I'm trying to merge two very similar queries. The only different thing is in the WHERE clause:
SELECT
CONVERT(VARCHAR(10), Date, 101) as Date,
COUNT(*) as WinnerCount
FROM
table t1
WHERE
t1.Result = 'Winner'
GROUP BY
CONVERT(VARCHAR(10), Date, 101)
and the second with Loser clause:
SELECT
CONVERT(VARCHAR(10), Date, 101) as Date,
COUNT(*) as LoserCount
FROM
table t1
WHERE
t1.Result = 'Loser'
GROUP BY
CONVERT(VARCHAR(10), Date, 101)
What I'm trying to achieve is to get a result set like this:
Date | WinnerCount | LoserCount
01/01/2017 24 16
17/02/2017 13 9
I've tried to merge this with join as two resultset:
SELECT
FirstSet.Date
FROM
(SELECT
CONVERT(VARCHAR(10), Date, 101) as Date,
COUNT(*) as Count
FROM
table t1
WHERE
t1.Result = 'Winner'
GROUP BY
CONVERT(VARCHAR(10), Date, 101)) AS FirstSet
JOIN
(SELECT
CONVERT(VARCHAR(10), Date, 101) as Date,
COUNT(*) as Count
FROM
table t1
WHERE
t1.Result = 'Loser'
GROUP BY
CONVERT(VARCHAR(10), Date, 101)) AS SecondSet ON FirstSet.Date = SecondSet.Date
ORDER BY
FirstSet.Date
but in results I got only dates :/
You may use this query. Insted of counting all the rows, you may SUM all the occurrences of the required text (*Winner" or "Loser" in this case).
SELECT
CONVERT(VARCHAR(10), Date, 101) as Date,
SUM(CASE WHEN t1.Result = 'Winner' THEN 1 ELSE 0 END) as WinnerCount,
SUM(CASE WHEN t1.Result = 'Loser' THEN 1 ELSE 0 END) as LoserCount
from table t1
where t1.Result in ( 'Winner', 'Loser')
group by
CONVERT(VARCHAR(10), Date, 101)
The above accepted answer will provide you with the correct result however if you wanted to keep the Count and not use Sum to aggregate the results then you could alternatively use the below:
select
CONVERT(VARCHAR(10), Date, 101) as Date,
COUNT(CASE WHEN t1.Result = 'Winner' THEN 1 ELSE NULL END) as WinnerCount,
COUNT(CASE WHEN t1.Result = 'Loser' THEN 1 ELSE NULL END) as LoserCount
from table as t1
where t1.Result in ('Winner', 'Loser')
group by
CONVERT(VARCHAR(10), Date, 101)
You can try something like:
SELECT
CONVERT(VARCHAR(10), Date, 101) as Date,
SUM(CASE WHEN t1.Result = 'Winner' THEN 1 ELSE 0) AS WinnerCount,
SUM(CASE WHEN t1.Result = 'Loser' THEN 1 ELSE 0) AS LoserCount
FROM
table t1
group by
CONVERT(VARCHAR(10), Date, 101)
Related
Assume a table of purchase transactions with columns CustId, Amount, DatePosted where Amount is the value of the transaction, and DatePosted is a DATETIME value. Given a specific CustId, how would I write a select such that it returns a single row with the following columns: CustId, total value of transactions in the last 3 days, last 60 days, 1 year, 2 years (5 columns total).
Example table:
CustId
Amount
DatePosted
1234
698.02
2023-01-23Z12:34:56
1234
582.69
2022-12-15Z19:57:23
1234
7775.22
2022-12-02Z02:34:32
1234
18.72
2022-01-23Z12:34:56
1234
2.27
2021-01-23Z12:34:56
Expected output given the sample data above when searching using CustId=1234:
CustId
3-day Total
60-day Total
1 year Total
2 year Total
1234
698.02
9055.93
9074.65
9076.92
You could get all purchase data for the last 2 years, then using SUM with SQL CASE expression to calculate total value for each time-range.
SELECT
CustId,
SUM(CASE WHEN DatePosted >= Last3Day THEN Amount ELSE 0 END) AS [3-day Total],
SUM(CASE WHEN DatePosted >= Last60Day THEN Amount ELSE 0 END) AS [60-day Total],
SUM(CASE WHEN DatePosted >= Last1Year THEN Amount ELSE 0 END) AS [1 year Total],
SUM(CASE WHEN DatePosted >= Last2Year THEN Amount ELSE 0 END) AS [2 year Total]
FROM
<your data table>,
(SELECT
DATEADD(DAY, -3, GETDATE()) AS Last3Day,
DATEADD(DAY, -60, GETDATE()) AS Last60Day,
DATEADD(YEAR, -1, GETDATE()) AS Last1Year,
DATEADD(YEAR, -2, GETDATE()) AS Last2Year) timerange
WHERE DatePosted >= Last2Year
GROUP BY CustId;
Demo: http://sqlfiddle.com/#!18/9eecb/179880
This query assumes 2 year max. If you want to go further back then change the where clause as well. No need to use coalesce or a derived table. SQL server query planner may be smart enough to provide similar performance for all these solutions but this is easier to understand:
SELECT
CustId,
SUM(CASE WHEN DatePosted >= DATEADD(day, -3, GETDATE()) THEN Amount ELSE 0 END) AS [3-day Total],
SUM(CASE WHEN DatePosted >= DATEADD(day, -60, GETDATE()) THEN Amount ELSE 0 END) AS [60-day Total],
SUM(CASE WHEN DatePosted >= DATEADD(year, -1, GETDATE()) THEN Amount ELSE 0 END) AS [1 year Total],
SUM(Amount) AS [2 year Total]
FROM PurchaseTransactions
WHERE CustId = 1234 AND DatePosted >= DATEADD(year, -2, GETDATE())
GROUP BY CustId
This is set up so that you can set #CustID = null and the query will return results for all customers in the set.
EDIT: Updated my query below to give you more flexibility across your desired ranges should you wish to derive additional heuristics. (Counts, averages, etc.)
Also removed coalesce as it's simply not needed here.
DECLARE #CustID BIGINT;
SELECT table1.custID,
SUM([3Day].amount) AS [3DayTotal],
COUNT([3Day].amount) AS [3DayCount]
SUM([60Day].amount) AS [60DayTotal],
SUM([1Year].amount) AS [1YearTotal],
Sum([2Year].amount) AS [2YearTotal],
AVG([2Year].amount) AS [2YearAverage]
FROM table1 LEFT OUTER JOIN
(SELECT custID, Amount FROM table1 WHERE DatePosted > DATEADD(DAY, -3, GETDATE())) AS [3Day] ON table1.CustID = [3Day].CustID LEFT OUTER JOIN
(SELECT custID, Amount FROM table1 WHERE DatePosted > DATEADD(DAY, -60, GETDATE())) AS [60Day] ON table1.CustID = [60Day].CustID LEFT OUTER JOIN
(SELECT custID, Amount FROM table1 WHERE DatePosted > DATEADD(YEAR, -1, GETDATE())) AS [1Year] ON table1.CustID = [1Year].CustID LEFT OUTER JOIN
(SELECT custID, Amount FROM table1 WHERE DatePosted > DATEADD(YEAR, -2, GETDATE()) AS [2Year] ON table1.CustID = [2Year].CustID
WHERE table1.CustID = #CustID
OR #CustID IS NULL
GROUP BY table1.CustID
I am trying to get data for last 2 month ...but the query does not give perfect result....
SELECT DAY(table_A.PaymentDate) as date1 ,
(case when MONTH(table_A.PaymentDate) = MONTH(CURRENT_TIMESTAMP) - 1
then CAST(SUM(table_A.Total_Amount) AS INT)
else 0
end) AS last_month_CNT,
(case when MONTH(table_A.PaymentDate) = MONTH(CURRENT_TIMESTAMP)
then CAST(SUM(table_A.Total_Amount) As INT)
else 0
end) as This_month_CNT
FROM Tbl_Pan_Paymentdetails table_A
FULL OUTER JOIN Tbl_Pan_Paymentdetails table_B
ON table_A.PaymentDate=table_B.PaymentDate
WHERE YEAR(table_A.PaymentDate) = YEAR(CURRENT_TIMESTAMP)
AND
table_A.PaymentDate >= DATEADD(MONTH, -1, GETDATE())
GROUP BY
DAY(table_A.PaymentDate) ,MONTH(table_A.PaymentDate)
order by
DAY(table_A.PaymentDate);
Move the entire case expression inside the sum function and don't include the month in the group by. Also, the full outer join seems unnecessary so I removed it.
This should be what you are looking for:
SELECT
DAY(PaymentDate) as date1 ,
SUM(CASE WHEN MONTH(PaymentDate) = MONTH(CURRENT_TIMESTAMP)-1 THEN CAST(Total_Amount AS INT) ELSE 0 END) AS last_month_CNT,
SUM(CASE WHEN MONTH(PaymentDate) = MONTH(CURRENT_TIMESTAMP) THEN CAST(Total_Amount AS INT) ELSE 0 END) AS This_month_CNT
FROM Tbl_Pan_Paymentdetails
WHERE YEAR(PaymentDate) = YEAR(CURRENT_TIMESTAMP)
AND PaymentDate >= DATEADD(MONTH, -1, GETDATE())
GROUP BY DAY(PaymentDate)
ORDER BY DAY(PaymentDate);
I have Table1 and I need a query to populate Table2:
Problem here is with Date column. I want to know the process of location/partner combination per day. Main issue here is that I can't pick DateCreated and make it as default date since it doesn't necessarily cover whole date range, like in this example where it doesn't have 2015-01-07 and 2015-01-09. Same case with other dates.
So, my idea is to first select dates from some table which contains needed date range and then perform calculation for each day/location/partner combination from cte but in that case I can't figure out how to make a join for LocationId and PartnerId.
Columns:
Date - CreatedItems - number of created items where Table1.DateCreated = Table2.Date
DeliveredItems - number of delivered items where Table1.DateDateOut = Table2.Date
CycleTime - number of days delivered item was in the location (DateOut - DateIn + 1)
I started with something like this but it's very like that I completely missed the point with it:
with d as
(
select date from DimDate
where date between DATEADD(DAY, -365, getdate()) and getdate()
),
cr as -- created items
(
select
DateCreated,
LocationId,
PartnerId,
CreatedItems = count(*)
from Table1
where DateCreated is not null
group by DateCreated,
LocationId,
PartnerId
),
del as -- delivered items
(
select
DateOut,
LocationId,
ParnerId,
DeliveredItems = count(*),
CycleTime = DATEDIFF(Day, DateOut, DateIn)
from Table1
where DateOut is not null
and Datein is not null
group by DateOut,
LocationId,
PartnerId
)
select
d.Date
from d
LEFT OUTER JOIN cr on cr.DateCreated = d.Date -- MISSING JOIN PER LocationId and PartnerId
LEFT OUTER JOIN del on del.DateCompleted = d.Date -- MISSING JOIN PER LocationId and PartnerId
with range(days) as (
select 0 union all select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 /* extend as necessary */
)
select dateadd(day, r.days, t.DateCreated) as "Date", locationId, PartnerId,
sum(
case
when dateadd(day, r.days, t.DateCreated) = t.DateCreated
then 1 else 0
end) as CreatedItems,
sum(
case
when dateadd(day, r.days, t.DateCreated) = t.Dateout
then 1 else 0
end) as DeliveredItems,
sum(
case
when dateadd(day, r.days, t.DateCreated) = t.Dateout
then datediff(days, t.DateIn, t.DateOut) + 1 else 0
end) as CycleTime
from
<yourtable> as t
inner join range as r
on r.days between 0 and datediff(day, t.DateCreated, t.DateOut)
group by dateadd(day, r.days, t.DateCreated), LocationId, PartnerId;
If you only want the end dates (rather than all the dates in between) this is probably a better approach:
with range(dt) as (
select distinct DateCreated from T union
select distinct DateOut from T
)
select r.dt as "Date", locationId, PartnerId,
sum(
case
when r.dt = t.DateCreated
then 1 else 0
end) as CreatedItems,
sum(
case
when r.dt = t.Dateout
then 1 else 0
end) as DeliveredItems,
sum(
case
when r.dt = t.Dateout
then datediff(days, t.DateIn, t.DateOut) + 1 else 0
end) as CycleTime
from
<yourtable> as t
inner join range as r
on r.dt in (t.DateCreated, t.DateOut)
group by r.dt, LocationId, PartnerId;
If to specify WHERE clause? Something Like that:
WHERE cr.LocationId = del.LocationId AND
cr.PartnerId = del.PartnerId
I have a dataset I retrieve from multiple joins. I have used SELECT DISTINCT in my statements but I still see duplicates in the result set. Here is the code:
SELECT DISTINCT Account
, PayoffAmtDOL as 'Payoff Amount DOL'
, PayoffAmtLOG as 'Payoff Amount LOG'
, PayoffAmountLive as 'Payoff Amount Live'
, [Difference]
, PrincipalBalance as 'Principal Balance'
, CreationDate as 'Date Entered System'
, CACSState as 'CACS State at Entry'
, PaymentsMade AS 'Payments Made'
, TotalPaymentAmount as 'Total Payment Amount'
, 'Liquidation Percentage' = CASE WHEN PayoffAmountLive = 0 THEN 1
WHEN ISNULL([Difference],0) = ISNULL(PayoffAmtDOL, 0) THEN 1
WHEN ISNULL([Difference],0) < 0 AND ISNULL(PayoffAmtDOL, 0) > 0 THEN 0
WHEN ISNULL([Difference],0) > 0 AND ISNULL(PayoffAmtDOL, 0) < 0 THEN 1
WHEN ISNULL([Difference],0) > ISNULL(PayoffAmtDOL, 0) THEN 1
WHEN [Difference] > 0 AND ISNULL(PayoffAmtDOL, 0) = 0 THEN 1
WHEN ISNULL(PayoffAmtDOL, 0) = 0 THEN 0
ELSE ISNULL([Difference],0)/ISNULL(PayoffAmtDOL, 0) END
, Cnt = 1
FROM
(
SELECT DISTINCT a.Account,
c.PayoffAmtDOL,
c.PayoffAmtLOG,
(ISNULL(c.PayoffAmtCACS, cacs.payoff_amt)) as 'PayoffAmountLive',
(ISNULL(c.PayoffAmtDOL, 0) - (ISNULL(c.PayoffAmtCACS , ISNULL(cacs.payoff_amt, 0)))) as 'Difference',
c.PrincipalBalance,
c.CreationDate,
c.CACSState,
(SELECT COUNT(PaymentID)
FROM tblATLPaymentInfo p
WHERE p.AccountID = a.AccountID
AND CONVERT(DATETIME, CONVERT(VARCHAR(10), p.CreationDate, 101)) >= '1/1/2014'
AND CONVERT(DATETIME, CONVERT(VARCHAR(10), p.CreationDate, 101)) <= '3/27/2014'
) as 'PaymentsMade',
(SELECT SUM(PaymentAmount)
FROM tblATLPaymentInfo p
WHERE p.AccountID = a.AccountID
AND CONVERT(DATETIME, CONVERT(VARCHAR(10), p.CreationDate, 101)) >= '1/1/2014'
AND CONVERT(DATETIME, CONVERT(VARCHAR(10), p.CreationDate, 101)) <= '3/27/2014'
) as 'TotalPaymentAmount'
FROM tblATLAcctInfo a
RIGHT JOIN tblATLClaimInfo c
ON c.AccountID = a.AccountID
LEFT JOIN SCFLOKYDCMSQL03.CACS_DM.dbo.Cacs_Info cacs
ON cacs.Account = a.Account
WHERE CONVERT(DATETIME, CONVERT(VARCHAR(10), c.CreationDate, 101)) >= '1/1/2014'
AND CONVERT(DATETIME, CONVERT(VARCHAR(10), c.CreationDate, 101)) <= '3/27/2014'
AND c.ClaimTypeID = (SELECT DISTINCT ClaimTypeID FROM tblATLClaimType WHERE ClaimType = 'N02 - Claims')
) a
ORDER BY Account
Here is an example of the duplicate rows:
AccountID DateEntered
123 01/19/2014
123 01/21/2014
345 02/1/2014
345 02/10/2014
The difference between appears to be the date entered. Maybe selecting the Row_Number() and then deleting the later date could be a solution
DISTINCT should not return multiple rows.. there should be at least one column that is different in each row, no? With character data, sometimes one can be fooled by non-visible differences, such as trailing spaces. Not sure if that is the case here, though.
Can you give an example of the duplicate rows?
OK, I see your edit. You have to select which of the dates to display. Try this to get the earliest date per AccountID:
SELECT AccountID, MIN(DateEntered) AS DateEntered
FROM ....
GROUP BY AccountID
ORDER BY AccountID
You can add more columns in the SELECT, as long as they are distinct you will not get more rows.
If you want, you can add COUNT(*) to the select to get the number of rows grouped.
DISTINCT will only reject lines that are exact duplicates, the DateEntered is different on each ID. If you want the latest, use Max(DateEntered)
I am trying to count instances of a status by current day and current week, grouped by town.
(The table has just 3 columns: Town, status, status_date)
SELECT
MAX(dbo.Clients.Town) AS Town,
CASE
WHEN MAX(datepart(wk, status_date)) = DATEPART(wk, getdate()) THEN COUNT(Town)
ELSE 0
END AS wkTotal,
CASE
WHEN MAX(CONVERT(date, status_date, 106)) = CONVERT(date, getdate(), 106) THEN COUNT(Town)
ELSE 0
END AS dayTotal
FROM
dbo.Clients
WHERE
dbo.Clients.Status LIKE 'Status 1%'
AND MONTH(GETDATE()) = MONTH(dbo.Clients.Status_date)
AND YEAR(GETDATE())= YEAR(dbo.Clients.Status_date)
GROUP BY
dbo.Clients.Town
ORDER BY
dbo.Clients.Town
This code just returns a month count for both day total and week total columns
Hope you can help.
I surgest you do this:
SELECT dbo.Clients.Town AS Town,
count(*) AS wkTotal,
sum(CASE WHEN datepart(dayofyear, status_date) = DATEPART(dayofyear, getdate()) THEN 1 ELSE 0 END) AS dayTotal
FROM dbo.Clients
WHERE dbo.Clients.Status LIKE 'Status 1%' AND
datepart(week, GETDATE()) = datepart(week, dbo.Clients.Status_date)
AND YEAR(GETDATE())= YEAR(dbo.Clients.Status_date)
GROUP BY dbo.Clients.Town
ORDER BY dbo.Clients.Town