Related
I have a string that contains some text:
Example:
XPTOP XPTOP 4WS00632 BLACK VERNIS
I want to extract only
4WS00632
and ignore everything else.
I did try indexing the spaces, using charindex for searching all the spaces and then a substring to start at x, end at y.
But, no luck. Sometimes it returns "4WS0063" or "P 4WS00632".
This data is not coherent only "XPTOP XPTOP" is somewhat coherent.
For instance "4WS00632" this has 8 digits, but it might have 9 or 12.
So, I really need to catch everything in between the 3rd space and 4th space.
Yet another option is with a bit of JSON
Example or dbFiddle
Select A.SomeCol
,NewVal = JSON_VALUE('["'+replace(SomeCol,' ','","')+'"]','$[2]')
From YourTable A
Results
SomeCol NewVal
XPTOP XPTOP 4WS00632 BLACK VERNIS 4WS00632
Try this technique:
DECLARE #text NVARCHAR(MAX) = 'XPTOP XPTOP 4WS00632 BLACK VERNIS';
DECLARE #text_xml XML = '<a>' + REPLACE(#text, ' ', '</a><a>')+ '</a>';
WITH DataSource (element_pos, element_text) AS
(
SELECT ROW_NUMBER() OVER (ORDER BY T.c)
,T.c.value('(.)[1]', 'nvarchar(128)')
FROM #text_xml.nodes('a') T(c)
)
SELECT element_text
FROM DataSource
WHERE element_pos = 3;
The idea is to split the string by space and order the strings by their position. Then simply get the 3rd one.
One method is string_split() along with some like comparisons:
select t.*, s.value
from t cross apply
(select s.value
from string_split(t.str, ' ') s
where t.str like concat('% % % ', s.value, ' %') and
t.str not like concat('% % % % ', s.value, ' %')
) s
This is one way of using a combination of charindex and stuff.
It could be done in a single statement but I broke it into a couple of logical steps to make it clearer.
create table #test (col1 varchar(100))
insert into #test values ('XPTOP XPTOP 4WS00632 BLACK VERNIS')
with s1(s) as (select Stuff(col1,1,CharIndex(' ',col1),'') from #test),
s2(s) as (select Stuff(s,1, CharIndex(' ',s),'') from s1)
select Left(s, charIndex(' ',s) )
from s2;
Here is a solution using charindex - and substring:
Declare #testTable Table (TestString varchar(100));
Insert Into #testTable (TestString)
Values ('XPTOP XPTOP 4WS00632 BLACK VERNIS')
, ('XYZ XYZ JW2B0037VK3 S17 SENAPE BLACK');
Select tt.TestString
, part1 = ltrim(substring(v.TestString, 1, p01.pos - 2))
, part2 = ltrim(substring(v.TestString, p01.pos, p02.pos - p01.pos - 1))
, part3 = ltrim(substring(v.TestString, p02.pos, p03.pos - p02.pos - 1))
From #testTable As tt
Cross Apply (Values (concat(tt.TestString, replicate(' ', 3)))) As v(TestString)
Cross Apply (Values (charindex(' ', v.TestString, 1) + 1)) As p01(pos)
Cross Apply (Values (charindex(' ', v.TestString, p01.pos) + 1)) As p02(pos)
Cross Apply (Values (charindex(' ', v.TestString, p02.pos) + 1)) As p03(pos)
There are some objects encoded as key:value strings and stored in a table, I'd like to increase sequence number of all objects, which is one field in the object.
For example:
ID Value
--------------------------
504 s:0;d:n;e:test;
506 s:1;d:y;e:branch;
507 s:2;d:y;e:;
I'd like to change them to:
ID Value
--------------------------
504 s:1;d:n;e:test;
506 s:2;d:y;e:branch;
507 s:3;d:y;e:;
Is there a simple way to do this?
Is there a simple way to do this?
No not really.
You can find the positions of s: and d: and then use that to extract the number inbetween, increase it by one and stuff it back into where it belongs.
declare #T table
(
ID int,
Value varchar(50)
);
insert into #T values
(504, 's:0;d:n;e:test;'),
(506, 's:1;d:y;e:branch;'),
(507, 's:2;d:y;e:;');
select T.ID,
stuff(T.Value, P.S, P.D - P.S - 1, S.Value) as NewValue
from #T as T
cross apply (values(charindex('s:', T.Value) + 2,
charindex('d:', T.Value))) as P(S, D)
cross apply (values(substring(T.Value, P.S, P.D - P.S - 1) + 1)) as S(Value)
A version where you find the ; after s: instead of d: as suggested by Eric in a comment.
select T.ID,
stuff(T.Value, S.Pos, SEnd.Pos - S.Pos, V.NewValue) as NewValue
from #T as T
cross apply (values(charindex('s:', T.Value) + 2)) as S(Pos)
cross apply (values(charindex(';', T.Value, S.Pos))) as SEnd(Pos)
cross apply (values(substring(T.Value, S.Pos, SEnd.Pos - S.Pos) + 1)) as V(NewValue)
DECLARE #val nvarchar(200)
SET #val = 's:1;d:y;e:branch;'
SELECT 's:' + CONVERT(nvarchar(100), CONVERT(INT, SUBSTRING(#val, charindex(':', #val) + 1, charindex(';', #val) - charindex(':', #val) -1)) + 1) + SUBSTRING(#val, charindex(':', #val),1000)
You can use what's in the SELECT's query in an UPDATE statement to change the table values
Using the split string functions from here:Split strings the right way – or the next best way
declare #string varchar(max)
set #string='504 s:0;d:n;e:test;'
;with cte as(select * from
[dbo].[SplitStrings_Numbers]
(#string,':'))
select b.item+1 from cte c
cross apply
(select * from [dbo].[SplitStrings_Numbers](c.item,';')) b
where isnumeric(b.item)=1
This accounts for empty or non-integer values; it will ignore them in the event they can't be incremented by one.
-- Build Test Data
IF OBJECT_ID('tempdb..#test') IS NOT NULL DROP TABLE #test
CREATE TABLE #test (ID INT, Value VARCHAR(100))
INSERT #test
VALUES
(504,'s:0;d:n;e:test;'),
(506,'s:1;d:y;e:branch;'),
(507,'s:2;d:y;e:;'),
(508,'s:;d:y;e:;'),
(509,'s:xyz;d:y;e:;');
-- Update S: values
WITH sVals AS
(
SELECT ID, Value, TRY_PARSE(SUBSTRING(Value,CHARINDEX('s:',Value)+2,CHARINDEX(';',Value,CHARINDEX('s:',Value))-(CHARINDEX('s:',Value)+2)) AS INT) AS sVal
FROM #test AS t
)
UPDATE s
SET Value = IIF(sVal IS NOT NULL, STUFF(Value,CHARINDEX('s:',Value)+2,CHARINDEX(';',Value,CHARINDEX('s:',Value))-(CHARINDEX('s:',Value)+2),sVal+1), Value)
FROM sVals AS s
-- Check the results
SELECT *
FROM #test
You can as the below:
DECLARE #val VARCHAR(100) = 's:12;d:n;e:test;'
SELECT REPLACE(#val, ':' + SUBSTRING(#val, 3, PATINDEX('%;d:%', #val) - 3) + ';', ':' + CAST(SUBSTRING(#val, 3, PATINDEX('%;d:%', #val) - 3)+ 1 AS VARCHAR(MAX)) + ';')
Result: s:13;d:n;e:test;
I have data as below
98-45.3A-22
104-44.0A-23
00983-29.1-22
01757-42.5A-22
04968-37.3A2-23
Output Looking for output as below in SQL Server
00098-BA45.3A-IN-22
00104-BA44.0A-IN-23
00983-BA29.1-IN-22
01757-BA42.5A-IN-22
04968-BA37.3A2-IN-23
I splitted parts to cope with tricky data templates. This should work even with non-dash-2-digit tail:
WITH Src AS
(
SELECT * FROM (VALUES
('98-45.3A-22'),
('104-44.0A-23'),
('00983-29.1-22'),
('01757-42.5A-22'),
('04968-37.3A2-23')
) T(X)
), Parts AS
(
SELECT *,
RIGHT('00000'+SUBSTRING(X, 1, CHARINDEX('-',X, 1)-1),5) Front,
'BA'+SUBSTRING(X, CHARINDEX('-',X, 1)+1, 2) BA,
SUBSTRING(X, PATINDEX('%.%',X), LEN(X)-CHARINDEX('-', REVERSE(X), 1)-PATINDEX('%.%',X)+1) P,
SUBSTRING(X, LEN(X)-CHARINDEX('-', REVERSE(X), 1)+1, LEN(X)) En
FROM Src
)
SELECT Front+'-'+BA+P+'-IN'+En
FROM Parts
It returns:
00098-BA45.3A-IN-22
00104-BA44.0A-IN-23
00983-BA29.1-IN-22
01757-BA42.5A-IN-22
04968-BA37.3A2-IN-23
Try this,
DECLARE #String VARCHAR(100) = '98-45.3A-22'
SELECT ISNULL(REPLICATE('0',6 - CHARINDEX('-',#String)),'') -- Add leading Zeros
+ STUFF(
STUFF(#String,CHARINDEX('-',#String),1,'-BA'), -- Add 'BA'
CHARINDEX('-',#String,CHARINDEX('-',#String)+1)+2, -- 2 additional for the character 'BA'
1,'-IN') -- Add 'IN'
What if I have more than 6 digit number before first hyphen and want to remove the leading zeros to make it 6 digits.
DECLARE #String VARCHAR(100) = '0000098-45.3A-22'
SELECT CASE WHEN CHARINDEX('-',#String) <= 6
THEN ISNULL(REPLICATE('0',6 - CHARINDEX('-',#String)),'') -- Add leading Zeros
+ STUFF(
STUFF( #String,CHARINDEX('-',#String),1,'-BA'), -- Add 'BA'
CHARINDEX('-',#String,CHARINDEX('-',#String)+1)+2, -- 2 additional for the character 'BA'
1,'-IN') -- Add 'IN'
ELSE STUFF(
STUFF(
STUFF(#String,CHARINDEX('-',#String),1,'-BA'), -- Add 'BA'
CHARINDEX('-',#String,CHARINDEX('-',#String)+1)+2, -- 2 additional for the character 'BA'
1,'-IN'), -- Add 'IN'
1, CHARINDEX('-',#String) - 6, '' -- remove extra leading Zeros
)
END
Making assumptions that the format is consistent (e.g. always ends with "-" + 2 characters....)
DECLARE #Data TABLE (Col1 VARCHAR(100))
INSERT #Data ( Col1 )
SELECT Col1
FROM (
VALUES ('98-45.3A-22'), ('104-44.0A-23'),
('00983-29.1-22'), ('01757-42.5A-22'),
('04968-37.3A2-23')
) x (Col1)
SELECT RIGHT('0000' + LEFT(Col1, CHARINDEX('-', Col1) - 1), 5)
+ '-BA' + SUBSTRING(Col1, CHARINDEX('-', Col1) + 1, CHARINDEX('.', Col1) - CHARINDEX('-', Col1))
+ SUBSTRING(Col1, CHARINDEX('.', Col1) + 1, LEN(Col1) - CHARINDEX('.', Col1) - 3)
+ '-IN-' + RIGHT(Col1, 2)
FROM #Data
It's not ideal IMO to do this string manipulation all the time in SQL. You could shift it out to your presentation layer, or store the pre-formatted value in the db to save the cost of this every time.
Use REPLICATE AND CHARINDEX:
Replicate: will repeat given character till reach required count specify in function
CharIndex: Finds the first occurrence of any character
Declare #Data AS VARCHAR(50)='98-45.3A-22'
SELECT REPLICATE('0',6-CHARINDEX('-',#Data)) + #Data
SELECT
SUBSTRING
(
(REPLICATE('0',6-CHARINDEX('-',#Data)) +#Data)
,0
,6
)
+'-'+'BA'+ CAST('<x>' + REPLACE(#Data,'-','</x><x>') + '</x>' AS XML).value('/x[2]','varchar(max)')
+'-'+ 'IN'+ '-' + CAST('<x>' + REPLACE(#Data,'-','</x><x>') + '</x>' AS XML).value('/x[3]','varchar(max)')
In another way by using PARSENAME() you can use this query:
WITH t AS (
SELECT
PARSENAME(REPLACE(REPLACE(s, '.', '###'), '-', '.'), 3) AS p1,
REPLACE(PARSENAME(REPLACE(REPLACE(s, '.', '###'), '-', '.'), 2), '###', '.') AS p2,
PARSENAME(REPLACE(REPLACE(s, '.', '###'), '-', '.'), 1) AS p3
FROM yourTable)
SELECT RIGHT('00000' + p1, 5) + '-BA' + p2 + '-IN-' + p3
FROM t;
i have a table with a column have value seperated by semi colon.
the concern is value in the column are not fixed. it starts from 1 and end upto 80 semicolon sepaeration.
i am trying to put each individual value to seperate column
SQL SERVER 2008 code
DECLARE #Table TABLE(
Val VARCHAR(50)
)
INSERT INTO #Table (Val) SELECT '2Xcalcium; kidney' union all SELECT '3XMagnessium; liver' union all SELECT '2-ECG;3XSODIUM;DIALYSIS'
SELECT *,
CAST(LEFT(Val,CHARINDEX(';',Val)-1) AS VARCHAR) FirstValue,
CAST(RIGHT(Val,LEN(Val) - CHARINDEX(';',Val)) AS VARCHAR) SecondValue
FROM #Table
I tried the above code but this is limited to 2 semicolon only. please share your expertise.
Try it like this:
DECLARE #Table TABLE(
Val VARCHAR(50)
)
INSERT INTO #Table (Val) SELECT '2Xcalcium; kidney' union all SELECT '3XMagnessium; liver' union all SELECT '2-ECG;3XSODIUM;DIALYSIS';
;WITH Splitted AS
(
SELECT *
,CAST('<x>' + REPLACE(Val,';','</x><x>') + '</x>' AS XML) ValuesAsXML
FROM #Table
)
SELECT *
,ValuesAsXML.value('x[1]','varchar(max)') AS FirstCol
,ValuesAsXML.value('x[2]','varchar(max)') AS SecondCol
,ValuesAsXML.value('x[3]','varchar(max)') AS ThirdCol
,ValuesAsXML.value('x[4]','varchar(max)') AS FourthCol
,ValuesAsXML.value('x[5]','varchar(max)') AS FifthCol
FROM Splitted
The result
Val FirstCol SecondCol ThirdCol FourthCol FifthCol
2Xcalcium; kidney 2Xcalcium kidney NULL NULL NULL
3XMagnessium; liver 3XMagnessium liver NULL NULL NULL
2-ECG;3XSODIUM;DIALYSIS 2-ECG 3XSODIUM DIALYSIS NULL NULL
Most of the link provided extract the element into rows.
If you prefer to use your existing logic and extract the individual element into separate column, you can use multiple cascaded CROSS APPLY.
SELECT t.Val,
v1.V as V1,
v2.V as V2,
v3.V as V3
FROM #Table t
cross apply
(
select V = LEFT(t.Val, CHARINDEX(';', t.Val + ';') - 1),
Val = STUFF(t.Val, 1, CHARINDEX(';', t.Val + ';'), '')
) v1
cross apply
(
select V = LEFT(v1.Val, CHARINDEX(';', v1.Val + ';') - 1),
Val = STUFF(v1.Val, 1, CHARINDEX(';', v1.Val + ';'), '')
) v2
cross apply
(
select V = LEFT(v2.Val, CHARINDEX(';', v2.Val + ';') - 1),
Val = STUFF(v2.Val, 1, CHARINDEX(';', v2.Val + ';'), '')
) v3
From your question ,it seems that you have data in below format..This can be done easily with numbers table..
declare #string varchar(max)
set #string='s,t,a,c,k'
select substring(','+#string+',',n+1,charindex(',',','+#string+',',n+1)-n-1)
from
numbers
where n<=len(#string)
and substring(','+#string+',',n,1)=','
Output:
s
t
a
c
k
Few more Gems:
https://dba.stackexchange.com/questions/11506/why-are-numbers-tables-invaluable
http://sqlperformance.com/2012/07/t-sql-queries/split-strings
I have some data that I would like to split based on a delimiter that may or may not exist.
Example data:
John/Smith
Jane/Doe
Steve
Bob/Johnson
I am using the following code to split this data into First and Last names:
SELECT SUBSTRING(myColumn, 1, CHARINDEX('/', myColumn)-1) AS FirstName,
SUBSTRING(myColumn, CHARINDEX('/', myColumn) + 1, 1000) AS LastName
FROM MyTable
The results I would like:
FirstName---LastName
John--------Smith
Jane--------Doe
Steve-------NULL
Bob---------Johnson
This code works just fine as long as all the rows have the anticipated delimiter, but errors out when a row does not:
"Invalid length parameter passed to the LEFT or SUBSTRING function."
How can I re-write this to work properly?
May be this will help you.
SELECT SUBSTRING(myColumn, 1, CASE CHARINDEX('/', myColumn)
WHEN 0
THEN LEN(myColumn)
ELSE CHARINDEX('/', myColumn) - 1
END) AS FirstName
,SUBSTRING(myColumn, CASE CHARINDEX('/', myColumn)
WHEN 0
THEN LEN(myColumn) + 1
ELSE CHARINDEX('/', myColumn) + 1
END, 1000) AS LastName
FROM MyTable
For those looking for answers for SQL Server 2016+. Use the built-in STRING_SPLIT function
Eg:
DECLARE #tags NVARCHAR(400) = 'clothing,road,,touring,bike'
SELECT value
FROM STRING_SPLIT(#tags, ',')
WHERE RTRIM(value) <> '';
Reference: https://msdn.microsoft.com/en-nz/library/mt684588.aspx
Try filtering out the rows that contain strings with the delimiter and work on those only like:
SELECT SUBSTRING(myColumn, 1, CHARINDEX('/', myColumn)-1) AS FirstName,
SUBSTRING(myColumn, CHARINDEX('/', myColumn) + 1, 1000) AS LastName
FROM MyTable
WHERE CHARINDEX('/', myColumn) > 0
Or
SELECT SUBSTRING(myColumn, 1, CHARINDEX('/', myColumn)-1) AS FirstName,
SUBSTRING(myColumn, CHARINDEX('/', myColumn) + 1, 1000) AS LastName
FROM MyTable
WHERE myColumn LIKE '%/%'
SELECT CASE
WHEN CHARINDEX('/', myColumn, 0) = 0
THEN myColumn
ELSE LEFT(myColumn, CHARINDEX('/', myColumn, 0)-1)
END AS FirstName
,CASE
WHEN CHARINDEX('/', myColumn, 0) = 0
THEN ''
ELSE RIGHT(myColumn, CHARINDEX('/', REVERSE(myColumn), 0)-1)
END AS LastName
FROM MyTable
ALTER FUNCTION [dbo].[split_string](
#delimited NVARCHAR(MAX),
#delimiter NVARCHAR(100)
) RETURNS #t TABLE (id INT IDENTITY(1,1), val NVARCHAR(MAX))
AS
BEGIN
DECLARE #xml XML
SET #xml = N'<t>' + REPLACE(#delimited,#delimiter,'</t><t>') + '</t>'
INSERT INTO #t(val)
SELECT r.value('.','varchar(MAX)') as item
FROM #xml.nodes('/t') as records(r)
RETURN
END
I just wanted to give an alternative way to split a string with multiple delimiters, in case you are using a SQL Server version under 2016.
The general idea is to split out all of the characters in the string, determine the position of the delimiters, then obtain substrings relative to the delimiters. Here is a sample:
-- Sample data
DECLARE #testTable TABLE (
TestString VARCHAR(50)
)
INSERT INTO #testTable VALUES
('Teststring,1,2,3')
,('Test')
DECLARE #delimiter VARCHAR(1) = ','
-- Generate numbers with which we can enumerate
;WITH Numbers AS (
SELECT 1 AS N
UNION ALL
SELECT N + 1
FROM Numbers
WHERE N < 255
),
-- Enumerate letters in the string and select only the delimiters
Letters AS (
SELECT n.N
, SUBSTRING(t.TestString, n.N, 1) AS Letter
, t.TestString
, ROW_NUMBER() OVER ( PARTITION BY t.TestString
ORDER BY n.N
) AS Delimiter_Number
FROM Numbers n
INNER JOIN #testTable t
ON n <= LEN(t.TestString)
WHERE SUBSTRING(t.TestString, n, 1) = #delimiter
UNION
-- Include 0th position to "delimit" the start of the string
SELECT 0
, NULL
, t.TestString
, 0
FROM #testTable t
)
-- Obtain substrings based on delimiter positions
SELECT t.TestString
, ds.Delimiter_Number + 1 AS Position
, SUBSTRING(t.TestString, ds.N + 1, ISNULL(de.N, LEN(t.TestString) + 1) - ds.N - 1) AS Delimited_Substring
FROM #testTable t
LEFT JOIN Letters ds
ON t.TestString = ds.TestString
LEFT JOIN Letters de
ON t.TestString = de.TestString
AND ds.Delimiter_Number + 1 = de.Delimiter_Number
OPTION (MAXRECURSION 0)
The examples above work fine when there is only one delimiter, but it doesn't scale well for multiple delimiters. Note that this will only work for SQL Server 2016 and above.
/*Some Sample Data*/
DECLARE #mytable TABLE ([id] VARCHAR(10), [name] VARCHAR(1000));
INSERT INTO #mytable
VALUES ('1','John/Smith'),('2','Jane/Doe'), ('3','Steve'), ('4','Bob/Johnson')
/*Split based on delimeter*/
SELECT P.id, [1] 'FirstName', [2] 'LastName', [3] 'Col3', [4] 'Col4'
FROM(
SELECT A.id, X1.VALUE, ROW_NUMBER() OVER (PARTITION BY A.id ORDER BY A.id) RN
FROM #mytable A
CROSS APPLY STRING_SPLIT(A.name, '/') X1
) A
PIVOT (MAX(A.[VALUE]) FOR A.RN IN ([1],[2],[3],[4],[5])) P
These all helped me get to this. I am still on 2012 but now have something quick that will allow me to split a string, even if string has varying numbers of delimiters, and grab the nth substring from that string. It's quick too. I know this post is old, but it took me forever to find something so hopefully this will help someone else.
CREATE FUNCTION [dbo].[SplitsByIndex]
(#separator VARCHAR(20) = ' ',
#string VARCHAR(MAX),
#position INT
)
RETURNS VARCHAR(MAX)
AS
BEGIN
DECLARE #results TABLE
(id INT IDENTITY(1, 1),
chrs VARCHAR(8000)
);
DECLARE #outResult VARCHAR(8000);
WITH X(N)
AS (SELECT 'Table1'
FROM(VALUES(0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0), (0)) T(C)),
Y(N)
AS (SELECT 'Table2'
FROM X A1,
X A2,
X A3,
X A4,
X A5,
X A6,
X A7,
X A8), -- Up to 16^8 = 4 billion
T(N)
AS (SELECT TOP (ISNULL(LEN(#string), 0)) ROW_NUMBER() OVER(
ORDER BY
(
SELECT NULL
)) - 1 N
FROM Y),
Delim(Pos)
AS (SELECT t.N
FROM T
WHERE(SUBSTRING(#string, t.N, LEN(#separator + 'x') - 1) LIKE #separator
OR t.N = 0)),
Separated(value)
AS (SELECT SUBSTRING(#string, d.Pos + LEN(#separator + 'x') - 1, LEAD(d.Pos, 1, 2147483647) OVER(
ORDER BY
(
SELECT NULL
))-d.Pos - LEN(#separator))
FROM Delim d
WHERE #string IS NOT NULL)
INSERT INTO #results(chrs)
SELECT s.value
FROM Separated s
WHERE s.value <> #separator;
SELECT #outResult =
(
SELECT chrs
FROM #results
WHERE id = #position
);
RETURN #outResult;
END;
This can be used like this:
SELECT [dbo].[SplitsByIndex](' ',fieldname,2)
from tablename
I would protect the substring operation by always appending a delimiter to the test strings. This makes the parsing much simpler. Your code may now rely on finding the right pattern, and not need to cope with special cases.
SELECT SUBSTRING(myColumn + '/', 1, CHARINDEX('/', myColumn)-1) AS FirstName,
SUBSTRING(myColumn + '/', CHARINDEX('/', myColumn) + 1, 1000) AS LastName
FROM MyTable
It eliminates edge cases and conditionals and cases.
Always add an extra delimiter at the end, then the challenge case is no problem.