raw SQL to laravel query - sql

Question

Can anybody please help me to write a DB query version of the SQL statement below.
I need a little help around the select statement and the partitioned joins.
I have managed to do this so far.
$query = DB::table(raw('SapakInAdminOrder a'))
->select(raw('a.*'))
->leftJoin(raw('currency cu'), 'a.currency', '=', 'cu.id')
->leftJoin(raw('moodboards m'), 'a.orderMoodboardID', '=', 'm.id')
->join(raw('clients b'), 'a.clientID', '=', 'b.id')
->leftJoin(raw('moodboards mc'), 'b.moodboardID', 'mc.id')
->join(raw('sapakim c'), 'b.sapakID', '=', 'c.id')
->leftJoin(raw('sapakim sm'), 'c.managerid', '=', 'sm.id')
->leftJoin(raw('products p'), 'a.productKey', '=', 'p.id')
->where(function ($query) {
$query->whereNull('a.isDeleted');
$query->orWhere('a.isDeleted', '!=', 1);
});
But I need to achieve this.
select * from (select ROW_NUMBER() OVER(ORDER BY case when (indesign.status=4 or indesign.statusdate is null) then getdate()+2 else indesign.statusdate end ASC) AS RowNum,a.*
FROM sapakInAdminOrder a
left join currency cu on cu.id=a.currency
left join moodboards m on m.id=a.orderMoodboardID
inner join Clients b on a.clientID=b.id
left join moodboards mc on mc.id=b.moodboardID
inner join Sapakim c on b.sapakID=c.id
left join Sapakim sm on sm.id=c.managerid
left join products p on p.id=a.productKey
left join (select * from (select ROW_NUMBER() over(PARTITION BY orderID ORDER BY id DESC) r, * from orderCommunication ) f where r=1) chat on chat.orderId = a.id
left join (select id,[status],orderid,approveSMSDate,coverImage,statusDate from (SELECT id,[status],statusDate,approveSMSDate,coverImage,orderid,ROW_NUMBER() OVER(PARTITION BY orderid ORDER BY id DESC) AS r FROM SapakimInAdminDesigns) f where r=1) indesign on a.id=indesign.orderid
where (a.isDeleted is null or a.isDeleted != 1) and
c.inAdminManagerID=(select id from sapakim where sapakguid='test') and
c.sapakguid='test' and
a.isFreeDesign=0 and
a.transactionID = -1 and
(a.designerPaid is null or a.designerPaid=0) and
(chat.sentToPrinter is null and chat.sentToManager is null and chat.sentToDesigner is null)
) bb where RowNum>=1 and RowNum<31
ORDER BY RowNum asc
I can do the simple ones but couldn't quite really wrap my head around the partitioned joins and the select statement.
I would really appreciate a help on this.
Thanks in advance.

Answer 1

Maybe you should create a database view for these partitioned queries?
Then you can join the view from database afterwards.
Technically these analytical functions are usually not supported by frameworks.

Answer 2

You can use the following package for this purpose.
Features
Converts SQL Queries to Laravel Query Builder.
Assists on building queries as instructed in Laravel Documentation.
Provides options to interact with, for generating different results.
SQL to Laravel Query Builder, A Converter written in PHP

Answer 3

I am also stuck with this type of problem but I got a solution and its working fine for me!
use DB::unprepared() for this type of query :
$path = base_path() . "/storage/agency.sql";
$sql = file_get_contents($path);
DB::unprepared(DB::raw($sql));
All SQL commands in Laravel are prepared by default, but sometimes you need to execute a command in an unprepared mode, because some commands in some database cannot be ran in prepared mode.

Answer 4

Is this what you meant?
$result = DB::Select("select * from (select ROW_NUMBER() OVER(ORDER BY case when (indesign.status=4 or indesign.statusdate is null) then getdate()+2 else indesign.statusdate end ASC) AS RowNum,a.*
FROM sapakInAdminOrder a
left join currency cu on cu.id=a.currency
left join moodboards m on m.id=a.orderMoodboardID
inner join Clients b on a.clientID=b.id
left join moodboards mc on mc.id=b.moodboardID
inner join Sapakim c on b.sapakID=c.id
left join Sapakim sm on sm.id=c.managerid
left join products p on p.id=a.productKey
left join (select * from (select ROW_NUMBER() over(PARTITION BY orderID ORDER BY id DESC) r, * from orderCommunication ) f where r=1) chat on chat.orderId = a.id
left join (select id,[status],orderid,approveSMSDate,coverImage,statusDate from (SELECT id,[status],statusDate,approveSMSDate,coverImage,orderid,ROW_NUMBER() OVER(PARTITION BY orderid ORDER BY id DESC) AS r FROM SapakimInAdminDesigns) f where r=1) indesign on a.id=indesign.orderid
where (a.isDeleted is null or a.isDeleted != 1) and
c.inAdminManagerID=(select id from sapakim where sapakguid='test') and
c.sapakguid='test' and
a.isFreeDesign=0 and
a.transactionID = -1 and
(a.designerPaid is null or a.designerPaid=0) and
(chat.sentToPrinter is null and chat.sentToManager is null and chat.sentToDesigner is null)
) bb where RowNum>=1 and RowNum<31
ORDER BY RowNum asc");

Answer 5

Check out this new Laravel tool called Orator. It lets you simply paste "legacy" SQL and returns Laravel's DB Query Builder syntax.
Laravel Orator News Article
Online Conversion Tool

Answer 6

Assuming you want to display this on the frontend use the relationships wit the eloquent model,
https://laravel.com/docs/master/eloquent-relationships#one-to-one
In the model User there is a One to One relation called identified by the method phone(), if you go to the show view which im assuming passes a $user variable do the following
<?php dd($user->phone); ?>
I might be missing the whole point of the question if you don't mean this.