I have to generate year wise, weekly reports for some data. Now When I aggregate date on week number, and week number is calculated from extract from creation date.
Now the problem is these both queries return week number 52.
SELECT EXTRACT(WEEK FROM TIMESTAMP '2006-01-01');
SELECT EXTRACT(WEEK FROM TIMESTAMP '2006-12-31');
First query return 52 (52nd week of 2005) and 2nd query return 52 (52nd week of year 2006). thats documented behavior.
But I want to Calculate local week number, and results for first query should be 1 and other query would return 53.
You can't do this with the exctract() function, it only supports ISO weeks.
But the to_char() function has an option for this:
SELECT to_char(DATE '2006-01-01', 'WW')::int` --> 1
SELECT to_char(DATE '2006-12-31', 'WW')::int` --> 53
For date 2006-01-01 end week is start in 2005 year, that same problem is 1999 year.
Clausule EXTRACT(WEEK getting year where week is started not ending.
You can use this code:
SELECT floor(EXTRACT(doy FROM TIMESTAMP '2006-01-01')/7 + 1);
SELECT floor(EXTRACT(doy FROM TIMESTAMP '2006-12-31')/7 + 1);
Related
I google data studio, I have a field called week that contains the week number the value is string 'Week 2' for example. How can I extract the last day of the week based on the week number. In this case I want to get 2023-01-14 which is the last day of week 2?
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Have you tried the last_day function?
I would build from the using the date using last_day, because from the week number it would require a bit more code.
SELECT *,
LAST_DAY(today, WEEK) AS last_day_of_week,
EXTRACT(WEEK FROM today) AS week_number
FROM (SELECT CURRENT_DATE() AS today)
But if you need to go with just the week number, I recommend taking a look into this other question How to create date based on year, week number and day in bigquery .
The following code works:
DATEtime_ADD(DATEtime_TRUNC(DATEtime_ADD(DATEtime_TRUNC(date, WEEK), INTERVAL (week-1) * 1 DAY), WEEK), INTERVAL 6 DAY)
Could anyone provide a code to calculate week no from current date in current quarter? E.g. today is Oct 6 2022, it lies in quarter 4, so week no is 1. Code should be in big query sql.
Considering 13 weeks per quarter and using ISO week number, you can try this:
SELECT EXTRACT(ISOWEEK FROM CURRENT_DATE()) - (13 * (EXTRACT(QUARTER FROM CURRENT_DATE())-1))
Output:
1
I have a revenue table with data for last year and current year. I need to calculate the YTD last year and YTD current year, BUT I need to only consider data from min(date) from last year PER branch for current year YTD calculation.
eg: Branch KTM has data from 2018-02-25 not from Jan 1st.
Now I want to get YTD for the current year from the same date on 2019 till today.
I am able to get whole YTD for last year and this year, and also the minimum date/weeknumber for each branch for last year, but unable to calculated partial YTD for the current year.
Here is one drive link to mydata and sql : https://1drv.ms/u/s!Ave_-9o8DQVEgRS7FaJmm48UNsWz?e=lRfOJF
A snippet from my code
I need help with the SQL query to do this.
This returns the number of days between the same day-of-year of a last year's date and today's date:
select current_date - (date'2018-02-25' + interval '1' year); -- PostgreSQL
select datediff(current_date, (date'2018-02-25' + interval '1' year)); -- MySQL
Alternative version:
select extract(doy from current_date) - extract(doy from date'2018-02-25'); -- PostgreSQL
doy stands for day of year. At the time of the answer (2019-09-24) all queries return 211.
To sum values in that date range, use BETWEEN:
SELECT sum(revenue)
FROM your_table
WHERE date BETWEEN date'2018-02-25' + interval '1' year AND current_date
select datepart(year, '2017/08/25') as week;
I believe this is for mysql but does not work for oracle sql
Week of year (1-53) where week 1 starts on the first day of the year and continues to the seventh day of the year.
select to_char(trunc(sysdate),'WW') from dual;
Week of year (1-52 or 1-53) based on the ISO standard.
select to_char(trunc(sysdate),'IW') from dual;
Taken from Oracle docs
I want to calculate Last Week Number of Month in SQL. I am having Week Number and Year.
Eg. If I pass WeekNo=51 , Year=2008 , than function should return LastWeekofMonth= 52.
I want to calculate Week number using below standards.
According to ISO 8601:1988 that is used in Sweden the first week of the year is the first week that has at least four days within the new year.
So if your week starts on a Monday the first Thursday any year is within the first week. You can DateAdd or DateDiff from that.
Please Help me..........
Thanks in advance.
SELECT WEEK(LAST_DAY(STR_TO_DATE('2008-51-Mon', '%x-%v-%a')));
Should do the trick for getting the last week number of month with MySQL :
I first convert to a date, then I get the last day of the month (here: 2008-12-31), then I compute the week of the last day of the month (52).
It should be easy to turn it into a function.
Hope this helps.
This is fairly straightforward if you use a calendar table. The month you need is given by this query.
select iso_year, month_of_year
from calendar c
where iso_year = 2008 and iso_week = 51
group by iso_year, month_of_year
--
iso_year month_of_year
2008 12
So you can use that result in a join on the calendar table, like this.
select max(c.iso_week) as last_week_of_month
from calendar c
inner join
(select iso_year, month_of_year
from calendar c
where iso_year = 2008 and iso_week = 51
group by iso_year, month_of_year) m
on m.iso_year = c.iso_year and m.month_of_year = c.month_of_year;
--
last_week_of_month
52
Here's one example of a calendar table, but it's pretty thin on CHECK constraints.
If you're using SQL Server, you can perform a calculation by using a master table, without creating a calendar table. This fellow gives you a very good explanation, which I recommend that you read. His SQL for calculating the first and last Sundays of each month can be adapted for your use:
declare #year int
set #year =2011
select min(dates) as first_sunday,max(dates) as last_sunday from
(
select dateadd(day,number-1,DATEADD(year,#year-1900,0))
as dates from master..spt_values
where type='p' and number between 1 and
DATEDIFF(day,DATEADD(year,#year-1900,0),DATEADD(year,#year-1900+1,0))
) as t
where DATENAME(weekday,dates)='sunday'
group by DATEADD(month,datediff(month,0,dates),0)
Edit: Once you have the date of the Thursday, you can get the week number from that date like this:
DECLARE #Dt datetime
SELECT #Dt='02-21-2008'
SELECT DATEPART( wk, #Dt)