Bold text in a Concatenate formula - vba

I would like to be able to make one or two specific words bold in my sentence when using a concatenate formula. An example is shown below.
The first sentence is using the concatenate formula. The second sentence is manually typed and formatted. Is there a way to have this formatting in the concatenate formula without having to do it manually every time?
Please note that this is just an example and I may need to use it to make a string of three consecutive words bold in a different sentence. If a general rule was provided that I can work with going forwards that would be great!
I am somewhat proficient with formulae but have never used VBA. However I suspect the solution for this problem may only be available using VBA. Please be considerate if a VBA solution is required as it'll take some time and effort for me to start-up and understand.
Thanks for your time and help.
Edit:
Public Sub ExampleConcatenate()
Dim str1 As String, str2 As String, str3 As String, str4 As String, str5 As String, str6 As String
str1 = "First string "
str2 = "Second string "
str3 = "Third string"
str4 = "Fourth string "
str5 = "Fifth string "
str6 = "Sixth string"
Range("A1").Value = str1 & str2 & str3 & str4 & str5 & str6 'concatenate strings
'format bold starts 1 character after str1 and is as long as str2
Range("A1").Characters(Start:=Len(str1) + 1, Length:=Len(str2)).Font.Bold = True
End Sub
How would I further extend the final part to make the fourth and sixth strings bold?

You cannot format individual characters in a cell text if that cell contains a formula.
Excel doesn't support that.
Workaround
The only workaround is to write that cell text as constant text (with VBA) instead of a formula (if that meets your requirement).
Then you can format individual characters with:
Range("A1").Characters(Start:=1, Length:=10).Font.Bold = True
So to partly format a string you could adjust the following example
Public Sub ExampleConcatenate()
Dim str1 As String, str2 As String, str3 As String
str1 = "First string "
str2 = "Second string "
str3 = "Third string"
Range("A1").Value = str1 & str2 & str3 'concatenate strings
'format bold starts 1 character after str1 and is as long as str2
Range("A1").Characters(Start:=Len(str1) + 1, Length:=Len(str2)).Font.Bold = True
End Sub
For more sub strings it would be easier to use an array.
Public Sub ExampleConcatenate()
Dim SubStrings As Variant
SubStrings = Array("First string ", _
"Second string ", _
"Third string ", _
"Fourth string ", _
"Fifth string ", _
"Sixth string")
Range("A1").Value = Join(SubStrings, "")
'Note array counting starts with 0 not 1 so "First string" is SubStrings(0)
'format bold starts 1 character after str1 and is as long as str2
Range("A1").Characters(Start:=Len(SubStrings(0)) + 1, Length:=Len(SubStrings(1))).Font.Bold = True
'format sub string 4
Range("A1").Characters(Start:=Len(SubStrings(0)) + Len(SubStrings(1)) + Len(SubStrings(2)) + 1, Length:=Len(SubStrings(3))).Font.Bold = True
'format sub string 6
Range("A1").Characters(Start:=Len(SubStrings(0)) + Len(SubStrings(1)) + Len(SubStrings(2)) + Len(SubStrings(3)) + Len(SubStrings(4)) + 1, Length:=Len(SubStrings(5))).Font.Bold = True
End Sub

While you cannot make text bold within a formula, you CAN make text u̲n̲d̲e̲r̲l̲i̲n̲e̲d̲. No VBA needed; the magic here is unicode special characters.
After each character that you want underlined, insert the unicode combining low line character U+0332. You can copy-paste it from that site, or use this site to apply it after each character in the text you want to print.
See the example below to apply it to an arbitrary word in a text string.
=LEFT(B2,B6)&TEXTJOIN("̲",TRUE,MID(B2,ROW(OFFSET(A1,B6,0,B7)),1))&MID(B2,B6+B7,LEN(B2))
Starting with LEFT(B2,B6) returns up until the fifth word. Similarly MID(B2,B6+B7,LEN(B2)) returns everything after the fifth word.
The real magic happens with TEXTJOIN(). This function repeats the first argument in between each element of the reference in the third argument. Notice the underline is combined with the double quote character when rendered in the equation bar. The third argument uses MID() to return the fifth word, but with each letter a separate reference so that it is combined with the combining low line character by TEXTJOIN(). Splitting the fifth word by each character is achieved by passing an array as the second argument of MID() using ROW(OFFSET()) to count from the start to the end of the fifth word.

Related

MS Access VBA: Split string into pre-defined width

I have MS Access form where the user pastes a string into a field {Vars}, and I want to reformat that string into a new field so that (a) it retains whole words, and (b) "fits" within 70 columns.
Specifically, the user will be cutting/pasting variable names from SPSS. So the string will go into the field as whole names---no spaces allowed---with line breaks between each variable. So the first bit of VBA code looks like this:
Vars = Replace(Vars, vbCrLf, " ")
which removes the line breaks. But from there, I'm stumped---ultimately I want the long string that is pasted in the Vars field to be put on consecutive multiple lines that each are no longer than 70 columns.
Any help is appreciated!
Okay, for posterity, here is a solution:
The field name on the form that captures the user input is VarList. The call to the SPSS_Syntax function below returns the list of variable names (in "Vars") that can then be used elsewhere:
Vars = SPSS_Syntax(me.VarList)
Recall that user input into Varlist comes in as each variable (word) with a line break in between each. The problem is that we want the list to be on one line (horizontal, not vertical) AND a line can be no more than 256 characters in length (I'm setting it to 70 characters below). Here's the function:
Public Function SPSS_Syntax(InputString As String)
InputString = Replace(InputString, vbNewLine, " ") 'Puts the string into one line, separated by a space.
MyLength = Len(InputString) 'Computes length of the string
If MyLength < 70 Then 'if the string is already short enough, just returns it as is.
SPSS_Syntax = InputString
Exit Function
End If
MyArray = Split(InputString, " ") 'Creates the array
Dim i As Long
For i = LBound(MyArray) To UBound(MyArray) 'for each element in the array
MyString = MyString & " " & MyArray(i) 'combines the string with a blank space in between
If Len(MyString) > 70 Then 'when the string gets to be more than 70 characters
Syntax = Syntax & " " & vbNewLine & MyString 'saves the string as a new line
MyString = "" 'erases string value for next iteration
End If
Next
SPSS_Syntax = Syntax
End Function
There's probably a better way to do it but this works. Cheers.

reverse some text in cell selected - VBA

I'm rooky for VBA. I have some problem about reversing my data on VBA-Excel. My data is "3>8 , 6>15 , 26>41 (each data on difference cells)" that i could reverse "3>8" to "8>3" follow my requirement by using function reverse. But i couldn't reverse "6>15" and "26>41" to "15>6" and "41>26". It will be "51>6" and "14>62" that failure, I want to be "15>6" and "41>26".
Reverse = StrReverse(Trim(str))
Help me for solve my issue please and thank for comment.
You first need to find the position of the ">" in the cell. you do this by taking the contents of the cell and treating it as a String and finding the ">"
This is done in the line beginning arrowPosition. This is the integer value of the position of the ">" in you original string
Next use Left to extract the text up to the ">" and Right to extract the text after the ">"
Then build a new String of rightstr & ">" & leftStr.
Note I input my data from Sheet1 B5 but you can just use any source as long as it is a String in the correct format.
Sub Test()
Dim myString As String
myString = Sheets("Sheet1").Range("B5")
Debug.Print myString
Debug.Print reverseString(myString)
End Sub
Function reverseString(inputString As String) As String
Dim leftStr As String
Dim rightStr As String
Dim arrowPosition As Integer
arrowPosition = InStr(1, inputString, ">")
leftStr = Left(inputString, arrowPosition - 1)
rightStr = Right(inputString, Len(inputString) - arrowPosition)
reverseString = rightStr & ">" & leftStr
End Function
just because you look for a VBA, you can add this function into your code:
Function rev(t As String) As String
s = Split(t, ">", 2)
rev = s(1) & ">" & s(0)
End Function
of course only if you have to reverse 2 number, otherwise you'll loop the "s", but the function would lose its usefulness

Split( "TEXT" , "+" OR "-" ,2)

I need to separate a string with Visual Basic.
The downside is that i have more then one separator.
One is "+" and the other one is "-".
I need the code to check for the string if "+" is the one in the string then use "+"
if "-" is in the string then use "-" as separator.
Can I do this?
For example: Split( "TEXT" , "+" OR "-" ,2)
easiest way is to replace out the second character and then split by only one:
Dim txt As String, updTxt As String
Dim splitTxt() As String
updTxt = Replace(txt, "-", "+")
splitTxt = Split(updTxt, "+")
or more complex. The below returns a collection of the parts after being split. Allows you to cusomize the return data a bit more if you require:
Dim txt As String, outerTxt As Variant, innerTxt As Variant
Dim splitOuterTxt() As String
Dim allData As New Collection
txt = "test + test - testing + ewfwefwef - fwefwefwf"
splitOuterTxt = Split(txt, "+")
For Each outerTxt In splitOuterTxt
For Each innerTxt In Split(outerTxt, "-")
allData.Add innerTxt
Next innerTxt
Next outerTxt
What you describe seems pretty straightforward. Just check if the text contains a + to decide which separator you should use.
Try this code:
dim separator as String
separator = Iif(InStr(txt, "+") <> 0, "+", "-")
splitResult = Split(txt, separator, 2)
The code assumes that the text you want to split is in the txt variable.
Please note that I don't have VBA here and wasn't able to actually run the code. If you get any error, let me know.

Comparing character only to character at end of string

I am writing a program in Visual Basic 2010 that lists how many times a word of each length occurs in a user-inputted string. Although most of the program is working, I have one problem:
When looping through all of the characters in the string, the program checks whether there is a next character (such that the program does not attempt to loop through characters that do not exist). For example, I use the condition:
If letter = Microsoft.VisualBasic.Right(input, 1) Then
Where letter is the character, input is the string, and Microsoft.VisualBasic.Right(input, 1) extracts the rightmost character from the string. Thus, if letter is the rightmost character, the program will cease to loop through the string.
This is where the problems comes in. Let us say the string is This sentence has five words. The rightmost character is an s, but an s is also the fourth and sixth character. That means that the first and second s will break the loop just as the others will.
My questions is whether there is a way to ensure that only the last s, or whatever character is the last one in the string can break the loop.
There are a few methods you can use for this, one as Neolisk shows; here are a couple of others:
Dim breakChar As Char = "s"
Dim str As String = "This sentence has five words"
str = str.Replace(".", " ")
str = str.Replace(",", " ")
str = str.Replace(vbTab, " ")
' other chars to replace
Dim words() As String = str.ToLower.Split(New Char() {" "}, StringSplitOptions.RemoveEmptyEntries)
For Each word In words
If word.StartsWith(breakChar) Then Exit For
Console.WriteLine("M1 Word: ""{0}"" Length: {1:N0}", word, word.Length)
Next
If you need to loop though chars for whatever reason, you can use something like this:
Dim breakChar As Char = "s"
Dim str As String = "This sentence has five words"
str = str.Replace(".", " ")
str = str.Replace(",", " ")
str = str.Replace(vbTab, " ")
' other chars to replace
'method 2
Dim word As New StringBuilder
Dim words As New List(Of String)
For Each c As Char In str.ToLower.Trim
If c = " "c Then
If word.Length > 0 'support multiple white-spaces (double-space etc.)
Console.WriteLine("M2 Word: ""{0}"" Length: {1:N0}", word.ToString, word.ToString.Length)
words.Add(word.ToString)
word.Clear()
End If
Else
If word.Length = 0 And c = breakChar Then Exit For
word.Append(c)
End If
Next
If word.Length > 0 Then
words.Add(word.ToString)
Console.WriteLine("M2 Word: ""{0}"" Length: {1:N0}", word.ToString, word.ToString.Length)
End If
I wrote these specifically to break on the first letter in a word as you ask, adjust as needed.
VB.NET code to calculate how many times a word of each length occurs in a user-inputted string:
Dim sentence As String = "This sentence has five words"
Dim words() As String = sentence.Split(" ")
Dim v = From word As String In words Group By L = word.Length Into Group Order By L
Line 2 may need to be adjusted to remove punctuation characters, trim extra spaces etc.
In the above example, v(i) contains word length, and v(i).Group.Count contains how many words of this length were encountered. For debugging purposes, you also have v(i).Group, which is an array of String, containing all words belonging to this group.

Display first and last half of any string entered into textbox

I want to display the first and last characters of any given string entered into a textbox. The strings can be of any length as the user wants (as long as it is one word) I would like to be able to do something like this... "william = will and iam" or "Celtic = Cel and tic"
I understand I would have to split or divide the string. How would I go about doing this? Any help is appreciated, thanks.
EDIT:
Thanks for your help once again guys, this is how the code ended up!
Dim strInput = txtString.Text
Dim halflength = strInput.Length / 2
Dim firsthalf = strInput.Substring(0, halflength)
Dim secondhalf = strInput.Substring(halflength)
Dim strResults = firsthalf
Dim secondResult = secondhalf
MessageBox.Show(firsthalf)
MessageBox.Show(secondhalf)
MessageBox.Show("First half of string contains... " & " " & strResults.Length.ToString & " characters", "Character Count")
MessageBox.Show("Second half of string contains... " & " " & secondResult.Length.ToString & " characters", "Character Count")
EDIT:
Also meant to mention my current incorrect code.
Dim strInput As String
Dim strLength As String
Dim strResults As String
strInput = txtString.Text
strLength = strInput.Length / 2
strResults = txtString.Text
MessageBox.Show(strInput.Length.ToString, "Length of characters")
MessageBox.Show(strLength.ToString)
MessageBox.Show(strResults.Substring(0, 3))
String.Substring and String.Length should give you everything you need to get started on this.
Seeing your existing code will make this easier. Let's walk through what we have now.
Let's assume we have just a plain, simple string like this instead of a textbox for the sake of making things easier:
Dim txtString = "Hello World"
Now, in order to split the length of the string in half; we need to get the length. The `Length property will give is that, and then divide it by two.
Dim halfLength = txtString.Length \ 2
This will perform integer division; so any remaining decimal is truncated.
Now we know where the middle of the string is. We can now use String.Substring to carve out a peice of the string by index. Substring takes two parameters, the index where to start the string, and number of characters to take. There is a second overload that takes the index to start at and consumes till the end of the string. Indexes are zero based. So for example, if we wanted to start at the beginning of the string, we'd use zero. If we wanted to skip the first character, we'd use one.
For the first half of the string, we don't want to skip any characters, so we'll use zero. The number of characters we want is half length of the string, so we pass in halfLength:
Dim firstHalf = txtString.Substring(0, halfLength)
For the second half, we want to start in the middle of the string, and consume characters till the end, so we'll use the other overload:
Dim secondHalf = txtString.Substring(halfLength)
You now have your string split in half.
The final result looks like this:
Dim txtString = "Hello World"
Dim halfLength = txtString.Length \ 2
Dim firstHalf = txtString.Substring(0, halfLength)
Dim secondHalf = txtString.Substring(halfLength)
Assuming the rules are "each side is half the length with the left side taking precedence", you would use Substring and some simple division:
Dim str As String = "william"
Dim part1 As String = str.Substring(0, CInt(Math.Ceiling(str.Length / 2.0#)))
Dim part2 As String = str.Substring(part1.Length)
part1 & " and " & part2 'will and iam
Here's a demo.
My code displays first half and last half of any number of characters entered.
Declare Variable
Dim strResults As String
Fetch text from textbox
strResults = Textbox1.Text
Display the first half of the text
MessageBox.Show(strResults.Substring(0, strResults.Length / 2), "First Half Characters")
Display the last half of the text
MessageBox.Show(strResults.Substring(strResults.Length / 2), "Last Half Characters")
Full code:
Dim strResults As String
strResults = Textbox1.Text
MessageBox.Show(strResults.Substring(0, strResults.Length / 2), "First Half Characters")
MessageBox.Show(strResults.Substring(strResults.Length / 2), "Last Half Characters")