Remove Characters in a String in SQL - sql

Question

I have a column u_manualdoc which contains the values are like this CGY DR# 7405. I want to remove the CGY DR#.
Here's the code:
select u_manualdoc, cardcode, cardname from ODLN
I want only the 7405 number. Thanks!

Answer 1

Try this:
--sample data you provided in comments
declare #tbl table(codes varchar(20))
insert into #tbl values
('CGY PST - 58277') , ('CGY RMC PST # 58083'), ('CGY DR # 7443'), ('CSI # 1304'), ('PO# 0568 , 0570'), ('CGY DR# 7446')
--actual query that you can apply to your table
select SUBSTRING(codes, PATINDEX('%[0-9]%', codes), len(codes)) from #tbl
The key point here is to use patindex, which searches for a pattern and returns index where such pattern occur. I specified %[0-9]% which means that we search for any digit - it will return first occurrence of a digit. Now- since this would be our starting point to substring, we pass it to such function. Third parameter of substring is length. Since we want the rest of a string, len function makes sure that we get that :)
Applying to your naming:
select SUBSTRING(u_manualdoc, PATINDEX('%[0-9]%', u_manualdoc), len(u_manualdoc)),
cardcode,
cardname
from ODLN

Answer 2

You should use string functions charindex,len and substring to get it.
See the code below.
select SUBSTRING(u_manualdoc,CHARINDEX('#',u_manualdoc)+1,LEN(u_manualdoc)- CHARINDEX('#',u_manualdoc))

Answer 3

EDIT
In addition to the other answers, you can use this simple method:
select
substring(
u_manualdoc,
len(u_manualdoc) - patindex('%[^0-9]%', reverse(u_manualdoc)) + 2,
len(u_manualdoc)
),
cardcode, cardname
from ODLN
In this example, patindex finds the first non-digit (as specified by ^[0-9]) from the right side of the string, and then uses that as the starting point of the substring.
This will work on all of your sample strings (including 'PO# 0568 , 0570 CGY DR# 7446').
Or use SQL Server Regex, which lets you use more powerful regular expressions within your queries.

Answer 4

TRY THIS
DECLARE #table TABLE(DirtyCol VARCHAR(100));
INSERT INTO #table
VALUES('AB ABCDE # 123'), ('ABCDE# 123'), ('AB: ABC# 123 AB: ABC# 123'), ('AB#'), ('AB # 1 000 000'), ('AB # 1`234`567'), ('AB # (9)(876)(543)');
WITH tally
AS (
SELECT TOP (100) N = ROW_NUMBER() OVER(ORDER BY ##spid)
FROM sys.all_columns),
data
AS (
SELECT DirtyCol,
Col
FROM #table
CROSS APPLY
(
SELECT
(
SELECT C+''
FROM
(
SELECT N,
SUBSTRING(DirtyCol, N, 1) C
FROM tally
WHERE N <= DATALENGTH(DirtyCol)
) [1]
WHERE C BETWEEN '0' AND '9'
ORDER BY N FOR XML PATH('')
)
) p(Col)
WHERE p.Col IS NOT NULL)
SELECT DirtyCol,
CAST(Col AS INT) IntCol
FROM data;