I have two tables :
Table1
id | name | age | d_o_b
=====================================
1 | ASD | 22 | 12/01/1992
2 | QWE | 21 | 04/04/1993
3 | FRG | 24 | 04/04/1990
Table2
id | age
===============
1 | 22
2 | 21
3 | 24
Is it possible to order by two columns one from first Table1 and then by one column from Table2.
Something like ..
SELECT * FROM Table1 order by d_o_b , age in (SELECT * FROM Table2)
To order by a column in other table you may need to join them. This should work:
SELECT a.* FROM Table1 a
join table2 b
on a.id=b.id
order by d_o_b,b.age
Related
It is possible in MS ACCESS 2016 to join a table that is a multi-conditional SUM of another table?
Example:
Table 1 - Columns
ID, NAME, TOTAL
Table 2 - Columns
ID, NAME, IDREF, ROOTID, CUSTO
Data:
Table 1
ID | Name | Total
---+-------+------
35 | Test | "SUM(CUSTO) of ALL ELEMENTS OF TABLE 2 WHERE table2.IDREF = table1.ID **or** table2.ROOTID = table1.ID"
Table 2
ID | Name | IDREF | CUSTO | ROOTID |
---+-------+-------+-------+----------+
1 | Test | 35 | 50 | 0 |
2 | Test | 35 | 30 | 0 |
3 | ALFA | 12 | 30 | 0 |
4 | BETA | 17 | 10 | 35 |
The result should be:
table 1
ID | Name | Total
---+------+------
35 | Test | 90 (50 + 30 from table 2 where idref = 35 and + 10 from table 2 where rootid = 35)
it is very similar as one of my previous question, but i think a multi condional sum is very hard to do in ms-access need some help.
thanks.
You can use a couple of sub-queries to get the total for each, and add them together:
SELECT T1.ID,
NZ((SELECT SUM(T2.Custo) FROM Table2 AS T2 WHERE T1.ID=T2.IDRef),0) +
NZ((SELECT SUM(T2A.Custo) FROM Table2 AS T2A WHERE T1.ID=T2A.RootID) ,0) AS Total
FROM Table1 AS T1;
Regards,
You can use inner join with multiple ON conditions as below,
SELECT
t1.ID,
t1.Name,
SUM(t2.CUSTID) AS Total
FROM
t2
INNER JOIN
t1
ON
t2.IDREF = t1.ID
OR
t2.ROOTID =t1.ID
GROUP BY
t1.ID,
t1.NAME
Output:
ID Name Total
35 Test 90
I have two tables. I need to combine two table.
This First table.
----------------------------
| row_no | Part No |Qty_A |
----------------------------
| 1 | A | 100 |
| 2 | A | 300 |
----------------------------
Second table.
----------------------------
| row_no | Part No |Qty_B |
----------------------------
| 1 | A | 400 |
| 2 | B | 200 |
----------------------------
This is my result:
--------------------------------------
| row_no | Part No | Qty_A | Qty_B |
--------------------------------------
| 1 | A | 100 | 400 |
| 2 | A | 300 | - |
| 2 | B | - | 200 |
--------------------------------------
Two tables was joined by "row_no" and "Part_no" column.
I try to use "LEFT OUTER JOIN" but results not as expected.
SELECT t1.row_no ,t1.part_no ,t1.Qty_A ,t2.Qty_B
FROM
(SELECT 1 as row_no,'A' as part_no,100 as Qty_A) as t1
LEFT OUTER JOIN
(SELECT 1 as row_no, 'B' as part_no,200 as Qty_B) as t2
ON t1.row_no = t2.row_no and t1.part_no = t2.part_no
Sorry for my unclear example.
Update
This is example from a large transaction.
And I need to group it by Part_no and re-arrange by row number like these.
Try below query with union all:
select row_no ,part_no ,Qty_A , '-' as Qty_B from tableA
union all
select row_no ,part_no ,'-' as Qty_A , Qty_B from tableb
or you can try with full outer join:
SELECT t1.row_no ,t1.part_no ,t1.Qty_A ,t2.Qty_B
FROM
(SELECT 1 as row_no,'A' as part_no,100 as Qty_A) as t1
full OUTER JOIN
(SELECT 1 as row_no, 'B' as part_no,200 as Qty_B) as t2
ON t1.row_no = t2.row_no and t1.part_no = t2.part_no
The UNION operator is used to combine the result-set of two or more SELECT statements.
- Each SELECT statement within UNION must have the same number of
columns
- The columns must also have similar data types
- The columns in each SELECT statement must also be in the same order
The first query in the union statement defines the column names.
So in your case you could
select row_no ,part_no ,Qty_A , null as Qty_B from table1
union all
select row_no ,part_no , null, Qty_B from table2
Can someone help me to join the two tables without any primary or secondary keys. Sample table is
TABLE 1
| ID | NAME |
| 1 | x |
| 2 | Y |
| 3 | z |
TABLE 2
| Num | NAME | DATE |
| 52 | X | 12-aug-17 |
| 53 | X | 11-apr-17 |
| 62 | X | 10-aug-11 |
| 12 | y | 2-jan-16 |
| 23 | Y | 3-apr-18 |
I want retrieve data from X
select *
from table2
where name = 'x';
| Num | NAME | DATE |
| 52 | X | 12-aug-17 |
| 53 | X | 11-apr-17 |
| 62 | X | 10-aug-11 |
Now I will get three data from table2. I'm little stuck after this step. I want to get top of data the from table 2 and combine with table one.
I want final output should be
| ID | NAME | Num | DATE |
| 1 | x | 52 | 12-aug-17 |
Can someone suggest me how can I join this table? Its easy to join when we have any primary key but here not the case
Thanks
You can use this:
SELECT TOP(1) table1.ID, table2.Num, table2.Name, table2.DATE
FROM table2 INNER JOIN table1 ON table1.NAME = table2.NAME
WHERE table2.NAME = 'x'
ORDER BY table2.DATE ASC
OR
SELECT table1.ID, table2.Num, table2.Name, table2.DATE
FROM table1 INNER JOIN
(SELECT TOP(1) * FROM table2 WHERE NAME = 'x' ORDER BY DATE ASC) table2
ON table1.NAME = table2.NAME
You need to get the maximum DATE using a subquery, as in:
select t1.id, t2.*
from table1 t1
join table2 t2 on t2.name = t1.name
where t2.date = (
select max(date) from table2 where name = 'x'
);
Given table t1 with columns Id ( text, primary key ) and place (text) like below.
+-------+-----------+
| Id | place |
+-------+-----------+
| abcde | Santori |
| bcdef | Krypt |
| cdefg | Bali |
| defgh | Bangkok |
| abcde | Colombo |
+-------+-----------+
I need to find out the records for Ids having more than one distinct place. In the above example the output shall be
+-------+-----------+
| Id | place |
+-------+-----------+
| abcde | Santori |
| abcde | Colombo |
+-------+-----------+
I would use exists :
select t.*
from table t
where exists (select 1 from table t1 where t1.id = t.id and t1.place <> t.place);
I think it is OK for you:
SELECT ID, PLACE FROM T1 as A
WHERE A.ID IN
(SELECT ID FROM T1 AS B
GROUP BY ID
HAVING count(*) > 1
)
In a subquery, you need to get count of distinct place and get the ID. And then use an outer query to fetch all records.
Fiddle Example
select * From T1
where T1.ID in
(select ID from T1
group by ID
having count(distinct PLACE) > 1
)
I'm trying to get a query that get me a data that exist in table1 but not on table2, but has the same id with data table2.
In the following example, I'm trying to get 'SecID-by_Bank' 12456 which shares the same ISIN as another 2 items in table2.
I've tried the following query, but it returned me every data that's not on table2, not just the one that shares the same ISIN.
Query:
SELECT tb1_isin, tb1_SecID_by_Bank
FROM table1
WHERE not EXISTS (
SELECT top 1 null
FROM table2
WHERE table1.tb1_ISIN = table2.tb2_isin
)
Table 1
--------------------------------------------
Row | SecID_by_Bank | Desc | ISIN
--------------------------------------------
1 | 421345 | BlaBla | US1354
--------------------------------------------
499 | 34345 | 2.US | XS1545
--------------------------------------------
500 | 45676 | 2/US | XS1545
--------------------------------------------
501 | 12456 | 2-US | XS1545
--------------------------------------------
Table 2
--------------------------------------------
Row | SecID_by_Bank | Desc | ISIN
--------------------------------------------
1 | 34345 | 2.US | XS1545
--------------------------------------------
2 | 45676 | 2/US | XS1545
Query result needed:
SecID_by_Bank | Desc | ISIN
-------------------------------------
| 12456 | 2-US | XS1545
-------------------------------------
What am I missing?
Thank you!
If you build query in Access try:
SELECT Table1.*
FROM Table1
WHERE (((Table1.[ISIN]) In (SELECT ISIN FROM Table2)) AND ((Table1.SecID_by_Bank) Not In (SELECT SecID_by_BANK FROM Table2)));
Or using 1 subquery:
SELECT Table1.*, Table2.ISIN
FROM Table2 RIGHT JOIN Table1 ON Table2.SecID_by_Bank = Table1.SecID_by_Bank
WHERE (((Table1.ISIN) In (SELECT ISIN FROM Table2)) AND ((Table2.ISIN) Is Null));
For query in SQLServer:
select distinct a.SecID_by_Bank, a.[desc], a.isin from #table1 a left join #table2 b
on a.SecID_by_Bank=b.SecID_by_Bank and a.isin=b.isin
join #table2 c on a.isin=c.isin
where b.isin is null