i have this query that works , but the result is not like i want
returns only year and weeks that has data , i want to return 0 to the result
for example this returns
year week totalstop
2017 50 7
2018 1 3
2018 3 5
but i want to return
year week totalstop
2017 50 7
2017 51 0
2017 52 0
2018 1 3
2018 2 0
2018 3 5
and so on
here is the current query
SELECT year(Stopdate)[year],datepart(week,date1) [week],sum(stop) totalstop
from Table1 where
building in (select item from dbo.fn_Split('A1,A2,A3,A4,A5',','))
and
date1 between '2017-12-12' and '2018-05-08'
and grp = 1
group by year(date1),datepart(week,date1)
order by year(date1),[week]
iam using ms sql-server 2016
need help to modify it to my needs as iam out of ideas atm.
Related
I would like to group Highest values in month column group by year and Sum the value column
value
Year
Month
4
2019
10
1
2019
11
5
2019
11
1
2019
11
1
2019
12
8
2019
12
1
2019
12
1
2020
1
10
2020
1
3
2021
1
2
2021
2
11
2021
2
1
2021
2
3
2021
2
2
2021
3
In above table I would like to extract highest value of month group by year
in year 2019 highest month is 12 so there are 3 rows and sum of value column will be 10
The output should be
value
Year
Month
10
2019
12
11
2020
1
2
2021
3
supposing that the table is called "example_table" you can use the following query:
select sum(example_table.value), example_table.year, example_table.month
from example_table
join (
select year, max(month) "month"
from example_table
group by year
) sub on example_table.year = sub.year and example_table.month = sub.month
group by example_table.year, example_table.month
order by example_table.year
I have a table with the following structure:
Employee Project Task Accomplishment Score Year
John A 1 5 60 2016
John A 1 6 40 2018
John A 2 3 30 2016
Simon B 2 0 30 2017
Simon B 2 4 30 2019
David C 1 3 20 2015
David C 1 2 40 2016
David C 3 0 25 2017
David C 3 5 35 2017
I want to create a view with Oracle SQLout of the above table which looks like as follows:
Employee Project Task Accomplishment Score Year UpdateScore Comment
John A 1 5 60 2016 60
John A 1 6 40 2018 100 (=60+40)
John A 2 3 30 2016 30
Simon B 2 0 30 2017 30
Simon B 2 4 40 2019 40 (no update because Accomplishement was 0)
David C 1 3 20 2015 20
David C 1 2 40 2016 60 (=20+40)
David C 3 0 25 2017 25
David C 3 5 35 2017 35 (no update because Accomplishement was 0)
The Grouping is: Employee-Project-Task.
The Rule of the UpdateScore column:
If for a specific Employee-Project-Task group Accomplishment column value is greater than 0 for the previous year, add the previous year's score to the latest year for the same Employee-Project-Task group.
For example: John-A-1 is a group which is different from John-A-2. So as we can see for John-A-1 the Accomplishment is 5 (which is greater than 0) in 2016, so we add the Score from 2016 with the score of 2018 for the John-A-1 and the updated score becomes 100.
For Simon-B-2, the accomplishment was 0, so there will be no update for 2019 for Simon-B-2.
Note: I don't need the Comment field, it is there just for more clarification.
Use analytic functions to determine if there was a score for the previous year, and if so, add it to the UpdatedScore.
select Employee, Project, Task, Accomplishment, Score, Year,
case when lag(Year) over (partition by Employee, Project order by Year) = Year - 1
then lag(Score) over (partition by Employee, Project order by Year)
else 0
end + Score as UpdatedScore
from EmployeeScore;
This is a bit strange -- you are counting the accomplishment of 0 in one year but not the next. Okay.
Use analytic functions:
select t.*,
(case when lag(accomplishment) over (partition by Employee, Project, Task order by year) > 0
then lag(score) over (partition by Employee, Project, Task order by year)
else 0
end) + score as update_score
from t;
from t
My sql table is
Week Year Applications
1 2017 0
2 2017 10
3 2017 20
4 2017 50
5 2017 0
1 2018 10
2 2018 0
3 2018 40
4 2018 50
5 2018 10
And I want SQL query which give below output
Week Year Applications
1 2017 0
2 2017 10
3 2017 30
4 2017 80
5 2017 80
1 2018 10
2 2018 10
3 2018 50
4 2018 100
5 2018 110
Can anyone help me to write below query?
You could use SUM() OVER to get cumulative sum:
SELECT *, SUM(Applications) OVER(PARTITION BY Year ORDER BY Week)
FROM tab
It looks like you want a cumulative sum:
select week, year,
sum(applications) over (partition by year order by week) as cumulative_applications
from t;
I've searched the forum but can't quite find what I'm looking for. Apologies if this has already been answered.
I have a table with the following example values:
FY Period Version Value
2013 3 1 9954
2013 3 2 9954
2013 4 1 11498
2013 4 2 11498
2013 4 3 11498
2014 1 1 448
2014 1 2 448
2014 1 3 0
2014 2 1 3150
2014 2 2 3150
2014 3 1 0
2014 3 2 0
2014 3 3 5059
2014 4 1 11118
2014 4 2 0
2014 4 3 11118
I'm looking to sum the values for the highest version number, within each period and each FY, so the expected result for this particular data set would be:
(9954 + 11498 + 0 + 3150 + 5059 + 11118) = 40,779
I've done something similar previously with the over partition approach but i can't get it to work on this data set. Any pointers would be greatly appreciated.
A simple approach is to use row_number():
select sum(value)
from (select t.*,
row_number() over (partition by fy, period order by version desc) as seqnum
from table t
) t
where seqnum = 1;
How should i form a query if i wanted dates/records from the below table such that Year is greater than or equals 2012 and Month is greater than September.
This query does not work it brings Months 2012 (7,8, 9,10,11,12) , 2013(1 upto 12) which is not right because i wanted to see 2012(9,10,11,12) 2013( 1 upto 12). It is including 7 and 8 th month of 2012 Year
select * from ConfigurationDate
where Year >= 2012 OR ( Year = 2012 AND Month >= 9 )
Order By Year,Month ASC
Table Schema
DateId INT Auto Inc
Year INT
Month INT
Dummy Data
DateId Year Month
1 2012 7
2 2012 8
3 2012 9
4 2012 10
5 2012 11
6 2012 12
7 2013 1
8 2013 2
9 2013 3
10 2013 4
11 2013 5
12 2013 6
13 2013 7
14 2013 8
15 2013 9
16 2013 10
Actually thinking of it, i don't need to include the 2012 date in First where condition again since it is covered by second condition. So the answer is below
select * from ConfigurationDate
where Year > 2012 OR ( Year = 2012 AND Month >= 9 )
Order By Year,Month ASC