Scenario:
open "google.co.in".
click in the search input box.
type something.
click Enter.
get the text of all links.
The xpaths of some links are:
.//*[#id='rso']/div[2]/div/div[2]/div/div/h3/a
.//*[#id='rso']/div[2]/div/div[3]/div/div/h3/a
.//*[#id='rso']/div[2]/div/div[4]/div/div/h3/a
.//*[#id='rso']/div[2]/div/div[5]/div/div/h3/a
.//*[#id='rso']/div[2]/div/div[6]/div/div/h3/a
All the xpaths have the same pattern. the third div needs to be incremented by 1 to get the next xpath. I've read somewhere that in the scenarios like this generic xpath can be used. According to his suggestion, the xpath will be ".//*[#id='rso']/div[2]/div/div/div/div/h3/a". just removed the predicate of the third div. This is not working. Is this the way to locate elements?
You can try below XPath to fetch all result links:
//div[#class="g"]//h3/a
If you want to avoid links from "People also ask" block:
//div[#class="g"]//h3/a[not(ancestor::div[#class="_OKe"])]
Related
im trying to find an element with dinamic values , for example <span class="ms-Button-label label-175" id="id__177">Save</span> in inspect element, the id and class values tend to change for every refresh, how can i in this case find the element in selenium? i tried troguht xpath but seems doesnt work because can not find the path, i was thinking to find "Save" world torught always find by xpath but actually i dont know if im doing well : driver.find_element_by_xpath(//span(#.... but then? how can insert element if it changes everytime? thanks!
Something like this may work:
driver.find_element_by_xpath('//span[text()="Save"]')
But this will fail, if there is more than one button with text "Save" on the page.
In that case you may try to find some specific outer element (div, form, etc.) which does not change and contains the button. Then find the button inside of it.
With few requests with driver:
specific_div = driver.find_element_by_id("my_specific_div")
button = specific_div.find_element_by_tag_name("span") # e.g. there is only one span in that div
Or with more specific xpath:
button = driver.find_element_by_xpath('//div[#class="some-specific-class"]/span[text()="Save"]')
If needed, search for more nested elements before the button, so you can get more narrow search field.
More examples in the docs.
I am not able locate a webelement, this web application opens in Internet explorer only and I have used all the possible ways to click but no luck.
Xpath locators that I have tried :
"//form[#id='Form1']//a[contains(text(),'Age Range')]"
and
"//form[#id='Form1']//a[#id='rptTables1_ctl07_hlTablename1']"
also I have tried click on the element using action class and javascript as well.
Attached DOM in the URL, please have a look here
In the node a, id value is not static so you can't locate that element using the id value but you can use partial id value for example, looks like rptTables1_ is unique in id value and the remaining part is changing so applying contains() on this may works.
Try the below xpath if there is only match :
//a[contains(#id, 'rptTables1_')]
Try the below xpath by providing the matching index if there are multiple xpath matches :
(//a[contains(#id, 'rptTables1_')])[Matching index number]
for example if the matching index is 3 then you can write like this (//a[contains(#id, 'rptTables1_')])[3].
Or you can use the Advanced Performance Parameters Panel Topics text to identify that element.
//a[contains(text(), 'Advanced Performance Parameters Panel Topics')]
Again if there are multiple matches then try to use indexing method as mentioned above.
Or you can try the below modified your xpaths :
//form[#id='Form1']//a[contains(#id, 'rptTables1_')]
or
(//form[#id='Form1']//a[contains(#id, 'rptTables1_')])[Matching index number]
or
//form[#id='Form1']//a[contains(text(), 'Advanced Performance Parameters Panel Topics')]
I hope it helps...
I haven't tried any automation in IE at all but in firefox, sometimes I encounter those issues and my work around other than the .click() function is send_keys(Keys.RETURN). Also, i'm using time.sleep(x) before clicking or sending keys to make sure the element has been loaded.
I want to use XPath to locate a link behind a text.
I want to use XPath to locate a link behind a text. For example, locate "one4" by "what10". You can only use the text message "what10", but you can't use it in any other way, because the information on this page will change. I want to get is the "one4" link node.
<body>
<p>
so
<br>what1 one
<br>what2two
<br>what11one4
<br>what3three
<br>what4one1
<br>what5two2
<br>what6three3
<br>what7one3
<br>what8two3
<br>what9three3
<br>what10one4
<br>just return
<br></p>
</body>
For some special reasons, what I want to pass is that the text of what10 is positioned to one4.
Please help me.
You can use below line
WebElement loginLink = driver.findElement(By.linkText("one4"));
Selenium doesn't supports xpath-2.0 but uses xpath-1.0
The element which you are trying to refer i.e. which contains the text what10 is a Text Node and Selenium can't use it as a reference. So finding the node with text as one4 with reference to the text what10 won't be possible. As an alternative if the desired node is always the last but one node you can use the following solution:
xpath:
driver.findElement(By.xpath("//body/p//a[position()=last()-1]"));
Update
As per #MosheSlavin counter question here is the snapshot to demonstrate that the XPath works perfecto:
There are many span tags as mentioned in the image below and each has its own a-tag with unique id as "chooseitem". I need to choose particular a tag using names in the span tags.
Need to click the a-tag button using the text Mayo Chicken from the above HTML snippet in the image.
I have tried the below Selenium script
WebElement select = driver.findElement(By.xpath("//*[contains(text(),'Mayo Chicken (Single)')]"));
WebElement add = select.findElement(By.id("chooseitem"));
It doesn't work for me.
driver.findElement(By.id("chooseitem"));
The above code chooses the first item in the page by default as its id is also 'chooseitem', but need to define what to be chosen.
Can anybody help me out?
We need to get the common parent(ancestor) element of the chicked and the clickable 'a' tag, then we can navigate to the tag 'a'. Below xpath should ideally work.
"//span[contains(text(),'Mayo chicken')]/ancestor::div[4]//a"
Note: Here i have used div[4] because fourth parent is the common ancestor for 'Mayo chicken' and tag 'a'.
For more details about different xpath axis refer this->https://www.w3schools.com/xml/xpath_axes.asp
Hope this helps you. thanks.
You can do that by using the xpath position, press F12 for developer tools click on "Select element button", click the element that interests you on the page, as in your picture you will see one or more lines highlighted, right click the line -> Copy -> Copy xpath. You will have something like the line below:
//*[#id="comment-76500216"]/td[2]/div/span[1]
The xpath position will be:
//td[2]/div/span[1]
You can use that when you have multiple elements that share the name or id or so on.
And you will have:
WebElement select = driver.findElement(By.xpath("//td[2]/div/span[1]"));
PS: I used google chrome
When we use selenium command at that time command not find and attribute not get? See below command.
<table>
<tr><td>open</td><td>http://www.wikipedia.org/</td><td></td></tr>
<tr><td>verifyAttribute</td><td>css=input#searchInput</td><td>(Search Input)</td></tr>
<tr><td>assertAttribute</td><td>css=input#searchInput</td><td>(Search Input)</td></tr>
<tr><td>verifyAttribute</td><td>css=input#searchInput</td><td>language</td></tr>
<tr><td>verifyAttribute</td><td>xpath=//div[2]#class central-featured</td><td>central-featured</td></tr>
<tr><td>verifyAttribute</td><td>xpath=//div[2]#class central-featured</td><td>search1</td></tr>
<tr><td>assertAttribute</td><td>xpath=//div[2]#class central-featured</td><td>central-featured</td></tr>
</table>
I am using Selenium IDE 2.5.0 in Mozilla Firefox and Ubuntu.
Xpath //div[2]#class central-featured is invalid. Try changing it to //div[#class='central-featured']/#class if you mean to select a class.
You could also use assertElementPresent function instead of selecting attribute, if the whole point is to check that element exists, i.e.:
<tr><td>assertElementPresent</td><td>xpath=//div[#class='central-featured']</td><td></td></tr>
Much simpler that way.
Use xPaths in this case.
Use google chrome's built in developer tool for this
Place your cursor on the element
Press Ctrl+Shift+C
Click the Element
That clicked Element's code is highlighted in the short window on the bottom
Right-Click on highlighted code
Select Copy > Copy XPath
Here it is you have copied the xPath for that specific element. This is shown in the image:
Click to see how to copy xPath
The Xpath you have used in Invalid.
You can use xpath as follows and through this you can fins xpath of any object - just need to study the concept:
Here as we can see we want to search Google Search just by writing its xpath in console
So to find the Google Search button we have to write xpath like this
//span[#id='gbqfsa']
Once we hit enter it would bring
[ gbqfsa">Google Search ],
It shows that xpath for Google Search Button is correctly written
Now suppose we want to search Google Search button if we are just familiar that id attributes start with gbqfs
then we have to use function starts-with like this
//span[starts-with(#id,'gbqfs')]
and once when we hit enter on console it would reflect two button one is Google Searchand Second one is I’m Feeling Lucky
[
gbqfsa">Google Search
,
I'm Feeling Lucky
]
So to find out the Google Search uniquely we need to complete id attribute to gbqfsa
“//span[starts-with(#id,'gbqfsa')]
and hit to enter and now it would reflect only
[
Google Search
],
It proves that we have written right xpath for Google Search
In the same fashion we can use Contains function to find the Google Search button like this
here I have taken fsa from gbqfsa
//span[contains(#id,'fsa')]
hit enter and hopefully it will return
[
Google Search
],
if there are multiple attributes then we can use:
//span[contains(#id,'fsa') and contains(#class, 'xyz')] hit enter and hopefully it will return
Information Source: Sumit Mittal Blog
You can use CssSelector as below
webDriver.findElements(By.cssSelector("div.central-featured")) // for more than 1 elements with same class
webDriver.findElement(By.cssSelector("div.central-featured")) // for 1 element