I have two date columns and I would like to calculate their differences in Months/Days and exclude years.
Assuming the first date is 10/30/2017, comparing it to the current date, its difference should one. If the current date is 10/30/2018, the difference should also be one.
A few examples:
Schedule Date:10/30/2017 Current Date 10/29/2017 Diff 1
Schedule Date:10/30/2017 Current Date 11/30/2017 Diff 30
Schedule Date:10/30/2017 Current Date 10/29/2018 Diff 1
Schedule Date:10/30/2017 Current Date 11/30/2018 Diff 30
Schedule Date:10/30/2017 Current Date 10/29/2019 Diff 1
Schedule Date:10/30/2017 Current Date 11/30/2019 Diff 30
Try This
SELECT ABS(365 * DATEDIFF(year, '10/30/2017', '11/30/2018')
- DATEDIFF(day, '10/30/2017', '11/30/2018')) AS DateDiff;
Note that the difference between 10/30/ and 11/30/ can't be 30 days as you have shown.It is 31 days.
You can use Common Table Expression to get your results like below :
DECLARE #Schedule_Date datetime = '10/30/2017'
DECLARE #Current_Date datetime = '11/30/2019'
;WITH usingCTE AS
(
SELECT CAST(STUFF(CONVERT(varchar, #Schedule_Date, 102), 1, 4, CAST(YEAR(#Current_Date) AS varchar)) AS datetime) AS Schedule_Date
)
SELECT abs(DATEDIFF(day, #Current_Date, Schedule_Date)) FROM usingCTE
Another approach of the query :
DECLARE #Schedule_Date datetime = '10/30/2017'
DECLARE #Current_Date datetime = '11/30/2017'
SELECT ABS(DATEDIFF(day,
REPLACE(#Schedule_Date, DATEPART(year, #Schedule_Date),
DATEPART(year, #Current_Date)), -- replace the year with current year
#Current_Date))
This might work for you, first adjust the date to be in the same year, then calculate the number of days different between the two dates:
DECLARE #ScheduleDate DATE = '2017-10-30';
DECLARE #Dates TABLE (CurrentDate DATE);
INSERT INTO #Dates VALUES ('2017-10-29'),('2017-11-30'),('2018-10-29'),('2018-11-30'),('2019-10-29'),('2019-11-30');
SELECT #ScheduleDate ScheduleDate, *
FROM #Dates a
CROSS APPLY (SELECT AdjustedDate=DATEADD(YEAR, YEAR(#ScheduleDate) - YEAR(a.CurrentDate), a.CurrentDate)) b
CROSS APPLY (SELECT Diff=ABS(DATEDIFF(DAY, #ScheduleDate, b.AdjustedDate))) c
Related
I have a problem where I need to query a database which includes multiple lines of trade activity for the past 90 days. Currently the query is built to determine the average amount over the 90 day period - so each day has a single exposure value and the query helps us determine the average exposure over 90 days by just summing the daily values and then dividing by 90. And it does this as the date rolls forward, so the value is updated each day the query is run.
The above is simple enough to execute, but now I need to determine the average month-end amounts for the past 3 months. I've figured out how to pull just month-end dates, but not sure how to join that with the current query. Additionally, needs to be able to update itself rolling forward.
/* Test query below */
DECLARE #Date DATETIME = Getdate()
DECLARE #daycount INT = 90
DECLARE #startDate DATETIME = Dateadd(dd, #daycount*-1, #Date)
SELECT sub.Instrument,
( Sum(sub.GrossExposure) / #daycount ) AS AvgGrossExposure
FROM (SELECT DateField,
Instrument,
GrossExposure
FROM table
WHERE DateField <= #Date
AND Datefield >= #startDate
) sub
GROUP BY Instrument
To calculate month-ends in the past 90 days, I've fiddled around with this, but it also includes today's date and I do not need that value in this case.
/* Test query for month-end dates, past 90 days */
DECLARE #Date DATETIME = GetDate()
DECLARE #daycount INT = 90
DECLARE #startDate DATETIME = Dateadd(dd, #daycount*-1, #Date)
SELECT max(datefield) AS month_ends
FROM table
WHERE datefield <= #Date
AND datefield >= #startDate
GROUP BY month(datefield),
year(datefield)
ORDER BY month_ends
Give this a try - you can use a common table expression to append the month end date of each DateField value using EOMONTH(DateField), and then use that in your GROUP BY, with the Average of all GrossExposure values that have that same EOMONTH value for each instrument.
WITH CTE AS (
SELECT EOMONTH(DateField) AS EndOfMonthDate
,DateField
,Instrument
,GrossExposure
FROM TABLE
WHERE DateField BETWEEN GETDATE()-90 AND GETDATE()
)
SELECT CTE.Instrument,
CTE.EndOfMonthDate,
AVG(CTE.GrossExposure) AS AvgGrossExposure
FROM CTE
GROUP BY CTE.Instrument, CTE.EndOfMonthDate
I am trying to script a query that inserts a date into a table every 7 days for the next 10 years. This will prevent me from having to have to type these dates by hand.
Is there a way to specify a start date and add 7 days to that date on each insert until the end date is reached?
Attached is my query. not sure where to being on this one. Any help is most appreciated.
declare #startDate date
declare #endDate date
set #startDate='2015-01-03'
set #endDate='2015-01-04'
INSERT INTO TimePeriod (YearsA)
VALUES ('2015-01-03'),
('2015-01010'),
(etc.)
('2025-01-04)
The below query will give you weekend dates for till 2042-05-17 years.
SELECT DISTINCT DATEADD(DAY, - DATEPART(WEEKDAY, DayNumber), CAST(DayNumber AS DATE))
FROM(
SELECT TOP (10000)
DATEADD(DAY
,ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) -1
, CAST(YEAR(GETDATE()) AS VARCHAR(4)) + '0101' ) DayNumber
From master..spt_values x Cross Join master..spt_values y
)x
ORDER BY DATEADD(DAY, - DATEPART(WEEKDAY, DayNumber), CAST(DayNumber AS DATE))
Result
2015-01-03
2015-01-10
2015-01-17
2015-01-24
2015-01-31
2015-02-07
2015-02-14
2015-02-21
2015-02-28
You can use recursive CTE to get all the dates:
try;
declare #startDate date
declare #endDate date
set #startDate='2015-03-01' -- YYYY-MM-DD format
set #endDate='2015-04-01'
;with all_date as (
select #startDate Dates
union all
select DATEADD(day, 7, Dates)
from all_date
where Dates < #endDate
)
INSERT INTO TimePeriod (YearsA)
select Dates from all_date
I need to find anniversary date and anniversary year of employees and send email in every 14 days.But I have a problem with last week of December when using the following query if start date and end date are in different years.
Select * from Resource
where (DATEPART(dayofyear,JoinDate)
BETWEEN DATEPART(dayofyear,GETDATE())
AND DATEPART(dayofyear,DateAdd(DAY,14,GETDATE())))
Instead of comparing to a dayofyear (which resets to zero at jan 1st and is the reason your query breaks within 14 days of the end of the year) you could update the employee's joindate to be the current year for the purpose of the query and just compare to actual dates
Select * from Resource
-- Add the number of years difference between joinDate and the current year
where DATEADD(year,DATEDIFF(Year,joinDate,GetDate()),JoinDate)
-- compare to range "today"
BETWEEN GetDate()
-- to 14 days from today
AND DATEADD(Day,14,GetDate())
-- duplicate for following year
OR DATEADD(year,DATEDIFF(Year,joinDate,GetDate())+1,JoinDate) -- 2016-1-1
BETWEEN GetDate()
AND DATEADD(Day,14,GetDate())
Test query:
declare #joindate DATETIME='2012-1-1'
declare #today DATETIME = '2015-12-26'
SELECT #joinDate
where DATEADD(year,DATEDIFF(Year,#joinDate,#today),#JoinDate) -- 2015-1-1
BETWEEN #today -- 2015-12-26
AND DATEADD(Day,14,#today) -- 2016-01-09
OR DATEADD(year,DATEDIFF(Year,#joinDate,#today)+1,#JoinDate) -- 2016-1-1
BETWEEN #today -- 2015-12-26
AND DATEADD(Day,14,#today) -- 2016-01-09
(H/T #Damien_The_Unbeliever for a simple fix)
The above correctly selects the joinDate which is in the first week of Jan (note I've had to fudge #today as Ive not managed to invent time travel).
The above solution should also solve the issue with leap years that was hiding in your original solution.
Update
You expressed in comments the requirement to select AnniversaryDate and Years of service, you need to apply some CASE logic to determine whether to add 1 (year or date) to your select
select *,
CASE
WHEN DATEADD(YEAR,DATEDIFF(Year,JoinDate,GETDATE()),JoinDate) < GetDate()
THEN DATEDIFF(Year,JoinDate,GETDATE())+1
ELSE DATEDIFF(Year,JoinDate,GETDATE())
END as [Years],
CASE WHEN DATEADD(YEAR,DATEDIFF(Year,JoinDate,GETDATE()),JoinDate) < GetDate()
THEN DATEADD(YEAR,DATEDIFF(Year,JoinDate,GETDATE())+1,JoinDate)
ELSE DATEADD(YEAR,DATEDIFF(Year,JoinDate,GETDATE()),JoinDate)
end as [AnniversaryDate]
.... // etc
You could do this:
Select * from Resource
where DATEPART(dayofyear,JoinDate)
BETWEEN DATEPART(dayofyear,GETDATE())
AND DATEPART(dayofyear,DateAdd(DAY,14,GETDATE()))
OR
DATEPART(dayofyear,JoinDate)
BETWEEN (DATEPART(dayofyear,GETDATE()) + 365)
AND (DATEPART(dayofyear,DateAdd(DAY,14,GETDATE())) + 365)
Try this:
DECLARE #Today DATE = GETDATE() --'12/25/2013'
DECLARE #Duration INT = 14
;WITH Recur AS
(
SELECT #Today AS RecurDate
UNION ALL
SELECT DATEADD(DAY, 1, RecurDate)
FROM Recur
WHERE DATEDIFF(DAY, #Today, RecurDate)+1 < #Duration
)
SELECT
r.*
FROM
Resource r
JOIN Recur
ON CONVERT(VARCHAR(5), JoinDate, 101) = CONVERT(VARCHAR(5), RecurDate, 101)
WHERE JoinDate < #Today
You can use the SQL DATEADD() function with week number parameter
Here is how you can use it:
DECLARE #date date = getdate()
Select * from Resource
where
JoinDate BETWEEN #date AND DATEADD(ww,2,#date)
I am looking for an SQL query for the sum of minutes between start and end date for a particular month.
Eg.
I'm looking for the amount of minutes used in February.
Start Date Time: 27-02-13 00:00:00
End Date Time: 05-03-13 00:00:00
Because im only looking for the sum of february it should only give me the sum of 3 days (in minutes) and not the extra 5 days going into march.
I have no way to validate it but it should looks like:
SELECT DATEDIFF(minute, startDate, CASE when endDate > EOMONTH(startDate) THEN EOMONTH(startDate) ELSE endDate END) FROM ...
GL!
I left it in steps to illustrate each process. You can of course easily collapse this down, but I'll leave it up to you to do that.
Here's my solution http://www.sqlfiddle.com/#!3/b4991/1/0
SELECT *
, DATEDIFF(minute, StartDAte, NewEndDate) AS TotalMinutes
FROM
(
SELECT *
, CASE WHEN TempDate > EndDate THEN EndDate ELSE TempDate END AS NewEndDate -- Either EOM or old EndDate, whichever is smaller
FROM
(
SELECT *
, DATEADD(month, 1, CAST(Year + '-' + Month + '-1' AS DATETIME)) AS TempDate -- first day of the next month
FROM
(
select *
, CAST(DATEPART(month, StartDate) AS char(2)) AS Month
, CAST(DATEPART(year, StartDate) AS char(4)) AS Year
from tbl
) t0
) t1
) t2
First I get the year and month from the original StartDate. I then construct a first-of-the-month date from that. I then add one month to that to get me the first-of-the-month of the next month. Then I check if that new date is > or < the previous EndDate. I take the smaller of the two dates. Then I use the original StartDate and whichever is smaller between the TempDate and EndDate to determine my total minutes.
See Also EOMONTH: http://msdn.microsoft.com/en-us/library/hh213020.aspx
Look into using DATEDIFF -- this will just help you to get started:
SELECT DATEDIFF(minute, starttime, endtime)
http://msdn.microsoft.com/en-us/library/ms189794.aspx
To get the last day of the start month, use DATEADD:
SELECT DATEADD(second,-1,DATEADD(month, DATEDIFF(month,0,starttime)+1,0))
SQL Fiddle Demo
I recently had to solve a similar problem, I added two new functions to help with this:
CREATE FUNCTION [dbo].[GREATESTDATE]
(
-- Add the parameters for the function here
#Date1 DATETIME,
#Date2 DATETIME
)
RETURNS DATETIME
AS
BEGIN
IF (#Date1 < #Date2)
RETURN #Date2
ELSE
RETURN #Date1
END
and...
CREATE FUNCTION [dbo].[LEASTDATE]
(
-- Add the parameters for the function here
#Date1 DATETIME,
#Date2 DATETIME
)
RETURNS DATETIME
AS
BEGIN
IF (#Date1 > #Date2)
RETURN #Date2
ELSE
RETURN #Date1
END
Then use them like:
DATEDIFF(D,dbo.GREATESTDATE(#StartDate1,#StartDate2),dbo.LEASTDATE(#EndDate1,#EndDate2))
I'm attempting to group contiguous date ranges to show the minimum and maximum date for each range. So far I've used a solution similar to this one: http://www.sqlservercentral.com/articles/T-SQL/71550/ however I'm on SQL 2000 so I had to make some changes. This is my procedure so far:
create table #tmp
(
date smalldatetime,
rownum int identity
)
insert into #tmp
select distinct date from testDates order by date
select
min(date) as dateRangeStart,
max(date) as dateRangeEnd,
count(*) as dates,
dateadd(dd,-1*rownum, date) as GroupID
from #tmp
group by dateadd(dd,-1*rownum, date)
drop table #tmp
It works exactly how I want except for one issue: weekends. My data sets have no records for weekend dates, which means any group found is at most 5 days. For instance, in the results below, I would like the last 3 groups to show up as a single record, with a dateRangeStart of 10/6 and a dateRangeEnd of 10/20:
Is there some way I can set this up to ignore a break in the date range if that break is just a weekend?
Thanks for the help.
EDITED
I didn't like my previous idea very much. Here's a better one, I think:
Based on the first and the last dates from the set of those to be grouped, prepare the list of all the intermediate weekend dates.
Insert the working dates together with weekend dates, ordered, so they would all be assigned rownum values according to their normal order.
Use your method of finding contiguous ranges with the following modifications:
1) when calculating dateRangeStart, if it's a weekend date, pick the nearest following weekday;
2) accordingly for dateRangeEnd, if it's a weekend date, pick the nearest preceding weekday;
3) when counting dates for the group, pick only weekdays.
Select from the resulting set only those rows where dates > 0, thus eliminating the groups formed only of the weekends.
And here's an implementation of the method, where it is assumed, that a week starts on Sunday (DATEPART returns 1) and weekend days are Sunday and Saturday:
DECLARE #tmp TABLE (date smalldatetime, rownum int IDENTITY);
DECLARE #weekends TABLE (date smalldatetime);
DECLARE #minDate smalldatetime, #maxDate smalldatetime, #date smalldatetime;
/* #1 */
SELECT #minDate = MIN(date), #maxDate = MAX(date)
FROM testDates;
SET #date = #minDate - DATEPART(dw, #minDate) + 7;
WHILE #date < #maxDate BEGIN
INSERT INTO #weekends
SELECT #date UNION ALL
SELECT #date + 1;
SET #date = #date + 7;
END;
/* #2 */
INSERT INTO #tmp
SELECT date FROM testDates
UNION
SELECT date FROM #weekends
ORDER BY date;
/* #3 & #4 */
SELECT *
FROM (
SELECT
MIN(date + CASE DATEPART(dw, date) WHEN 1 THEN 1 WHEN 7 THEN 2 ELSE 0 END)
AS dateRangeStart,
MAX(date - CASE DATEPART(dw, date) WHEN 1 THEN 2 WHEN 7 THEN 1 ELSE 0 END)
AS dateRangeEnd,
COUNT(CASE WHEN DATEPART(dw, date) NOT IN (1, 7) THEN date END) AS dates,
DATEADD(d, -rownum, date) AS GroupID
FROM #tmp
GROUP BY DATEADD(d, -rownum, date)
) s
WHERE dates > 0;