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I am trying to get string between second and third instance of ",," using SQL SELECT.
Apparently functions substring and charindex are useful, and I have tried them but the problem is that I need the string between those specific ",,"s and the length of the strings between them can change.
Can't find working example anywhere.
Here is an example:
Table: test
Column: Column1
Row1: cat1,,cat2,,cat3,,cat4,,cat5
Row2: dogger1,,dogger2,,dogger3,,dogger4,,dogger5
Result: cat3dogger3
Here is my closest attempt, it works if the strings are same length every time, but they aren't:
SELECT SUBSTRING(column1,LEN(LEFT(column1,CHARINDEX(',,', column1,12)+2)),LEN(column1) - LEN(LEFT(column1,CHARINDEX(',,', column1,20)+2)) - LEN(RIGHT(column1,CHARINDEX(',,', (REVERSE(column1)))))) AS column1
FROM testi
Just repeat sub-string 3 times, each time moving onto the next ",," e.g.
select
-- Substring till the third ',,'
substring(z.col1, 1, patindex('%,,%',z.col1)-1)
from (values ('cat1,,cat2,,cat3,,cat4,,cat5'),('dogger1,,dogger2,,dogger3,,dogger4,,dogger5')) x (col1)
-- Substring from the first ',,'
cross apply (values (substring(x.col1,patindex('%,,%',x.col1)+2,len(x.col1)))) y (col1)
-- Substring from the second ',,'
cross apply (values (substring(y.col1,patindex('%,,%',y.col1)+2,len(y.col1)))) z (col1);
And just to reiterate, this is a terrible way to store data, so the best solution is to store it properly.
Here is an alternative solution using charindex. The base idea is the same as in Dale K's an answer, but instead of cutting the string, we specify the start_location for the search by using the third, optional parameter, of charindex. This way, we get the location of each separator, and could slip each value off from the main string.
declare #vtest table (column1 varchar(200))
insert into #vtest ( column1 ) values('dogger1,,dogger2,,dogger3,,dogger4,,dogger5')
insert into #vtest ( column1 ) values('cat1,,cat2,,cat3,,cat4,,cat5')
declare #separetor char(2) = ',,'
select
t.column1
, FI.FirstInstance
, SI.SecondInstance
, TI.ThirdInstance
, iif(TI.ThirdInstance is not null, substring(t.column1, SI.SecondInstance + 2, TI.ThirdInstance - SI.SecondInstance - 2), null)
from
#vtest t
cross apply (select nullif(charindex(#separetor, t.column1), 0) FirstInstance) FI
cross apply (select nullif(charindex(#separetor, t.column1, FI.FirstInstance + 2), 0) SecondInstance) SI
cross apply (select nullif(charindex(#separetor, t.column1, SI.SecondInstance + 2), 0) ThirdInstance) TI
For transparency, I saved the separator string in a variable.
By default the charindex returns 0 if the search string is not present, so I overwrite it with the value null, by using nullif
IMHO, SQL Server 2016 and its JSON support in the best option here.
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE (ID INT IDENTITY PRIMARY KEY, Tokens VARCHAR(500));
INSERT INTO #tbl VALUES
('cat1,,cat2,,cat3,,cat4,,cat5'),
('dogger1,,dogger2,,dogger3,,dogger4,,dogger5');
-- DDL and sample data population, end
WITH rs AS
(
SELECT *
, '["' + REPLACE(Tokens
, ',,', '","')
+ '"]' AS jsondata
FROM #tbl
)
SELECT rs.ID, rs.Tokens
, JSON_VALUE(jsondata, '$[2]') AS ThirdToken
FROM rs;
Output
+----+---------------------------------------------+------------+
| ID | Tokens | ThirdToken |
+----+---------------------------------------------+------------+
| 1 | cat1,,cat2,,cat3,,cat4,,cat5 | cat3 |
| 2 | dogger1,,dogger2,,dogger3,,dogger4,,dogger5 | dogger3 |
+----+---------------------------------------------+------------+
It´s the same as #"Yitzhak Khabinsky" but i think it looks clearer
WITH CTE_Data
AS(
SELECT 'cat1,,cat2,,cat3,,cat4,,cat5' AS [String]
UNION
SELECT 'dogger1,,dogger2,,dogger3,,dogger4,,dogger5' AS [String]
)
SELECT
A.[String]
,Value3 = JSON_VALUE('["'+ REPLACE(A.[String], ',,', '","') + '"]', '$[2]')
FROM CTE_Data AS A
I am trying to run a query where
,replace(b.[X.Logs],' ','.') as 'logs'
,CT2 as
(
Select *
, CHARINDEX('Diagnostics',[logs]) as 'DiagBGN1'
, CHARINDEX('.',[logs],CHARINDEX('Diagnostics',[logs])) as 'DiagEND1'
From CT1
)
,CT3 as
(
Select *
,SUBSTRING([logs],[EPSABGN1]+1,[EPSAEND1]-[EPSABGN1]-1) as 'EPSA_CODE'
From CT2
)
I would like the Code to Skip the first . and select the next preceding . as the delimiter.
You can use it like below:
declare #S varchar(200) = 'Diagnostics.Passed.hardware';
select substring(#s, charindex('.', #S)+1, len(#s));
CharIndex will provide the 'index' of the first '.' and then use it to get substring from the string. This will 'ignore' the word "Diagnostics." from the string.
I have a field which is a concatenation of single letters. I am trying to order these strings within a view. These values can't be hard coded as there are too many. Is someone able to provide some guidance on the function to use to achieve the desired output below? I am using MSSQL.
Current output
CustID | Code
123 | BCA
Desired output
CustID | Code
123 | ABC
I have tried using a UDF
CREATE FUNCTION [dbo].[Alphaorder] (#str VARCHAR(50))
returns VARCHAR(50)
BEGIN
DECLARE #len INT,
#cnt INT =1,
#str1 VARCHAR(50)='',
#output VARCHAR(50)=''
SELECT #len = Len(#str)
WHILE #cnt <= #len
BEGIN
SELECT #str1 += Substring(#str, #cnt, 1) + ','
SET #cnt+=1
END
SELECT #str1 = LEFT(#str1, Len(#str1) - 1)
SELECT #output += Sp_data
FROM (SELECT Split.a.value('.', 'VARCHAR(100)') Sp_data
FROM (SELECT Cast ('<M>' + Replace(#str1, ',', '</M><M>') + '</M>' AS XML) AS Data) AS A
CROSS APPLY Data.nodes ('/M') AS Split(a)) A
ORDER BY Sp_data
RETURN #output
END
This works when calling one field
ie.
Select CustID, dbo.alphaorder(Code)
from dbo.source
where custid = 123
however when i try to apply this to top(10) i receive the error
"Invalid length parameter passed to the LEFT or SUBSTRING function."
Keeping in mind my source has ~4million records, is this still the best solution?
Unfortunately i am not able to normalize the data into a separate table with records for each Code.
This doesn't rely on a id column to join with itself, performance is almost as fast
as the answer by #Shnugo:
SELECT
CustID,
(
SELECT
chr
FROM
(SELECT TOP(LEN(Code))
SUBSTRING(Code,ROW_NUMBER() OVER(ORDER BY (SELECT NULL)),1)
FROM sys.messages) A(Chr)
ORDER by chr
FOR XML PATH(''), type).value('.', 'varchar(max)'
) As CODE
FROM
source t
First of all: Avoid loops...
You can try this:
DECLARE #tbl TABLE(ID INT IDENTITY, YourString VARCHAR(100));
INSERT INTO #tbl VALUES ('ABC')
,('JSKEzXO')
,('QKEvYUJMKRC');
--the cte will create a list of all your strings separated in single characters.
--You can check the output with a simple SELECT * FROM SeparatedCharacters instead of the actual SELECT
WITH SeparatedCharacters AS
(
SELECT *
FROM #tbl
CROSS APPLY
(SELECT TOP(LEN(YourString)) ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) FROM master..spt_values) A(Nmbr)
CROSS APPLY
(SELECT SUBSTRING(YourString,Nmbr,1))B(Chr)
)
SELECT ID,YourString
,(
SELECT Chr As [*]
FROM SeparatedCharacters sc1
WHERE sc1.ID=t.ID
ORDER BY sc1.Chr
FOR XML PATH(''),TYPE
).value('.','nvarchar(max)') AS Sorted
FROM #tbl t;
The result
ID YourString Sorted
1 ABC ABC
2 JSKEzXO EJKOSXz
3 QKEvYUJMKRC CEJKKMQRUvY
The idea in short
The trick is the first CROSS APPLY. This will create a tally on-the-fly. You will get a resultset with numbers from 1 to n where n is the length of the current string.
The second apply uses this number to get each character one-by-one using SUBSTRING().
The outer SELECT calls from the orginal table, which means one-row-per-ID and use a correalted sub-query to fetch all related characters. They will be sorted and re-concatenated using FOR XML. You might add DISTINCT in order to avoid repeating characters.
That's it :-)
Hint: SQL-Server 2017+
With version v2017 there's the new function STRING_AGG(). This would make the re-concatenation very easy:
WITH SeparatedCharacters AS
(
SELECT *
FROM #tbl
CROSS APPLY
(SELECT TOP(LEN(YourString)) ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) FROM master..spt_values) A(Nmbr)
CROSS APPLY
(SELECT SUBSTRING(YourString,Nmbr,1))B(Chr)
)
SELECT ID,YourString
,STRING_AGG(sc.Chr,'') WITHIN GROUP(ORDER BY sc.Chr) AS Sorted
FROM SeparatedCharacters sc
GROUP BY ID,YourString;
Considering your table having good amount of rows (~4 Million), I would suggest you to create a persisted calculated field in the table, to store these values. As calculating these values at run time in a view, will lead to performance problems.
If you are not able to normalize, add this as a denormalized column to the existing table.
I think the error you are getting could be due to empty codes.
If LEN(#str) = 0
BEGIN
SET #output = ''
END
ELSE
BEGIN
... EXISTING CODE BLOCK ...
END
I can suggest to split string into its characters using referred SQL function.
Then you can concatenate string back, this time ordered alphabetically.
Are you using SQL Server 2017? Because with SQL Server 2017, you can use SQL String_Agg string aggregation function to concatenate characters splitted in an ordered way as follows
select
t.CustId, string_agg(strval, '') within GROUP (order by strval)
from CharacterTable t
cross apply dbo.SPLIT(t.code) s
where strval is not null
group by CustId
order by CustId
If you are not working on SQL2017, then you can follow below structure using SQL XML PATH for concatenation in SQL
select
CustId,
STUFF(
(
SELECT
'' + strval
from CharacterTable ct
cross apply dbo.SPLIT(t.code) s
where strval is not null
and t.CustId = ct.CustId
order by strval
FOR XML PATH('')
), 1, 0, ''
) As concatenated_string
from CharacterTable t
order by CustId
I have a column u_manualdoc which contains the values are like this CGY DR# 7405. I want to remove the CGY DR#.
Here's the code:
select u_manualdoc, cardcode, cardname from ODLN
I want only the 7405 number. Thanks!
Try this:
--sample data you provided in comments
declare #tbl table(codes varchar(20))
insert into #tbl values
('CGY PST - 58277') , ('CGY RMC PST # 58083'), ('CGY DR # 7443'), ('CSI # 1304'), ('PO# 0568 , 0570'), ('CGY DR# 7446')
--actual query that you can apply to your table
select SUBSTRING(codes, PATINDEX('%[0-9]%', codes), len(codes)) from #tbl
The key point here is to use patindex, which searches for a pattern and returns index where such pattern occur. I specified %[0-9]% which means that we search for any digit - it will return first occurrence of a digit. Now- since this would be our starting point to substring, we pass it to such function. Third parameter of substring is length. Since we want the rest of a string, len function makes sure that we get that :)
Applying to your naming:
select SUBSTRING(u_manualdoc, PATINDEX('%[0-9]%', u_manualdoc), len(u_manualdoc)),
cardcode,
cardname
from ODLN
You should use string functions charindex,len and substring to get it.
See the code below.
select SUBSTRING(u_manualdoc,CHARINDEX('#',u_manualdoc)+1,LEN(u_manualdoc)- CHARINDEX('#',u_manualdoc))
EDIT
In addition to the other answers, you can use this simple method:
select
substring(
u_manualdoc,
len(u_manualdoc) - patindex('%[^0-9]%', reverse(u_manualdoc)) + 2,
len(u_manualdoc)
),
cardcode, cardname
from ODLN
In this example, patindex finds the first non-digit (as specified by ^[0-9]) from the right side of the string, and then uses that as the starting point of the substring.
This will work on all of your sample strings (including 'PO# 0568 , 0570 CGY DR# 7446').
Or use SQL Server Regex, which lets you use more powerful regular expressions within your queries.
TRY THIS
DECLARE #table TABLE(DirtyCol VARCHAR(100));
INSERT INTO #table
VALUES('AB ABCDE # 123'), ('ABCDE# 123'), ('AB: ABC# 123 AB: ABC# 123'), ('AB#'), ('AB # 1 000 000'), ('AB # 1`234`567'), ('AB # (9)(876)(543)');
WITH tally
AS (
SELECT TOP (100) N = ROW_NUMBER() OVER(ORDER BY ##spid)
FROM sys.all_columns),
data
AS (
SELECT DirtyCol,
Col
FROM #table
CROSS APPLY
(
SELECT
(
SELECT C+''
FROM
(
SELECT N,
SUBSTRING(DirtyCol, N, 1) C
FROM tally
WHERE N <= DATALENGTH(DirtyCol)
) [1]
WHERE C BETWEEN '0' AND '9'
ORDER BY N FOR XML PATH('')
)
) p(Col)
WHERE p.Col IS NOT NULL)
SELECT DirtyCol,
CAST(Col AS INT) IntCol
FROM data;
How can I get the value from the sixth field in the following column? I am trying to get the 333 field:
ORGPATHTXT
2123/2322/12323/111/222/333/3822
I believe I have to use select substring, but am unsure how to format the query
Assuming SQL Server
The easiest way I can think of is create a Split function that splits based on '/' and you extract the sixth item like below
declare #text varchar(50) = '2123/2322/12323/111/222/333/3822'
select txt_value from fn_ParseText2Table(#text, '/') t where t.Position = 6
I used the function in this url. See it worked at SQLFiddle
Try this - for a string variable or wrap into a function to use with a select query (Sql-Demo)
Declare #s varchar(50)='2123/2322/12323/111/222/333/3822'
Select #s = right(#s,len(#s)- case charindex('/',#s,1) when 0 then len(#s)
else charindex('/',#s,1) end)
From ( values (1),(2),(3),(4),(5)) As t(num)
Select case when charindex('/',#s,1)>0 then left(#s,charindex('/',#s,1)-1)
else #s end
--Results
333
I'd like to offer a solution that uses CROSS APPLY to split up any delimited string in MSSQL and ROW_NUMBER() to return the 6th element. This assumes you have a table with ORGPATHTXT as a field (it can easily be converted to work without the table though):
SELECT ORGPATHTXT
FROM (
SELECT
Split.a.value('.', 'VARCHAR(100)') AS ORGPATHTXT,
ROW_NUMBER() OVER (PARTITION BY ID ORDER BY (SELECT 1)) RN
FROM
(SELECT ID, CAST ('<M>' + REPLACE(ORGPATHTXT, '/', '</M><M>') + '</M>' AS XML) AS String
FROM MyTable
) AS A
CROSS APPLY String.nodes ('/M') AS Split(a)
) t
WHERE t.RN = 6;
Here is some sample Fiddle to go along with it.
Good luck.
For sql, you can use
declare #string varchar(65) = '2123/2322/12323/111/222/333/3822'
select substring(string,25,27) from table_name
If you are using MySQL, then you can use:
select substring_index(orgpathtxt, '/', 6)
Let me just say that it is less convenient in most other databases.
Also you can use option with dynamic management function sys.dm_fts_parser
DECLARE #s nvarchar(50) = '2123/2322/12323/111/222/333/3822'
SELECT display_term
FROM sys.dm_fts_parser('"'+ #s + '"', 1033, NULL, 0)
WHERE display_term NOT LIKE 'nn%' AND occurrence = 6