I have a numeric column formatted that contains data like:
8547.22
-1254.22
For reasons beyond my control I need to present the results of a select in this format (this is one field of a much larger select statement) I can't add any new functions either.
-$8,547.22
$1,254.22
So to be clear I need to add money formatting ('$' and ',') and also reverse positive numbers to negative and vice versa.
I've tried the following which obviously doesn't work:
case
when a.principal_outstanding like '-%'
then '$' + (SELECT RIGHT(REPLACE(CONVERT(varchar(20), (CAST(SUM(a.principal_outstanding) AS money)), 1), '.00', ''), LEN((REPLACE(CONVERT(varchar(20), (CAST(SUM(a.principal_outstanding) AS money)), 1), '.00', '')))) - 1)
when a.principal_outstanding not like '-%'
then '-' + '$' + (REPLACE(CONVERT(varchar(20), (CAST(SUM(a.principal_outstanding) AS money)), 1), '.00', ''))
else 'ERROR2'
end as '<currentBalance>'
Any suggestions?
If you must do this in your SQL query (and not the client):
SELECT '$' + CONVERT(VARCHAR, CAST(TheValue * -1 AS MONEY), 1)
FROM TheTable
Edit: Since you're using negative numbers, it gets even more ugly, but does the job.
SELECT CASE WHEN TheValue <= 0
THEN '$' + CONVERT(VARCHAR, CAST(TheValue * -1 AS MONEY), 1)
ELSE '-$' + CONVERT(VARCHAR, CAST(TheValue AS MONEY), 1)
END
FROM TheTable
Related
I'm looking a simple way to remove an unwanted Duplicate value.
The Dupe is part of a reference to another column, and not within the column itself, but the column I want to remove the dupe value from is multi-delimited with other values.
Here is an example table:
ID,Thing
Dog,Cat;Dog;Bird
Snake,Horse;Fish;Snake
Car,Car;Bus;Bike
As you can see Dog,Snake,Car are the values I need to remove from the Thing column.
Output:
ID,Thing
Dog,Cat;Bird
Snake,Horse;Fish
Car,Bus;Bike
Is there a way to match within a multidelimited field and pull out the exact match?
I'm using SQL Server MGMT studio. Thanks.
WITH CTE AS
(
SELECT ID, Thing, ROW_NUMBER() OVER (PARTITION BY Thing) AS rn
)
DELETE
FROM CTE
WHERE rn > 1
I believe this will do it. Test first by running just the CTE part of the query so you can see what rn is.
Your question and sample data is not very clear. I think what you want is to remove anything from the second column that is in the first column, in which case you can try using replace
select Id,
replace(replace(thing,id,''),';;',';')
from table
Storing multi-value elements in a column is never a good idea and is a conflict of interest with the relational data model; it pretty much always causes problems at some point.
What you can do is concatenate a leading and a trailing ; to the value of Thing and then replace the value of ID with an empty string.
Then remove the leading and trailing ;.
If your version of SQL Server is 2017+, you can use the function TRIM():
SELECT Id,
TRIM(';' FROM REPLACE(';' + Thing + ';', ';' + ID + ';', ';')) Thing
from tablename;
For previous versions use SUBSTRING():
SELECT Id,
SUBSTRING(
REPLACE(';' + Thing + ';', ';' + ID + ';', ';'),
2,
LEN(REPLACE(';' + Thing + ';', ';' + ID + ';', ';')) - 2
) Thing
from tablename;
If you want to update the table:
UPDATE tablename
SET Thing = TRIM(';' FROM REPLACE(';' + Thing + ';', ';' + ID + ';', ';'));
or:
UPDATE tablename
SET Thing = SUBSTRING(
REPLACE(';' + Thing + ';', ';' + ID + ';', ';'),
2,
LEN(REPLACE(';' + Thing + ';', ';' + ID + ';', ';')) - 2
);
See the demo.
I don't really understand what "multi-delimited" means with respect to a string. In your context it seems to suggest that you might have different types of delimiters. It definitely does mean that you have a really poor data model. If you want to remove the id from the things column, then my first suggestion is to fix the delimiters.
In SQL Server, you could use:
select t.*,
(select string_agg(s.value, ';')
from string_split(replace(t.things, ',', ';'), ';') s
where s.value <> t.id
) as new_things
from t;
If the delimited have some intrinsic meaning (did I mentioned that you should fix the data model?), then you can use a more brute force approach. Here is one method:
select t.*,
(case when things = id then ''
when things like concat(id, '[,;]%')
then stuff(things, 1, len(id) + 1, '')
when things like concat('%[,;]', id)
then left(things, len(things) - len(id) - 1)
when things like concat('%[,;]', id, '[,;]%')
then stuff(things, patindex(concat('%[,;]', id, '[,;]%'), things), len(id) + 1, '')
else things
end)
from t;
Here is a db<>fiddle.
Your Question is a good one. I used simple case statement to get the answer. It is CHARINDEX that helped to find the location of the value in Id column and then identified the position of the value in id and according to the position, string was replaced by required values.
--Preparing the table
SELECT *
INTO t
FROM (VALUES
('Dog', 'Cat;Dog;Bird'),
('Snake', 'Horse;Fish;Snake'),
('Car', 'Car;Bus;Bike')
) v(id, things)
--Query
SELECT id
,CASE WHEN CHARINDEX(reverse(id), reverse(things), 1) = 1 THEN REPLACE(things,';'+id ,'')
WHEN CHARINDEX(id, things, 1) < LEN(things) AND CHARINDEX(id, things, 1) > 1 THEN REPLACE(things, id +';' ,'')
WHEN CHARINDEX(id, things, 1) = 1 THEN REPLACE(things, id +';' ,'')
ELSE 'End'
END as [things]
FROM t
I have a SQL Server 2008 table and a specific column Title which contains a mixture of strings that all start with 'WM' and end in a store number, for example WM24 or WM1234.
What I'd like to do is normalize all the rows to a standard format of WMXXXX' (where XXXX is a 4-digit store number). So WM26 would become WM0026 and WM123 would become WM0123, but WM1234 is unaffected.
Is this doable?
You can use SUBSTRING(Title, 3, LEN(Title) - 2) or RIGHT(Title, Len(Title)-2)) or Replace(Title, 'WM', '') to pull off the numbers from the WM. Then pad it out with zeros.
Here it is with the Substring():
SELECT 'WM' + Right('0000' + Substring(Title, 3, LEN(Title) - 2), 4) as title
FROM yourtable;
Or Right():
SELECT 'WM' + Right('0000' + RIGHT(Title, Len(Title)-2)), 4) as title
FROM yourtable;
Or Replace():
SELECT 'WM' + Right('0000' + Replace(Title, 'WM', '')), 4) as title
FROM yourtable;
Sure this is pretty simple. But I have to ask, if every single row starts with "WM" why bother? That is incredibly redundant. Start by removing that prefix then make a 4 character string of what is left.
select 'WM' + right('0000' + substring(YourColumn, 3, len(YourColumn)), 4)
from YourTable
I have to extract the next number out of given numbers. My table contains numbers like below. The main product is always with .1 at the end and could or not contains his subproducts e.g:
07.0001.1 (main product)
07.0001.2 (his sub)
07.0001.3 (his sub)
etc..
01.1453.1
01.1453.2
03.3456.1
03.3456.2
03.3456.3
03.5436.1
03.5436.2
03.5436.3
03.5436.4
12.7839.1
12.7839.2
12.3232.1
12.4444.1
12.4444.2
13.7676.1
i want to pass first to digits of a number to the query and based on that get all which starts with that and then get the highest number out of next four and return this number + 1.
So if we would take above example inputs if i say 12 then it should find this product: 12.7839.x and return 12.7839 + 1 so 12.7840
Another example if i say 03 then should find 03.5436 so 03.5436 + 1 so should return 03.5437
Hope you know what i mean.
I am not so familiar with SQL but this is how far i am:
select * from tbArtikel where Nummer LIKE '12.%'
This is another alternate for achieving the desired results. Providing the option to pass number to be queried. Consider following SQL statements
CREATE TABLE tblDummyExample
(
Number VARCHAR(64)
)
INSERT INTO tblDummyExample
VALUES ('07.0001.1')
, ('07.0001.2')
, ('07.0001.3')
, ('01.1453.1')
, ('01.1453.2')
, ('03.3456.1')
, ('03.3456.2')
, ('03.3456.3')
, ('03.5436.1')
, ('03.5436.2')
, ('03.5436.3')
, ('03.5436.4')
, ('12.7839.1')
, ('12.7839.2')
, ('12.3232.1')
, ('12.4444.1')
, ('12.4444.2')
, ('13.7676.1')
DECLARE #startWith VARCHAR(2) = '12' -- provide any number as input
SELECT #startWith + '.'+ CAST((MAX(CAST(SUBSTRING(ex.Number, (CHARINDEX('.', ex.Number, 1) + 1), (CHARINDEX('.', ex.Number, (CHARINDEX('.', ex.Number, 1) + 1)) - (CHARINDEX('.', ex.Number, 1) + 1))) AS INT)) + 1) AS VARCHAR(16))
FROM tblDummyExample ex
WHERE ex.Number LIKE #startWith+'%'
I'm sure, this solution is not restricted to any specific SQL Server version.
Try this, extract the first two parts, convert the 2nd to a numeric value, add one and convert back to a string again:
select
parsename(max(nummer), 3) + '.' -- 03
+ ltrim(max(cast(parsename(nummer, 2) as int) +1)) -- 5436 -> 5437
+ '.1'
from tbArtikel
where Nummer LIKE '03.%'
Try like this,
DECLARE #table TABLE (col VARCHAR(10))
INSERT INTO #table
VALUES ('01.1453.1')
,('01.1453.2')
,('03.3456.1')
,('03.3456.2')
,('03.3456.3')
,('03.5436.1')
,('03.5436.2')
,('03.5436.3')
,('03.5436.4')
,('12.7839.1')
,('12.7839.2')
,('12.3232.1')
,('12.4444.1')
,('12.4444.2')
,('13.7676.1')
SELECT TOP 1 left(col, charindex('.', col, 1) - 1) + '.' + convert(VARCHAR(10), convert(INT, substring(col, charindex('.', col, 1) + 1, charindex('.', col, charindex('.', col, 1) + 1) - (charindex('.', col, 1) + 1))) + 1)
FROM #table
WHERE col LIKE '03.%'
ORDER BY 1 DESC
I have a field that holds an account code. I've managed to extract the first 2 parts OK but I'm struggling with the last 2.
The field data is as follows:
812330/50110/0-0
812330/50110/BDG001-0
812330/50110/0-X001
I need to get the string between the second "/" and the "-" and after the "-" .Both fields have variable lengths, so I would be looking to output 0 and 0 on the first record, BDG001 and 0 on the second record and 0 and X001 on the third record.
Any help much appreciated, thanks.
You can use CHARINDEX and LEFT/RIGHT:
CREATE TABLE #tab(col VARCHAR(1000));
INSERT INTO #tab VALUES ('812330/50110/0-0'),('812330/50110/BDG001-0'),
('812330/50110/0-X001');
WITH cte AS
(
SELECT
col,
r = RIGHT(col, CHARINDEX('/', REVERSE(col))-1)
FROM #tab
)
SELECT col,
r,
sub1 = LEFT(r, CHARINDEX('-', r)-1),
sub2 = RIGHT(r, LEN(r) - CHARINDEX('-', r))
FROM cte;
LiveDemo
EDIT:
or even simpler:
SELECT
col
,sub1 = SUBSTRING(col,
LEN(col) - CHARINDEX('/', REVERSE(col)) + 2,
CHARINDEX('/', REVERSE(col)) -CHARINDEX('-', REVERSE(col))-1)
,sub2 = RIGHT(col, CHARINDEX('-', REVERSE(col))-1)
FROM #tab;
LiveDemo2
EDIT 2:
Using PARSENAME SQL SERVER 2012+ (if your data does not contain .):
SELECT
col,
sub1 = PARSENAME(REPLACE(REPLACE(col, '/', '.'), '-', '.'), 2),
sub2 = PARSENAME(REPLACE(REPLACE(col, '/', '.'), '-', '.'), 1)
FROM #tab;
LiveDemo3
...Or you can do this, so you only go from left side to right, so you don't need to count from the end in case you have more '/' or '-' signs:
SELECT
SUBSTRING(columnName, CHARINDEX('/' , columnName, CHARINDEX('/' , columnName) + 1) + 1,
CHARINDEX('-', columnName) - CHARINDEX('/' , columnName, CHARINDEX('/' , columnName) + 1) - 1) AS FirstPart,
SUBSTRING(columnName, CHARINDEX('-' , columnName) + 1, LEN(columnName)) AS LastPart
FROM table_name
One method way is to download a split() function off the web and use it. However, the values end up in separate rows, not separate columns. An alternative is a series of nested subqueries, CTEs, or outer applies:
select t.*, p1.part1, p12.part2, p12.part3
from table t outer apply
(select t.*,
left(t.field, charindex('/', t.field)) as part1,
substring(t.field, charindex('/', t.field) + 1) as rest1
) p1 outer apply
(select left(p1.rest1, charindex('/', p1.rest1) as part2,
substring(p1.rest1, charindex('/', p1.rest1) + 1, len(p1.rest1)) as part3
) p12
where t.field like '%/%/%';
The where clause guarantees that the field value is in the right format. Otherwise, you need to start sprinkling the code with case statements to handle misformated data.
I need some help with a sql transformation. This part of query that I have been provided with:
'$' + replace(cast((CAST(p.Price1 AS decimal(10,2)) * cast(isnull(p.Multiplier,1) as decimal(10,2))) as varchar), '.0000', '')
Basically, it ends up being a varchar that looks like this: $26980
I need to insert a comma at the thousand and million mark (if applicable). So in this instance, $26,980
What's the easiest way to do that without having to rewrite the whole thing?
Do it on the client side. Having said that, this example should show you the way.
with p(price1, multiplier) as (select 1234.5, 10)
select '$' + replace(cast((CAST(p.Price1 AS decimal(10,2)) * cast(isnull(p.Multiplier,1) as decimal(10,2))) as varchar), '.0000', ''),
'$' + parsename(convert(varchar,cast(p.price1*isnull(p.Multiplier,1) as money),1),2)
from p
The key is in the last expression
'$' + parsename(convert(varchar,cast(p.price1*isnull(p.Multiplier,1) as money),1),2)
Note: if p.price1 is of a higher precision than decimal(10,2), then you may have to cast it in the expression as well to produce a faithful translation since the original CAST(p.Priced1 as decimal(10,2)) will be performing rounding.
If you really must do it in TSQL you can use CONVERT(), but this sort of thing really doesn't belong in the database:
declare #m money = 12345678
-- with decimal places
select '$' + convert(varchar, #m, 1)
-- without decimal places
select '$' + replace(convert(varchar, #m, 1), '.00', '')
You could turn this into a function, it only goes 50 characters back.
DECLARE #input VARCHAR(50)
SELECT #input = '123123123.00'
SELECT #input = CASE WHEN CHARINDEX('.', #input) > offset +1
THEN STUFF(#input, CHARINDEX('.', #input) - offset, 0, ',')
ELSE #input END
FROM (SELECT 3 offset UNION SELECT 7 UNION SELECT 12 UNION SELECT 18 UNION SELECT 25 UNION SELECT 33 UNION SELECT 42) b
PRINT #input
The offset grows by +1 for each position, because it's assuming you've already inserted the commas for the previous positions.