My sql table is
Week Year Applications
1 2017 0
2 2017 10
3 2017 20
4 2017 50
5 2017 0
1 2018 10
2 2018 0
3 2018 40
4 2018 50
5 2018 10
And I want SQL query which give below output
Week Year Applications
1 2017 0
2 2017 10
3 2017 30
4 2017 80
5 2017 80
1 2018 10
2 2018 10
3 2018 50
4 2018 100
5 2018 110
Can anyone help me to write below query?
You could use SUM() OVER to get cumulative sum:
SELECT *, SUM(Applications) OVER(PARTITION BY Year ORDER BY Week)
FROM tab
It looks like you want a cumulative sum:
select week, year,
sum(applications) over (partition by year order by week) as cumulative_applications
from t;
Related
id
year
1
2014
10
2015
10
2019
102
2015
102
2019
104
2015
104
2017
104
2019
104
2021
The output I want in postgres is below. The max year is populated based on the id and the count should also count based on id. If id = 10 then it should show the max date within id 10 and also count how many records have the id as 10.
id
year
max year
count
1
2014
2014
1
10
2015
2017
2
10
2017
2017
2
102
2015
2019
2
102
2019
2019
2
104
2015
2021
4
104
2017
2021
4
104
2019
2021
4
104
2021
2021
4
SELECT aa.id,
aa.year,
aa.max_year,
count(aa.id)
from (SELECT id,MAX(year) AS year FROM table
GROUP BY id) aa
FULL JOIN table2 b ON aa.id = b.id
You can use window functions:
select id,
year,
max(year) over (partition by id) as max_year,
count(*) over (partition by id)
from the_table
I would like to group Highest values in month column group by year and Sum the value column
value
Year
Month
4
2019
10
1
2019
11
5
2019
11
1
2019
11
1
2019
12
8
2019
12
1
2019
12
1
2020
1
10
2020
1
3
2021
1
2
2021
2
11
2021
2
1
2021
2
3
2021
2
2
2021
3
In above table I would like to extract highest value of month group by year
in year 2019 highest month is 12 so there are 3 rows and sum of value column will be 10
The output should be
value
Year
Month
10
2019
12
11
2020
1
2
2021
3
supposing that the table is called "example_table" you can use the following query:
select sum(example_table.value), example_table.year, example_table.month
from example_table
join (
select year, max(month) "month"
from example_table
group by year
) sub on example_table.year = sub.year and example_table.month = sub.month
group by example_table.year, example_table.month
order by example_table.year
I need to create a custom quarter calculator to start always from previous month no matter month, year we are at and count back to get quarter. Previous year wuarters are to be numbered 5, 6 etc
So the goal is to move quarter grouping one month back.
Assume we run query on December 11th, result should be:
YEAR MNTH QTR QTR_ALT
2017 1 1 12
2017 2 1 12
2017 3 1 11
2017 4 2 11
2017 5 2 11
2017 6 2 10
2017 7 3 10
2017 8 3 10
2017 9 3 9
2017 10 4 9
2017 11 4 9
2017 12 4 8
2018 1 1 8
2018 2 1 8
2018 3 1 7
2018 4 2 7
2018 5 2 7
2018 6 2 6
2018 7 3 6
2018 8 3 6
2018 9 3 5
2018 10 4 5
2018 11 4 5
2018 12 4 1
2019 1 1 1
2019 2 1 1
2019 3 1 2
2019 4 2 2
2019 5 2 2
2019 6 2 3
2019 7 3 3
2019 8 3 3
2019 9 3 4
2019 10 4 4
2019 11 4 4
2019 12 4 THIS IS SKIPPED
Starting point is eliminating current_date so data end at previous month's last day
SELECT DISTINCT
YEAR,
MNTH,
QTR
FROM TABLE
WHERE DATA BETWEEN
(SELECT DATE_TRUNC(YEAR,ADD_MONTHS(CURRENT_DATE, -24))) AND
(SELECT DATE_TRUNC(MONTH,CURRENT_DATE)-1)
ORDER BY YEAR, MNTH, QTR
The following gets you all the dates you need, with the extra columns.
select to_char(add_months(a.dt, -b.y), 'YYYY') as year,
to_char(add_months(a.dt, -b.y), 'MM') as month,
ceil(to_number(to_char(add_months(a.dt, -b.y), 'MM')) / 3) as qtr,
ceil(b.y/3) as alt_qtr
from
(select trunc(sysdate, 'MONTH') as dt from dual) a,
(select rownum as y from dual connect by level <= 24) b;
i have this query that works , but the result is not like i want
returns only year and weeks that has data , i want to return 0 to the result
for example this returns
year week totalstop
2017 50 7
2018 1 3
2018 3 5
but i want to return
year week totalstop
2017 50 7
2017 51 0
2017 52 0
2018 1 3
2018 2 0
2018 3 5
and so on
here is the current query
SELECT year(Stopdate)[year],datepart(week,date1) [week],sum(stop) totalstop
from Table1 where
building in (select item from dbo.fn_Split('A1,A2,A3,A4,A5',','))
and
date1 between '2017-12-12' and '2018-05-08'
and grp = 1
group by year(date1),datepart(week,date1)
order by year(date1),[week]
iam using ms sql-server 2016
need help to modify it to my needs as iam out of ideas atm.
How can I select data from this table
Yr Month El1 Value
---- ------ ------- ------
2017 2 AT010 100
2017 3 AT010 100
2017 4 AT010 50
2017 5 AT010 150
2017 3 BE020 10
.......
and insert it into another table in the following way
Yr Month El1 Value
---- ------ ------- ------
2017 0 AT010 0
2017 1 AT010 0
2017 2 AT010 100
2017 3 AT010 200
2017 4 AT010 250
2017 5 AT010 400
2017 6 AT010 400
2017 7 AT010 400
2017 8 AT010 400
2017 9 AT010 400
2017 10 AT010 400
2017 11 AT010 400
2017 12 AT010 400
2017 0 BE020 0
2017 1 BE020 0
2017 2 BE020 0
2017 3 BE020 10
2017 4 BE020 10
2017 5 BE020 10
2017 6 BE020 10
2017 7 BE020 10
2017 8 BE020 10
2017 9 BE020 10
2017 10 BE020 10
2017 11 BE020 10
2017 12 BE020 10
.......
I am trying to insert missing months from 0 to 12 and calculate running total at the same time.
I used this suggestion for running total calculation; however, I can't figure out how to enter missing month.
This code will be used in the stored procedure for a daily ETL job.
Hmmm . . . Generate the rows and then use left join or outer apply to bring in the values. Here is one way:
with yyyymm as (
select 2017 as yr, 1 as mom
union all
select yr, mon + 1
from yyyymm
where mon + 1 <= 12
)
select yyyymm.yr, yyyymm.mon, coalesce(e.el1, 0) as el1
from yyyymm cross join
(select distinct el1 from t) e outer apply
(select sum(t.value)
from t
where t.el1 = e.el1 and
t.yr = yyyy.yr and
t.month <= yyyy.mon
) tt
order by e.el1, yyyy.yr, yyyy.month;