I have a column called cost_calc_date of type Date in my database table named as account.
The value in a particular cell is 2018-03-20 which is in YYYY-MM-DD format. I need to return only the month, that is 03 as the output.
Please let me know how I can achieve this.
You can try the following code:
SELECT MONTH(cost_calc_date) as 'Month'
FROM account
Or this code:
SELECT DATEPART(month, cost_calc_date) AS 'Month'
from account;
You can use extract() to get parts of a date (or timestamp) column.
To get the month, use:
extract(month from cost_calc_date);
This will return a number, e.g. 3
select datepart(mm,cost_calc_date) from account
Related
I am trying to extract the month from the the Order_date column by using postgres SQL , and the format is required to come in the name of the month format ;for example, December.
When I applied the extract function , It gave me an error message saying that the date setting has to be changed.
Please advise how to extract the month from the mentioned column ?
The data has been enclosed
SELECT EXTRACT(MONTH FROM order_date::date)
FROm think_sales;
The error message :
[22008] ERROR: date/time field value out of range: "25/06/2021" Hint: Perhaps you need a different "datestyle" setting.
Data :
You may need to define your date format using the to_date function:
select to_char(to_date('25/06/2021', 'dd/mm/yyyy'), 'Month');
Output: June
In your case, you would use:
select to_char(to_date(order_date, 'dd/mm/yyyy'), 'Month');
This work for me:
SELECT EXTRACT(MONTH FROM TIMESTAMP '25/06/2021');
https://www.postgresqltutorial.com/postgresql-date-functions/postgresql-extract/
set date format to dmy (day - month - year )
SET datestyle = dmy;
This answer
I have a table with column DATE. Date is 'dd/mm/yyyy' and I want only days. So I try with extract and return what I need, but I what using transpose for column to row.
The select statement is:
select EXTRACT (DAY FROM "DATE") DAY
from people;
Is this thing possible?
Thank you!
If you have a string, then just use the leftmost two characters:
select substr("DATE", 1, 2) as day
That said, you should not be storing dates as strings. It is wrong, wrong, wrong. You cannot use the built-in date/time functions. You cannot use inequality comparisons either. Fix your data model.
The date format doesn't matter. It is linked to your NLS local settings and this is how you see this.
To have it generic and extract DAY from the date do this:
select to_char(sysdate, 'DD') from dual;
Would return 07 since it's September 7th 2020.
I have teradata scripts
AND ADD_MONTHS('?StartDate',1)-1 BETWEEN A.CNTSTRT_DT AND COALESCE(A.CNTEND_DT, DATE)
This script looks like it prompts for a date, then adds one month to that date. But I'm not clear on what the -1 does.
Additionally, I see that it compares the date to see if they are between the CNTSTRT_DT and CNTEND_DT, but what does the DATE do specifically?
The -1 is to substruct one day, for example the query:
select ADD_MONTHS(cast('2016/01/25' as date),1)-1
returns: 24/02/2016
Also, "Date" is a function which returns current date.
What I'm trying to achieve is fairly straight forward, to get one date format to another;
From This: Jan 30 2013 12:00:00:000AM
To This: DD/MM/YYYY or in this case 30/01/2013
However, when it's the 1st to the 9th of the month the date format is missing a zero and there is two spaces, as shown;
Jul 3 2014 12:00:00:000AM
I've hunted round for a solution but without success, the format of the date is unusual and varies depending on the day of the month however this format is generated by an internal system and can't be changed. Would I then have to pattern match in order to change the format? How would I go about doing this?
An example of part of the query is this;
SELECT
PREFIX_TableName.ColumnName1 AS Name,
PREFIX_TableName.ColumnName2 AS E-Mail,
PREFIX_TableName.ColumnName3 AS TransactionDate,
PREFIX_TableName.ColumnName4 AS OrderNumber,
...
The line to be edited is this PREFIX_TableName.ColumnName3 AS TransactionDate,
If DB is SQL Server then
select Convert(varchar(10),CONVERT(date,YourDateColumn,106),103)
If I understood your question, try something like this
declare #dd varchar(50)='Jan 30 2013 12:00:00:000AM'
Select convert(varchar,(CONVERT(date,#dd,103)),103)
Update
SELECT
PREFIX_TableName.ColumnName1 AS Name,
PREFIX_TableName.ColumnName2 AS E-Mail,
convert(varchar,(CONVERT(date,PREFIX_TableName.ColumnName3,103)),103) AS TransactionDate,
PREFIX_TableName.ColumnName4 AS OrderNumber
If you have a Date (or Datetime) column, look at http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
SELECT DATE_FORMAT(datecolumn,'%d/%m/%Y') FROM ...
Should do the job for MySQL, for SqlServer I'm sure there is an analog function.
If you have a VARCHAR column, you might have at first to convert it to a date, see STR_TO_DATE for MySQL.
SELECT CONVERT(varchar(11),Getdate(),105)
Try http://www.sql-server-helper.com/tips/date-formats.aspx. Lists all formats needed.
In this case select Convert(varchar(10),CONVERT(date,YourDateColumn,106),103)
change 103 to 104 id you need dd.mm.yyyy
I have a column named DC34_DATE of type DATE (defined this way: DATE '2013-04-17'). I need to select all rows for a specific month (for example April). I have used WHERE MONTH(DC34_DATE)=04; but it doesn't work.
You can use the extract from date function to get the date. Try this.
WHERE EXTRACT(month from DC34_DATE) = '4';
select yourColumns
from yourTable
where datepart(month,yourDateColumn)=4
TSQL solution..don't know which dialect you're using.