I'm trying to get a query that get me a data that exist in table1 but not on table2, but has the same id with data table2.
In the following example, I'm trying to get 'SecID-by_Bank' 12456 which shares the same ISIN as another 2 items in table2.
I've tried the following query, but it returned me every data that's not on table2, not just the one that shares the same ISIN.
Query:
SELECT tb1_isin, tb1_SecID_by_Bank
FROM table1
WHERE not EXISTS (
SELECT top 1 null
FROM table2
WHERE table1.tb1_ISIN = table2.tb2_isin
)
Table 1
--------------------------------------------
Row | SecID_by_Bank | Desc | ISIN
--------------------------------------------
1 | 421345 | BlaBla | US1354
--------------------------------------------
499 | 34345 | 2.US | XS1545
--------------------------------------------
500 | 45676 | 2/US | XS1545
--------------------------------------------
501 | 12456 | 2-US | XS1545
--------------------------------------------
Table 2
--------------------------------------------
Row | SecID_by_Bank | Desc | ISIN
--------------------------------------------
1 | 34345 | 2.US | XS1545
--------------------------------------------
2 | 45676 | 2/US | XS1545
Query result needed:
SecID_by_Bank | Desc | ISIN
-------------------------------------
| 12456 | 2-US | XS1545
-------------------------------------
What am I missing?
Thank you!
If you build query in Access try:
SELECT Table1.*
FROM Table1
WHERE (((Table1.[ISIN]) In (SELECT ISIN FROM Table2)) AND ((Table1.SecID_by_Bank) Not In (SELECT SecID_by_BANK FROM Table2)));
Or using 1 subquery:
SELECT Table1.*, Table2.ISIN
FROM Table2 RIGHT JOIN Table1 ON Table2.SecID_by_Bank = Table1.SecID_by_Bank
WHERE (((Table1.ISIN) In (SELECT ISIN FROM Table2)) AND ((Table2.ISIN) Is Null));
For query in SQLServer:
select distinct a.SecID_by_Bank, a.[desc], a.isin from #table1 a left join #table2 b
on a.SecID_by_Bank=b.SecID_by_Bank and a.isin=b.isin
join #table2 c on a.isin=c.isin
where b.isin is null
Related
I have two tables. I need to combine two table.
This First table.
----------------------------
| row_no | Part No |Qty_A |
----------------------------
| 1 | A | 100 |
| 2 | A | 300 |
----------------------------
Second table.
----------------------------
| row_no | Part No |Qty_B |
----------------------------
| 1 | A | 400 |
| 2 | B | 200 |
----------------------------
This is my result:
--------------------------------------
| row_no | Part No | Qty_A | Qty_B |
--------------------------------------
| 1 | A | 100 | 400 |
| 2 | A | 300 | - |
| 2 | B | - | 200 |
--------------------------------------
Two tables was joined by "row_no" and "Part_no" column.
I try to use "LEFT OUTER JOIN" but results not as expected.
SELECT t1.row_no ,t1.part_no ,t1.Qty_A ,t2.Qty_B
FROM
(SELECT 1 as row_no,'A' as part_no,100 as Qty_A) as t1
LEFT OUTER JOIN
(SELECT 1 as row_no, 'B' as part_no,200 as Qty_B) as t2
ON t1.row_no = t2.row_no and t1.part_no = t2.part_no
Sorry for my unclear example.
Update
This is example from a large transaction.
And I need to group it by Part_no and re-arrange by row number like these.
Try below query with union all:
select row_no ,part_no ,Qty_A , '-' as Qty_B from tableA
union all
select row_no ,part_no ,'-' as Qty_A , Qty_B from tableb
or you can try with full outer join:
SELECT t1.row_no ,t1.part_no ,t1.Qty_A ,t2.Qty_B
FROM
(SELECT 1 as row_no,'A' as part_no,100 as Qty_A) as t1
full OUTER JOIN
(SELECT 1 as row_no, 'B' as part_no,200 as Qty_B) as t2
ON t1.row_no = t2.row_no and t1.part_no = t2.part_no
The UNION operator is used to combine the result-set of two or more SELECT statements.
- Each SELECT statement within UNION must have the same number of
columns
- The columns must also have similar data types
- The columns in each SELECT statement must also be in the same order
The first query in the union statement defines the column names.
So in your case you could
select row_no ,part_no ,Qty_A , null as Qty_B from table1
union all
select row_no ,part_no , null, Qty_B from table2
Given table t1 with columns Id ( text, primary key ) and place (text) like below.
+-------+-----------+
| Id | place |
+-------+-----------+
| abcde | Santori |
| bcdef | Krypt |
| cdefg | Bali |
| defgh | Bangkok |
| abcde | Colombo |
+-------+-----------+
I need to find out the records for Ids having more than one distinct place. In the above example the output shall be
+-------+-----------+
| Id | place |
+-------+-----------+
| abcde | Santori |
| abcde | Colombo |
+-------+-----------+
I would use exists :
select t.*
from table t
where exists (select 1 from table t1 where t1.id = t.id and t1.place <> t.place);
I think it is OK for you:
SELECT ID, PLACE FROM T1 as A
WHERE A.ID IN
(SELECT ID FROM T1 AS B
GROUP BY ID
HAVING count(*) > 1
)
In a subquery, you need to get count of distinct place and get the ID. And then use an outer query to fetch all records.
Fiddle Example
select * From T1
where T1.ID in
(select ID from T1
group by ID
having count(distinct PLACE) > 1
)
Table 1
id | check | status
1 | abc | 1
2 | def | 3
Table 2
Column1 | rawvalue | to_be_updated_value|
check | abc | new
status | 3 | 3333
Please help me to write select statement to get the following output in Oracle11g
Expected Output:
id | check | status
1 | **new** | 1
2 | def | **3333**
This is the first thing I think you want to do (applies to SQL Server):
SELECT ISC.COLUMN_NAME, T2.*
FROM <YourDatabase>.INFORMATION_SCHEMA.COLUMNS ISC
INNER JOIN Table2 T2
ON T2.Column1 = ISC.COLUMN_NAME
WHERE ISC.TABLE_NAME = N'Table1';
I have two tables.They have the same data but from different sources. I would like to find all columns from both tables that where id in table 2 occurs more than once in table 1. Another way to look at it is if table2.id occurs only once in table1.id dont bring it back.
I have been thinking it would be some combination of group by and order by clause that can get this done but its not getting the right results. How would you express this in a SQL query?
Table1
| id | info | state | date |
| 1 | 123 | TX | 12-DEC-09 |
| 1 | 123 | NM | 12-DEC-09 |
| 2 | 789 | NY | 14-DEC-09 |
Table2
| id | info | state | date |
| 1 | 789 | TX | 14-DEC-09 |
| 2 | 789 | NY | 14-DEC-09 |
Output
|table2.id| table2.info | table2.state| table2.date|table1.id|table1.info|table1.state|table1.date|
| 1 | 789 | TX | 14-DEC-09 | 1 | 123 | TX | 12-DEC-09 |
| 1 | 789 | TX | 14-DEC-09 || 1 | 123 | NM | 12-DEC-09 |
If you using MSSQL try using a Common Table Expression
WITH cte AS (SELECT T1.ID, COUNT(*) as Num FROM Table1 T1
INNER JOIN Table2 T2 ON T1.ID = T2.ID
GROUP BY T1.ID
HAVING COUNT(*) > 1)
SELECT * FROM cte
INNER JOIN Table1 T1 ON cte.ID = T1.ID
INNER JOIN Table2 T2 ON cte.ID = T2.ID
First, I would suggest adding an auto-incrementing column to your tables to make queries like this much easier to write (you still keep your ID as you have it now for relational-mapping). For example:
Table 1:
TableID int
ID int
Info int
State varchar
Date date
Table 2:
TableID int
ID int
Info int
State varchar
Date date
Then your query would be really easy, no need to group, use CTEs, or row_over partitioning:
SELECT *
FROM Table2 T2
JOIN Table1 T1
ON T2.ID = T1.ID
JOIN Table1 T1Duplicate
ON T2.ID = ID
AND T1.TableID <> T1Duplicate.TableID
It's a lot easier to read. Furthermore, there are lots of scenarios where an auto-incrementing ID field is benefitial.
I find this a much simpler way to do it:
select TableA.*,TableB.*
from TableA
inner join TableB
on TableA.id=TableB.id
where TableA.id in
(select distinct id
from TableA
group by id
having count(*) > 1)
I have two tables :
Table1
id | name | age | d_o_b
=====================================
1 | ASD | 22 | 12/01/1992
2 | QWE | 21 | 04/04/1993
3 | FRG | 24 | 04/04/1990
Table2
id | age
===============
1 | 22
2 | 21
3 | 24
Is it possible to order by two columns one from first Table1 and then by one column from Table2.
Something like ..
SELECT * FROM Table1 order by d_o_b , age in (SELECT * FROM Table2)
To order by a column in other table you may need to join them. This should work:
SELECT a.* FROM Table1 a
join table2 b
on a.id=b.id
order by d_o_b,b.age