I'm using a SQL Server 2014 database and I have a column that contains comma-separated values such as:
1,2,3
4,5
3,6,2
4,2,8
2
What I need to do is to replace the number 2 with the number 3 (string values) in each record and not duplicate the 3 if possible. I'm not sure that this can be done unless I use a function and I'm not sure how to do it in a function.
I think I need to split a string into a table and then loop the values and put it back together with the new value. Is there an easier way? Any help is appreciated.
Expect output would therefore be:
1,3
4,5
3,6
4,3,8
3
While it is possible, I do not encourage this:
DECLARE #old AS VARCHAR(3) = '2';
DECLARE #new AS VARCHAR(3) = '3';
WITH opdata(csv) AS (
SELECT '1,22,3' UNION ALL
SELECT '1,2,3' UNION ALL
SELECT '4,5' UNION ALL
SELECT '3,6,2' UNION ALL
SELECT '4,2,8' UNION ALL
SELECT '2'
), cte1 AS (
SELECT
csv,
CASE
WHEN ',' + csv + ',' LIKE '%,' + #old + ',%' THEN
CASE
WHEN ',' + csv + ',' LIKE '%,' + #new + ',%' THEN REPLACE(',' + csv + ',', ',' + #old + ',', ',') -- new already present so just delete old
ELSE REPLACE(',' + csv + ',', ',' + #old + ',', ',' + #new + ',') -- replace old with new
END
ELSE ',' + csv + ','
END AS tmp
FROM opdata
)
SELECT
csv,
STUFF(STUFF(tmp, 1, 1, ''), LEN(tmp) - 1, 1, '') AS res
FROM cte1
Result:
csv | res
-------+-------
1,22,3 | 1,22,3
1,2,3 | 1,3
4,5 | 4,5
3,6,2 | 3,6
4,2,8 | 4,3,8
2 | 3
Note that the plethora of ',...,' is required to avoid replacing values such as 22. If you are using SQL Server 2017 you can ditch the extra CTE + STUFF and use TRIM(',' FROM ...).
This isn't going to perform particularly well, however:
WITH CTE AS (
SELECT *
FROM (VALUES ('1,2,3'),
('4,5'),
('3,6,2'),
('4,2,8'),
('2')) V(DS))
SELECT CASE WHEN DS LIKE '%3%' THEN REPLACE(REPLACE(DS,'2,',''),',2','')
WHEN DS LIKE '%2%' THEN REPLACE(DS,'2','3')
ELSE DS
END
FROM CTE;
May be you are looking something like this.
SELECT REPLACE(CASE WHEN CHARINDEX('2', '1,2,3') > 0 THEN REPLACE('1,2,3', '2','') ELSE REPLACE('1,2,3', '2','3') END, ',,',',')
I have taken a hard coded value for demonstration. You can replace'1,2,3' with column name in the table.
To update:
DECLARE #was nvarchar(2) = 2,
#willbe nvarchar(2) = 3,
#d nvarchar(1) = ','
UPDATE strings
SET string = REVERSE(
STUFF(
REVERSE(
STUFF(
CASE WHEN CHARINDEX(#d+#willbe+#d,#d+string+#d) > 0
THEN REPLACE(#d+string+#d,#d+#was+#d,#d)
ELSE REPLACE(#d+string+#d,#d+#was+#d,#d+#willbe+#d)
END,1,1,'')
),1,1,''))
Output:
1,3
4,5
3,6
4,3,8
3
Related
I'm trying to count how many words there are in a string in SQL.
Select ("Hello To Oracle") from dual;
I want to show the number of words. In the given example it would be 3 words though there could be more than one space between words.
You can use something similar to this. This gets the length of the string, then substracts the length of the string with the spaces removed. By then adding the number one to that should give you the number of words:
Select length(yourCol) - length(replace(yourcol, ' ', '')) + 1 NumbofWords
from yourtable
See SQL Fiddle with Demo
If you use the following data:
CREATE TABLE yourtable
(yourCol varchar2(15))
;
INSERT ALL
INTO yourtable (yourCol)
VALUES ('Hello To Oracle')
INTO yourtable (yourCol)
VALUES ('oneword')
INTO yourtable (yourCol)
VALUES ('two words')
SELECT * FROM dual
;
And the query:
Select yourcol,
length(yourCol) - length(replace(yourcol, ' ', '')) + 1 NumbofWords
from yourtable
The result is:
| YOURCOL | NUMBOFWORDS |
---------------------------------
| Hello To Oracle | 3 |
| oneword | 1 |
| two words | 2 |
Since you're using Oracle 11g it's even simpler-
select regexp_count(your_column, '[^ ]+') from your_table
Here is a sqlfiddle demo
If your requirement is to remove multiple spaces too, try this:
Select length('500 text Oracle Parkway Redwood Shores CA') - length(REGEXP_REPLACE('500 text Oracle Parkway Redwood Shores CA',
'( ){1,}', '')) NumbofWords
from dual;
Since I have used the dual table you can test this directly in your own development environment.
DECLARE #List NVARCHAR(MAX) = ' ab a
x'; /*Your column/Param*/
DECLARE #Delimiter NVARCHAR(255) = ' ';/*space*/
DECLARE #WordsTable TABLE (Data VARCHAR(1000));
/*convert by XML the string to table*/
INSERT INTO #WordsTable(Data)
SELECT Data = y.i.value('(./text())[1]', 'VARCHAR(1000)')
FROM
(
SELECT x = CONVERT(XML, '<i>'
+ REPLACE(#List, #Delimiter, '</i><i>')
+ '</i>').query('.')
) AS a CROSS APPLY x.nodes('i') AS y(i)
/*Your total words*/
select count(*) NumberOfWords
from #WordsTable
where Data is not null;
/*words list*/
select *
from #WordsTable
where Data is not null
/from this Logic you can continue alon/
I am writing a query that roughly has this structure:
SELECT Name, <calculated-valued> as Version FROM <tables>
This calculated value needs to work like so: I have a varchar column 'Name' that could contain something like 'ABC' and I want to convert each letter into ASCII, and append them back together to form '65.66.67' in this example. (An empty string should return '0') Is there any way to do this?
My approach wasn't very good, but up to 5 characters I could do the following:
SELECT
CASE WHEN LEN(Name) = 0 THEN '0'
ELSE CAST(ASCII(SUBSTRING(Name, 1, 1)) as varchar(max)) +
CASE WHEN LEN(Name) = 1 THEN ''
ELSE '.' + CAST(ASCII(SUBSTRING(Name, 2, 1)) as varchar(max)) +
CASE WHEN LEN(Name) = 2 THEN ''
ELSE '.' + CAST(ASCII(SUBSTRING(Name, 3, 1)) as varchar(max)) +
CASE WHEN LEN(Name) = 3 THEN ''
ELSE '.' + CAST(ASCII(SUBSTRING(Name, 4, 1)) as varchar(max)) +
CASE WHEN LEN(Name) = 4 THEN ''
ELSE '.' + CAST(ASCII(SUBSTRING(Name, 5, 1)) as varchar(max))
END
END
END
END
END AS MyColumn
FROM <tables>
Is there a better way to do this? Ideally a method that can take any length of string?
Either that or can I cast letters into a hierarchyid datatype? I need to create things like 1/2/a/bc/4// or whatever, but hierarchyid doesn't support that. So instead I'm trying to convert it to 1/2/97/98.99/4/0 so I can convert and maintain the correct order. This column is only used for sorting.
Thanks for any help!
One method is a recursive CTE:
with cte as (
select Name, 1 as lev
cast(ascii(substring(name, 1, 1)) as varchar(max)) as ascii_name
from t
union all
select Name, lev + 1,
ascii_name + '.' + cast(ascii(substring(name, lev + 1, 1)) as varchar(max))
from cte
where len(Name) > lev
)
select Name, ascii_name
from cte;
Another option is with an ad-hoc tally table and a CROSS APPLY
Declare #YourTable table (Name varchar(25))
Insert Into #YourTable values
('ABC'),
('Jack'),
('Jill'),
('')
Select A.Name
,Version = isnull(B.String,'0')
From #YourTable A
Cross Apply (
Select String=Stuff((Select '.' +cast(S as varchar(5))
From (Select Top (len(A.Name))
S=ASCII(substring(A.Name,Row_Number() Over (Order By (Select NULL)),1))
From master..spt_values ) S
For XML Path ('')),1,1,'')
) B
Returns
Name String
ABC 65.66.67
Jack 74.97.99.107
Jill 74.105.108.108
0
I'm trying to count how many words there are in a string in SQL.
Select ("Hello To Oracle") from dual;
I want to show the number of words. In the given example it would be 3 words though there could be more than one space between words.
You can use something similar to this. This gets the length of the string, then substracts the length of the string with the spaces removed. By then adding the number one to that should give you the number of words:
Select length(yourCol) - length(replace(yourcol, ' ', '')) + 1 NumbofWords
from yourtable
See SQL Fiddle with Demo
If you use the following data:
CREATE TABLE yourtable
(yourCol varchar2(15))
;
INSERT ALL
INTO yourtable (yourCol)
VALUES ('Hello To Oracle')
INTO yourtable (yourCol)
VALUES ('oneword')
INTO yourtable (yourCol)
VALUES ('two words')
SELECT * FROM dual
;
And the query:
Select yourcol,
length(yourCol) - length(replace(yourcol, ' ', '')) + 1 NumbofWords
from yourtable
The result is:
| YOURCOL | NUMBOFWORDS |
---------------------------------
| Hello To Oracle | 3 |
| oneword | 1 |
| two words | 2 |
Since you're using Oracle 11g it's even simpler-
select regexp_count(your_column, '[^ ]+') from your_table
Here is a sqlfiddle demo
If your requirement is to remove multiple spaces too, try this:
Select length('500 text Oracle Parkway Redwood Shores CA') - length(REGEXP_REPLACE('500 text Oracle Parkway Redwood Shores CA',
'( ){1,}', '')) NumbofWords
from dual;
Since I have used the dual table you can test this directly in your own development environment.
DECLARE #List NVARCHAR(MAX) = ' ab a
x'; /*Your column/Param*/
DECLARE #Delimiter NVARCHAR(255) = ' ';/*space*/
DECLARE #WordsTable TABLE (Data VARCHAR(1000));
/*convert by XML the string to table*/
INSERT INTO #WordsTable(Data)
SELECT Data = y.i.value('(./text())[1]', 'VARCHAR(1000)')
FROM
(
SELECT x = CONVERT(XML, '<i>'
+ REPLACE(#List, #Delimiter, '</i><i>')
+ '</i>').query('.')
) AS a CROSS APPLY x.nodes('i') AS y(i)
/*Your total words*/
select count(*) NumberOfWords
from #WordsTable
where Data is not null;
/*words list*/
select *
from #WordsTable
where Data is not null
/from this Logic you can continue alon/
I have a table like:
ID | Value
----------------
1 | One
2 | Two
3 | Three
What I need to do is create a single string from these values, in the format:
'1: One, 2: Two, 3: Three'
I know how to do this using cursors, but it will be used as a column in a view, so it's not really a performant option.
Any pointers?
WITH T(ID,Value) AS
(
SELECT 1, 'One' UNION ALL
SELECT 2, 'Two' UNION ALL
SELECT 3, 'Three'
)
SELECT STUFF(
(SELECT ', ' + CAST(ID as varchar(11)) + ': ' + Value
FROM T
FOR XML PATH (''))
, 1, 2, '')
Have a look at something like
DECLARE #Table TABLE(
ID INT,
Value VARCHAR(20)
)
INSERT INTO #Table SELECT 1,'One'
INSERT INTO #Table SELECT 2,'Two'
INSERT INTO #Table SELECT 3,'Three'
SELECT STUFF(
(
SELECT ', ' + CAST(ID AS VARCHAR(MAX)) + ': ' + Value
FROM #Table
FOR XML PATH(''), TYPE
).value('.','varchar(max)')
,1,2, ''
)
SELECT STUFF((
SELECT ' ' + CAST(ID AS VARCHAR(2)) + ': '+ Value
FROM dbo.Table
FOR XML PATH('')
), 1, 1, ''
) As concatenated_string
DECLARE #ans VARCHAR(max)
SET #ans=''
SELECT #ans = #ans + str(id)+':'+value FROM table
SELECT #ans
Change the max to 8000 if your version of SQL doesn't support it
I would simply not do this in the database if at all possible. It's not designed for formatting data in a certain way; let the calling application handle that.
In C# (assuming data is an instance of SqlDataReader):
var l = new List<string>();
while (reader.Read())
l.Add(string.Format("{0}: {1}", reader[0], reader[1]));
var s = string.Join(", ", l.ToArray());
Right now, I have a SQL Query like this one:
SELECT X, Y FROM POINTS
It returns results like so:
X Y
----------
12 3
15 2
18 12
20 29
I'd like to return results all in one row, like this (suitable for using in an HTML <AREA> tag):
XYLIST
----------
12,3,15,2,18,12,20,29
Is there a way to do this using just SQL?
Thanks for the quick and helpful answers guys!
I just found another fast way to do this too:
SELECT STUFF(( SELECT ',' + X + ',' + Y
FROM Points
FOR
XML PATH('')
), 1, 1, '') AS XYList
Credit goes to this guy:
Link
DECLARE #XYList varchar(MAX)
SET #XYList = ''
SELECT #XYList = #XYList + CONVERT(varchar, X) + ',' + CONVERT(varchar, Y) + ','
FROM POINTS
-- Remove last comma
SELECT LEFT(#XYList, LEN(#XYList) - 1)
Using the COALESCE trick, you don't have to worry about the trailing comma:
DECLARE #XYList AS varchar(MAX) -- Leave as NULL
SELECT #XYList = COALESCE(#XYList + ',', '') + CONVERT(varchar, X) + ',' + CONVERT(varchar, Y)
FROM POINTS
Starting in SQL 2017, you can use STRING_AGG
SELECT STRING_AGG (X + ',' + Y, ',') AS XYLIST
FROM POINTS
https://learn.microsoft.com/en-us/sql/t-sql/functions/string-agg-transact-sql?view=sql-server-2017
DECLARE #s VarChar(8000)
SET #s = ''
SELECT #s = #s + ',' + CAST(X AS VarChar) + ',' + CAST(Y AS VarChar)
FROM POINTS
SELECT #s
Just get rid of the leading comma