Question for the SQL Geeks out there.
I'm trying to set a flag on a table if any of the 3 below conditions return a 'N' value. Basically, if any of the 3 conditions are met, then I need to set a flag on a Control table. I can't figure out quite how to do this, because I'd also like to return a Reason that the Control table will be set to 'N'. This worked fine with one condition but with 3 I'm not sure.
Here's the SQL:
select Reason, TheCount,Dating_OK_to_Proceed
from
(
SELECT 'More than 2 Seasons Are Open' as Reason, COUNT(SEASCLOSED) as TheCount,
case when COUNT(SEASCLOSED) > 2 then 'N' else 'Y' END as Dating_OK_to_Proceed
FROM dbo.DATING
GROUP BY SEASCLOSED
HAVING (SEASCLOSED = 0)
union all
SELECT 'More than 1 Season has Ordering Switched On' as Reason,
COUNT(ORDERON) as TheCount,
case when COUNT(ORDERON) > 1 then 'N' else 'Y' END as Dating_OK_to_Proceed
FROM dbo.DATING
GROUP BY seasclosed, ORDERON
HAVING (ORDERON > 0) and SEASCLOSED = 0
union all
SELECT 'More than 1 Season has Invoicing Switched On' as Reason,
COUNT(INVOICEON) as TheCount,
case when COUNT(INVOICEON) > 1 then 'N' else 'Y' END as Dating_OK_to_Proceed
FROM dbo.DATING
GROUP BY seasclosed, INVOICEON
HAVING (INVOICEON > 0) and SEASCLOSED = 0
) as OkGo
If all 3 conditions return a Y, instead of 3 rows, I want to return a single row with 'Y'.
But if any of the conditions return a 'N' then I want to return a single row with the corresponding reason and the 'N'.
Is this possible?
One way to solve this:
with OkGo as
(
SELECT 'More than 2 Seasons Are Open' as Reason, COUNT(SEASCLOSED) as TheCount,
case when COUNT(SEASCLOSED) > 2 then 'N' else 'Y' END as Dating_OK_to_Proceed
FROM dbo.DATING
GROUP BY SEASCLOSED
HAVING (SEASCLOSED = 0)
union all
SELECT 'More than 1 Season has Ordering Switched On' as Reason,
COUNT(ORDERON) as TheCount,
case when COUNT(ORDERON) > 1 then 'N' else 'Y' END as Dating_OK_to_Proceed
FROM dbo.DATING
GROUP BY seasclosed, ORDERON
HAVING (ORDERON > 0) and SEASCLOSED = 0
union all
SELECT 'More than 1 Season has Invoicing Switched On' as Reason,
COUNT(INVOICEON) as TheCount,
case when COUNT(INVOICEON) > 1 then 'N' else 'Y' END as Dating_OK_to_Proceed
FROM dbo.DATING
GROUP BY seasclosed, INVOICEON
HAVING (INVOICEON > 0) and SEASCLOSED = 0
)
, RankedReasons as
( select Reason, TheCount, Dating_OK_to_Proceed,
-- if there's any 'N' it will be sorted first and gets rank 1,
-- otherwise 1 is assigned to the first 'Y'
row_number()
over (order by Dating_OK_to_Proceed) as rnk
from OkGo
)
select * from RankedReasons
where rnk = 1 --return a single row for 'Y' or one out of multiple 'N's
To get all rows with 'N' you just have to add a final
or Dating_OK_to_Proceed = 'N'
Related
I need help How can I merge the column into a single column, here is my code, is this method is correct. I want to get the count of the selected row in the table for the columns.
SELECT
CAT_MGR,
SUM ( case when CAT_MGR = 'A' THEN 1 else 0 end ) AS DESIGN,
sum (case when CAT_MGR = 'b' THEN 1 else 0 END) AS DESIGN,
sum (case when CAT_MGR = 'c' THEN 1 else 0 END) AS DESIGN
from Table_A
GROUP BY
CAT_MGR
Can you guys help me I'm a beginner at SQL.
Thank you in advance
If you want just one row in the resultset, then remove the group by clause. Then, if you want to count the three cat mgr together, you can use in:
select
sum(case when cat_mgr = 'a' then 1 else 0 end ) as design_a,
sum(case when cat_mgr = 'b' then 1 else 0 end ) as design_b,
sum(case when cat_mgr = 'c' then 1 else 0 end ) as design_c,
sum(case when cat_mgr in ('a', 'b', 'c') then 1 else 0 end ) as design
from Table_a
You just need to make addion like below in order to get one column "Design"
SELECT
CAT_MGR,
SUM (case when CAT_MGR = 'A' THEN 1 else 0 end )
+ sum (case when CAT_MGR = 'b' THEN 1 else 0 END)
+ sum (case when CAT_MGR = 'c' THEN 1 else 0 END)
AS DESIGN
from TJD_CORE_CATPB_TB
GROUP BY
CAT_MGR
I have to Case statements that count the same column just with a differnt criteria. The problem i am having is that the first case creates a null entry in the Test2 column but then counts it on my second case statement and leaves the Test 1 column null. I would like to have both counts side by side instead of created a duplicate row.
select m.no,
Case when itemtype = 'S' THEN count(ITEMKEY) end as Test1,
case when ItemType='C' THEN count(ITEMKEY) END as Test2
from test m
I'm pretty sure you want conditional aggregation. The case expression is an argument to the aggregation function:
select m.no,
sum(case when itemtype = 'S' then 1 else 0 end) as test1,
sum(case when itemtype = 'C' then 1 else 0 end) as test2
from test m
group by m.no;
This assumes that itemKey is never null, so the count() is just counting rows.
Following query can display records which having Itemtype 'S' or 'C' with count of itemkey. if itemkey is null it will display 0 else count of item key
select m.no,
Case when isnull( m.itemtype = 'S',0) THEN (select count(a.ITEMKEY) from test a where a.itemtype = 'S' ) else 0 end as Test1,
case when isnull( m.itemtype='C',0) THEN (select count(b.ITEMKEY) from test b where b.itemtype = 'C') else 0 END as Test2
from test m
I have a 2 column table with the columns : "user_name" and "characteristic". Each user_name may appear multiple times with a different characteristic.
The values in characteristic are:
Online
Instore
Account
Email
I want to write a sql statement that goes like this - but obviously this isn't working:
SELECT user_name,
case
when characteristic in ("online","instore") then 1
else 0
END as purchase_yn,
case
when characteristic in ("online","instore") and
characteristic in ("email",'account') then 1
else 0
END as purchaser_with_account
FROM my_table
GROUP BY user_name;
Essentially the first is a flag where I check for the presence of either value for that user_name.
The Second field is that they meet this criteria AND that they meet the criteria for having either 'email' or 'account'
An example the structure of your data would help better understand what you are trying to accomplish. But I think I get what you are trying to do.
You have to use an aggregate function in order to use a group by.
Something like SUM or AVG.
But you need first to build a pivot of your data and then you could use that pivot to check for your criterias:
This would create a table pivot that shows for each record what criterias are met:
SELECT
user_name,
case when characteristic = "online" then 1 else 0 end as online_yn,
case when characteristic = "instore" then 1 else 0 end as instore_yn,
case when characteristic = "account" then 1 else 0 end as account_yn,
case when characteristic = "email" then 1 else 0 end as email_yn,
FROM my_table
Now what you might wanted to do is to create an averaged version of these entries grouped by user_name and use those averages to create the fields you wanted. For that you need to use the same statement created earlier as an inline table :
Select
user_name,
case when avg(online_yn + instore_yn) >= 1 then 1 else 0 end as purchase_yn,
case when avg(online_yn + instore_yn) >= 1 and avg(email_yn + account_yn) >= 1 then 1 else 0 end as purchaser_with_account
From
(SELECT
user_name,
case when characteristic = "online" then 1 else 0 end as online_yn,
case when characteristic = "instore" then 1 else 0 end as instore_yn,
case when characteristic = "account" then 1 else 0 end as account_yn,
case when characteristic = "email" then 1 else 0 end as email_yn,
FROM my_table) avg_table
group by
user_name;
This should help.
It may not be efficient in terms of performance but you'll get what you want.
You just have to enclose the CASE expressions in COUNT aggregates:
SELECT user_name,
COUNT(case when characteristic in ("online","instore") then 1 END) as purchase_yn,
COUNT(case when characteristic in ("email",'account') then 1 END) as user_with_account
FROM my_table
GROUP BY user_name
If purchase_yn > 0 then you first flag is set. If purchase_yn > 0 and user_with_account > 0 then you second flag is set as well.
Note: You have to remove ELSE 0 from the CASE expressions because COUNT takes into account all not null values.
You haven't mentioned a specific RDBMS, but if SUM(DISTINCT ...) is available the following is quite nice:
SELECT
username,
SUM(DISTINCT
CASE
WHEN characteristic in ('online','instore') THEN 1
ELSE 0
END) AS purchase_yn,
CASE WHEN (
SUM(DISTINCT
CASE
WHEN characteristic in ('online','instore') THEN 1
WHEN characteristic in ('email','account') THEN 2
ELSE 0 END
)
) = 3 THEN 1 ELSE 0 END as purchaser_with_account
FROM
my_table
GROUP BY
username
If I correctly understand, if user have 'online' or 'instore', then for this user you want 1 as purchase_yn column, and if user also have 'email' or 'account', then 1 as purchaser_with_account column.
If this is correct, then one way is:
with your_table(user_name, characteristic) as(
select 1, 'online' union all
select 1, 'instore' union all
select 1, 'account' union all
select 1, 'email' union all
select 2, 'account' union all
select 2, 'email' union all
select 3, 'online'
)
-- below is actual query:
select your_table.user_name, coalesce(max(t1.purchase_yn), 0) as purchase_yn, coalesce(max(t2.purchaser_with_account), 0) as purchaser_with_account
from your_table
left join (SELECT user_name, 1 as purchase_yn from your_table where characteristic in('online','instore') ) t1
on your_table.user_name = t1.user_name
left join (SELECT user_name, 1 as purchaser_with_account from your_table where characteristic in('email', 'account') ) t2
on t1.user_name = t2.user_name
group by your_table.user_name
I have folllowing select query
SELECT
Table.ID
SUM(CASE WHEN Table.Status = 1 THEN 1 ELSE null END) AS NormalCount,
SUM(CASE WHEN Table.status = 2 THEN 1 ELSE null END) AS AbnormalCount
FROM Table
GROUP BY Table.ID
I want to get above results and generate new result set with following conditions
IF(NormalCount > 0 or AbnormalCount == NULL)
SELECT
Table.ID
Table.Status AS "Normal"
FROM Table
GROUP BY Table.ID
ELSE IF ( AbnormalCount > 0)
SELECT
Table.ID
Table.Status AS "Abnormal"
SUM(CASE WHEN Header.status = 2 THEN 1 ELSE null END) AS AbnormalCount
FROM Table
GROUP BY Table.ID
I think the logic you want is to label each ID group as being abnormal if it has one or more abnormal observation. If so, then you can use another CASE statement to check the conditional abnormal sum and label the status appropriately. Normal groups would have the characteristic of having an abnormal count of zero, but this count would appear for all groups.
SELECT t.ID,
CASE WHEN SUM(CASE WHEN t.status = 2 THEN 1 ELSE 0 END) > 0
THEN "Abnormal"
ELSE "Normal" END AS Status,
SUM(CASE WHEN t.status = 2 THEN 1 ELSE 0 END) AS AbnormalCount
FROM Table t
GROUP BY t.ID
I have a inventory table with a condition i.e. new, used, other, and i am query a small set of this data, and there is a possibility that all the record set contains only 1 or all the conditions. I tried using a case statement, but if one of the conditions isn't found nothing for that condition returned, and I need it to return 0
This is what I've tried so far:
select(
case
when new_used = 'N' then 'new'
when new_used = 'U' then 'used'
when new_used = 'O' then 'other'
end
)as conditions,
count(*) as count
from myDB
where something = something
group by(
case
when New_Used = 'N' then 'new'
when New_Used = 'U' then 'used'
when New_Used = 'O' then 'other'
end
)
This returns the data like:
conditions | count
------------------
new 10
used 45
I am trying to get the data to return like the following:
conditions | count
------------------
new | 10
used | 45
other | 0
Thanks in advance
;WITH constants(letter,word) AS
(
SELECT l,w FROM (VALUES('N','new'),('U','used'),('O','other')) AS x(l,w)
)
SELECT
conditions = c.word,
[count] = COUNT(x.new_used)
FROM constants AS c
LEFT OUTER JOIN dbo.myDB AS x
ON c.letter = x.new_used
AND something = something
GROUP BY c.word;
try this -
DECLARE #t TABLE (new_used CHAR(1))
INSERT INTO #t (new_used)
SELECT t = 'N'
UNION ALL
SELECT 'N'
UNION ALL
SELECT 'U'
SELECT conditions, ISNULL(r.cnt, 0) AS [count]
FROM (
VALUES('U', 'used'), ('N', 'new'), ('O', 'other')
) t(c, conditions)
LEFT JOIN (
SELECT new_used, COUNT(1) AS cnt
FROM #t
--WHERE something = something
GROUP BY new_used
) r ON r.new_used = t.c
in output -
new 2
used 1
other 0
You can do it as a cross-tab:
select
sum(case when new_used = 'N' then 1 else 0 end) as N,
sum(case when new_used = 'U' then 1 else 0 end) as U,
sum(case when new_used = 'O' then 1 else 0 end) as Other
from myDB
where something = something