Its pretty simple question, I know, but I really stacked with a problem with it...
I have a table customer_customer and a column code in it. So I need to find all items with a specific code value. So I wrote that:
SELECT * FROM customer_customer WHERE code LIKE "КL-12345"
and got an error:
column "КL-12345" does not exist
Why КL-12345 became a column if I specify it as value of code column? What am I doing wrong?
String literals must be enclosed in single quotes.
By enclosing it in double quotes, you specified a variable name.
Also, note that your where condition is the same as writing
where code = 'КL-12345'
LIKE is used for pattern matching. For instance you would match all codes that contain 'KL-12345' like this
where code like '%KL-12345%'
Change it to single quotes
SELECT * FROM customer_customer WHERE code LIKE 'КL-12345'
or
SELECT * FROM customer_customer WHERE code = 'КL-12345'
Related
I need to work through how to take stored procedure functions from
region-us.INFORMATION_SCHEMA.ROUTINES
and modify the backticks that default to coming through around the project and place them around the dataset.schema.table()
The reason is more for uniform results across our system than a technical error need.
currently when I run this query
SELECT
replace(ddl, 'CREATE PROC', 'CREATE OR REPLACE PROC'),
FROM region-us.INFORMATION_SCHEMA.ROUTINES
where lower(routine_type) = 'procedure'
It will return the below:
`project-data-sandbox`.schema.MySP()
`project-data-sandbox`.schema.YourSP(MySP)
`project-data-sandbox`.inv.partnumber(orderid)
`project-data-sandbox`.inv_part.part_number(part_id)
I have tried the below query
SELECT
REGEXP_REPLACE(ddl, r"project-data-sandbox`.", "project-data-sandbox.") AS replaced_word
, REGEXP_REPLACE(ddl, r'`([a-zA-Z]+(-[a-zA-Z]+)+)`\.[a-zA-Z]+\.[a-zA-Z]+\(\)','Apples') tester
FROM region-us.INFORMATION_SCHEMA.ROUTINES
where lower(routine_type) = 'procedure'
I get part of what I want. However, the problem is our stored procedures can be named any sort of names and they could require objects to be passed to them.
I added the tester column to see if I could replace the project string with another word (or regex) but it isn't even replacing it with apples yet.
which I would want turned into this:
`project-data-sandbox.schema.MySP`()
`project-data-sandbox.schema.YourSP`(MySP)
`project-data-sandbox.inv.partnumber`(orderid)
`project-data-sandbox.inv_part.part_number`(part_id)
I'm working through Regexp_replace but I'm having difficulty figuring out how to get the backtick between the parenthesis and the last letter.
Thanks for any help!
I have a table in my database called systemconfig which has some configs that I'll use on my reports. The idea is, instead of adjusting the 'number formats' directly in the textboxes properties of the report, I just change a value in this table, and then through a custom expression in the format property, it gets the value from this table
The query of the dataset 'ds_DecimalValues' is like this:
DECLARE #DecimalValue Nvarchar(500)
SELECT #DecimalValue =
( SELECT Value as 'DecimalValue' FROM SystemConfig WHERE Key = Decimal_Value )
SELECT
DecimalValue = #DecimalValue
ok, the result of this query is ##
In the textbox properties I have this expression in the Format line:
=First(Fields!DecimalValue.Value, "ds_DecimalValue")
But the report is showing 2 decimal values instead of none. I'm not sure if the decimal values are correct on the systemconfig table, I assume that '##' is correct to show no decimal values but I'm not sure about it. Any ideas guys??
Regards.
Would something like this work for you? Should round it to the nearest integer
=Floor(First(Fields!DecimalValue.Value, "ds_DecimalValue"))
When I have done this in the past I would typically use someting like f0 or n0 as the format code.
Try using this instead of ##.
If this does not work then a couple of things to debug.
Add a textbox that contains the same expression as you are using in your format property expression, make sure it is returning what you expect
Type the format code directly in and make sure that it formats as you expected.
remember that you don't need to use quotes when using codes like f0 etc.
In vba I am openening a table from access with a column that look like the following:
1300nm11-53-0202 0302.SOR
I would like to look for the very first time "nm" is found in the string and write everything that is before that into a variable "strGolfLengte" (so In this case strGolflengte would be "1300")
NB:
I can't be sure that there won't be several nm's in the string, I just want to look for the first time they are found.
NB2:
The string before nm could be "n" characters, in all cases, I want the full lenght (n) of the string written in strGolflengte
I would use the `instr()' function like this:
strGolfLengte = left(myLine,instr(1,myLine,"nm",1))
I think it is the easiest way to do this:
strGolfLengte = Split(myLine,"nm")(0)
I have a field called OrderNumber and there's already a record with that field value of "JY8023".
I tried querying using this SQL code, but it returned nothing.
SELECT .... WHERE OrderNumber LIKE "JY8023"
I also tried using wildcards and it worked
SELECT .... WHERE OrderNumber Like "%JY8023%"
So does that mean OrderNumber Like "JY9023" is not the same as OrderNumber = "JY8023"?
the string has characters before or after it, that you can't see. try something like select length(OrderNumber) WHERE OrderNumber Like "%JY8023%" to confirm this. Some characters are not only invisible, but unselectable with a cursor. But, they're there and they affect string comparisons.
additional debugging steps to follow will be to use substring to extract the offending part, and other string functions to further inspect the value. like, maybe selecting the string as a hex encoded string will help you identify the bytes.
I have a text field which acts a filter field. It checks for equals, contains and starts with. My problem is, with out changing any of my code, can I check for the 'does not contain', 'does not start with' and so on by just using the string i'm passing with something like '!' operator or "<>"?
for example:
I want to get all the records that do not have 'a' in them, so can I pass the string as "!a" or "<>a" or something so that I can get the required records? (I know these two don't work cause I tried.)
You have to use the keyword NOT, e.g.
SELECT * FROM Table WHERE Foo NOT LIKE '%bar%'
Please refer http://www.sqlservercentral.com/Forums/Topic1213442-338-1.aspx
Can solve with case in where clause