Sometimes I would find very useful to search (ctrl - shift - f) in intellij idea all files containing "string1" AND "string2".
Is this somehow possible?
Search for string1, then for string2 while using scope Files in Previous Search Result
You could use a regex search. Here's an example:
This regex: (?s)^(?=.*?string1)(?=.*?string2) matches any file that contains both strings, it doesn't care about order (i.e. which string comes first in a given file) nor does it care about the number of strings you search for so you can add additional criteria by appending another (?=.*?_your_text_here).
In addition, it can be easily extended to cover logical ORs ...
(?s)^(?=.*?string1)|(?=.*?string2)
Related
I find what I want by using regex search, let's say I find all the telphone numbers in my file using regex and then I want to add a string "(+1)" in front of the results I found. What should I put in the "replace" input?
Is this possible? I searched a lot but all I found is that how to use regex and replace the whole stuff.
All.
I am used to programming VBA in Excel, but am new to the structures in Word.
I am working through a library of text files to update them. Many of them are either OCR documents, or were manually entered.
Each has a recurring pattern, the most common of which is unnecessary carriage returns.
For example, I am looking at several text files where there is a double return after each line. A search and replace of all double carriage returns removes all paragraph distinctions.
However, each line is approximately 30 characters long, and if I manually perform the following logic, it gives me a functional document.
If there is a double carriage return after 30+ characters, I replace them with a space.
If there were less than 30 characters prior to the double return, I replace them with a single return.
Can anyone help me with some rudimentary code that would help me get started on that? I could then modify it for each "pattern" of text documents I have.
e.g.
In this case, there are more than
thirty characters per line. And I
will keep going to illustrate this
example.
This would be a new paragraph, and
would be separated by another of
the single returns.
I want code that would return:
In this case, there are more than thirty character returns. And I will keep going to illustrate this example.
This would be a new paragraph, and would be separated by another of the single returns.
Let me know if anyone can throw something out that I can play with!
You can do this without code (which RegEx requires), simply using Word's own wildcard Find/Replace tools, where:
Find = ([!^13]{30,})[^13]{1,}
Replace = \1^32
and, to clean up the residual multi-paragraph breaks:
Find = [^13]{2,}
Replace = ^p
You could, of course, record the above as a macro...
Here is a RegEx that might work for you:
(\n\n)(?<!\.(\n\n))
The substitution is just a plain space, you can try it out (and modify / tweak it) here: https://regex101.com/r/zG9GPw/4
This 'pattern' tells the RegEx engine to look for the newline character \n which occurs x2 like this \n\n (worth noting this is from your question and might be different in your files, e.g. could be \r\n) and it assumes that a valid line break will be proceeded by a full stop: \..
In RegEx the full stop symbol is a single character wild card so it needs to be escaped with the '\' (n and r are normal characters, escaping them tells the RegEx engine they represent newline and return characters).
So... the expression is looking for a group of x2 newline characters but then uses a negative look-behind to exclude any matches where the previous character was a full stop.
Anyway, it's all explained on the site:
Here is how you could do a RegEx find and replace using NotePad++ (I'm not sure if it comes with RegEx or if a plugin is needed, either way it is easy). But you can set a location, filters (to target specific file types), and other options (such as search in sub-directories).
Other than that, as #MacroPod pointed out you could also do this with MS Word, document by document, not using any code :)
I have a localized string that looks something like this in English:
"
5 Mile(s)
5,252 Step(s)
"
My app is localized both in left-to-right and right-to-left languages so I don't want to make assumptions either about the ordering of the step(s) or about the formatting of the number (e.g. 5,252 can be 5.252 depending on user locale). So I need to account for possibilities that can include things like
Step(s) 5.252
as well as what's above.
A few other caveats
All I know is that if the Step(s) line is in there, it will be on its own line (hence in my regex I require \n at each end of the string)
No guarantee that the Mile(s) information will be in the string at all, let alone whether it will be before or after Step(s)
Here's my attempt at pattern extraction:
NSString *patternString = [NSString stringWithFormat:#"\\n(([0-9,\\.]*)\s*%#|%#\s*([0-9,\\.]*))\\n",
NSLocalizedString(#"Step(s)",nil), NSLocalizedString(#"Step(s)",nil)];
There appear to be two problems with this:
XCode is indicating Unknown escape sequence '\s' for the second \s in the pattern string above
No matches are being found even for strings like the following:
0.2 Mile(s)
1,482 Step(s)
Ideally I would extract the 1,482 out of this string in a way that is localization friendly. How should I modify my regex?
as far as the regex, perhaps this approach might work - it simply matches (with named groups) each couplet of numbers in sequence, with the assumption the first is miles and the second is steps. Decimals in the . or , form are optional:
(?<miles>\d+(?:[.,]\d+)?).*?(?<steps>\d+(?:[.,]\d+)?)
(and i think it should be \\s) - i'm not an ios guy, but if you can use a regex literal it would be way more readable.
regular expression demo
First I'd like to ask - Why is Mile(s) mentioned in the question at all?
And now to my two bits - you could simply use a positive look-ahead:
^(?=.*Step\(s\))[^\d]*(\d+(?:[.,]\d+)?)
It makes sure the expected word is present on the line, and then captures the number on it, allowing for localized, optional, decimal separator and decimals. This way it doesn't matter if the numer is before, or after, the "word".
It doesn't take localization of the "word" into account, but that you seem to have handled by yourself ;)
See it here at regex101.
Your regex is close, although in Obj-C you need to double-escape the \s and (s):
^(([0-9,.]*)\\s*%#|%#\\s*([0-9,.]*))$
In your NSLocalizedString you likely also need to escape the parentheses enclosing (s):
NSString *patternString = [NSString stringWithFormat:#"^(([\\d,.]+)\\s%#|%#\\s([\\d,.]+))$",
NSLocalizedString(#"Step\\(s\\)",nil), NSLocalizedString(#"Step\\(s\\)",nil)];
If you don't escape (s) then the regex engine is probably going to interpret it as a capture group.
Looking at NSLog you can see what the pattern actually reads like:
NSLog(#"patternString: %#", patternString);
Output:
patternString: ^(([\d,.]+)\sStep\(s\)|Step\(s\)\s([\d,.]+))$
Since you mentioned the Mile(s) part may not be in the string at all I'm assuming it isn't relevant to the regular expression. As I understand from the question, you just need to capture the number of steps and nothing else. On this basis, here's a modified version of your existing regex:
NSString *patternString =
[NSString stringWithFormat:#"^(?:([0-9,.]*)\\s*%#|%#\\s*([0-9,.]*))$",
NSLocalizedString(#"Step\\(s\\)",nil), NSLocalizedString(#"Step\\(s\\)",nil)];
Demo:
https://www.regex101.com/r/Q6ff1b/1
This is based on the following tips/modifications:
Use the m (= UREGEX_MULTILINE) flag option when creating the regex to specify that ^ and $ match the start and end of each line. This is more sophisticated than using \n as it will also handle the start and end of the string where this might not be present. See here.
Always use a double backslash (\\) for regex escaping - otherwise NSString will interpret the single backslash to be escaping the next character and convert it before it gets to the regex.
Literal parentheses need to be escaped - e.g. Step\\(s\\) instead of Step(s).
Characters within a character class (i.e. anything within the [] square brackets) don't need to be escaped - so it would be . rather than \\. - the latter.
If you are using (x|y|...) as a choice and don't need it to be a capturing group, use ?: after the first parenthesis to ensure it doesn't get captured - i.e. (?:x|y|...).
I need to parse a CSV file with blocks of text being processed in different ways according to certain rules, e.g.
userone,columnone,columntwo
userthirteen,columnone,columntwo
usertwenty,columnone,columntwo
customerone,columnone<br>
customertwo,columntwo<br>
singlevalueone
singlevaluetwo
singlevalueone_otherruleapplies
singlevaluethree_otherruleapplies
Each block of text will be grouped so the first three rows will be parsed using certain rules and so on. Notice that the last two groups have only one single column but each group must be handled in a different way.
I have the chance to propose the customer the format of the file so I'm thinking to propose the following.
[group 1]
userone,columnone,columntwo
userthirteen,columnone,columntwo
usertwenty,columnone,columntwo
[group N]
rowN
A kind of sections like the INI files from some years ago. However I'd like to hear your comments because I think there must be a better way to handle this.
I proposed to use XML but the customer prefers the text files.
Any suggestions are welcome.
m0dest0.
Ps. using VB.net and VS 2008
You can use regular expression groups set to either an enum line mode if each line has the same format, or to an enum multi-line if the format is not constrained to a single line. For each line in multiline you can include \n in your pattern to cross multiple lines to find you pattern. If its on a single line you don't need to include \n also know as Carriage return line feed in your regex matching pattern.
vb.net as well as many other modern programming language has extensive support for grouping operations. You can use index groups, or named groups.
Each name such as header1 or whatever you want to name it would be in this format: <myname>
See this link for more info: How do I access named capturing groups in a .NET Regex?.
Good luck.
Is there a way to verify only part of text present?
If there is a text "Warning: A15P09 has not been activated." I need to verify the text is present. However, 'A15P09' is not always the same, so I cannot do something like
Selenium.IsTextPresent("Warning: A15P09 has not been activated.");
I might do something like:
Selenium.IsTextPresent("has not been activated.");
But is there another way to verify this in Selenium. Please let me know if there is.
Thanks!
You could use getText and then do any normal regex that your language supplies for examining that result.
Edit: And for some languages you can do isTextPresent on a pattern modified string. The documentation states:
Various Pattern syntaxes are available
for matching string values:
glob:pattern: Match a string against a
"glob" (aka "wildmat") pattern. "Glob"
is a kind of limited
regular-expression syntax typically
used in command-line shells. In a glob
pattern, "*" represents any sequence
of characters, and "?" represents any
single character. Glob patterns match
against the entire string.
regexp:regexp: Match a string using a
regular-expression. The full power of
JavaScript regular-expressions is
available.
exact:string: Match a
string exactly, verbatim, without any
of that fancy wildcard stuff.
If no
pattern prefix is specified, Selenium
assumes that it's a "glob" pattern.