How can I select unique and duplicated rows exlude with different values - sql

Question

How can I fetch this table as expected in Oracle. I'm try to do this like below select but its not give me the right result. What I expect is fetch only the unique ones and exclude if these is a record like different values. Sorry for if asked before but I couldn't find it.
SELECT *
FROM ...
WHERE number IN ( SELECT name
FROM (SELECT *
FROM table
WHERE number IN ('Mel','Jose','Kim')
) ds
GROUP BY number
HAVING COUNT (*) = 1)
Current result:
number name
aaa Mel
asd Jose
fsa Jose
xdf Jose
zzz Kim
zzz Kim
Expected result:
aaa Mel
zzz Kim

Answer 1

You're close - I think you were just missing the distinct in the count in your having clause.
E.g.:
WITH your_table AS (SELECT 100 nmbr, 'Mel' NAME FROM dual UNION ALL
SELECT 112 nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 212 nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 313 nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 101 nmbr, 'Kim' NAME FROM dual UNION ALL
SELECT 101 nmbr, 'Kim' NAME FROM dual)
-- end of mimicking data in your table
-- you already have this table, so you would just need the below sql:
SELECT min(nmbr) nmbr,
NAME
FROM your_table
GROUP BY NAME
HAVING COUNT(DISTINCT nmbr) = 1;
NMBR NAME
---------- ----
101 Kim
100 Mel
Just to prove that it doesn't matter whether the nmbr column is of NUMBER or VARCHAR2 datatype:
WITH your_table AS (SELECT 'aaa' nmbr, 'Mel' NAME FROM dual UNION ALL
SELECT 'asd' nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 'fsa' nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 'xfd' nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 'zzz' nmbr, 'Kim' NAME FROM dual UNION ALL
SELECT 'zzz' nmbr, 'Kim' NAME FROM dual)
-- end of mimicking data in your table
-- you already have this table, so you would just need the below sql:
SELECT min(nmbr) nmbr,
NAME
FROM your_table
GROUP BY NAME
HAVING COUNT(DISTINCT nmbr) = 1;
NMBR NAME
---- ----
zzz Kim
aaa Mel

Answer 2

You can do by nested sql with the inner part eliminate repeating ones with respect to id & name, and in the outer part eliminate repeating ones with only name like in the following statement :
SELECT MAX(id),name
FROM (SELECT id,name FROM mytable GROUP BY id, name)
GROUP BY name
HAVING COUNT(1) = 1
ORDER BY MAX(id);
OUTPUT:
ID NAME
----- ------
100 Mel
101 Kim
D e m o 1
exactly the same sql works for your second case :
D e m o 2