I want to extract the phone number from a NSString.
For ex: In the string Nandu # +91-(123)-456-7890, I want to extract +91-(123)-456-7890.
I have tried code like,
NSString *myString = #"Nandu # +91-(123)-456-7890";
NSString *myRegex = #"\\d{2}+\\d{3}-\\d{3}-\\d{4}";
NSRange range = [myString rangeOfString:myRegex options:NSRegularExpressionSearch];
NSString *phoneNumber = nil;
if (range.location != NSNotFound) {
phoneNumber = [myString substringWithRange:range];
NSLog(#"%#", phoneNumber);
} else {
NSLog(#"No phone number found");
}
how can I get phone number with +91 also.
You can use this Regex pattern
(\+\d{2}-\(\d{3}\)-\d{3}-\d{4})
https://regexr.com/3qcsi
Using NSCharacterSet you can get your output. see below code and let me know if you have any query then.
NSString *originalString = #"Nandu # +91-(123)-456-7890";
NSString *cleanedString = [[originalString componentsSeparatedByCharactersInSet:[[NSCharacterSet characterSetWithCharactersInString:#"0123456789-+()"] invertedSet]] componentsJoinedByString:#""];
NSLog(#"%#", cleanedString); //+91-(123)-456-7890
You can use componentsSeparatedByString
NSString *originalString = #"Nandu # +91-(123)-456-7890";
NSArray *arrayWithTwoStrings = [originalString componentsSeparatedByString:#"+"];
NSString *mobileNumberstring = [NSString stringWithFormat:#"+%#",[arrayWithTwoStrings objectAtIndex:1]];
NSLog (#"%#",mobileNumberstring);
Related
I want to remove only first space in below string.
NSString *str = #"IF_Distance (GET_Mi mi=km*1.4,STRING1,STRING2)";
Note: There is a space after IF_Distance and another space after
GET_Mi. I am unable to remove the space after IF_Distance.
Use rangeOfString: to locate the first space, then use stringByReplacingCharactersInRange:withString: to replace it with the empty string.
Remove space by using below code.
NSString *str = #"IF_Distance (GET_Mi mi=km*1.4,STRING1,STRING2)";
NSString *secondString = [str stringByReplacingOccurrencesOfString:#"IF_Distance " withString:#"IF_Distance"];
Try This:
NSString *str = #"IF_Distance (GET_Mi mi=km*1.4,STRING1,STRING2)";
NSString *firstStringContainingSpace = [[str componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]] firstObject];//firstStringContainingSpace = IF_Distance
str = [str stringByReplacingCharactersInRange:[str rangeOfString:[NSString stringWithFormat:#"%# ",firstStringContainingSpace]] withString:firstStringContainingSpace];
Output:
str = #"IF_Distance(GET_Mi mi=km*1.4,STRING1,STRING2)";
You can remove first space by using following code:
First find space by using rangeOfString: and then remove by using stringByReplacingCharactersInRange:withString: method.
Like,
NSString *str = #"IF_Distance (GET_Mi mi=km*1.4,STRING1,STRING2)";
NSString *strSpace = #" ";
NSRange range = [str rangeOfString:strSpace];
NSString *strFinal;
if (NSNotFound != range.location) {
strFinal = [str stringByReplacingCharactersInRange:range withString:#""];
}
If you are looking for some more universal way - this is the variant of it:
- (NSString *)removeWhitespaces:(NSString *)string {
NSMutableArray * stringComponents = [[string componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]] mutableCopy];
NSString * fStringComponent = [stringComponents firstObject];
[stringComponents removeObject:fStringComponent];
return [fStringComponent stringByAppendingString:[stringComponents componentsJoinedByString:#" "]];
}
For instance
NSString *string = #"I need help finding a string";
NSString *newString = #"need";
I would need this to work not only to work for this string. An example would be to take a string and remove everything after the word "I " and before the word " help".
Thank you very much!
Moved from a comment for legibility:
NSString *string = #"I need help finding a string";
NSRange rr2 = [TWEET rangeOfString:#"I "];
NSRange rr3 = [TWEET rangeOfString:#" help"];
int lengt = rr3.location - rr2.location;
int location = rr2.location + rr2.length;
NSRange aa;
aa.location = location;
aa.length = lengt;
NSString *link;
link = [TWEET substringWithRange:aa];
NSLog(#"The link is %#", link);
One way would be to split the string into single words, and iterate through it, first searching for the first word, while adding every word to a new string until you found it and the searching for the second word and after you found that just add the remaining words.
This could look like this in code:
NSString *myString = #"I need help finding a string";
NSString *firstWord = #"need";
NSString *secondWord = #"a";
NSMutableString *newString = [NSMutableString stringWithString:#""];
int index = 0;
for (NSString *word in [myString componentsSeparatedByString:#" "]) {
if(index == 0) {
if([word isEqualToString:firstWord])
index = 1;
[newString appendFormat:#"%# ", word];
}
else if(index == 1) {
if([word isEqualToString:secondWord])
index = 2;
}
else
[newString appendFormat:#"%# ", word];
}
I need to parse a string like [abc]000, and what I want to get is an array containing abc and 000. Is there an easy way to do it?
I'm using code like this:
NSString *sampleString = #"[abc]000";
NSArray *sampleParts = [sampleString componentsSeparatedByString:#"]"];
NSString *firstPart = [[[sampleParts objectAtIndex:0] componentsSeparatedByString:#"["] lastObject];
NSString *lastPart = [sampleParts lastObject];
But it's inefficient and didn't check whether the string is in a format like [**]**.
For this simple pattern, can just parse yourself like:
NSString *s = #"[abc]000";
NSString *firstPart = nil;
NSString *lastPart = nil;
if ([s characterAtIndex: 0] == '[') {
NSUInteger i = [s rangeOfString:#"]"].location;
if (i != NSNotFound) {
firstPart = [s substringWithRange:NSMakeRange(1, i - 1)];
lastPart = [s substringFromIndex:i + 1];
}
}
Or you could learn to use the NSScanner class.
As always, there are lots of ways to do this.
OPTION 1
If these are fixed length strings (each part is always three characters) then you can simply get the substrings directly:
NSString *sampleString = #"[abc]000";
NSString *left = [sampleString substringWithRange:NSMakeRange(1, 3)];
NSString *right = [sampleString substringWithRange:NSMakeRange(5, 3)];
NSArray *parts = #[ left, right ];
NSLog(#"%#", parts);
OPTION 1 (shortened)
NSArray *parts = #[ [sampleString substringWithRange:NSMakeRange(1, 3)],
[sampleString substringWithRange:NSMakeRange(5, 3)] ];
NSLog(#"%#", parts);
OPTION 2
If they aren't always three characters, then you can use NSScanner:
NSString *sampleString = #"[abc]000";
NSScanner *scanner = [NSScanner scannerWithString:sampleString];
// Skip the first character if we know that it will always start with the '['.
// If we can not make this assumption, then we would scan for the bracket instead.
scanner.scanLocation = 1;
NSString *left, *right;
// Save the characters until the right bracket into a string which we store in left.
[scanner scanUpToString:#"]" intoString:&left];
// Skip the right bracket
scanner.scanLocation++;
// Scan to the end (You can use any string for the scanUpToString that doesn't actually exist...
[scanner scanUpToString:#"\0" intoString:&right];
NSArray *parts = #[ left, right ];
NSLog(#"%#", parts);
RESULTS (for all options)
2013-05-10 00:25:02.031 Testing App[41906:11f03] (
abc,
000
)
NOTE
All of these assume well-formed strings, so you should include your own error checking.
try like this ,
NSString *sampleString = #"[abc]000";
NSString *pNRegex = #"\\[[a-z]{3}\\][0-9]{3}";
NSPredicate *PNTest = [NSPredicate predicateWithFormat:#"SELF MATCHES %#", pNRegex];
BOOL check=[PNTest evaluateWithObject:sampleString ];
NSLog(#"success:%i",check);
if success comes as 1 then you can perform the action for separating string into array.
I am adding string into a pickerView like this :
NSString *string = [NSString stringWithFormat:#"%# %#", xxx, xxx];
[pickerViewObjects addObject:string];
what i want to do is to hide the first part of the string, or of there's something to use like charachterAtIndex it will be useful because the first part of my string has a specific number of characters.
Use this method to get "(whitespaces) John"
NSString *string = #"Hello John";
NSUInteger spacePosition = [string rangeOfString:#" "].location;
NSMutableString *newString = [[NSMutableString alloc]init ];
for (int i=0; i<spacePosition; i++)
[newString appendString:#" "];
NSString *otherPartofString = [string substringFromIndex:(spacePosition)];
[newString appendString:otherPartofString];
NSLog(#"new String is '%#'",newString);
[newString release];
You can use [string substringWithRange:NSMakeRange(start, count)], that way you will only get a new string that you can use for displaying.
you can do like this:
find the position of space between two strings like this:
NSUInteger spacePosition = [string rangeOfString:#" "].location
then use:
NSString *otherPartofString = [string substringFromIndex:(spacePosition+1)];
I want to take all values after a new line character \n from my string. How can I get those values?
Try this:
NSString *substring = nil;
NSRange newlineRange = [yourString rangeOfString:#"\n"];
if(newlineRange.location != NSNotFound) {
substring = [yourString substringFromIndex:newlineRange.location];
}
Take a look at method componentsSeparatedByString here.
A quick example taken from reference:
NSString *list = #"Norman, Stanley, Fletcher";
NSArray *listItems = [list componentsSeparatedByString:#", "];
this will produce a NSArray with strings separated: { #"Norman", #"Stanley", #"Fletcher" }
Here is similar function which splits the string by delimeter and return array with two trimmed values.
NSArray* splitStrByDelimAndTrim(NSString *string, NSString *delim)
{
NSRange range = [string rangeOfString: delim];
NSString *first;
NSString *second;
if(range.location == NSNotFound)
{
first = #"";
second = string;
}
else
{
first = [string substringToIndex: range.location];
first = [first stringByTrimmingCharactersInSet: [NSCharacterSet whitespaceCharacterSet]];
second = [string substringFromIndex: range.location + 1];
second = [second stringByTrimmingCharactersInSet: [NSCharacterSet whitespaceCharacterSet]];
}
return [NSArray arrayWithObjects: first, second, nil];
}