AS n
FROM ( SELECT SUBSTRING(n, PATINDEX('%[0-9]%', n),
CHARINDEX('-', n + '-') - PATINDEX('%[0-9]%', n)) AS n
FROM #t
) t
Output:
n
01234
00222
00390
00965
If the first 3 chars are always needed to be removed, then you can do something like that (will work if the characters will start only after '-' sign):
DECLARE #a AS TABLE ( a VARCHAR(100) );
INSERT INTO #a
VALUES
( 'XXX01234' ),
( 'XXX222' ),
( 'XXX0390-A2' ),
( 'XXX00965-A1' );
SELECT RIGHT('00000' + SUBSTRING(a, 4, CHARINDEX('-',a+'-')-4),5)
FROM #a
-- OUTPUT
01234
00222
00390
00965
Another option (will extract numbers after first 3 characters):
SELECT
RIGHT('00000' + LEFT(REPLACE(a, LEFT(a, 3), ''),
COALESCE(NULLIF(PATINDEX('%[^0-9]%',
REPLACE(a, LEFT(a, 3), '')),
0) - 1,
LEN(REPLACE(a, LEFT(a, 3), '')))), 5)
FROM
#a;
-- OUTPUT
01234
00222
00390
00965
I select data from a database. The values are (field name is ADR_KOMP_VL) :
4 , 61A, 100, 12, 58, 123C, 6 A, 5
I need to convert these values to 3 digits (except when there is a letter then it is 4)
So the converted values should be:
004, 061A, 100, 012, 058, 123C, 006A, 005
The rules are:
Always 3 digits
No spaces
If the original value is less than three digits, put 0's in front of it.(The length is 3)
If the original value contains a letter, put 0's in front of it (but the length is 4)
For the "no space" part I have this:
select REPLACE(ADR_KOMP_VL, ' ','')
The solution I have so far is:
SELECT RIGHT('000' + CONVERT(VARCHAR(4),REPLACE(ADR_KOMP_VL, ' ','')), 3)
But this only gives me the right length, when there is no letter in the value. My problem is how to handle the values with a letter in them??
This only check if the last character is letter. Additional logic will be required if that's not the case
SELECT REPLICATE('0', CASE WHEN ISNUMERIC(RIGHT(ADR_KOMP_VL, 1)) = 0 THEN 4
ELSE 3
END - LEN(REPLACE(ADR_KOMP_VL, ' ', '')))
+ REPLACE(ADR_KOMP_VL, ' ', '')
FROM TX
EDIT - actually this might work better, checks for whole ADR_KOMP_VL if it's numeric:
SELECT REPLICATE('0', CASE WHEN ISNUMERIC(REPLACE(ADR_KOMP_VL, ' ', '')) = 0 THEN 4
ELSE 3
END - LEN(REPLACE(ADR_KOMP_VL, ' ', '')))
+ REPLACE(ADR_KOMP_VL, ' ', '')
FROM TX
SQLFiddle DEMO
You can use a case statement:
SELECT (case when ADR_KOMP_VL like '%[A-Z]%'
then RIGHT('0000' + CONVERT(VARCHAR(4),REPLACE(ADR_KOMP_VL, ' ','')), 4)
else RIGHT('000' + CONVERT(VARCHAR(4),REPLACE(ADR_KOMP_VL, ' ','')), 3)
end)