Calculate the sum of the digits using python [duplicate] - sum

Question

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Competitive Programming Python: Repeated sum of digits Error
(1 answer)
Closed 5 years ago.
I would like to find the sum of the digits using python. when i enter a birth year 1982 the result should be 1+9+8+2 = 20 final total result is 2+0 = 2.
The reason that i am posting this question is i didn't find any simple python solution for this.
This is my code
num = int(input("Enter your birth year: "))
x = num //1000
x1 = (num - x*1000)//100
x2 = (num - x*1000 - x1*100)//10
x3 = num - x*1000 - x1*100 - x2*10
x4 = x+x1+x2+x3
num2 = int(x4)
x6 = num2 //10
x7 = (num2 -x6)//10
print("your birth number is" ,x6+x7)
but i am not getting the correct sum value.

Answer 1

Sum the digits of an integer until the result is a one-digit integer:
def sum_digits(num):
num = str(num)
if len(num) < 2:
return int(num)
else:
return sum_digits(sum([int(dig) for dig in str(num)]))
>> sum_digits(1982)
2
Or a simpler version for the case your number is a year:
def sum_digits(num):
return sum([int(dig) for dig in str(num)])
Just call the function twice
>> sum_digits(sum_digits(1982))
2

Answer 2

Try adding some debug statements to inspect values as your program runs.
num = int(input("Enter your birth year: "))
x = num //1000
x1 = (num - x*1000)//100
x2 = (num - x*1000 - x1*100)//10
x3 = num - x*1000 - x1*100 - x2*10
print (x, x1, x2, x3)
x4 = x+x1+x2+x3
print (x4)
num2 = int(x4)
x6 = num2 //10
x7 = (num2 -x6)//10
print (x6, x7)
print("your birth number is" ,x6+x7)
You'll quickly find your problem.