I want to split the below string (present in a single column) separated by spaces from the end. For the below 3 rows, I want the following output
OUTPUT:
Country STATE STREET UNIT
AU NSW 2 12
AU NSW 51
AU NSW 12
INPUT:
12 2 NOELA PLACE ST MARYS NSW 2760 AU
51 MALABAR ROAD SOUTH COOGEE NSW 2034 AU
12 LISTER STREET WINSTON HILLS NSW 2153 AU
of course such conditional parsing is not reliable:
t=# with v(a) as( values('12 2 NOELA PLACE ST MARYS NSW 2760 AU')
,('51 MALABAR ROAD SOUTH COOGEE NSW 2034 AU')
,('12 LISTER STREET WINSTON HILLS NSW 2153 AU')
)
select reverse(split_part(reverse(a),' ',1)), reverse(split_part(reverse(a),' ',3)), case when split_part(a,' ',2) ~ '\d' then split_part(a,' ',2) end st, split_part(a,' ',1) un from v;
reverse | reverse | st | un
---------+---------+----+----
AU | NSW | 2 | 12
AU | NSW | | 51
AU | NSW | | 12
(3 rows)
Related
I would like to get a cartesian product of several tables in SQL (which are actually only one column, so no common key). For example:
TABLE A
Robert
Pierre
Samuel
TABLE B
Montreal
Chicago
TABLE C
KLM
AIR FRANCE
FINAL TABLE (CROSS PRODUCT)
Robert | Montreal | KLM
Pierre | Montreal | KLM
Samuel | Montreal | KLM
Robert | Chicago | KLM
Pierre | Chicago | KLM
Samuel | Chicago | KLM
Robert | Montreal | AIR FRANCE
Pierre | Montreal | AIR FRANCE
Samuel | Montreal | AIR FRANCE
Robert | Chicago | AIR FRANCE
Pierre | Chicago | AIR FRANCE
Samuel | Chicago | AIR FRANCE
I tried CROSS JOIN, but I couldn't find an example with multiple tables. Is the only way to do it is nesting? What if we have 15 tables to join that way... it creates a very long code.
Thank you!
You would simply use:
select *
from a cross join b cross join c;
Do note that if any of the tables are empty (i.e. no rows), you will get no results.
Sorry if this has been asked before, I couldn't find it.
I have census population dataframe that contains the population of each county in the US.
The relevant part of df looks like:
+----+--------+---------+----------------------------+---------------+
| | REGION | STNAME | CTYNAME | CENSUS2010POP |
+----+--------+---------+----------------------------+---------------+
| 1 | 3 | Alabama | Autauga County | 54571 |
+----+--------+---------+----------------------------+---------------+
| 2 | 3 | Alabama | Baldwin County | 182265 |
+----+--------+---------+----------------------------+---------------+
| 69 | 4 | Alaska | Aleutians East Borough | 3141 |
+----+--------+---------+----------------------------+---------------+
| 70 | 4 | Alaska | Aleutians West Census Area | 5561 |
+----+--------+---------+----------------------------+---------------+
How I can get the np.std of the states population (sum of counties' population) for each of the four regions in the US without modifying the df?
You can use transform:
df['std_col'] = df.groupby('STNAME')['CENSUS2010POP'].transform("std")
IIUC, if you want sum of counties, you do:
state_pop = df.groupby('STNAME')['CTYNAME'].nunique().apply(np.std)
You can also directly use the standard deviation method std()
new_df=df.groupby(['REGION'])[['CENSUS2010POP']].std()
I am having a hive table with column state as
**state**
taxes, TX
Washington, WA
New York, NY
New Jersey, NJ
Now I want to separate the state column and I want to write it in new columns as
**state** **code**
taxes TX
Washington WA
New York NY
New Jersey NJ
select split(state,',')[0] as state
,ltrim(split(state,',')[1]) as code
from mytable
+------------+------+
| state | code |
+------------+------+
| taxes | TX |
| Washington | WA |
| New York | NY |
| New Jersey | NJ |
+------------+------+
select substr (name,0,instr(name,',')-1), substr (name ,instr(name,',')+1,10) from aa
I have Two tables in Postgresql and I'm trying to get the number of times a hashtag is repeated by place.
I've made this query:
SELECT tweets_with_location.user_location,
tweets_with_location.my_new_id,
all_hashtags_with_location.regexp_split_to_table
FROM tweets_with_location, all_hashtags_with_location
WHERE tweets_with_location.my_new_id = all_hashtags_with_location.my_new_id;
Which returns the Location, the tweet id and the hashtag:
USER_LOCATION | MY_NEW_ID | HASHTAG
New York, NY | 33 | Happy
New York, NY | 40 | BigApple
Bronx, NY | 12 | Happy
Bronx, NY | 45 | Happy
Queens, NY | 23 | Trump
Queens, NY | 20 | Trump
Then, I've made another SQL Query but it seems it doesn't sums up the number of times a hashtag was displayed by place, the Count value is always 1:
SELECT tweets_with_location.user_location,
all_hashtags_with_location.regexp_split_to_table,
COUNT(DISTINCT all_hashtags_with_location.regexp_split_to_table) AS CountOf
FROM tweets_with_location, all_hashtags_with_location
WHERE tweets_with_location.my_new_id = all_hashtags_with_location.my_new_id
GROUP BY tweets_with_location.user_location,
all_hashtags_with_location.regexp_split_to_table
ORDER BY CountOf DESC;
I need is this result:
USER_LOCATION - HASHTAG - COUNT
New York, NY | Happy | 1
Bronx, NY | Happy | 2
Queens, NY | Trump | 2
New York, NY | Happy | 1
How do I do this? What is wrong with my SQL Query?
Or just remove the DISTINCT qualifier in the COUNT() function.
You were really close, you are counting the wrong field:
SELECT tweets_with_location.user_location,
all_hashtags_with_location.regexp_split_to_table,
COUNT(DISTINCT tweets_with_location.my_new_id) AS CountOf
FROM tweets_with_location, all_hashtags_with_location
WHERE tweets_with_location.my_new_id = all_hashtags_with_location.my_new_id
GROUP BY tweets_with_location.user_location,
all_hashtags_with_location.regexp_split_to_table
ORDER BY CountOf DESC;
I have three tables like this:
Person table:
person_id | name | dob
--------------------------------
1 | Naveed | 1988
2 | Ali | 1985
3 | Khan | 1987
4 | Rizwan | 1984
Address table:
address_id | street | city | state | country
----------------------------------------------------
1 | MAJ Road | Karachi | Sindh | Pakistan
2 | ABC Road | Multan | Punjab | Pakistan
3 | XYZ Road | Riyadh | SA | SA
Person_Address table:
person_id | address_id
----------------------
1 | 1
2 | 2
3 | 3
Now I want to get all records of Person_Address table but also with their person and address records like this by one query:
person_id| name | dob | address_id | street | city | state | country
----------------------------------------------------------------------------------
1 | Naveed | 1988 | 1 | MAJ Road | Karachi | Sindh | Pakistan
2 | Ali | 1985 | 2 | ABC Road | Multan | Punjab | Pakistan
3 | Khan | 1987 | 3 | XYZ Road | Riyadh | SA | SA
How it is possible using zend? Thanks
The reference guide is the best starting point to learn about Zend_Db_Select. Along with my example below, of course:
//$db is an instance of Zend_Db_Adapter_Abstract
$select = $db->select();
$select->from(array('p' => 'person'), array('person_id', 'name', 'dob'))
->join(array('pa' => 'Person_Address'), 'pa.person_id = p.person_id', array())
->join(array('a' => 'Address'), 'a.address_id = pa.address_id', array('address_id', 'street', 'city', 'state', 'country'));
It's then as simple as this to fetch a row:
$db->fetchRow($select);
In debugging Zend_Db_Select there's a clever trick you can use - simply print the select object, which in turn invokes the toString method to produce SQl:
echo $select; //prints SQL
I'm not sure if you're looking for SQL to do the above, or code using Zend's facilities. Given the presence of "sql" and "joins" in the tags, here's the SQL you'd need:
SELECT p.person_id, p.name, p.dob, a.address_id, street, city, state, country
FROM person p
INNER JOIN Person_Address pa ON pa.person_id = p.person_id
INNER JOIN Address a ON a.address_id = pa.address_id
Bear in mind that the Person_Address tells us that there's a many-to-many relationship between a Person and an Address. Many Persons may share an Address, and a Person may have more than one address.
The SQL above will show ALL such relationships. So if Naveed has two Address records, you will have two rows in the result set with person_id = 1.