Please consider the below Repair_Table of a car-repair workshop.
I'm trying to get the last "Repair_Status" value for each car within a given day.
"Repair_Update" column will have a new entry for each change during the car repair process: like the repair status, the repair name or the repair team and repair sub-task which are stored in a different table..
I tried this query but it's not giving me what I need:
select distinct(Car_ID), Repair_Status
from Repair_Table r1
left join (select Car_ID, max(Repair_Update) from Repair_Table
group by Car_ID) r2
on r2.Repair_Update = r1.Repair_Update
where convert(date,Repair_Start) = '20180122'
Window functions are an easy way to do this:
select rt.*
from (select rt.*,
row_number() over (partition by car_id, cast(repair_update as date)
order by repair_update desc
) as seqnum
from Repair_Table rt
where convert(date, Repair_Start) = '20180122'
) rt
where seqnum = 1;
You can remove the where clause if you want this information on multiple dates -- or even on all dates.
Using row_number() function:
select Car_ID, Repair_Status
from (
select Car_ID, Repair_Status
row_number() over (partition by Car_ID order by Repair_Update desc) as rnk
from Repair_Table
) t
where t.rnk = 1
Related
select * from
(select Id, Prodcut, Billing_date
, row_number() over (partition by Id, product order by Billing_date desc) as RowNumber
,sum(Revenue)
from Table1
group by 1,2,3,4,1) a
where a.rowNumber = 1
There are rows where Id+product combination repeats for latest billing date and which causing some data to be missed out. I am trying to add sum with row_number to sum all the ID&product combinations for the latest date but not able to make it work.
Can anyone please help me out here!
Data Sample Image
Database: Athena, Dbeaver
I would expect this to do what you want:
select *
from (select Id, Product, Billing_date,
row_number() over (partition by Id, product order by Billing_date desc) as seqnum,
sum(Revenue)
from Table1
group by Id, Product, Billing_date
) t1
where seqnum = 1;
Your group by columns do not seem correct. I'm surprised your query runs in any datbase.
I need to select the data of all my customers with the records displayed in the image. But I need to get the most recent record only, for example I need to get the order # E987 for John and E888 for Adam. As you can see from the example, when I do the select statement, I get all the order records.
You don't mention the specific database, so I'll answer with a generic solution.
You can do:
select *
from (
select t.*,
row_number() over(partition by name order by order_date desc) as rn
from t
) x
where rn = 1
You can use analytical function row_number.
Select * from
(Select t.*,
Row_number() over (partition by customer_id order by order_date desc) as rn
From your_table t) t
Where rn = 1
Or you can use not exists as follows:
Select *
From yoir_table t
Where not exists
(Select 1 from your_table tt
Where t.customer_id = tt.custome_id
And tt.order_date > t.order_date)
You can do it with a subquery that finds the last order date.
SELECT t.*
FROM yoir_table t
JOIN (SELECT tt.custome_id,
MAX(tt.order_date) MaxOrderDate
FROM yoir_table tt
GROUP BY tt.custome_id) AS tt
ON t.custome_id = tt.custome_id
AND t.order_date = tt.MaxOrderDate
Example query:
SELECT *,
lag(sum(sales), 1) OVER(PARTITION BY department
ORDER BY date ASC) AS end_date_sales
FROM revenue
GROUP BY department, date;
I want to show only the rows where end_date is not NULL.
Is there a clause used specifically for these cases? WHERE or HAVING does not allow aggregate or window function cases.
One method uses a subquery:
SELECT r.*
FROM (SELECT r. *,
LAG(sum(sales), 1) OVER (ORDER BY date ASC) AS end_date
FROM revenue r
) r
WHERE end_date IS NOT NULL;
That said, I don't think the query is correct as you have written it. I would assume that you want something like this:
SELECT r.*
FROM (SELECT r. *,
LEAD(end_date, 1) OVER (PARTITION BY ? ORDER BY date ASC) AS end_date
FROM revenue r
) r
WHERE end_date IS NOT NULL;
Where ? is a column such as the customer id.
Try this
select * from (select distinct *,SUM(sales) OVER (PARTITION BY dept) from test)t
where t.date in(select max(date) from test group by dept)
order by date,dept;
And one more simpler way without sub query
SELECT distinct dept,MAX(date) OVER (PARTITION BY dept),
SUM(sales) OVER (PARTITION BY dept)
FROM test;
I have tried many solutions and nothing seems to work. I am trying to return the MAX status date for a project. If that project has multiple items on the same date, then I need to return the MAX ID. So far I have tried this:
SELECT PRJSTAT_ID, PRJSTAT_PRJA_ID, PRJSTAT_STATUS, PRJSTAT_DATE
From Project_Status
JOIN
(SELECT MAX(PRJSTAT_PRJA_ID) as MaxID, MAX(PRJSTAT_DATE) as MaxDate
FROM Project_Status
Group by PRJSTAT_PRJA_ID)
On
PRJSTAT_PRJA_ID = MaxID and PRJSTAT_DATE = MaxDate
Order by PRJSTAT_PRJA_ID
It returns the following:
I am getting multiple records for PRJSTAT_PRJA_ID, but I only want to return the row with the MAX PRJSTAT_ID. Any thoughts?
Take out the MAX on the ID on the subquery:
SELECT PRJSTAT_ID, PRJSTAT_PRJA_ID, PRJSTAT_STATUS, PRJSTAT_DATE
From Project_Status
JOIN
(SELECT PRJSTAT_PRJA_ID as ID, MAX(PRJSTAT_DATE) as MaxDate
FROM Project_Status
Group by PRJSTAT_PRJA_ID)
On
PRJSTAT_PRJA_ID = ID and PRJSTAT_DATE = MaxDate
Order by PRJSTAT_PRJA_ID
Or remove the need to join:
SELECT * FROM
(SELECT PRJSTAT_ID, PRJSTAT_PRJA_ID, PRJSTAT_STATUS, PRJSTAT_DATE,
ROW_NUMBER() OVER (PARTITION BY PRJSTAT_PRJA_ID ORDER BY PRJSTAT_DATE DESC)
AS SEQ,
ROW_NUMBER() OVER (PARTITION BY PRJSTAT_PRJA_ID ORDER BY PRJSTAT_PRJA_ID
DESC) AS IDSEQ
From Project_Status
)PR
WHERE SEQ = 1
AND IDSEQ = 1
Your problem is ties. You want the record with the maximum date per PRJSTAT_PRJA_ID and in case of a tie the record with the highest ID. The easiest way to rank records per group and only keep the best record is ROW_NUMBER:
select prjstat_id, prjstat_prja_id, prjstat_status, prjstat_date
from
(
select
project_status.*,
row_number() over (partition by prjstat_prja_id
order by prjstat_date desc, prjstat_id desc) as rn
from project_status
)
where rn = 1
order by prjstat_prja_id;
I hope i can explain the issue i'm having and hopefully so can point me in the same direction.
I'm trying to do a group by (Email Address) on a subset of data, then i'm using a max() on a date field but because of different values in other fields its bring back more rows then require.
I would just like to return the max record per email address and return the fields that are on the same row that are on the max record.
Not sure how i can write this query?
This is a task for ROW_NUMBER:
select *
from
(
select t.*,
-- assign sequential number starting with 1 for the maximum date
row_number() over (partiton by email_address order by datecol desc) as rn
from tab
) as dt
where rn = 1 -- only return the latest row
You can write this query using row_number():
select t.*
from (select t.*,
row_number() over (partition by emailaddress order by date desc) as seqnum
from t
) t
where seqnum = 1;
How about something like this?
select a.*
from baseTable as a
inner join
(select Email,
Max(EmailDate) as EmailDate
from baseTable
group by Email) as b
on a.Email = b.Email
and a.EmailDate = b.EmailDate