Repeating ID based on - sql

Question

I have a very simple requirement but I'm struggling to find a way around this.
I have a very simple query:
SELECT
ServiceCode,
StartDate,
Available,
Nights,
BookingID
FROM #tmpAvailability
LEFT JOIN vwRSBooking B
ON B.Depart = A.StartDate
AND B.ServiceCode = A.SupplierCode
AND B.StatusID IN (2640, 2621)
ORDER BY StartDate;
Made up of 2 tables
#tmpAvailability which consists of the following fields:
SupplierCode
StartDate
Available
vwRSBooking which consists of the following fields
BookingID
DepartDate
Code
Nights
StatusID
Departure and startdate can be joined to link the first day, and the servicecode and suppliercode can be joined to make sure that the availability is linked to the same supplier.
Which produces an output like this:
Code | Dates | Available | Nights | BookingID
TEST | 2018-01-04 | 1 | NULL | NULL
TEST | 2018-01-05 | 1 | NULL | NULL
TEST | 2018-01-06 | 0 | 4 | 123456
TEST | 2018-01-07 | 0 | NULL | NULL
TEST | 2018-01-08 | 0 | NULL | NULL
TEST | 2018-01-09 | 0 | NULL | NULL
TEST | 2018-01-10 | 1 | NULL | NULL
TEST | 2018-01-11 | 1 | NULL | NULL
TEST | 2018-01-12 | 1 | NULL | NULL
TEST | 2018-01-13 | 0 | NULL | 234567
TEST | 2018-01-14 | 0 | NULL | NULL
TEST | 2018-01-15 | 0 | NULL | NULL
What I need is when the BookingID in for 4 days that the bookingID and the nights are spread across those days, for example:
Code | Dates | Available | Nights | BookingID
TEST | 2018-01-04 | 1 | NULL | NULL
TEST | 2018-01-05 | 1 | NULL | NULL
TEST | 2018-01-06 | 0 | 4 | 123456
TEST | 2018-01-07 | 0 | 4 | 123456
TEST | 2018-01-08 | 0 | 4 | 123456
TEST | 2018-01-09 | 0 | 4 | 123456
TEST | 2018-01-10 | 1 | NULL | NULL
TEST | 2018-01-11 | 1 | NULL | NULL
TEST | 2018-01-12 | 1 | NULL | NULL
TEST | 2018-01-13 | 0 | 3 | 234567
TEST | 2018-01-14 | 0 | 3 | 234567
TEST | 2018-01-15 | 0 | 3 | 234567
TEST | 2018-01-16 | 1 | NULL | NULL
If anyone has any ideas on how to solve it would be most appreciated.
Andrew

Answer 1

You could replace your vwRSBooking with another view which uses a CTE to obtain all the dates the booking covers. Then use the view's coverdate for joining to the #tmpAvailability table:
CREATE VIEW vwRSBookingFull
AS
WITH cte ( bookingid, nights, depart, code, coverdate)
AS (SELECT bookingid,
nights,
depart,
code,
depart
FROM vwRSBooking
UNION ALL
SELECT c.bookingid,
c.nights,
c.depart,
c.code,
DATEADD(d, 1, c.coverdate)
FROM cte c
WHERE DATEDIFF(d, c.depart, c.coverdate) < (c.nights - 1))
SELECT c.bookingid,
c.nights,
c.depart,
c.code,
c.coverdate
FROM cte c
GO

Answer 2

You will need a calendar table with all the dates in the date range your dates may fall into. For this example, I build one for January 2018. We can then join onto this table to create the additional rows.
Here is the sample code I used. You can see it at SQL Fiddle.
CREATE TABLE code (
code varchar(max),
dates date,
available int,
nights int,
bookingid int
)
INSERT INTO code VALUES
('TEST','2018-01-04','1',NULL,NULL),
('TEST','2018-01-05','1',NULL,NULL),
('TEST','2018-01-06','0',4,123456),
('TEST','2018-01-07','0',NULL,NULL),
('TEST','2018-01-08','0',NULL,NULL),
('TEST','2018-01-09','0',NULL,NULL),
('TEST','2018-01-10','1',NULL,NULL),
('TEST','2018-01-11','1',NULL,NULL),
('TEST','2018-01-12','1',NULL,NULL),
('TEST','2018-01-13','0',3,234567),
('TEST','2018-01-14','0',NULL,NULL),
('TEST','2018-01-15','0',NULL,NULL)
CREATE TABLE dates (
dates date
)
INSERT INTO dates VALUES
('2018-01-01'),('2018-01-02'),('2018-01-03'),('2018-01-04'),('2018-01-05'),('2018-01-06'),('2018-01-07'),('2018-01-08'),('2018-01-09'),('2018-01-10'),('2018-01-11'),('2018-01-12'),('2018-01-13'),('2018-01-14'),('2018-01-15'),('2018-01-16'),('2018-01-17'),('2018-01-18'),('2018-01-19'),('2018-01-20'),('2018-01-21'),('2018-01-22'),('2018-01-23'),('2018-01-24'),('2018-01-25'),('2018-01-26'),('2018-01-27'),('2018-01-28'),('2018-01-29'),('2018-01-30'),('2018-01-31')
Here is the query based on this dataset:
SELECT
code.code,
dates.dates,
code.available,
code.nights,
code.bookingid
FROM code
LEFT JOIN dates ON
dates.dates >= code.dates
AND dates.dates < DATEADD(DAY,nights,code.dates)
Edit: Here is an example using your initial query as a subquery to join your result set onto the dates table if you want a copy & paste. Still requires creating the dates table.
SELECT
ServiceCode,
StartDate,
Available,
Nights,
BookingID
FROM (
SELECT
ServiceCode,
StartDate,
Available,
Nights,
BookingID
FROM #tmpAvailability
LEFT JOIN vwRSBooking B
ON B.Depart = A.StartDate
AND B.ServiceCode = A.SupplierCode
AND B.StatusID IN (2640, 2621)
) code
LEFT JOIN dates ON
dates.dates >= code.dates
AND dates.dates < DATEADD(DAY,nights,code.dates)
ORDER BY StartDate;