Related
How can I replace 'a' to blank?
`Name` `ID`
----------------------------------
`b,c,d,e,abb,a` `1`
`b,c,d,a,e,abb` `2`
`a,b,c,d,a,e,abb` `3`
One way to do it would be to add a , to the beginning and end of each Name, then replace every occurence of ',a,' with ',', then trim the result of the ,:
update table_name
set Name = trim(',' from replace(concat(',', Name, ','), ',a,', ','));
Fiddle
Or if you just want to do a select without changing the rows:
select trim(',' from replace(concat(',', Name, ','), ',a,', ',')) as Name, ID
from table_name;
To address #Iptr's comment, if there can be consecutive a such as a, a, ..., you could use STRING_SPLIT to get rows from comma-separated values, then filter out where the value is a, then STRING_AGG and group by to get the comma separated values back:
select ID, STRING_AGG(u.Value, ',') as Name
from table_name
cross apply STRING_SPLIT (Name, ',') u
where Value <> 'a'
group by ID
Fiddle
Here is a solution based on tokenization via XML/XQuery.
It will work starting from SQL Server 2012 onwards.
Steps:
We are tokenizing a string of tokens via XML.
XQuery FLWOR expression is filtering out the 'a' token.
Reverting it back to a string of tokens.
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE (ID INT IDENTITY PRIMARY KEY, tokens VARCHAR(1000));
INSERT INTO #tbl (tokens) VALUES
('b,c,d,e,abb,a'),
('b,c,d,a,e,abb'),
('a,b,c,d,a,e,abb');
-- DDL and sample data population, end
DECLARE #separator CHAR(1) = ',';
SELECT t.*
, REPLACE(c.query('
for $x in /root/r/text()
return if ($x = "a") then ()
else data($x)
').value('.', 'VARCHAR(MAX)'), SPACE(1), #separator) AS Result
FROM #tbl AS t
CROSS APPLY (SELECT TRY_CAST('<root><r><![CDATA[' +
REPLACE(tokens, #separator, ']]></r><r><![CDATA[') +
']]></r></root>' AS XML)) AS t1(c);
Output
+----+-----------------+-------------+
| ID | tokens | Result |
+----+-----------------+-------------+
| 1 | b,c,d,e,abb,a | b,c,d,e,abb |
| 2 | b,c,d,a,e,abb | b,c,d,e,abb |
| 3 | a,b,c,d,a,e,abb | b,c,d,e,abb |
+----+-----------------+-------------+
Try as follow:
select Replace(name, N'a', N'') as RepName , ID from yourTable
Try this.
SELECT ID,Name, REPLACE(Name, 'a', ' ')
FROM tableName;
I am trying to update column in table where data is in below format:
Id | ColA
----------
1 Peter,John:Ryan,Jack:Evans,Chris
2 Peter,John:Ryan,Jack
3 Hank,Tom
4
5 Cruise,Tom
I need to split the string by ':' and remove ',' and need to reverse the name and again append the same data separated by: and finally data should be as shown
Id | ColA
----------
1 John Peter:Jack Ryan:Chris Evans
2 John Peter:Jack Ryan
3 Tom Hank
4
5 Tom Cruise
Please let me know how can we achieve this
I tried to use Replace and Substring but how can we do it if we have data some are separated by two colon and some are separated by single colon.
Is there any way to identify and achieve the data in the above formatted one.
Here is a solution for SQL Server 2008 onwards.
It is based on XML and XQuery.
Using XQuery's FLWOR expression allows to tokenize odd vs. even XML elements. The rest is just a couple of the REPLACE() function calls to compose the desired output.
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE (ID INT IDENTITY PRIMARY KEY, tokens VARCHAR(1024));
INSERT INTO #tbl (tokens) VALUES
('Peter,John:Ryan,Jack:Evans,Chris'),
('Peter,John:Ryan,Jack'),
('Hank,Tom'),
(''),
('Cruise,Tom');
-- DDL and sample data population, end
DECLARE #separator CHAR(1) = ':'
, #comma CHAR(1) = ',';
SELECT ID, tokens
, REPLACE(REPLACE(c.query('
for $x in /root/r[position() mod 2 eq 0]
let $pos := count(root/r[. << $x])
return concat($x, sql:variable("#comma"), (/root/r[$pos])[1])
').value('text()[1]', 'VARCHAR(8000)')
, SPACE(1), #separator), #comma, SPACE(1)) AS result
FROM #tbl
CROSS APPLY (SELECT CAST('<root><r><![CDATA[' +
REPLACE(REPLACE(tokens,#comma,#separator), #separator, ']]></r><r><![CDATA[') +
']]></r></root>' AS XML)) AS t1(c)
ORDER BY ID;
Output
+----+----------------------------------+----------------------------------+
| ID | tokens | result |
+----+----------------------------------+----------------------------------+
| 1 | Peter,John:Ryan,Jack:Evans,Chris | John Peter:Jack Ryan:Chris Evans |
| 2 | Peter,John:Ryan,Jack | John Peter:Jack Ryan |
| 3 | Hank,Tom | Tom Hank |
| 4 | | NULL |
| 5 | Cruise,Tom | Tom Cruise |
+----+----------------------------------+----------------------------------+
SQL #2 (don't try it, it won't work)
Unfortunately, SQL Server doesn't fully support even XQuery 1.0 standard. XQuery 3.1 is the latest standard. XQuery 1.0 functions fn:substring-after() and fn:substring-before() are badly missing.
In a dream world a solution would be much simpler, along the following:
SELECT *
, c.query('
for $x in /root/r
return concat(fn:substring-after($x, ","), ",", fn:substring-before($x, ","))
')
FROM #tbl
CROSS APPLY (SELECT TRY_CAST('<root><r><![CDATA[' +
REPLACE(tokens, #separator, ']]></r><r><![CDATA[') +
']]></r></root>' AS XML)) AS t1(c);
Please up-vote the following suggestion to improve SQL Server:
SQL Server vNext (post 2019) and NoSQL functionality
It became one of the most popular requests for SQL Server.
The current voting tally is 590 and counting.
Something like this should work:
CREATE TABLE YourTableNameHere (
Id int NULL
,ColA varchar(1000) NULL
);
INSERT INTO YourTableNameHere (Id,ColA) VALUES
(1, 'Peter,John:Ryan,Jack:Evans,Chris')
,(2, 'Peter,John:Ryan,Jack')
,(3, 'Hank,Tom')
,(4, '')
,(5, 'Cruise,Tom');
SELECT
tbl.Id
,STUFF((SELECT
CONCAT(':'
,RIGHT(REPLACE(ss.value, ',', ' '), LEN(REPLACE(ss.value, ',', ' ')) - CHARINDEX(' ', REPLACE(ss.value, ',', ' '), 1)) /*first name*/
,' '
,CASE WHEN CHARINDEX(',', ss.value, 1) > 1 THEN LEFT(REPLACE(ss.value, ',', ' '), CHARINDEX(' ', REPLACE(ss.value, ',', ' '), 1) - 1) /*last name*/ ELSE '' END)
FROM
YourTableNameHere AS tbl_inner
CROSS APPLY string_split(tbl_inner.ColA, ':') AS ss
WHERE
tbl_inner.Id = tbl.Id
FOR XML PATH('')), 1, 1, '') AS ColA
FROM
YourTableNameHere AS tbl;
This uses the string_split function within a FOR XML clause to split the values in ColA by the : character, then replace the , with a space, parse to the left and right of the space, then recombine the parsed values delimited by a : character.
One thing to note here, per Microsoft the output of string_split is not guaranteed to be in the same order as the input:
Note
The order of the output may vary as the order is not guaranteed to match the order of the substrings in the input string.
So in order to guarantee the output of this function is going to concatenate the names back in the same order that they existed in the input column you would either need to implement your own function to split the string or come up with some criteria for combining them in a certain order. For example, you could recombine them in alphabetical order by adding ORDER BY ss.value to the inner query for ColA in the final result set. In my testing using your input the final values were ordered the same as the input column, but it is worth noting that that behaviour is not guaranteed and in order to guarantee it then you need to do more work.
I'm using a SQL Server 2014 database and I have a column that contains comma-separated values such as:
1,2,3
4,5
3,6,2
4,2,8
2
What I need to do is to replace the number 2 with the number 3 (string values) in each record and not duplicate the 3 if possible. I'm not sure that this can be done unless I use a function and I'm not sure how to do it in a function.
I think I need to split a string into a table and then loop the values and put it back together with the new value. Is there an easier way? Any help is appreciated.
Expect output would therefore be:
1,3
4,5
3,6
4,3,8
3
While it is possible, I do not encourage this:
DECLARE #old AS VARCHAR(3) = '2';
DECLARE #new AS VARCHAR(3) = '3';
WITH opdata(csv) AS (
SELECT '1,22,3' UNION ALL
SELECT '1,2,3' UNION ALL
SELECT '4,5' UNION ALL
SELECT '3,6,2' UNION ALL
SELECT '4,2,8' UNION ALL
SELECT '2'
), cte1 AS (
SELECT
csv,
CASE
WHEN ',' + csv + ',' LIKE '%,' + #old + ',%' THEN
CASE
WHEN ',' + csv + ',' LIKE '%,' + #new + ',%' THEN REPLACE(',' + csv + ',', ',' + #old + ',', ',') -- new already present so just delete old
ELSE REPLACE(',' + csv + ',', ',' + #old + ',', ',' + #new + ',') -- replace old with new
END
ELSE ',' + csv + ','
END AS tmp
FROM opdata
)
SELECT
csv,
STUFF(STUFF(tmp, 1, 1, ''), LEN(tmp) - 1, 1, '') AS res
FROM cte1
Result:
csv | res
-------+-------
1,22,3 | 1,22,3
1,2,3 | 1,3
4,5 | 4,5
3,6,2 | 3,6
4,2,8 | 4,3,8
2 | 3
Note that the plethora of ',...,' is required to avoid replacing values such as 22. If you are using SQL Server 2017 you can ditch the extra CTE + STUFF and use TRIM(',' FROM ...).
This isn't going to perform particularly well, however:
WITH CTE AS (
SELECT *
FROM (VALUES ('1,2,3'),
('4,5'),
('3,6,2'),
('4,2,8'),
('2')) V(DS))
SELECT CASE WHEN DS LIKE '%3%' THEN REPLACE(REPLACE(DS,'2,',''),',2','')
WHEN DS LIKE '%2%' THEN REPLACE(DS,'2','3')
ELSE DS
END
FROM CTE;
May be you are looking something like this.
SELECT REPLACE(CASE WHEN CHARINDEX('2', '1,2,3') > 0 THEN REPLACE('1,2,3', '2','') ELSE REPLACE('1,2,3', '2','3') END, ',,',',')
I have taken a hard coded value for demonstration. You can replace'1,2,3' with column name in the table.
To update:
DECLARE #was nvarchar(2) = 2,
#willbe nvarchar(2) = 3,
#d nvarchar(1) = ','
UPDATE strings
SET string = REVERSE(
STUFF(
REVERSE(
STUFF(
CASE WHEN CHARINDEX(#d+#willbe+#d,#d+string+#d) > 0
THEN REPLACE(#d+string+#d,#d+#was+#d,#d)
ELSE REPLACE(#d+string+#d,#d+#was+#d,#d+#willbe+#d)
END,1,1,'')
),1,1,''))
Output:
1,3
4,5
3,6
4,3,8
3
I'm trying to count how many words there are in a string in SQL.
Select ("Hello To Oracle") from dual;
I want to show the number of words. In the given example it would be 3 words though there could be more than one space between words.
You can use something similar to this. This gets the length of the string, then substracts the length of the string with the spaces removed. By then adding the number one to that should give you the number of words:
Select length(yourCol) - length(replace(yourcol, ' ', '')) + 1 NumbofWords
from yourtable
See SQL Fiddle with Demo
If you use the following data:
CREATE TABLE yourtable
(yourCol varchar2(15))
;
INSERT ALL
INTO yourtable (yourCol)
VALUES ('Hello To Oracle')
INTO yourtable (yourCol)
VALUES ('oneword')
INTO yourtable (yourCol)
VALUES ('two words')
SELECT * FROM dual
;
And the query:
Select yourcol,
length(yourCol) - length(replace(yourcol, ' ', '')) + 1 NumbofWords
from yourtable
The result is:
| YOURCOL | NUMBOFWORDS |
---------------------------------
| Hello To Oracle | 3 |
| oneword | 1 |
| two words | 2 |
Since you're using Oracle 11g it's even simpler-
select regexp_count(your_column, '[^ ]+') from your_table
Here is a sqlfiddle demo
If your requirement is to remove multiple spaces too, try this:
Select length('500 text Oracle Parkway Redwood Shores CA') - length(REGEXP_REPLACE('500 text Oracle Parkway Redwood Shores CA',
'( ){1,}', '')) NumbofWords
from dual;
Since I have used the dual table you can test this directly in your own development environment.
DECLARE #List NVARCHAR(MAX) = ' ab a
x'; /*Your column/Param*/
DECLARE #Delimiter NVARCHAR(255) = ' ';/*space*/
DECLARE #WordsTable TABLE (Data VARCHAR(1000));
/*convert by XML the string to table*/
INSERT INTO #WordsTable(Data)
SELECT Data = y.i.value('(./text())[1]', 'VARCHAR(1000)')
FROM
(
SELECT x = CONVERT(XML, '<i>'
+ REPLACE(#List, #Delimiter, '</i><i>')
+ '</i>').query('.')
) AS a CROSS APPLY x.nodes('i') AS y(i)
/*Your total words*/
select count(*) NumberOfWords
from #WordsTable
where Data is not null;
/*words list*/
select *
from #WordsTable
where Data is not null
/from this Logic you can continue alon/
I have a sql table called UsersInAuthentication like
-----------------------
| AuthUserId | UserId |
| 1 | 4 |
| 1 | 5 |
| 1 | 8 |
-----------------------
I wish to get all users in format "(4,5,8)" as string with a single stored proc and
If possible I also wish to insert,update,delete operations with this format.
Edit:
I'm using SQL Server 2005
Beats the purpose of a table a bit. Also UPDATING this can and will get tricky.
Seems like you should either rethink the design of your table, either rethink the way you are going to use it.
Since you're using SQL Server, you can do this:
declare #list nvarchar(max)
select #list = ''
select
#list = #list +
case when #list = '' then userid
else ',' + userid end
from
UsersInAuthentication
set #list = '(' + substring(#list, 1, 999) + ')'
print #list
This is a nifty trick that builds the variable by appending each row's value to the current value of the variable. It's rather handy with table operations, and the like.
For posterity:
In MySQL, you can uses group_concat:
select
concat('(' + group_concat(userid order by userid separator ',') + ')')
from
UserInAuthentication
In Oracle, you can use a cursor:
cursor c_users is
select userid from usersinauthentication;
out_users varchar2(4000);
begin
for r_user in c_users loop
if out_users is null then
out_users:= r_user.first_Name;
else
out_users:= out_users ||', '|| r_user.first_Name;
end if;
end loop;
return out_users;
Assuming SQLServer:
--//testdata
WITH UsersInAuthentication (AuthUserId, UserId) AS (
SELECT 1, 4
UNION ALL SELECT 1, 5
UNION ALL SELECT 1, 8
)
--// real query
SELECT AuthUserId,
( SELECT cast(UserId as varchar) + ','
FROM UsersInAuthentication
ORDER BY UserID
FOR XML PATH('')
) AS UserIds
FROM UsersInAuthentication
GROUP BY AuthUserId
to get:
AuthUserId UserIds
----------- --------
1 4,5,8,
The actual queries really depend on your DBMS. Assuming Mysql:
SELECT GROUP_CONCAT(UserId) FROM UsersInAuthentication;
UPDATE UsersInAuthentication SET ... WHERE UserId IN (4,5,8);
DELETE FROM UsersInAuthentication WHERE UserId IN (4,5,8);
INSERT INTO UsersInAuthentication(UserId) VALUES (4), (5), (8);
But note that working with comma-delimited values in a database somehow misses the point.
SELECT CONCAT('(', GROUP_CONCAT(UserId SEPARATOR ','), ')')
FROM UsersInAuthentication;