Groupin Clients when client is new in year ORACLE - sql

Question

I have list of invoices. I wonna group data into sales_departments but only this clients who have first invoice in 2018 Year.
Below my "data". Sory for mystake but i can't paste data better.
Client_Number sales_depart Netto Number_Invoice Invoice_Date
1022562 0140 113 51545121188 04.11.18
1022562 0140 139 5586258568 04.01.18
1022564 0140 171 5586713889 03.22.18
1022565 0140 211 5587169210 03.22.17
1022566 0140 259 5587624531 03.22.16
1022567 0140 319 5588079852 03.23.15
1022568 0140 392 5588535173 03.23.14
1022569 0140 483 5588990494 03.23.13
1022570 0140 594 5589445815 03.23.12
1022571 0140 730 5589901136 03.24.11
1008144 0530 898 5590356457 01.31.18
1008145 0530 104 5590811778 02.20.18
1008146 0530 358 5591267099 02.20.17
1008147 0530 671 5591722420 02.21.16
1008148 0530 055 5592177741 02.21.15
1008149 0530 528 5592633062 02.21.14
1008150 0530 109 5593088383 02.21.13
1016058 0130 825 5593543704 01.18.18
1051643 0290 704 5593999025 01.30.18
1051643 0290 175 5595199025 01.30.17
1049433 0180 786 5594454346 02.20.18
1010219 0180 117 5594909667 02.28.18
1033233 0180 754 5595364988 02.28.18
1004914 0160 767 5595820309 02.14.18
1011699 0140 244 5596275630 02.20.18
1007323 0160 290 5596730951 04.19.18
1004914 0160 036 5597186272 02.07.18
1005837 0530 645 5597641593 04.19.18
The data I would like to receive
Sales Dept Count_Clintr
0130 1
0160 2
0180 3

Answer 1

You can do it with a single table scan using the HAVING clause:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE table_name ( Client_Number, sales_depart, Netto, Number_Invoice, Invoice_Date ) AS
SELECT 1022562, '0140', 113, 51545121188, DATE '2018-04-11' FROM DUAL UNION ALL
SELECT 1022562, '0140', 139, 5586258568, DATE '2018-04-01' FROM DUAL UNION ALL
SELECT 1022564, '0140', 171, 5586713889, DATE '2018-03-22' FROM DUAL UNION ALL
SELECT 1022565, '0140', 211, 5587169210, DATE '2017-03-22' FROM DUAL UNION ALL
SELECT 1022566, '0140', 259, 5587624531, DATE '2016-03-22' FROM DUAL UNION ALL
SELECT 1022567, '0140', 319, 5588079852, DATE '2015-03-23' FROM DUAL UNION ALL
SELECT 1022568, '0140', 392, 5588535173, DATE '2014-03-23' FROM DUAL UNION ALL
SELECT 1022569, '0140', 483, 5588990494, DATE '2013-03-23' FROM DUAL UNION ALL
SELECT 1022570, '0140', 594, 5589445815, DATE '2012-03-23' FROM DUAL UNION ALL
SELECT 1022571, '0140', 730, 5589901136, DATE '2011-03-24' FROM DUAL UNION ALL
SELECT 1008144, '0530', 898, 5590356457, DATE '2018-01-31' FROM DUAL UNION ALL
SELECT 1008145, '0530', 104, 5590811778, DATE '2018-02-20' FROM DUAL UNION ALL
SELECT 1008146, '0530', 358, 5591267099, DATE '2017-02-20' FROM DUAL UNION ALL
SELECT 1008147, '0530', 671, 5591722420, DATE '2016-02-21' FROM DUAL UNION ALL
SELECT 1008148, '0530', 055, 5592177741, DATE '2015-02-21' FROM DUAL UNION ALL
SELECT 1008149, '0530', 528, 5592633062, DATE '2014-02-21' FROM DUAL UNION ALL
SELECT 1008150, '0530', 109, 5593088383, DATE '2013-02-21' FROM DUAL UNION ALL
SELECT 1016058, '0130', 825, 5593543704, DATE '2018-01-18' FROM DUAL UNION ALL
SELECT 1051643, '0290', 704, 5593999025, DATE '2018-01-30' FROM DUAL UNION ALL
SELECT 1051643, '0290', 175, 5595199025, DATE '2017-01-30' FROM DUAL UNION ALL
SELECT 1049433, '0180', 786, 5594454346, DATE '2018-02-20' FROM DUAL UNION ALL
SELECT 1010219, '0180', 117, 5594909667, DATE '2018-02-28' FROM DUAL UNION ALL
SELECT 1033233, '0180', 754, 5595364988, DATE '2018-02-28' FROM DUAL UNION ALL
SELECT 1004914, '0160', 767, 5595820309, DATE '2018-02-14' FROM DUAL UNION ALL
SELECT 1011699, '0140', 244, 5596275630, DATE '2018-02-20' FROM DUAL UNION ALL
SELECT 1007323, '0160', 290, 5596730951, DATE '2018-04-19' FROM DUAL UNION ALL
SELECT 1004914, '0160', 036, 5597186272, DATE '2018-02-07' FROM DUAL UNION ALL
SELECT 1005837, '0530', 645, 5597641593, DATE '2018-04-19' FROM DUAL;
Query 1:
SELECT sales_depart,
COUNT( client_number )
FROM (
SELECT sales_depart,
client_number
FROM table_name
GROUP BY
sales_depart,
client_number
HAVING MIN( Invoice_date ) >= DATE '2018-01-01'
)
GROUP BY sales_depart
Results:
| SALES_DEPART | COUNT(CLIENT_NUMBER) |
|--------------|----------------------|
| 0140 | 3 |
| 0530 | 3 |
| 0180 | 3 |
| 0130 | 1 |
| 0160 | 2 |

Answer 2

One method uses not exists for filtering:
select sales_department, sum(netto)
from t
where not exists (select 1
from t t2
where t2.client = t.client and
t2.invoice_date < date '2018-01-01'
)
group by sales_department;
For performance, you want an index on (client, invoice_date). Also not the use of the date keyword to define the constant using ISO/ANSI standard formats.

Answer 3

Here is the solution to your problem:
SELECT sales_depart, COUNT(Distinct client_Number) AS Distinct_Clients
FROM Table1
GROUP BY sales_depart
HAVING MIN(TO_DATE(invoice_date, 'MM.DD.YY')) >= TO_DATE('01-01-2018', 'DD-MM-YYYY')
ORDER BY sales_depart
OUTPUT:
SALES_DEPART DISTINCT_CLIENTS
0130 1
0160 2
0180 3
Note: Since, Client_Number = 1004914 repeats 2 times in Sales_depart = 0160 so it is counted 1 time only.
Link to the demo:
http://sqlfiddle.com/#!4/28c71/1

Answer 4

SELECT sd.sales_depart,COUNT(sd.Client_Number) AS Client_Number
FROM sales_departments sd
INNER JOIN
(
SELECT sales_depart,MIN(Invoice_Date) AS Invoice_Date
FROM sales_departments
WHERE Invoice_date >= DATE '2018-01-01'
GROUP BY sales_depart
) T
ON T.sales_depart=sd.sales_depart
GROUP BY sd.sales_depart