Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 4 years ago.
Improve this question
I have a id which is having more than one Accountid in a table with status Active . I need to find group of active for the particular ID .
Please find my below query .is it correct or something need to modify to get better optimized result .
select id,count(Accountid) from CustomerAccount
where status='Active'
group by id
having count(*)>( select min(maxxount) from(
select id,count(accountid) as maxxount
from CustomerAccount
group by id)A)
Use this query:
select id,count(Accountid) from CustomerAccount
where status='Active'
group by id
having count(*) >1
Related
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 10 months ago.
Improve this question
how to rank each country based on number of people in SQL.
Try
SELECT * FROM (
SELECT country, count(people) as count FROM your_table GROUP BY country
) ORDER BY count DESC
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 3 years ago.
Improve this question
How can I write this query without TOP and Limit only use the SQL
You just sort the data one way, grab the records you want, then sort it the other way:
SELECT SOME_FIELD
FROM (SELECT st.*
FROM SOME_TABLE st
ORDER BY SOME_FIELD DESC)
WHERE ROWNUM <= 7
ORDER BY SOME_FIELD ASC
dbfiddle here
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 4 years ago.
Improve this question
I have a table name customers with two columns, case id and owner. I need to write a query to select random 5 caseids for every name in owner column.please help
For a start, you need something like:
SELECT TOP 5
ID,
[Case ID],
[Owner],
Rnd(-Timer()*[ID]) AS RandomRecord
FROM
[Cases]
ORDER BY
Rnd(-Timer()*[ID]);
to be used as a subquery filtered on OwnerID of your Owners' table.
I once posted an article on this with a lot more details:
Random Rows in Microsoft Access
You can use in:
select t.*
from t
where t.id in (select top 5 id
from t as t2
where t2.name = t.name
order by Rnd(-Timer()*[ID])
);
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 8 years ago.
Improve this question
I have a table like the following
sl.no Machine Id date status
I need to get the last status for each machine ID for each day.(Everyday each machine ID will have many entries .I need to get the last entry for that day for each machine ID)
Please help
Hope this will solve your issue
Select MachineID, Date,
(Select Top 1 t1.Status
FROM table As t1
WHERE t1.MachineID = table.MachineID
AND t1.Date = table.Date
order by slno desc)
FROM table
Group BY MachineID, Date
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 9 years ago.
Improve this question
my situation is that i have one to many relation ,like order and orderdetails ,i need to get order which has single order details.
How about:
select *
from order
where order_number in
(select order_number
from order_details
group by order_number
having count(*) = 1)
SELECT O1.order_number
FROM Orders AS O1
WHERE 1 = (
SELECT COUNT(*)
FROM OrderDetails AS D1
WHERE O1.order_number = D1.order_number
);