I have a table Fields. Example:-
id remote unique_id
1 23 30007
1 24 30008
1 1 30009
2 4 30007
2 5 30008
2 1 30009
3 6 30007
3 7 30008
3 2 30009
here i want to get sum of unique_id field=30008 remote value where unique_id field=30009 remote value = 1;
basically, what i want is:
(query 1)
select SUM(remote) from Fields where unquie_id = '30008';
and one added filter where:(query 2)
select remote from Fields where unquie_id = '30009';
i want to select the _id record of query 2 where remote=1 for my query 1.
So the above output would be: 24+5=29.
Here i am selecting _id as 1,2. _id =3 would be rejected as it remote for unique_id = 30009 is 2.
This might be simple for you guys but i am new with sqlite. Hence please help.
If I understand your question correctly, then you want to sum the remote column where the unique_id is 30008, but only for those id groups having remote=1 and unique_id=30009.
SELECT SUM(f1.remote)
FROM Fields f1
INNER JOIN
(
SELECT id
FROM Fields
GROUP BY id
HAVING SUM(CASE WHEN unique_id = '30009' AND remote = 1 THEN 1 ELSE 0 END) > 0
) f2
ON f1.id = f2.id
WHERE unique_id = '30008';
I didn't actually run it, but something like this should do what you need:
select SUM(remote) from Fields as F where F.unique_id = '30008' and F.id in (select remote from Fields as G where G.unique_id = '30009');
So I tested it:
create table Fields(id integer, remote integer, unique_id integer);
insert into Fields(id, remote, unique_id) values (1, 23, 3007), (1, 24, 30008), (1 ,1 ,30009), (2, 4, 30007), (2 , 5 , 30008), (2 , 1 , 30009), (3 , 6, 30007), (3 , 7, 30008
), (3 , 2 , 30009);
/*select * from Fields;*/
select SUM(remote) from Fields as F where F.unique_id = '30008' and F.id in (select remote from Fields as G where G.unique_id = '30009');
And the ouput was: 29 as desired.
You could use exists
select sum(remote) total
from Fields f
where exists (
select 1 from Fields
where remote = f.id and unique_id = 30009
) and f.unique_id = 30008
Related
Let's say I am returning the following table from a select
CaseId
DocId
DocumentTypeId
DocumentType
ExpirationDate
1
1
1
I797
01/02/23
1
2
2
I94
01/02/23
1
3
3
Some Other Value
01/02/23
I want to select ONLY the row with DocumentType = 'I797', then if there is no 'I797', I want to select ONLY the row where DocumentType = 'I94'; failing to find either of those two I want to take all rows with any other value of DocumentType.
Using SQL Server ideally.
I think I'm looking for an XOR clause but can't work out how to do that in SQL Server or to get all other values.
Similar to #siggemannen answer
select top 1 with ties
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end gr
,docs.*
from docs
order by
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end
Shortest:
select top 1 with ties
docs.*
from docs
order by
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end
Something like this perhaps:
select *
from (
select t.*, DENSE_RANK() OVER(ORDER BY CASE WHEN DocumentType = 'I797' THEN 0 WHEN DocumentType = 'I94' THEN 1 ELSE 2 END) AS prioorder
from
(
VALUES
(1, 1, 1, N'I797', N'01/02/23')
, (1, 2, 2, N'I94', N'01/02/23')
, (1, 3, 3, N'Some Other Value', N'01/02/23')
, (1, 4, 3, N'Super Sekret', N'01/02/23')
) t (CaseId,DocId,DocumentTypeId,DocumentType,ExpirationDate)
) x
WHERE x.prioorder = 1
The idea is to rank rows by 1, 2, 3 depending on document type. Since we rank "the rest" the same, you will get all rows if I797 and I94 is missing.
select * from YourTable where DocumentType = 'I797'
union
select * from YourTable t where DocumentType = 'I94' and (not exists (select * from YourTable where DocumentType = 'I797'))
union
select * from YourTable t where (not exists (select * from YourTable where DocumentType = 'I797' or DocumentType = 'I94' ))
I have a table like below:
CREATE TABLE public.test_table
(
"ID" serial PRIMARY KEY NOT NULL,
"CID" integer NOT NULL,
"SEG" integer NOT NULL,
"DDN" character varying(3) NOT NULL
)
and data looks like this:
ID CID SEG DDN
1 1 1 "711"
2 1 2 "800"
3 1 3 "124"
4 2 1 "711"
5 3 1 "711"
6 3 2 "802"
7 4 1 "799"
8 5 1 "799"
9 5 2 "804"
10 6 1 "799"
I need to group these data by CID column and get column counts depends on DDN columns first values but counts must give me two different information, if it's more than 1 or not.
I'm really sorry if couldn't explains clearly. Let me show you what I need..
DDN END TRA
711 1 2
799 2 1
As you can see, DDN:711 has 1 record of single count (ID:4). This is END column.
But 2 times has multiple SEG count (ID:1to3 and ID:5to6). This is TRA column.
I can not be sure what column should be in group clause!
My solution:
Just found a solution like below
WITH x AS (
SELECT
(SELECT t1."DDN" FROM public.test_table AS t1
WHERE t1."CID"=t."CID" AND t1."SEG"=1) AS ddn,
COUNT("CID") AS seg_count
FROM public.test_table AS t
GROUP BY "CID"
)
SELECT ddn, COUNT(seg_count) AS "TOTAL",
SUM(CASE WHEN x.seg_count=1 THEN 1 ELSE 0 END) as "END",
SUM(CASE WHEN x.seg_count>1 THEN 1 ELSE 0 END) as "TRA"
FROM x
GROUP BY ddn;
Equivalent, faster query:
SELECT "DDN"
, COUNT(*) AS "TOTAL"
, COUNT(*) FILTER (WHERE seg_count = 1) AS "END"
, COUNT(*) FILTER (WHERE seg_count > 1) AS "TRA"
FROM (
SELECT DISTINCT ON ("CID")
"DDN" -- assuming min "SEG" is always 1
, COUNT(*) OVER (PARTITION BY "CID") AS seg_count
FROM test_table
ORDER BY "CID", "SEG"
) sub
GROUP BY "DDN";
db<>fiddle here
Notes
CTEs are typically slower and should only be used where needed in Postgres.
This is equivalent to the query in the question assuming that the minimum "SEG" per "CID" is always 1 - since this query returns the row with the minimum "SEG" while your query returns the one with "SEG" = 1. Typically, you would want the "first" segment and my query implements this requirement more reliably, but that's not clear from the question.
COUNT(*) is slightly faster than COUNT(column) and equivalent while not involving NULL values (applicable here). Related:
PostgreSQL: running count of rows for a query 'by minute'
About DISTINCT ON:
Select first row in each GROUP BY group?
The aggregate FILTER syntax requires Postgres 9.4+:
Conditional SQL count
Here is the solution i propose, the query can be simplified i guess.
CREATE TABLE test_table
(
ID serial PRIMARY KEY NOT NULL,
CID integer NOT NULL,
SEG integer NOT NULL,
DDN character varying(3) NOT NULL
);
insert into test_table(CID,SEG,DDN)
values
( 1, 1, '711'),
( 1, 2, '800'),
( 1, 3, '124'),
( 2, 1, '711'),
( 3, 1, '711'),
( 3, 2, '802'),
( 4, 1, '799'),
( 5, 1, '799'),
( 5, 2, '804'),
( 6, 1, '799');
with summary as (with ddn_t as (select cid,ddn,row_number() OVER( PARTITION BY cid)from test_table)
select a.cid,count(distinct a.ddn),b.ddn
from ddn_t a
join ddn_t b on b.cid=a.cid and b.row_number=1
group by a.cid, b.ddn)
select ddn,
sum (case when count >1 then 1 else 0 end) as TRA,
sum (case when count = 1 then 1 else 0 end) as END
from summary
group by ddn;
CREATE TABLE (
A INT NOT NULL,
B INT NOT NULL
)
A is an enumerated values of 1, 2, 3, 4, 5
B can be any values
I would like to count() the number of occurrence group by B, with a specific subset of A e.g. {1, 2}
Example:
A B
1 7 *
2 7 *
3 7
1 8 *
2 8 *
1 9
3 9
When B = 7, A = 1, 2, 3. Good
When B = 8, A = 1, 2. Good
When B = 9, A = 1, 3. Not satisfy, 2 is missing
So the count will be 2 (when B = 7 and 8)
If I've understood you correctly, we want to find B values for which we have both a 1 and a 2 in A, and then we want to know how many of those we have.
This query does this:
declare #t table (A int not null, B int not null)
insert into #t(A,B) values
(1,7),
(2,7),
(3,7),
(1,8),
(2,8),
(1,9),
(3,9)
select COUNT(DISTINCT B) from (
select B
from #t
where A in (1,2)
group by B
having COUNT(DISTINCT A) = 2
) t
One or both of the DISTINCTs may be unnecessary - it depends on whether your data can contain repeating values.
If I understand correctly and the requirement is to find Bs with a series of As that doesn't have any "gaps", you could compare the difference between the minimal and maximal A with number of records (per B, of course):
SELECT b
FROM mytable
GROUP BY b
HAVING COUNT(*) + 1 = MAX(a) - MIN(a)
SELECT COUNT(DISTINCT B) FROM TEMP T WHERE T.B NOT IN
(SELECT B FROM
(SELECT B,A,
LAG (A,1) OVER (PARTITION BY B ORDER BY A) AS PRE_A
FROM Temp) K
WHERE K.PRE_A IS NOT NULL AND K.A<>K.PRE_A+1);
This question already has answers here:
Pivoting in DB2
(3 answers)
Closed 5 years ago.
I have table A, below, where for each unique id, there are three codes with some value.
ID Code Value
---------------------
11 1 x
11 2 y
11 3 z
12 1 p
12 2 q
12 3 r
13 1 l
13 2 m
13 3 n
I have a second table B with format as below:
Id Code1_Val Code2_Val Code3_Val
Here there is just one row for each unique id. I want to populate this second table B from first table A for each id from the first table.
For the first table A above, the second table B should come out as:
Id Code1_Val Code2_Val Code3_Val
---------------------------------------------
11 x y z
12 p q r
13 l m n
How can I achieve this in a single SQL query?
select Id,
max(case when Code = '1' then Value end) as Code1_Val,
max(case when Code = '2' then Value end) as Code2_Val,
max(case when Code = '3' then Value end) as Code3_Val
from TABLEA
group by Id
SELECT Id,
max(DECODE(Code, 1, Value)) AS Code1_Val,
max(DECODE(Code, 2, Value)) AS Code2_Val,
max(DECODE(Code, 3, Value)) AS Code3_Val
FROM A
group by Id
If your version doesn't have DECODE(), you can also use this:
INSERT INTO B (id, code1_val, code2_val, code3_val)
WITH Ids (id) as (SELECT DISTINCT id
FROM A) -- Only to construct list of ids
SELECT Ids.id, a1.value, a2.value, a3.value
FROM Ids -- or substitute the actual id table
JOIN A a1
ON a1.id = ids.id
AND a1.code = 1
JOIN A a2
ON a2.id = ids.id
AND a2.code = 2
JOIN A a3
ON a3.id = ids.id
AND a3.code = 3
(Works on my V6R1 DB2 instance, and have an SQL Fiddle Example).
Here is a SQLFiddle example
insert into B (ID,Code1_Val,Code2_Val,Code3_Val)
select Id, max(V1),max(V2),max(V3) from
(
select ID,Value V1,'' V2,'' V3 from A where Code=1
union all
select ID,'' V1, Value V2,'' V3 from A where Code=2
union all
select ID,'' V1, '' V2,Value V3 from A where Code=3
) AG
group by ID
Here is the SQL Query:
insert into pivot_insert_table(id,code1_val,code2_val, code3_val)
select * from (select id,code,value from pivot_table)
pivot(max(value) for code in (1,2,3)) order by id ;
WITH Ids (id) as
(
SELECT DISTINCT id FROM A
)
SELECT Ids.id,
(select sub.value from A sub where Ids.id=sub.id and sub.code=1 fetch first rows only) Code1_Val,
(select sub.value from A sub where Ids.id=sub.id and sub.code=2 fetch first rows only) Code2_Val,
(select sub.value from A sub where Ids.id=sub.id and sub.code=3 fetch first rows only) Code3_Val
FROM Ids
You want to pivot your data. Since DB2 has no pivot function, yo can use Decode (basically a case statement.)
The syntax should be:
SELECT Id,
DECODE(Code, 1, Value) AS Code1_Val,
DECODE(Code, 2, Value) AS Code2_Val,
DECODE(Code, 3, Value) AS Code3_Val
FROM A
Having this table:
Row Pos Outdata Mismatch Other
1 10 S 0 A
2 10 S 5 A
3 10 R 0 B
4 10 R 7 B
5 20 24 0 A
6 20 24 5 B
6 20 32 10 C
How can I select all rows where Pos=10 having unique Outdata. If more than one row exists, I would like to have the row where the field Mismatch is smallest. Ie I would like to get rows 1 and 3, not 2 and 4.
In that select I would also like to do the same for all Pos=20, so the total result should be rows 1,3,5,6
(And I want to then access the "Other" field, so I cant only SELECT DISTINCT on Pos and OutData and Mismatch).
Is there a query to do this in MySQL?
Here I am assuming that (Pos, OutData, Mismatch) is not unique, but that (Row, Pos, OutData, Mismatch) is unique:
SELECT T3.*
FROM Codes T3
JOIN (
SELECT MIN(Row) AS Row
FROM (
SELECT Pos, OutData, Min(Mismatch) AS Mismatch
FROM Codes
GROUP BY Pos, OutData
) T1
JOIN Codes T2
ON T1.Pos = T2.Pos AND T2.OutData = T2.Outdata AND T1.Mismatch = T2.Mismatch
GROUP BY T2.Pos, T2.OutData, T2.Mismatch
) T4
ON T3.Row = T4.Row
Result:
1, 10, 'S', 0, 'A'
3, 10, 'R', 0, 'B'
5, 20, '24', 0, 'A'
7, 20, '32', 10, 'C'
Note that I have also corrected the second row 6 to become row 7, as I believe that this was a mistake in the question.
Rationale is to create a table with all values of Pos, OutData and the lowest Mismatch and use the combination of these fields as a unique key into your actual table.
SELECT t1.*
FROM MyTable t1
INNER JOIN (
SELECT Pos, OutData, Mismatch = MIN(Mismatch)
FROM MyTable
GROUP BY Pos, OutData
) t2 ON t2.Pos = t1.Pos
AND t2.OutData = t1.OutData
AND t2.Mismatch = t1.Mismatch
Try this:
Select * From Table ot
Where pos = 10
And MisMatch =
(Select Min(MisMatch) From Table
Where pos = 10
And Outdata = ot.OutData)
This should work for you:
SELECT *
FROM table T1
GROUP BY Pos, Outdata
HAVING Mismatch = (
SELECT MIN(Mismatch)
FROM table T2
WHERE Pos = T1.Pos AND
Outdata = T1.Outdata
)