I have below details in the table
GEMS#TEST1>select BUILTIN_ARGUMENTS from FND_FORM_CUSTOM_ACTIONS WHERE (RULE_ID = 2243);
BUILTIN_ARGUMENTS
--------------------------------------------------------------------------------
='http://prod.client.com:3001/ords/f?p=1:2:::NO::P_ORDER_HEADER_ID,P_SESSION
_ID:'||${item.ORDER.HEADER_ID.VALUE}||','||${ps.db_session_id.value}
For a need ,I have to update this "prod.client.com:3001" as
"test1-scan.client.com"
When I am executing below getting error
GEMS#TEST1>update FND_FORM_CUSTOM_ACTIONS set = '='http://test1-scan.client.com/ords/f?p=1:2:::NO::P_ORDER_HEADER_ID,P_SESSION
_ID:'||${item.ORDER.HEADER_ID.VALUE}||','||${ps.db_session_id.value}' WHERE (RULE_ID = 2243);
SP2-0552: Bind variable "NO" not declared.
GEMS#TEST1>
I know I might have to use escape character or declare the variable but not getting clue as I am not very good in coding .
Using REPLACE in this case is better.
UPDATE fnd_form_custom_actions
SET builtin_arguments = REPLACE (builtin_arguments, 'prod.client.com:3001',
'test1-scan.client.com')
WHERE rule_id = 2243 ;
You have obvious typos in your statement:
set = '='http://test1-scan.client.com/ords/f?p=1:2:::NO [.......]
set what = .....?
Then: what is with the second equal sign, in single quotes? (OR... I see - did you mean single quotes within the assigned string? You must enter TWO single quotes to represent one single quote in a string!)
Then: since the second equal sign consumes the single quotes, what follows AFTER it is not quoted. So :NO is seen as a bind variable. Correct the syntax and Oracle won't ask you about any bind variables.
With that fixed, look at Kaushik's answer for a better approach altogether.
Related
I have one execute SQL Task in SSIS 2012 which has update statement. I want to pass a string variable in the where clause of this update statement. The update section is as below:
where coalesce(s1.iteration, '') not like '%?%' and s2.Iteration = '?'
Here, ? needs to be replaced with a string variable, which in this case would be 08152017. I have added the variable to the Parameter Mapping. Screenshot is attached.
The task executes successfully but does not updates the value in the intended column. It seems the query is not passing the value.What am I doing wrong? How do I check that the SQL inside the Execute SQL Task is actually getting the value from the variable?
First of all, when you set your variable in parameter mapping, make sure the datatype is NVARCHAR and not LONG.
Second you need to write your statement like this:
where coalesce(s1.iteration, '') not like '%?%' and s2.Iteration = ?
You dont need '' because your variable is already set as a string.
Try to hardcode your value in your variable to see if it passes. Otherwise, set a breakpoint on pre-execute to see wheter your variable has a value.
If your variable has a value and your SQL is not working, maybe you should look into your SQL. Maybe try it directly in SSMS to see if it actually runs or does anything.
In scenario ? is Integer type variable, then please use below format:
SELECT ? +' Hello World!'
The above does not require the use of an additional string variable.
Create a user variable with % on it, for example, variable name is Like_Var with data type String
"%" + #Orig_Var + "%"
Let's say, Orig_Var has a value of 08152017, therefore Like_Var will have %08152017%
Then use Like_Var on your parameter in Execute SQL Task as parameter 0, data type VARCHAR in Parameter Mapping
WHERE COALESCE(s1.iteration, '') NOT LIKE ?
AND s2.Iteration = ?
Its pretty simple question, I know, but I really stacked with a problem with it...
I have a table customer_customer and a column code in it. So I need to find all items with a specific code value. So I wrote that:
SELECT * FROM customer_customer WHERE code LIKE "КL-12345"
and got an error:
column "КL-12345" does not exist
Why КL-12345 became a column if I specify it as value of code column? What am I doing wrong?
String literals must be enclosed in single quotes.
By enclosing it in double quotes, you specified a variable name.
Also, note that your where condition is the same as writing
where code = 'КL-12345'
LIKE is used for pattern matching. For instance you would match all codes that contain 'KL-12345' like this
where code like '%KL-12345%'
Change it to single quotes
SELECT * FROM customer_customer WHERE code LIKE 'КL-12345'
or
SELECT * FROM customer_customer WHERE code = 'КL-12345'
I am still getting my head around a PDO statement but the code below does not do what I assumed it would
$temp = "6c ";
$weather_report = "Its currently $temp " ;
$qry = $pdo->exec("UPDATE data_weather SET text= '$weather_report' WHERE period='report' ");
This does update my database but only with 'Its currently' and the temp value is missing ,
After reading some articles I believe I need to use quote but I am not sure how to implement it ?
any help please ?
Please use query parameters instead of interpolating variables into SQL strings.
It's safer, faster, and easier.
$temp = "6c ";
$weather_report = "It's currently $temp " ;
$sql = "UPDATE data_weather SET text= ? WHERE period='report'";
$stmt = $pdo->prepare($sql);
$stmt->execute(array($weather_report));
Note that you don't need to quote the string. In fact, you must not put quotes around the ? placeholder. You can use apostrophes inside your weather report string safely.
You can use a parameter placeholder any place you would normally put a single scalar value in an SQL expression. E.g. in place of a quoted string, quoted date, or numeric literal. But not for table names or column names, or for lists of values, or SQL keywords.
Although Bill has already answered the question, I'd like to add:
Do not use named parameters with TEXT columns, at least not with MySQL. It won't work. Use question marks instead.
I have the following variables:
[string]$eth_netmask = "ext_netmask"
[string]$ext_netmask = "255.255.252.0"
$($eth_netmask) is returning ext_netmask. I was expecting 255.255.252.0
What am I doing wrong?
Thanks for the help in advance!
The command $eth_netmask returns the value of the variable named eth_netmask. The expression $(something) has nothing to do with variables, but instead evaluates the contents of the parentheses before evaluating the rest of the statement. That means that the statement $($eth_netmask) will evaluate in two steps:
1: $($eth_netmask) evaluates to the command "ext_netmask"
2: "ext_netmask" evaluates as a command which has the result of printing ext_netmask to the output.
This format is unnecessary since variables are normally resolved before the rest of the command anyway. My recommendation would be to avoid needing to do this at all if there is any alternative. Putting this kind of roundabout referencing into a piece of code can only cause problems. However, if you can't avoid it for some reason, it is possible to reference a variable the name of which is stored in another variable.
[string]$eth_netmask = "ext_netmask"
[string]$ext_netmask = "255.255.252.0"
Get-Variable -Name $eth_netmask -ValueOnly
This is the point at which the $(something) syntax becomes useful. If you need to use the value that you have just returned in another command, such as if the value was an ip that you were trying to ping, you might do something like this:
Test-Connection $(Get-Variable -Name $eth_netmask -ValueOnly)
I have updated many records already, but when it came to a word that contains a quote I get this error: "ERROR: Unclosed quote # 1357"
I know why it's giving me this error, I just don't how to solve it.
Here's a sample:
UPDATE invnum SET cAccountName = replace(cAccountName,'JOHN'S','BEN')
Thanks in advance.
Escape quotes inside strings:
UPDATE invnum SET cAccountName = replace(cAccountName,'JOHN\'S','BEN')
You want to be really careful with this - not dealing with this properly is the source of SQL injection attacks, and is a major source of security problems.
if you’re using a script to update your records use a builtin escaping function. for php that would be mysql_real_escape_string
Try this instead:
UPDATE invnum SET cAccountName = replace(cAccountName,"JOHN'S","BEN")
If you need to use both types of quotes within a string, then you'll need to escape the type of quotes you use to surround the string when they occur within it (otherwise the SQL interpreter will think the string ends before it actually does.
For instance:
Johns becomes "Johns"
John's becomes "John's" or 'John\'s'
"John" becomes '"John"' or "\"John\""
et cetera.