I'm trying to create three columns based on date in seconds format.
My user.updated_at = 1521533490
I would like to get year, month and day separately and put these formatted values to columns for example:
year -> 2018, month -> 11, day -> 23
Does someone know how can I do that in pgSQL?
I would like to get year, month and day separately and put these formated values to columns
Don't do that.
Use a single column of type date or timestamp, depending on your application. Not every combination of your three columns will be a valid date. But every value in a single column of type date will be a valid date.
If you need the parts of a date separately, use PostgreSQL's date/time functions.
Try this approche to get differents arguments, then you can do whatever you want:
SELECT to_timestamp(1521533490); //2018-03-20T08:11:30.000Z
SELECT to_char(to_timestamp(1521533490), 'HH'); // 08 Hour
SELECT to_char(to_timestamp(1521533490), 'MI'); // 11 Minutes
SELECT to_char(to_timestamp(1521533490), 'SS'); // 30 Seconds
SELECT to_char(to_timestamp(1521533490), 'DD'); // 20 Day
SELECT to_char(to_timestamp(1521533490), 'Mon'); // MAR Month
SELECT to_char(to_timestamp(1521533490), 'YYYY'); // 2018 Year
Use the EXTRACT function.
SELECT to_timestamp(updated_at) "Date",
EXTRACT(YEAR FROM (to_timestamp(updated_at))) "Year",
EXTRACT(MONTH FROM (to_timestamp(updated_at))) "Month",
EXTRACT(DAY FROM (to_timestamp(updated_at))) "Day"
FROM users
Output
Date Year Month Day
2018-03-20T08:11:30Z 2018 3 20
SQL Fiddle: http://sqlfiddle.com/#!15/afe0e/15/0
More information on the EXTRACT function.
Related
I would like to select from a table where the date falls within a specific time each year f.e:
select * from Customer where date >= August 15th and date <= December 20th
Since this will be for a report that runs every year, I do not want to hardcore the date as I will have to change it every year. I would like to have it dynamic to pick the date from August 15th to December 20th of the current year.
I have the below query where I can retrieve the Month and Date:
SELECT DATENAME(month, date) AS Month,DATENAME(day, date) AS Day from Customer
However, I am struggling to have this selection date range.
TIA
In SQL SERVER 2017
maybe this can help you:
SELECT * FROM Customer WHERE date BETWEEN
CONVERT(DATETIME,CONCAT(YEAR(GETDATE()),'08','15')) AND
CONVERT(DATETIME,CONCAT(YEAR(GETDATE()),'12','20'))
This add the current year to a concatenated date you want, then convert it all into datetime type..
I have a date field in one of my tables and the column name is from_dt. Now I have to compare a month and year combination against this from_dt field and check whether the month has already passed. The current database function uses separate conditions for the month and the year, but this is wrong as it will compare month and year separately. The current code is like this
SELECT bill_rate, currency FROM table_name WHERE
emp_id = employee_id_param
AND EXTRACT(MONTH FROM from_dt) <= month_param
AND EXTRACT(YEAR FROM from_dt) <= year_param
Now the fromt_dt field has value 2021-10-11. If I give month_param as 01 and year_param as 2022, this condition will not work as the month 10 is greater than 1, which I have given. Basically, I need to check whether 01-2022 (Jan 2022) is greater than r equal to 2021-10-01(October 1st, 2021). It would be very much helpful if someone can shed some light here.
If you just want to check whether one date is >= then another:
# select '2022-01-01'::date >= '2021-10-11'::date;
?column?
----------
t
If you want to restrict to year/month then:
select date_trunc('month','2022-01-01'::date) >= date_trunc('month', '2021-10-11'::date);
?column?
----------
t
Where the date_trunc components are:
select date_trunc('month','2022-01-01'::date) ;
date_trunc
------------------------
2022-01-01 00:00:00-08
select date_trunc('month','2021-10-11'::date) ;
date_trunc
------------------------
2021-10-01 00:00:00-07
See Postgres date_trunc for more information.
Assuming the given year_param and month_param are integers you can use the make_date function to create the first of the year_month and date_trunc to get the first on the month from the table. Just compare those values. (See date functions) So:
select bill_rate, currency
from table_name
where emp_id = employee_id_param
and date_trunc('month',from_dt) =
make_date( year_param, month_param, 01);
I have to generate year wise, weekly reports for some data. Now When I aggregate date on week number, and week number is calculated from extract from creation date.
Now the problem is these both queries return week number 52.
SELECT EXTRACT(WEEK FROM TIMESTAMP '2006-01-01');
SELECT EXTRACT(WEEK FROM TIMESTAMP '2006-12-31');
First query return 52 (52nd week of 2005) and 2nd query return 52 (52nd week of year 2006). thats documented behavior.
But I want to Calculate local week number, and results for first query should be 1 and other query would return 53.
You can't do this with the exctract() function, it only supports ISO weeks.
But the to_char() function has an option for this:
SELECT to_char(DATE '2006-01-01', 'WW')::int` --> 1
SELECT to_char(DATE '2006-12-31', 'WW')::int` --> 53
For date 2006-01-01 end week is start in 2005 year, that same problem is 1999 year.
Clausule EXTRACT(WEEK getting year where week is started not ending.
You can use this code:
SELECT floor(EXTRACT(doy FROM TIMESTAMP '2006-01-01')/7 + 1);
SELECT floor(EXTRACT(doy FROM TIMESTAMP '2006-12-31')/7 + 1);
I have a date column in the format YY-MON-DD, e.g. 25-JUN-05. Is it possible to isolate this into 3 separate columns for year, month and day? Where month is converted from text to numerical, e.g. Year: 25, Month: 06, Day: 05?
MS SQL SERVER
As Nebi suggested, you can use DATEPART and extract each part and store it into different columns.
SELECT DATEPART(DAY,'2008-10-22'); -- Returns DAY part i.e 22
SELECT DATEPART(MONTH,'2008-10-22'); -- Returns MONTH part i.e 10
SELECT DATEPART(YEAR,'2008-10-22'); -- Returns YEAR part i.e 2008
Try with the below script,if you are using SQL Server.
SELECT 'Year: '+CAST(LEFT(YourdateColumn,2) as VARCHAR(2))+', Month: ' +CAST(MONTH('01-'+SUBSTRING(YourdateColumn,4,3)+'-15')as VARCHAR(2))+', Day:'+CAST(RIGHT(YourdateColumn,2)as VARCHAR(2))
FROM Yourtable
sample output :
You didn't specify your DBMS.
The following is standard SQL assuming that column really is a DATE column
select extract(year from the_column) as the_year,
extract(month from the_column) as the_month,
extract(day from the_column) as the_day
from the_table;
I have a query which uses needs to know how many days passed since 1st of January in the current year.
Which means that if the query runs for example in:
2nd Jan 2017 than it should return 2 (as 2 days passed since 1st Jan
2017).
10th Feb 2016 than it should return 41 (as 41 days passed since 1st
Jan 2016).
basically it needs to take Current Year from Curent Date and count the days since 1/1/(Year).
i have the current year with: SELECT EXTRACT(year FROM CURRENT_DATE);
I created the 1st of Jan with:
select (SELECT EXTRACT(year FROM CURRENT_DATE)::text || '-01-01')::date
How do I get the difference from this date to Current_Date?
Basically this question can be Given two dates, how many days between them?
Something like age(timestamp '2016-01-01', timestamp '2016-06-15') isn't good because I need the result only in days. while age gives in years,months and days.
An easier approach may be to extract the day of year ("doy") field from the date:
db=> SELECT EXTRACT(DOY FROM CURRENT_DATE);
date_part
-----------
41
And if you need it as a number, you could just cast it:
db=> SELECT EXTRACT(DOY FROM CURRENT_DATE)::int;
date_part
-----------
41
Note: The result 41 was produced by running the query today, February 9th.
Given two dates, how many days between them
Just subtract one from the other.
In your case you could just round the current_date to the start of the year and subtract that from the current date:
select current_date - date_trunc('year', current_date)::date
The ::date cast is necessary to get the result as an integer, otherwise the result will be an interval.
Another solution is to use DATEDIFF
SELECT DATE_PART('day', now()::timestamp - '2016-01-01 00:00:00'::timestamp);