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i want to retrieve records where a date field is set to future months
does this look correct
Select * from table1 WHERE
datesetto >MONTH(dateadd(dd, -1, GetDate())))
select * from tablename where month(columndate)>month(getdate()) and
year(columndate)>=year(getdate())
SELECT * FROM table1
WHERE datesetto >= DATEADD(month, DATEDIFF(month, 0, getdate())+1, 0)
Explanation:
DATEDIFF(month, 0, getdate()) calculates how many months have passed since 1900-01-01.
DATEADD(month, DATEDIFF(month, 0, getdate()), 0) returns the beginning of this month.
DATEADD(month, DATEDIFF(month, 0, getdate())+1, 0) returns the beginning of next month.
Try this:
Select * from table1 WHERE
((DATEPART(MONTH,datesetto) > DATEPART(MONTH,GETDATE())
AND DATEPART(YEAR,datesetto) = DATEPART(YEAR,GETDATE()))
OR (DATEPART(YEAR,datesetto) > DATEPART(YEAR,GETDATE())))
DATEPART(Month,GETDATE()) will give the month of the current date and then you can compare it with the datesetto
Update: The above query will give data for any months greater than the current month and any month greater in the year than the current year.
Need query to get records by comparing one of it's field with different values
Here is the my table
repeated 1 means Daily
2 means Weekly
3 means Monthly
I need query to get all records which are going to Tele caste and being Tele casting by comapring current date and time.
Thank you
Do you mean something like this?
--case for daily: only need to check times
select
*
from
schedules
where
repeated = 1
--this is to compare if it starts within the next hour, may have bugs not tested
--logic is if start time - 1 hour is less than now but start time is more than now must start within the next hour
and DATEADD(day, -DATEDIFF(day, 0, dateadd(hour,startdate),-1) ), dateadd(hour,startdate),-1) ) < DATEADD(day, -DATEDIFF(day, 0, Now()), Now())
and DATEADD(day, -DATEDIFF(day, 0, startdate), startdate) > DATEADD(day, -DATEDIFF(day, 0, Now()), Now())
union
--case for weekly: is the day of the week the same, if so check times
select
*
from
schedules
where
repeated = 2
and datepart(dw,startdate) = datepart(dw,Now)
and DATEADD(day, -DATEDIFF(day, 0, dateadd(hour,startdate),-1) ), dateadd(hour,startdate),-1) ) < DATEADD(day, -DATEDIFF(day, 0, Now()), Now())
and DATEADD(day, -DATEDIFF(day, 0, startdate), startdate) > DATEADD(day, -DATEDIFF(day, 0, Now()), Now())
union
--case for monthly is the day of the month the same, if so compare times
select
*
from
schedules
where
repeated = 3
and datepart(day,startdate) = datepart(day,Now)
and DATEADD(day, -DATEDIFF(day, 0, dateadd(hour,startdate),-1) ), dateadd(hour,startdate),-1) ) < DATEADD(day, -DATEDIFF(day, 0, Now()), Now())
and DATEADD(day, -DATEDIFF(day, 0, startdate), startdate) > DATEADD(day, -DATEDIFF(day, 0, Now()), Now())
and is monthly based on date of the month , number of weeks (e.g. 4) or week of the month + weekday (e.g. second tuesday of the month)
EDIT: i think that should work where a monthly cycle is means on that day of the month every month.
The above could be modified to use a separate time column by just using that field for all time comparisons e.g.:
...
where
repeated = 3
and datepart(day,startdate) = datepart(day,Now)
and DATEADD(day, -DATEDIFF(day, 0, dateadd(hour,starttime),-1) ), dateadd(hour,starttime),-1) ) < DATEADD(day, -DATEDIFF(day, 0, Now()), Now())
and DATEADD(day, -DATEDIFF(day, 0, starttime), starttime) > DATEADD(day, -DATEDIFF(day, 0, Now()), Now())
EXPLANATION:
the normal way i would process this question as a human would be:
whats the start date
whats the repeating cycle
does startdate * any multiple of repeating cycle period = today
if so is it on now
this is a procedural, step based solution
when i think of this as a set based problem then i need to know what is the set of programs that is on now
I am allowed to add sets (union) but i cannot step through rows considering each one.. so i split it into three sets and add them together:
daily shows are on every day so i only need to check times
weekly shows are on every week on the same day, so if its weekly if the days of the week matches compare times
monthly shows are on the same day of the month every months, so if its that day of the month compare the times
hope this helps.. sorry if my explanation is crap, just trying to help :D
are you looking for this :-
Declare #Today Datetime
Select #Today = Getdate()
Select s.ProgramId
,s.ProgramName
From schedules As s With (Nolock)
Where (Cast(s.startdate As Datetime) + Cast(s.StartTime As Datetime)) >= #Today
Order By s.repeated
,s.ProgramId
Example:
SELECT column_name
FROM table_name
WHERE column_name IN (value1, value2, value3)
You mean something like that?
I have a query (pasted below), and I would like to make it so that people don't need to update the completed date range. I would like for it to automatically just get results from last month. So if it is run in February, for example, it will give me results for all completed items that meet my criteria for January. Can anyone think of a way to do that?
select External_ID__c,
Ewrk_Tracking_Number__c,
PIF_Branch_Name,
Distribution_Branch_Name,
Transaction_Type__C,
submitter_date__c, Completed_Date__C,
COUNT(External_ID__c)
from Business_Solutions_D.dbo.Reporting_SalesForce_AspireBaseData
where PIF_Branch_Code = 977
and Completed_Date__C >= '2015-01-01'
and Completed_Date__C < '2015-02-01'
and Delete_Flag__C = 'FALSE'
group by External_ID__c,
Ewrk_Tracking_Number__c,
PIF_Branch_Name,
Distribution_Branch_Name,
Transaction_Type__C,
submitter_date__c,
Completed_Date__C
There is no "keyword" for last month. You have to put that in your predicates.
Here is an example of how to get some date values for this.
select dateadd(MONTH, datediff(MONTH, 0, GETDATE()), 0) as BeginningOfThisMonth
select dateadd(MONTH, datediff(MONTH, 0, GETDATE()) - 1, 0) as BeginningOfPreviousMonth
If you want to see a number of other date routines here is an excellent blog post with quite a few of them. http://www.sqlservercentral.com/blogs/lynnpettis/2009/03/25/some-common-date-routines/
If you mean the last month prior to this one, you can do it in two steps: first, find the first day of the current month
#firstDayOfThisMonth = DATEADD(day, DAY(GETDATE())-1, GETDATE())
then subtract one month:
#firstDayOfLastMonth = DATEADD(month, -1, #firstDayOfThisMonth)
Then your query would be:
and Completed_Date__C >= #firstDayOfLastMonth
and Completed_Date__C < #firstDayOfThisMonth
Another way would be to query where the difference (in months) between Completed_Date__C and the current date is 1:
and DATEDIFF(Completed_Date__C, GETDATE()) = 1
You can do this with date arithmetic. One trick to get the first date of the month is to subtract the current day of the month from the date and add one day. SQL Server allows you to do this with + and - instead of dateadd(), on a datetime value. Of course, you need to remove the time component as well (using cast( as date)).
The logic looks like this for the current month:
where Completed_Date__C >= cast(getdate() - day(getdate()) + 1 as date) and
Completed_Date__C < dateadd(month, 1, cast(getdate() - day(getdate()) + 1 as date))
And like this for the previous month:
where Completed_Date__C >= dateadd(month, -1, cast(getdate() - day(getdate()) + 1 as date)) and
Completed_Date__C < cast(getdate() - day(getdate()) + 1 as date)
This has the nice property that it is a sargeable as your original code, so it will take advantage of an index on the column, if appropriate.
You just need to have it do some date math to calculate it.
--Go to last day of prev month - 'Day' to account for varying month day counts
and Completed_Date__C >= GETDATE() - DATEPART(DAY, GETDATE()) - DATEPART(DAY, GETDATE() - DATEPART(DAY, GETDATE())) + 1
and Completed_Date__C < GETDATE() - DATEPART(DAY, GETDATE()) + 1
When you do additions on DateTimes + integer it assumes it day based addition.
I have the following code:
Declare #indDate date = '1/1/2014'
SELECT RecordID AS RID,
Name,
Company,
PhoneNumber,
CONVERT(VARCHAR(10),DateOfInduction,103) AS StartDate,
CONVERT(VARCHAR(10),DateOfExpiry,103) AS DateOfExpiry
FROM Records WHERE DateOfExpiry <= DATEFROMPARTS(DATEPART(YYYY,#indDate),DATEPART(MM,#indDate),DATEPART(DD,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#indDate)+1,0))))
AND DateOfExpiry >= DATEFROMPARTS(DATEPART(YYYY,#indDate),DATEPART(MM,#indDate),1)
Which basically gives me all expiring records for the month of the #indDate parameter.
What I am trying to do is add 1 to the month in the DATEFROMPARTS to get next month's values. Now I don't want to just change the #indDate to the other month because in the report the date will not be selected but only something like Expires This Month, Next Month, Previous Month, etc.
So if I change the WHERE clause to:
WHERE DateOfExpiry <= DATEFROMPARTS(DATEPART(YYYY,#indDate),DATEPART(MM,DATEADD(MM,1,#indDate)),DATEPART(DD,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#indDate)+1,0))))
AND DateOfExpiry >= DATEFROMPARTS(DATEPART(YYYY,#indDate),DATEPART(MM,DATEADD(MM,1,#indDate)),1)
I get error: Cannot construct data type date, some of the arguments have values which are not valid. and I am not sure why, it works fine If I try something like:
Declare #indDate date = '1/1/2014'
select DATEADD(mm,1,#indDate)
Can anyone see the problem?
In your error is coming from trying to create date from invalid date range,
if you run parts of your DATEFROMPARTS in the following manner
DECLARE #indDate DATE = '1/1/2014'
SELECT DATEPART(YYYY, #indDate)
,DATEPART(MM, DATEADD(MM, 1, #indDate))
,DATEPART(DD, DATEADD(s, -1, DATEADD(mm, DATEDIFF(m, 0, #indDate) + 1, 0)))
this generates 2014 2 31 which is not a valid date.
The following three examples will give you all records for previous, current or next month no matter if you passed in '01/01/2014' or '01/15/2014'
This will give you all records for last month.
WHERE DateOfExpiry >= DATEADD(MONTH, -1,DATEADD(dd,-DATEPART(day,#indDate)+1,#indDate)) AND
DateOfExpiry < DATEADD(dd,-DATEPART(day,#indDate)+1,#indDate)
This will give you all records for current month
WHERE DateOfExpiry >= DATEADD(dd,-DATEPART(day,#indDate)+1,#indDate)
and DateOfExpiry < DATEADD(MONTH, 1,DATEADD(dd,-DATEPART(day,#indDate)+1,#indDate))
Finally all records for next month
WHERE DateOfExpiry >= DATEADD(MONTH, 1, DATEADD(dd, -DATEPART(day, #indDate) + 1, #indDate))
AND DateOfExpiry < DATEADD(MONTH, 2, DATEADD(dd, -DATEPART(day, #indDate) + 1, #indDate))
why not use:
WHERE DateOfExpiry >= #indDate AND DateOfExpiry < DATEADD(month,1,#indDate)
Specifically MSSQL 2005.
Here's a solution that gives you the last second of the current month. You can extract the date part or modify it to return just the day. I tested this on SQL Server 2005.
select dateadd( s, -1, dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 ) );
To understand how it works we have to look at the dateadd() and datediff() functions.
DATEADD(datepart, number, date)
DATEDIFF(datepart, startdate, enddate)
If you run just the most inner call to datediff(), you get the current month number since timestamp 0.
select datediff(m, 0, getdate() );
1327
The next part adds that number of months plus 1 to the 0 timestamp, giving you the starting point of the next calendar month.
select dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 );
2010-09-01 00:00:00.000
Finally, the outer dateadd() just subtracts one second from the beginning timestamp of next month, giving you the last second of the current month.
select dateadd( s, -1, dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 ) );
2010-08-31 23:59:59.000
This old answer (below) has a bug where it doesn't work on the last day of a month that has more days than the next month. I'm leaving it here as a warning to others.
Add one month to the current date, and then subtract the value returned by the DAY function applied to the current date using the functions DAY and DATEADD.
dateadd(day, -day(getdate()), dateadd(month, 1, getdate()))
SELECT DATEADD(M, DATEDIFF(M, '1990-01-01T00:00:00.000', CURRENT_TIMESTAMP), '1990-01-31T00:00:00.000')
Explanation:
General approach: use temporal functionality.
SELECT '1990-01-01T00:00:00.000', '1990-01-31T00:00:00.000'
These are DATETIME literals, being the first time granule on the first day and last day respectively of the same 31-day month. Which month is chosen is entirely arbitrary.
SELECT DATEDIFF(M, '1990-01-01T00:00:00.000', CURRENT_TIMESTAMP)
This is the difference in whole months between the first day of the reference month and the current timestamp. Let's call this #calc.
SELECT DATEADD(M, #calc, '1990-01-31T00:00:00.000')
This adds #calc month granules to the last day of the reference month, the result of which is the current timestamp 'rounded' to the last day of its month. Q.E. D.
Try this:
DATEADD (DAY, -1, DATEADD (MONTH, DATEDIFF (MONTH, 0, CURRENT_TIMESTAMP) + 1, 0)
They key points are if you can get first day of current month,Last Day of Last Month and Last Day of Current Month.
Below is the Step by Step way to write query:
In SQL Server Date Starts from 1901/01/01( Date 0) and up to now each month can be identified by a number. Month 12 is first month of 1902 means January. Month 1200 is January of 2001. Similarly each day can be assigned by unique number e.g Date 0 is 1901/01/01. Date 31 is 1901/02/01 as January of 1901 starts from 0.
To find out First day of Current Month(Current Date or a given date)
First we need to check how many months have passed since date 0(1901/01/01).
SELECT DATEDIFF(MM,0,GETDATE())
Add same number of month to date 0(1901/01/01)
SELECT DATEADD(MM, DATEDIFF(MM,0,GETDATE()),0)
Then we will get first day of current month(Current Date or a given date)
To get Last Day of Last Month
We need to subtract a second from first day of current month
SELECT DATEADD(SS,-1,DATEADD(MM, DATEDIFF(MM,0,GETDATE()),0))
To get Last Day of Current Month
To get first day of current month first we checked how many months have been passed since date 0(1901/01/01). If we add another month with the total months since date 0 and then add total months with date 0, we will get first day of next month.
SELECT DATEADD(MM, DATEDIFF(MM,0,GETDATE())+1,0)
If we get first day of next month then to get last day of current month, all we need to subtract a second.
SELECT DATEADD(SS,-1,DATEADD(MM, DATEDIFF(MM,0,GETDATE())+1,0))
Hope that would help.
Using SQL2005, you do not have access to a helpful function EOMONTH(), So you must calculate this yourself.
This simple function will works similar to EOMONTH
CREATE FUNCTION dbo.endofmonth(#date DATETIME= NULL)
RETURNS DATETIME
BEGIN
RETURN DATEADD(DD, -1, DATEADD(MM, +1, DATEADD(DD, 1 - DATEPART(DD, ISNULL(#date,GETDATE())), ISNULL(#date,GETDATE()))))
END
Query to perform:
SELECT dbo.endofmonth(DEFAULT) --Current month-end date
SELECT dbo.endofmonth('02/25/2012') --User-defined month-end date
Some links to possible answers:
http://www.extremeexperts.com/sql/Tips/DateTrick.aspx
http://www.devx.com/tips/Tip/14405
http://blog.sqlauthority.com/2007/08/18/sql-server-find-last-day-of-any-month-current-previous-next/
http://www.sqlservercurry.com/2008/03/find-last-day-of-month-in-sql-server.html
DECLARE
#Now datetime,
#Today datetime,
#ThisMonth datetime,
#NextMonth datetime,
#LastDayThisMonth datetime
SET #Now = getdate()
SET #Today = DateAdd(dd, DateDiff(dd, 0, #Now), 0)
SET #ThisMonth = DateAdd(mm, DateDiff(mm, 0, #Now), 0)
SET #NextMonth = DateAdd(mm, 1, #ThisMonth)
SET #LastDayThisMonth = DateAdd(dd, -1, #NextMonth)
Sometimes you really do need the last day of this month, but frequently what you really want is to describe the time interval of this month. This is the best way to describe the time interval of this month:
WHERE #ThisMonth <= someDate and someDate < #NextMonth
For completeness, in Oracle you'd do something like ...
select add_months(trunc(sysdate,'MM'),1) ...
or
select last_day(sysdate)+1 ...
DATEADD(dd, -1, DATEADD(mm, +1, DATEADD(dd, 1 - DATEPART(dd, #myDate), #myDate)))