For each row, I need to calculate the integer part from dividing by 4. For each subsequent row, we add the remainder of the division by 4 previous and current lines and look at the whole part and the remainders from dividing by 4. Consider the example below:
id val
1 22
2 1
3 1
4 2
5 1
6 6
7 1
After dividing by 4, we look at the whole part and the remainders. For each id we add up the accumulated points until they are divided by 4:
id val wh1 rem1 wh2 rem2 RESULT(wh1+wh2)
1 22 5 2 0 2 5
2 1 0 1 (3/4=0) 3%4=3 0
3 1 0 1 (4/4=1) 4%4=0 1
4 2 0 2 (2/4=0) 2%4=2 0
5 1 0 1 (3/4=0) 3%4=3 0
6 7 1 2 (5/4=1) 5%4=1 2
7 1 0 1 (2/4=0) 2%4=1 0
How can I get the next RESULT column with sql?
Data of project:
http://sqlfiddle.com/#!18/9e18f/2
The whole part from the division into 4 is easy, the problem is to calculate the accumulated remains for each id, and to calculate which of them will also be divided into 4
Related
Having df of probabilities distribution, I get max probability for rows with df.idxmax(axis=1) like this:
df['1k-th'] = df.idxmax(axis=1)
and get the following result:
(scroll the tables to the right if you can not see all the columns)
0 1 2 3 4 5 6 1k-th
0 0.114869 0.020708 0.025587 0.028741 0.031257 0.031619 0.747219 6
1 0.020206 0.012710 0.010341 0.012196 0.812495 0.113863 0.018190 4
2 0.023585 0.735475 0.091795 0.021683 0.027581 0.054217 0.045664 1
3 0.009834 0.009175 0.013165 0.016014 0.015507 0.899115 0.037190 5
4 0.023357 0.736059 0.088721 0.021626 0.027341 0.056289 0.046607 1
the question is how to get the 2-th, 3th, etc probabilities, so that I get the following result?:
0 1 2 3 4 5 6 1k-th 2-th
0 0.114869 0.020708 0.025587 0.028741 0.031257 0.031619 0.747219 6 0
1 0.020206 0.012710 0.010341 0.012196 0.812495 0.113863 0.018190 4 3
2 0.023585 0.735475 0.091795 0.021683 0.027581 0.054217 0.045664 1 4
3 0.009834 0.009175 0.013165 0.016014 0.015507 0.899115 0.037190 5 4
4 0.023357 0.736059 0.088721 0.021626 0.027341 0.056289 0.046607 1 2
Thank you!
My own solution is not the prettiest, but does it's job and works fast:
for i in range(7):
p[f'{i}k'] = p[[0,1,2,3,4,5,6]].idxmax(axis=1)
p[f'{i}k_v'] = p[[0,1,2,3,4,5,6]].max(axis=1)
for x in range(7):
p[x] = np.where(p[x]==p[f'{i}k_v'], np.nan, p[x])
The loop does:
finds the largest value and it's column index
drops the found value (sets to nan)
again
finds the 2nd largest value
drops the found value
etc ...
I have a view with Columns:
WeekNo, MerchantId, Transactions
With a Select Query let's say that we have the following results:
TrnWeek AgencyId WeeklyTrn
1 110008 1
2 110008 2
3 110008 2
1 110045 4
3 110065 4
3 110124 1
1 110153 1
1 110155 3
2 110163 1
2 110165 1
making a pivot (stored procedure which creates dynamically the columns) i get the TrnWeek as Columns and as a result the following:
[1] [2] [3]
1 1 1
1 0 0
1 0 0
1 0 0
0 1 1
0 1 0
0 0 1
what I want to get is a "matrix" as follows:
TrnWeek 1 2 3
1 4 1 1
2 0 2 1
3 0 0 1
ih which i calculate how many merchants performed a transaction in the first week (position: 1,1), how many of them performed a transaction in the second one (position: 1,2), how many performed their first transaction in 2nd week (position: 2,2) etc.
I am creating an excel sheet that has three columns. Detail, month and month count
1 -- I would like for the formula to look at the detail column and if there is text add the previous cell number plus 1 to new month count, if not insert 0
2-- I would like the formula to add the previous cell before the cell with 0 and for the cell with 0 not to impact the other cells or reset the cells back to 1 witch is the problem am having
3-- I also need the formula to reset for every month from what ever number it was back to 0 or 1 depending if the new month first cell has text or not. for this I need the formula to look at the month column
This is what I have so far:
=IF(ISTEXT(G95), I94+ 1, 0)
The formula for the count column should be as follows.
=IF(A2<>"",COUNTIF($B$1:B2,B2)-COUNTIFS($A$1:A2,"",$B$1:B2,B2),0)
Breakdown of how this works:
A2<>"" Will check if the detail column is populated
COUNTIF($B$1:B2,B2) will figure out how many entries are above this row that reference the same month.
COUNTIFS($A$1:A2,"",$B$1:B2,B2) Will find how many cells are blank provided that it also matches the month. This subtracted from the previous section gives you how many are not blank.
The IF will return 0 if the detail is empty.
Which returned the following data
Orderly Random
Det Mon Count Det Mon Count
X 1 1 2 0
X 1 2 X 1 1
X 1 3 X 1 2
1 0 2 0
X 1 4 X 2 1
X 2 1 X 1 3
X 2 2 X 1 4
2 0 1 0
2 0 1 0
2 0 2 0
3 0 3 0
X 3 1 X 3 1
3 0 1 0
X 3 2 3 0
X 3 3 X 1 5
3 0 X 2 2
X 3 4 X 3 2
3 0 3 0
X 3 5 3 0
X 3 6 2 0
It sounds like you want to keep a running total for the month count in the column and put a 0 if there is not text. If that is the case, you can put this formula in I95.
=IF(ISTEXT(G95),MAX($I$2:I94)+1, 0)
I have 1 Virtual cube consists of 2 cubes.
Example of fact table of 1st cube.
id object_id time_id date_id state
1 10 2 1 0
2 11 5 1 0
3 10 7 1 1
4 10 3 1 0
5 11 4 1 0
6 11 7 1 1
7 10 8 1 0
8 11 5 1 0
9 10 7 1 1
10 10 9 1 2
Where State: 0 - Ok, 1 - Down, 2 - Unknown
For this cube I have one measure StateCount it should count States for each object_id.
Here for example we have such result:
for 10 : 3 times Ok , 2 times Down, 1 time Unknown
for 11 : 3 times Ok , 1 time Down
Second cube looks like this:
id object_id time_id date_id status
1 10 2 1 0
2 11 5 1 0
3 10 7 1 1
4 10 3 1 1
5 11 4 1 1
Where Status: 0 - out, 1 - in. I keep this in StatusDim.
In this table I keep records that should not be count. If object have status 1 that means that I have exclude it from count.
If we intersect these tables and use StateCount we will receive this result:
for 10 : 2 times Ok , 1 times Down, 1 time Unknown
for 11 : 2 times Ok , 1 time Down
As far as i know, i must use calculated member with IIF condition. Currently I'm trying something like this.
WITH MEMBER [Measures].[StateTimeCountDown] AS(
iif(
[StatusDimDown.DowntimeHierarchy].[DowntimeStatus].CurrentMember.MemberValue
<> "in"
, [Measures].[StateTimeCount]
, null )
)
The multidimensional way to do this would be to make attributes from your state and status columns (hopefully with user understandable members, i. e. using "Ok" and not "0"). Then, you can just use a normal count measure on the fact tables, and slice by these attributes. No need for complex calculation definitions.
I have two columns of integers between 1 and 16 in an excel file. I'd like to count the number of pairs of integers in these columns. There are 256 cases and I'd like to have a column which tells me how many pairs exist for each case. For instance, I have a table like below:
1 2
1 1
1 3
1 4
1 1
1 8
1 1
16 16
1 2
...
And I'd like to calculate a column like this:
3 (number of 1 1s)
2 (number of 1 2s)
1 (number of 1 3s)
1 (number of 1 4s)
0 (number of 1 5s)
0 (number of 1 6s)
0 (number of 1 7s)
1 (number of 1 8s)
...
1 (number of 16 16s)
I'd appreciate if someone can help me with the calculation.
First you need to create two columns with all possible combinations:
1 1
1 2
1 3
...
2 1
2 2
...
16 16
Let's assume these are in columns C,D and your data are in columns A, B, in rows 1 to 1000. Then you can use an array formula:
=SUM(IF(($A$1:$A$1000=C1)*($B$1:$B$1000=D1);1;0))
You must press Shift+Ctrl+Enter when entering array formula.