Best method for defining layers using tf keras api? - tensorflow

Question

tensorflow.keras api not working on while creating the layers reference, any other methods of creating layers reference?
code :
layer=keras.layers
Error message : NameError: name 'leyer' is not defined
Full code is pasted here...
import tensorflow as tf
from tensorflow import keras
import pandas as pd
from sklearn.model_selection import KFold
from sklearn.model_selection import cross_val_score
from sklearn.preprocessing import LabelEncoder
import numpy as np
#makin seed values
seed=7
np.random.seed(seed)
#setting up the dataset for training
dataframe=pd.read_csv("../datasets/iris.csv",header=None)
data=dataframe.values
input_x = data[:,0:4]
true_y = data[:,4]
#Encoding the true_y data to one hot encoding
le=LabelEncoder()
le.fit(true_y)
y_encoded = le.transform(true_y)
y_encoded = keras.utils.to_categorical(y_encoded,num_classes=3)
# creating the model
def base_fun():
layer=keras.layers
model = keras.models.Sequential()
model.add(layer.Dense(4,input_dim=4,kernel_initializer='normal',activation='relu'))
model.add(leyer.Dense(3, kernel_initializer='normal', activation='relu'))
estimator=keras.wrappers.scikit_learn.KerasClassifier(build_fn=base_fun,epochs=20,batch_size=10)
kfold = KFold(n_splits=10, shuffle=True, random_state=seed)
result = cross_val_score(estimator, input_x, y_encoded,cv=kfold)
print("Accuracy : %.2%% (%.2%%)" %(result.mean()*100, result.std()*100))

Answer 1

Well, this line:
model.add(leyer.Dnese(3, kernel_initializer='normal', activation='relu'))
has two typos, namely leyer should be layer and Dnese should be Dense like
model.add(layer.Dense(3, kernel_initializer='normal', activation='relu'))
Based on your comment, this line also causes an error:
estimator = keras.wrappers.scikit_learn.KerasClassifier( build_fn = base_fun, epochs = 20, batch_size = 10 )
From the Keras Scikit documentation:
build_fn should construct, compile and return a Keras model, which will then be used to fit/predict.
But you function base_fun() does not return anything. Append this line at the end of base_fun():
return model
As per your comment, the last print line could be changed to this (I don't know the % formatting, I generally use the syntax below):
print( "Accuracy : {:.2%} ({:.2%})".format( result.mean(), result.std() ) )