I've got these two tables:
___Subscriptions
|--------|--------------------|--------------|
| SUB_Id | SUB_HotelId | SUB_PlanName |
|--------|--------------------|--------------|
| 1 | cus_AjGG401e9a840D | Free |
|--------|--------------------|--------------|
___Rooms
|--------|-------------------|
| ROO_Id | ROO_HotelId |
|--------|-------------------|
| 1 |cus_AjGG401e9a840D |
| 2 |cus_AjGG401e9a840D |
| 3 |cus_AjGG401e9a840D |
| 4 |cus_AjGG401e9a840D |
|--------|-------------------|
I'd like to select the SUB_PlanName and count the rooms with the same HotelId.
So I tried:
SELECT COUNT(*) as 'ROO_Count', SUB_PlanName
FROM ___Rooms
JOIN ___Subscriptions
ON ___Subscriptions.SUB_HotelId = ___Rooms.ROO_HotelId
WHERE ROO_HotelId = 'cus_AjGG401e9a840D'
and
SELECT
SUB_PlanName,
(
SELECT Count(ROO_Id)
FROM ___Rooms
Where ___Rooms.ROO_HotelId = ___Subscriptions.SUB_HotelId
) as ROO_Count
FROM ___Subscriptions
WHERE SUB_HotelId = 'cus_AjGG401e9a840D'
But I get empty datas.
Could you please help ?
Thanks.
You need to use GROUP BY whenever you do some aggregation(here COUNT()). Below query will give you the number of ROO_ID only for the SUB_HotelId = 'cus_AjGG401e9a840D' because you have this condition in WHERE. If you want the COUNTs for all Hotel_IDs then you can simply remove the WHERE filter from this query.
SELECT s.SUB_PlanName, COUNT(*) as 'ROO_Count'
FROM ___Rooms r
JOIN ___Subscriptions s
ON s.SUB_HotelId = r.ROO_HotelId
WHERE r.ROO_HotelId = 'cus_AjGG401e9a840D'
GROUP BY s.SUB_PlanName;
To be safe, you can also use COUNT(DISTINCT r.ROO_Id) if you don't want to double count a repeating ROO_Id. But your table structures seem to have unique(non-repeating) ROO_Ids so using a COUNT(*) should work as well.
Related
I'm trying to get the sum of two columns, but it seems to be adding incorrectly. I have a table Tbl_Booths and another table called Tbl_Extras.
In the Tbl_Booths:
BoothId | ExhId | BoothPrice
1 | 1 | 400
2 | 1 | 500
3 | 2 | 400
4 | 3 | 600
So totalBoothPrice for ExhId = 1 is 900
Tbl_Extras:
ExtraId | ExhId | Item | ItemCost
1 | 1 | PowerSupply | 400
2 | 2 | PowerSupply | 400
3 | 1 | Lights | 600
4 | 3 | PowerSupply | 400
5 | 4 | Lights | 400
So totalItemCost for ExhId = 1 is 1000
I need to find a way to get the sum of totalBoothPrice + totalItemCost
The value should of course be 900 + 1000 = 1900
I'm a total beginner to SQL so please have patience :-)
Thank you in advance for any input you can give me, since I'm going made here !
It is used in a Caspio database system.
You can use union all to combine the two tables and then aggregate:
select exhid, sum(price)
from ((select exhid, boothprice as price
from tbl_booths
) union all
(select exhid, itemcost as price
from tbl_extras
)
) e
group by exhid;
This returns the sum for all exhid values. If you want to filter them, then you can use a where clause in either the outer query or both subqueries.
Here is a db<>fiddle.
Booth totals:
select exhid, sum(boothprice) as total_booth_price
from tbl_booths
group by exhid;
Extra totals:
select exhid, sum(itemcost) as total_item_cost
from tbl_extras
group by exhid;
Joined:
select
exhid,
b.total_booth_price,
e.total_item_cost,
b.total_booth_price + e.total_item_cost as total
from
(
select exhid, sum(boothprice) as total_booth_price
from tbl_booths
group by exhid
) b
join
(
select exhid, sum(itemcost) as total_item_cost
from tbl_extras
group by exhid
) e using (exhid)
order by exhid;
This only shows exhids that have both booth and extras, though. If one can be missing use a left outer join. If one or the other can be missing, you'd want a full outer join, which MySQL doesn't support.
I still tried select all customers which is in two group. Duplicate from customers is normal because select is from invoice but I need to know the customers who had a group in the first half year and jumped to another in the second half year.
Example:
SELECT
f.eankod as kod, --(groups)
ad.kod as firma, --(markComp)
f.nazfirmy as nazev, --(nameComp)
COUNT(ad.kod),
sum(f.sumZklZakl + f.sumZklSniz + f.sumOsv) as cena_bez_dph --(Price)
FROM
ddoklfak as f
LEFT OUTER JOIN aadresar ad ON ad.idfirmy = f.idfirmy
WHERE
f.datvyst >= '2017-01-01'
and f.datvyst <= '2017-12-31'
and f.modul like 'FAV'
GROUP BY
f.eankod,
ad.kod,
f.nazfirmy
HAVING COUNT (ad.kod) > 1
order by
ad.kod
Result:
GROUP markcomp nameComp price
| D002 | B5846 | Cosmopolis | price ... |
| D003 | B6987 | Tismotis | price ... |
| D009 | B8974 | Teramis | price ... |
| D006 | B8876 | Kesmethis | price ... | I need this, same company but diferent group, because this
| D008 | B8876 | Kesmethis | price ... | company jumped. I need know only jumped company. (last two rows from examples)
Thx for help.
You can use a CTE to find out which nameComp show up multiple times, and keep those ones only. For example:
with
x as (
-- your query
)
select * from x where nameComp in (
select nameComp from x group by nameComp having count(*) > 1
)
I am new to sql so looking for a little help - got the first part down however I am having issues with the second part.
I got the three tables tied together. First I needed to tie tblPatient.ID = tblPatientVisit.PatientID together to eliminate dups which works
Now I need to take those results and eliminate dups in the MRN but my query is only returning one result which is WRONG - LOL
Query
select
tblPatient.id,
tblPatient.firstname,
tblPatient.lastname,
tblPatient.dob,
tblPatient.mrn,
tblPatientSmokingScreenOrder.SmokeStatus,
tblPatientVisit.VisitNo
from
tblPatient,
tblPatientSmokingScreenOrder,
tblPatientVisit
Where
tblPatient.ID = tblPatientVisit.PatientID
and tblPatientVisit.ID = tblPatientSmokingScreenOrder.VisitID
and tblPatient.ID in(
Select Distinct
tblPatient.mrn
From
tblPatient
where
isdate(DOB) = 1
and Convert(date,DOB) <'12/10/2000'
and tblPatientVisit.PatientType = 'I')
Actual Results:
ID | firstName | LastName | DOB | MRN | SmokeStatus | VisitNO
12 | Test Guy | Today | 12/12/1023 | 0015396 | Never Smoker | 0013957431
Desired Results:
90 | BOB | BUILDER | 02/24/1974 | 0015476 | Former Smoker | 0015476001
77 | DORA | EXPLORER | 06/04/1929 | 0015463 | Never Smoker | 0015463001
76 | MELODY | VALENTINE | 09/17/1954 | 0015461 | Current | 0015461001
32 | STRAWBERRY | SHORTCAKE | 07/06/1945 | 0015415 | Current | 0015415001
32 | STRAWBERRY | SHORTCAKE | 07/06/1945 | 0015415 | Never Smoker | 0015415001
32 | STRAWBERRY | SHORTCAKE | 07/06/1945 | 0015415 | Former Smoker | 0015415001
12 | Test Guy | Today | 12/12/1023 | 0015345 | Never Smoker | 0013957431
Anyone have any suggestions on how I go down to the next level and get all the rows with one unique MRN. From the data above I should have 5 in my list. Any help would be appreciated.
Thanks
If I had to guess -- The only thing that looks odd (but maybe it's OK) is that you're comparing patient.ID from your parent query to patient.mrn in the subquery.
Beyond that -- things to check:
(1)
Do you get all your patients with the inner query?
Select Distinct
tblPatient.mrn
From
tblPatient
where
isdate(DOB) = 1
and Convert(date,DOB) <'12/10/2000'
and tblPatientVisit.PatientType = 'I'
(2)
What is your patient type for the missing records? (Your filtering it to tblPatientVisit.PatientType = 'I' -- do the missing records have that patient type as well?)
Perhaps you need to invert the logic here. As in,
Select Distinct
patients.mrn1
From (select
tblPatient.id as id1,
tblPatient.firstname as firstname1,
tblPatient.lastname as lastname1,
tblPatient.dob as DOB1,
tblPatient.mrn as mrn1,
tblPatientSmokingScreenOrder.SmokeStatus as SmokeStatus1,
tblPatientVisit.VisitNo as VisitNo1,
tblPatientVisit.PatientType as PatientType1,
from
tblPatient,
tblPatientSmokingScreenOrder,
tblPatientVisit
Where
tblPatient.ID = tblPatientVisit.PatientID
and tblPatientVisit.ID = tblPatientSmokingScreenOrder.VisitID
) as patients
where
isdate(patients.DOB1) = 1
and Convert(date,patients.DOB1) <'12/10/2000'
and patients.PatientType1 = 'I');
Cleaned it up a bit and I think they were right. MRN wont match patient id, at least not from your example data. You should not need an inner query. This query should give you what you want.
SELECT DISTINCT
p.id,
p.firstname,
p.lastname,
p.dob,
p.mrn,
s.SmokeStatus,
v.VisitNo
FROM
tblPatient p
JOIN tblPatientVisit v ON p.id = v.patientId
JOIN tblPatientSmokingScreenOrder s ON v.id = s.visitId
WHERE
isdate(p.DOB) = 1
AND CONVERT(date,p.DOB) <'12/10/2000'
AND v.PatientType = 'I'
i have a little problem with an Access query ( dont ask me why but i cannot use a true SGBD but Access )
i have a huge table with like 920k records
i have to loop through all those data and grab the ref that occur more than 5 time on the same date
table = myTable
--------------------------------------------------------------
| id | ref | date | C_ERR_ANO |
--------------------------------------------|-----------------
| 1 | A12345678 | 2012/02/24 | A 4565 |
| 2 | D52245708 | 2011/05/02 | E 5246 |
| ... | ......... | ..../../.. | . .... |
--------------------------------------------------------------
so to resume it a bit, i have like 900000+ records
there is duplicates on the SAME DATE ( oh by the way there is another collumn i forgot to add that have C_ERR_ANO as name)
so i have to loop through all those row, grab each ref based on date AND errorNumber
and if there is MORE than 5 time with the same errorNumber i have to grab them and display it in the result
i ended up using this query:
SELECT DISTINCT Centre.REFERENCE, Centre.DATESE, Centre.C_ERR_ANO
FROM Centre INNER JOIN (SELECT
Centre.[REFERENCE],
COUNT(*) AS `toto`,
Centre.DATESE
FROM Centre
GROUP BY REFERENCE
HAVING COUNT(*) > 5) AS Centre_1
ON Centre.REFERENCE = Centre_1.REFERENCE
AND Centre.DATESE <> Centre_1.DATESE;
but this query isent good
i tried then
SELECT DATESE, REFERENCE, C_ERR_ANO, COUNT(REFERENCE) AS TOTAL
FROM (
SELECT *
FROM Centre
WHERE (((Centre.[REFERENCE]) NOT IN (SELECT [REFERENCE]
FROM [Centre] AS Tmp
GROUP BY [REFERENCE],[DATESE],[C_ERR_ANO]
HAVING Count(*)>1 AND [DATESE] = [Centre].[DATESE]
AND [C_ERR_ANO] = [Centre].[C_ERR_ANO]
AND [LIBELLE] = [Centre].[LIBELLE])))
ORDER BY Centre.[REFERENCE], Centre.[DATESE], Centre.[C_ERR_ANO])
GROUP BY REFERENCE, DATESE, C_ERR_ANO
still , not working
i'm struggeling
Your group by clause needs to include all of the items in your select. Why not use:
select Centre.DATESE, Centre.C_ERR_ANO, Count (*)
Group by Centre.DATESE, Centre.C_ERR_ANO
HAVING COUNT (*) > 5
If you need other fields then you can add them, as long as you ensure the same fields appear in the select as the group by.
No idea what is going on with the formatting here!
I am trying to select the max value from one column, while grouping by another non-unique id column which has multiple duplicate values. The original database looks something like:
mukey | comppct_r | name | type
65789 | 20 | a | 7n
65789 | 15 | b | 8m
65789 | 1 | c | 1o
65790 | 10 | a | 7n
65790 | 26 | b | 8m
65790 | 5 | c | 1o
...
This works just fine using:
SELECT c.mukey, Max(c.comppct_r) AS ComponentPercent
FROM c
GROUP BY c.mukey;
Which returns a table like:
mukey | ComponentPercent
65789 | 20
65790 | 26
65791 | 50
65792 | 90
I want to be able to add other columns in without affecting the GROUP BY function, to include columns like name and type into the output table like:
mukey | comppct_r | name | type
65789 | 20 | a | 7n
65790 | 26 | b | 8m
65791 | 50 | c | 7n
65792 | 90 | d | 7n
but it always outputs an error saying I need to use an aggregate function with select statement. How should I go about doing this?
You have yourself a greatest-n-per-group problem. This is one of the possible solutions:
select c.mukey, c.comppct_r, c.name, c.type
from c yt
inner join(
select c.mukey, max(c.comppct_r) comppct_r
from c
group by c.mukey
) ss on c.mukey = ss.mukey and c.comppct_r= ss.comppct_r
Another possible approach, same output:
select c1.*
from c c1
left outer join c c2
on (c1.mukey = c2.mukey and c1.comppct_r < c2.comppct_r)
where c2.mukey is null;
There's a comprehensive and explanatory answer on the topic here: SQL Select only rows with Max Value on a Column
Any non-aggregate column should be there in Group By clause .. why??
t1
x1 y1 z1
1 2 5
2 2 7
Now you are trying to write a query like:
select x1,y1,max(z1) from t1 group by y1;
Now this query will result only one row, but what should be the value of x1?? This is basically an undefined behaviour. To overcome this, SQL will error out this query.
Now, coming to the point, you can either chose aggregate function for x1 or you can add x1 to group by. Note that this all depends on your requirement.
If you want all rows with aggregation on z1 grouping by y1, you may use SubQ approach.
Select x1,y1,(select max(z1) from t1 where tt.y1=y1 group by y1)
from t1 tt;
This will produce a result like:
t1
x1 y1 max(z1)
1 2 7
2 2 7
Try using a virtual table as follows:
SELECT vt.*,c.name FROM(
SELECT c.mukey, Max(c.comppct_r) AS ComponentPercent
FROM c
GROUP BY c.muke;
) as VT, c
WHERE VT.mukey = c.mukey
You can't just add additional columns without adding them to the GROUP BY or applying an aggregate function. The reason for that is, that the values of a column can be different inside one group. For example, you could have two rows:
mukey | comppct_r | name | type
65789 | 20 | a | 7n
65789 | 20 | b | 9f
How should the aggregated group look like for the columns name and type?
If name and type is always the same inside a group, just add it to the GROUP BY clause:
SELECT c.mukey, Max(c.comppct_r) AS ComponentPercent
FROM c
GROUP BY c.muke, c.name, c.type;
Use a 'Having' clause
SELECT *
FROM c
GROUP BY c.mukey
HAVING c.comppct_r = Max(c.comppct_r);